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NEET • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Medium

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61 Medium
61 of 123
Application +4 | -1
A force of 200 N is applied at one end of a wire of length 2m2m and having area of cross-section 10−2cm2{10^{ - 2}}c{m^2}. The other end of the wire is rigidly fixed. If coefficient of linear expansion of the wire α=8×10−6/ 0C\alpha = 8 \times {10^{ - 6}}/{\,^0}C and Young’s modulus Y=2.2×1011  N/m2Y = 2.2 \times {10^{11}}\;N/{m^2} and its temperature is increased by 50C{5^0}C, then the increase in the tension of the wire will be
View answer and explanation
Correct option: D
8.8 N
Option D (8.8 N) is correct because the increase in tension is calculated considering both the applied force and the thermal stress due to temperature change.
62 Medium
62 of 123
Application +4 | -1
An elastic material of Young’s modulus YY is subjected to a stress SS. The elastic energy stored per unit volume of the material is
View answer and explanation
Correct option: B
S22Y\frac{{{S^2}}}{{2Y}}
Option B (S22Y\frac{{{S^2}}}{{2Y}}) is correct because it represents the elastic energy stored per unit volume, derived from the formula involving stress and Young's modulus.
63 Medium
63 of 123
Application +4 | -1
A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is 4.8×107N/m24.8 \times {10^7}N/{m^2}. The area of cross section of the wire is 10−6m2{10^{ - 6}}{m^2}. The maximum angular velocity with which it can be rotated in a horizontal circle
View answer and explanation
Correct option: B
4 rad/secrad/sec
Option A (4 rad/sec) is correct because the maximum angular velocity is calculated using the breaking stress, area, mass, and length.
64 Medium
64 of 123
Remembering +4 | -1
The restoring force per unit area is known as:
View answer and explanation
Correct option: C
Stress
Option C (Stress) is correct because stress is defined as the restoring force per unit area within a deformable body.
65 Medium
65 of 123
Understanding +4 | -1
If Y,KY,K and η\eta are the values of Young’s modulus, bulk modulus and modulus of rigidity of any material, respectively. Choose the correct relation for these parameters.
View answer and explanation
Correct option: C
K=Yη9η−3YN/m2K = \frac{{Y\eta }}{{9\eta - 3Y}}N/{m^2}
Option C (K=Yη9η−3YN/m2K = \frac{{Y\eta }}{{9\eta - 3Y}}N/{m^2}) is the correct relation between Young’s modulus, bulk modulus and modulus of rigidity.
66 Medium
66 of 123
Remembering +4 | -1
Stress is a _____ quantity.
View answer and explanation
Correct option: D
Tensor
The correct answer is D (Tensor) because stress is a tensor quantity that describes forces acting on a cross-sectional area.
67 Medium
67 of 123
Application +4 | -1
Compressibility of water is 5×1010  m2N−1.  5 \times {10^{10}}\;{\mathrm{m}^2}{\mathrm{N}^{ - 1}}.\; The change in volume of 100 mL water subjected 15×106  Pa15 \times {10^6}\mathrm{\;Pa} pressure will
View answer and explanation
Correct option: D
Decrease by 0.75 mL
Option D (Decrease by 0.75 mL) is correct because the volume of water decreases under pressure, and the calculated decrease is 0.75 mL based on the given compressibility and pressure.
68 Medium
68 of 123
Understanding +4 | -1
If the length of a wire is reduced to half, then it can hold the Load
View answer and explanation
Correct option: B
Same
Option B (Same) is correct because the load a wire can hold depends on the breaking stress of the material and the cross-sectional area, not the length of the wire.
69 Medium
69 of 123
Application +4 | -1
A wire can be broken by a load of 20 kg-wt. The force required to break wire of same material with twice the diameter will be
View answer and explanation
Correct option: D
80 kg-wt
Option D (80 kg-wt) is correct because the breaking force is proportional to the cross-sectional area, which is proportional to the square of the diameter.
70 Medium
70 of 123
Application +4 | -1
When a pressure of 100 atmosphere is applied on a spherical ball, then its volume reduces to 0.01%0.01\%. The bulk modulus of the material of the rubber in dyne/cm2dyne/c{m^2} is
View answer and explanation
Correct option: C
1×10121 \times {10^{12}}
Option C (1×10121 \times {10^{12}}) is correct because it is the calculated bulk modulus of the rubber based on the given pressure and volume reduction.
