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NEET • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Mixed difficulty

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1 Medium
1 of 200
Understanding +4 | -1
Velocity-time curve for a body projected vertically upwards is
View answer and explanation
Correct option: D
Straight line
Option D (Straight line) is correct because the velocity changes linearly with time due to constant acceleration (gravity).
2 Medium
2 of 200
Understanding +4 | -1
Two cars A and B approach each other at the same speed, then what will be the velocity of A if velocity of B is 8 m/s8 \mathrm{~m} / \mathrm{s}?
View answer and explanation
Correct option: C
−8 m/s-8 \mathrm{~m} / \mathrm{s}
Option C (-8 m/s) is correct. Since the cars approach each other at the same speed, if the velocity of B is 8 m/s, the velocity of A must be -8 m/s, considering opposite directions.
3 Medium
3 of 200
Application +4 | -1
Two cars are moving in the same direction with a speed of 30kmh−130\mathrm{km}{\mathrm{h}^{ - 1}}. They are separated from each other by 5 km. Third car moving in the opposite direction meets the two cars after an interval of 4 min. What is the speed of the third car?
View answer and explanation
Correct option: D
45kmh−1\mathrm{45km}{\mathrm{h}^{ - 1}}
Option D (45kmh−1\mathrm{45km}{\mathrm{h}^{ - 1}}) is correct because it is calculated by using the concept of relative speed and the given time interval.
4 Easy
4 of 200
Application +4 | -1
A body is projected vertically up with ‘u’. Its velocity at half its maximum height is
View answer and explanation
Correct option: D
u/2u/\sqrt 2
Option D (u/2u/\sqrt 2) is correct because the velocity at half the maximum height is calculated using conservation of energy or kinematic equations.
5 Easy
5 of 200
Application +4 | -1
A scooter starts from rest have an acceleration of 1 ms−21 \mathrm{~ms}^{-2} while a car 150 m150 \mathrm{~m} behind it starts from rest with an acceleration of 2 ms−22 \mathrm{~ms}^{-2}. After how much time, the car catches up with the scooter?
View answer and explanation
Correct option: B
300 s\sqrt{300} \mathrm{~s}
Option B (300 s\sqrt{300} \mathrm{~s}) is correct because it represents the time when the distance traveled by the car equals the distance traveled by the scooter plus the initial separation.
6 Easy
6 of 200
Application +4 | -1
A motor vehicle travelled the first one third of a distance ‘S ’ at a speed of V1=10 kmph{V_1} = 10\,kmph, the second one third at a speed of V2=20 kmph{V_2} = 20\,kmph and the last one third at a speed of V3=60 kmph{V_3} = 60\,kmph determine the mean speed of the vehicle over the entire distance ‘S ’
View answer and explanation
Correct option: D
18 kmph
Option D (18 kmph) is correct because it is the harmonic mean of the three speeds, calculated appropriately for equal distances.
7 Hard
7 of 200
Application +4 | -1
A particle is projected with velocity v0{v_0} along x-axis.The deceleration on the particle is proportional to the square of the distance from the origin i.e., a=−ax2.a = - a{x^2}. The distance at which the particle stops is
View answer and explanation
Correct option: D
(3v022α)13{\left( {\frac{{3v_0^2}}{{2\alpha }}} \right)^{\frac{1}{3}}}
Option D ((3v022α)13{\left( {\frac{{3v_0^2}}{{2\alpha }}} \right)^{\frac{1}{3}}}) is correct because it is the distance at which the particle stops, derived by integrating the given deceleration function.
8 Easy
8 of 200
Application +4 | -1
A body starts from rest with uniform acceleration a.a. If its velocity after nn second is v,v, then its displacement in the last 2 s is
View answer and explanation
Correct option: D
2v(n−1)n\frac{{2v\left( {n - 1} \right)}}{n}
Option D (2v(n−1)n\frac{{2v\left( {n - 1} \right)}}{n}) is correct because the displacement in the last 2 seconds can be found by subtracting the displacement in (n-2) seconds from the displacement in n seconds.
9 Medium
9 of 200
Analyzing +4 | -1
Which of the following 4 statements is false
View answer and explanation
Correct option: B
A body can have a constant velocity and still have a varying speed
Option B (A body can have a constant velocity and still have a varying speed) is false because constant velocity implies constant speed and direction.
10 Easy
10 of 200
Understanding +4 | -1
A ball of mass m1{m_1} and another ball of mass m2{m_2} are dropped from equal height. If time taken by the balls are t1{t_1} and t2{t_2} respectively, then
View answer and explanation
Correct option: B
t1=t2{t_1} = {t_2}
Option B (t1=t2{t_1} = {t_2}) is correct because the time taken for an object to fall from a height is independent of its mass when air resistance is negligible.
11 Easy
11 of 200
Application +4 | -1
A stone is dropped from the top of a cliff. It is seen to hit the ground below after 4.2 s. How high is the cliff?
View answer and explanation
Correct option: A
86.44 m
Option A (86.44 m) is correct because it is calculated using the equation of motion for free fall, h=12gt2h = \frac{1}{2}gt^2.
12 Easy
12 of 200
Application +4 | -1
A particle is moving in a straight line such that its velocity is given by v=t4+3t2+8  m/sv = {t^4} + 3{t^2} + 8\,\,m/s. Find acceleration at time t=1 st = 1\,s
View answer and explanation
Correct option: A
10 m/s210\,m/{s^2}
Option A (10 m/s210\,m/{s^2}) is correct because it is the value obtained by differentiating the velocity function with respect to time and evaluating at t=1s.
13 Easy
13 of 200
Application +4 | -1
If t=x+4t=\sqrt{x}+4, then (dxdt)t=4\left(\frac{d x}{d t}\right)_{t=4} is
View answer and explanation
Correct option: B
zero
Option B (zero) is correct because when t=4, x=0, and therefore dx/dt at t=4 is zero.
14 Medium
14 of 200
Analyzing +4 | -1
Assertion: If two particles are moving with same speed but their velocity vectors are opposite, then the distance between the particles must be changing.
Reason: If the velocity of one particle w.r.t. other is zero, then separation between the particle must be constant.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason does not explain the assertion.
15 Medium
15 of 200
Application +4 | -1
An object accelerates from rest to a velocity 27.5  ms−127.5\;\mathrm{m}{\mathrm{s}^{ - 1}} in 10 s, then the distance covered after next 10 s is
View answer and explanation
Correct option: C
412.5 m
Option C (412.5 m) is correct because it is calculated by first finding the acceleration and then using the kinematic equation for distance with constant velocity.

Explore Other Chapters in PHYSICS

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UNITS & MEASUREMENTS 392 MCQs WORK-ENERGY-POWER 355 MCQs MECHANICAL PROPERTIES OF FLUIDS 317 MCQs MOTION IN PLANE 307 MCQs MAGNETIC EFFECT OF CURRENT 282 MCQs THERMAL PROPERTIES OF MATTER 269 MCQs
16 Easy
16 of 200
Application +4 | -1
A boy standing at the top of a tower of 20 m height drops a stone. Assuming g=10 m/s2,g = 10\,m/{s^2}, the velocity with which it hits the ground is
View answer and explanation
Correct option: C
20.0 m/s
Option C (20.0 m/s) is correct because it accurately calculates the final velocity using the kinematic equation v2=u2+2asv^2 = u^2 + 2as.
17 Hard
17 of 200
Application +4 | -1
A particle moves according to the equation dvdt=α−βv\frac{d v}{d t}=\alpha-\beta v, where α\alpha and β\beta are constants. Find velocity as a function of time. Assume, body starts from rest
View answer and explanation
Correct option: B
v=(α/β)(1−e−βt)v=(\alpha / \beta)\left(1-e^{-\beta t}\right)
Option B (v=(α/β)(1−e−βt)v=(\alpha / \beta)(1-e^{-\beta t})) is correct because it is the solution to the given differential equation with the initial condition that the body starts from rest.
18 Medium
18 of 200
Understanding +4 | -1
The ratio of the numerical values of the average velocity and average speed of a body is always
View answer and explanation
Correct option: B
Unity or less
Option B (Unity or less) is correct because the magnitude of average velocity is always less than or equal to the average speed.
19 Medium
19 of 200
Understanding +4 | -1
The distance travelled by a body is directly proportional to the time taken. Its speed
View answer and explanation
Correct option: D
Remains constant
Option D (Remains constant) is correct because if distance is directly proportional to time, the speed is constant.
20 Medium
20 of 200
Analyzing +4 | -1
A particle moves along a straight line such that its position x at any time t is x=6t2−t3.x = 6{t^2} - {t^3}.. Where x in metre and t is in second, then
View answer and explanation
Correct option: D
Both (1) and (2) are correct
Option D (Both (1) and (2) are correct) is correct because at t=0 the acceleration is indeed 12 m/s², and the x-t curve has a maximum at t=4s.