71 Medium
71 of 123
Understanding +4 | -1
The length of a wire under stress changes by 0.01%0.01\%. The strain produced is
View answer and explanation
Correct option: A
1×10−41 \times {10^{ - 4}}
Option A (1×10−41 \times {10^{ - 4}}) is correct because strain is defined as the change in length divided by the original length, which is 0.01% or 0.0001.
72 Medium
72 of 123
Analyzing +4 | -1
Assertion:- Elastic restoring forces may be conservative
Reason:- The value of strain for same stress are different while increasing the load and while decreasing the load.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because elastic restoring forces can be conservative, and hysteresis explains the difference in strain for the same stress during loading and unloading, but hysteresis doesn't explain why restoring forces *may* be conservative.
73 Medium
73 of 123
Remembering +4 | -1
Dimensions of stress are
View answer and explanation
Correct option: D
[ M L−1 T−2 ]\mathrm{[}\,\mathrm{M}\,{\mathrm{L}^{ - 1}}\,{\mathrm{T}^{ - 2}}\,]
Option D ([ M L−1 T−2 ]\mathrm{[}\,\mathrm{M}\,{\mathrm{L}^{ - 1}}\,{\mathrm{T}^{ - 2}}\,\mathrm{]}) is correct because stress is force per unit area, and the dimensions of force are [MLT−2][MLT^{-2}] and area are [L2][L^2], so stress is [ML−1T−2][ML^{-1}T^{-2}].
74 Medium
74 of 123
Understanding +4 | -1
A wire fixed at the upper end stretches by length ll by applying a force FF. The work done in stretching is
View answer and explanation
Correct option: D
Fl2\frac{{Fl}}{2}
Option D (Fl2\frac{{Fl}}{2}) is correct because the work done in stretching a wire is given by half the product of force and extension.
75 Medium
75 of 123
Understanding +4 | -1
Write copper, steel, glass and rubber in order of increasing coefficient of elasticity.
View answer and explanation
Correct option: D
Rubber, glass, copper, steel
Option D (Rubber, glass, copper, steel) is correct because it lists the materials in order of increasing Young's modulus (coefficient of elasticity).
76 Medium
76 of 123
Understanding +4 | -1
The Poisson’s ratio cannot have the value
View answer and explanation
Correct option: A
0.7\mathrm{0}\mathrm{.7}
Option A (0.7) is the correct answer because Poisson's ratio is generally between 0 and 0.5 for most materials, and 0.7 exceeds this range.
77 Medium
77 of 123
Application +4 | -1
The temperature of a wire of length 1m1\mathrm{ }m and area of cross section 1  cm21\,\,c{m^2} is increased from 00C  to  1000C{0^0}\mathrm{C}\,\,\mathrm{to}\,\,{100^0}C. If the rod is not allowed to increased in length, the force required will be (α=10−5/0C(\alpha = {10^{ - 5}}{/^0}C and Y=1011N/m2)Y = {10^{11}}\mathrm{N}/{\mathrm{m}^2})
View answer and explanation
Correct option: B
104 N{10^4}\,\mathrm{N}
Option B (104 N{10^4}\,\mathrm{N}) is correct because the force required is calculated using the formula F=YAαΔTF = YA\alpha \Delta T, where Y is Young's modulus, A is the area, α\alpha is the coefficient of linear expansion, and ΔT\Delta T is the change in temperature.
78 Medium
78 of 123
Remembering +4 | -1
Young's modulus is defined as the ratio of
View answer and explanation
Correct option: C
Tensile stress and longitudinal strain
Option C (Tensile stress and longitudinal strain) is correct because Young's modulus is defined as the ratio of tensile stress to longitudinal strain.
79 Medium
79 of 123
Remembering +4 | -1
The Young’s modulus of the material of a wire is equal to the
View answer and explanation
Correct option: B
Stress required to produce unit strain
Option B is correct because Young's modulus is defined as the stress required to produce unit strain.