21 Medium
21 of 200
Analyzing +4 | -1
The velocity of a particle depends upon the time t\mathrm{t} according to the equation: v=ab+bt+cd+t\mathrm{v}=\sqrt{\mathrm{a b}}+\mathrm{b t}+\frac{\mathrm{c}}{\mathrm{d+t}}. The physical quantities which are represented by a,b,c\mathrm{a, b, c} and d\mathrm{d}, are in the following order:
View answer and explanation
Correct option: B
Distance, acceleration, distance, time
Option B (Distance, acceleration, distance, time) is correct because, based on dimensional analysis, 'a' must represent distance, 'b' must represent acceleration, 'c' must represent distance, and 'd' must represent time to maintain consistent units for velocity.
22 Easy
22 of 200
Analyzing +4 | -1
Statement-1: Two balls of different masses are thrown vertically upwards with same speed. They will pass through their point of projection in the downward direction with the same speed in absence of air resistance.
Statement-2: In absence of air resistance, the mechanical energy of a projectile is conserved.
View answer and explanation
Correct option: A
Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1) is correct because both statements are true and the conservation of mechanical energy explains why the balls return with the same speed.
23 Easy
23 of 200
Application +4 | -1
Two stones are falling at a place from heights in the ratio 2 : 3. Their velocities on reaching the ground are in the ratio
View answer and explanation
Correct option: C
2:3\sqrt 2 :\sqrt 3
Option C (2:3\sqrt 2 :\sqrt 3) is correct because the final velocity is proportional to the square root of the height from which the stone falls, as derived from the kinematic equation v2=2ghv^2 = 2gh.
24 Medium
24 of 200
Application +4 | -1
An athlete completes one round of a circular track or radius R in 40 sec. What will be his displacement at the end of 2 min. 20 sec
View answer and explanation
Correct option: B
2R
Option B (2R) is correct because after 2 minutes and 20 seconds, the athlete completes 3.5 rounds, ending up diametrically opposite the starting point, hence the displacement is 2R.
25 Hard
25 of 200
Analyzing +4 | -1
A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after t1{t_1} and t2{t_2} seconds respectively, then
View answer and explanation
Correct option: C
t=t1t2t = \sqrt {{t_1}{t_2}}
Option C (t=t1t2t = \sqrt {{t_1}{t_2}}) is correct. By analyzing the equations of motion for each scenario and eliminating the initial velocity, we find that the time for the dropped stone is the geometric mean of the times for the stones thrown upwards and downwards.
26 Medium
26 of 200
Understanding +4 | -1
Two balls of same size but the density of one is greater than that of the other are dropped from the same height, then which ball will reach the earth first (air resistance is negligible)?
View answer and explanation
Correct option: C
Both simultaneously
Option C (Both simultaneously) is correct because in the absence of air resistance, the acceleration due to gravity is the same for all objects, regardless of their mass or density.
27 Medium
27 of 200
Application +4 | -1
A bomb is dropped from an aeroplane flying horizontally with a velocity of 720 kmph at an altitude of 980 m. Time taken by the bomb to hit the ground is
View answer and explanation
Correct option: C
14.14 S
Option C (14.14 S) is correct because it calculates the time it takes for the bomb to fall from a height of 980m under the influence of gravity, independent of its horizontal velocity.
28 Easy
28 of 200
Understanding +4 | -1
The velocity of a body at a given instant of time during motion is:
View answer and explanation
Correct option: C
Instantaneous velocity =lim⁡Δt→0Δs⃗Δt=\lim \limits_{{\Delta t \rightarrow 0}} \frac{\Delta \vec{s}}{\Delta t}
Option C (Instantaneous velocity =lim⁡Δt→0Δs⃗Δt=\lim \limits_{{\Delta t \rightarrow 0}} \frac{\Delta \vec{s}}{\Delta t}) is correct because it represents the definition of instantaneous velocity as the limit of the average velocity as the time interval approaches zero.
29 Medium
29 of 200
Application +4 | -1
The displacement of the particle varies with time according to the relation x=kb[1−e−bt].x = \frac{k}{b}\left[ {1 - {e^{ - bt}}} \right]. Then the velocity of the particle is
View answer and explanation
Correct option: A
k(e−bt)k\left( {{e^{ - bt}}} \right)
Option A (k(e−bt)k\left( {{e^{ - bt}}} \right)) is correct because it represents the derivative of the given displacement function with respect to time, which gives the velocity.
30 Easy
30 of 200
Application +4 | -1
A body moves from one corner of an equilateral triangle of side 10 cm to the same corner along the sides. Then the distance and displacement are respectively
View answer and explanation
Correct option: B
30 cm & 0 cm
Option B (30 cm & 0 cm) is correct because the distance is the total length traveled along the sides (10 cm + 10 cm + 10 cm = 30 cm), and the displacement is zero since the body returns to its starting point.
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