80 Medium
80 of 123
Remembering +4 | -1
To keep constant time, watches are fitted with balance wheel made of
View answer and explanation
Correct option: A
Invar
Option A is correct because Invar has a very low coefficient of thermal expansion, making it suitable for balance wheels in watches to maintain constant time.
81 Medium
81 of 123
Application +4 | -1
When a certain weight is suspended from a long uniform wire, its length increases by 1 cm. If the same weight is suspended from another wire of the same material and length but having a diameter half of the first one, the increase in length will be
View answer and explanation
Correct option: C
4 cm
Option C (4 cm) is correct because elongation is inversely proportional to the square of the diameter.
82 Medium
82 of 123
Application +4 | -1
A force FF is needed to break a copper wire having radius RR. The force needed to break a copper wire of radius 2R2R will be
View answer and explanation
Correct option: C
4 F4\,F
Option C (4 F4\,F) is correct because the force needed to break a wire is proportional to the cross-sectional area, which is proportional to the square of the radius.
83 Medium
83 of 123
Understanding +4 | -1
If xx longitudinal strain is produced in a wire of Young’s modulus yy, then energy stored in the material of the wire per unit volume is
View answer and explanation
Correct option: D
12yx2\frac{1}{2}y{x^2}
Option D (12yx2\frac{1}{2}y{x^2}) is correct because it represents the energy stored per unit volume in a wire with longitudinal strain x and Young's modulus y.
84 Medium
84 of 123
Analyzing +4 | -1
Statement I: Two identical solid balls, one of ivory and the other of wet-clay are dropped from the same height on the floor. Both the balls will rise to same height after bouncing.
Statement II: Ivory and wet-clay have same elasticity.
View answer and explanation
Correct option: D
Statement I is false and statement II is false
Option D is correct because Statement I is false as the ivory ball will bounce higher due to its higher elasticity, and Statement II is false because ivory and wet-clay do not have the same elasticity.
85 Medium
85 of 123
Remembering +4 | -1
Thermal stress, If developed in a solid on heating is given by
View answer and explanation
Correct option: A
yΔlly\frac{{\Delta l}}{l}
Option A (yΔlly\frac{{\Delta l}}{l}) is correct because thermal stress is given by Young's modulus times the strain.
86 Medium
86 of 123
Understanding +4 | -1
What is the Young's modulus of elasticity for a perfectly rigid body?
View answer and explanation
Correct option: A
Infinity
Option A is correct because a perfectly rigid body does not deform under any stress, thus its Young's modulus is infinite.
87 Medium
87 of 123
Application +4 | -1
A tensile force of 2×103 N2 \times {10^3}\,\mathrm{N} doubles the length of a rubber band of cross-sectional area 2×10−4 m22 \times {10^{ - 4}}\,{\mathrm{m}^2}. The Young’s modulus of elasticity of the rubber band is
View answer and explanation
Correct option: C
107 Nm−2{10^7}\,\mathrm{N}{\mathrm{m}^{ - 2}}
Option C is correct. Young's modulus is calculated using the formula Y = (F/A) / (ΔL/L), where the length doubles, meaning ΔL = L.
88 Medium
88 of 123
Understanding +4 | -1
The general form of potential energy curve for atoms or molecules can be represented by the following equation U(R)=ARn−BRmU\left( R \right) = \frac{A}{{{R^n}}} - \frac{B}{{{R^m}}} . Here, R is the interatomic or molecular distance, A and B are coefficients, nn and mm are the exponents. In the above equation
View answer and explanation
Correct option: B
Second term represents the attractive part of the potential
Option B (Second term represents the attractive part of the potential) is correct because the negative sign in front of the second term indicates an attractive force as the distance R increases.
89 Medium
89 of 123
Remembering +4 | -1
A metal wire of length L,L, area of cross section AA and Young's modulus YY behaves as a spring of spring constant kk given by:
View answer and explanation
Correct option: A
k=YA/Lk={YA} / {L}
Option A (k=YA/Lk={YA} / {L}) is correct because it represents the spring constant derived from Young's modulus definition.
90 Medium
90 of 123
Understanding +4 | -1
Which of the following statements is correct
View answer and explanation
Correct option: A
Hooke’s law is applicable only within elastic limit
Option A (Hooke’s law is applicable only within elastic limit) is correct because Hooke's law is only valid within the elastic limit of a material.
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