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NEET • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Mixed difficulty

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Showing 61-90 of 177 questions

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61 Medium
61 of 177
Understanding +4 | -1
The elastic energy stored in a wire of Young’s modulus YY is
View answer and explanation
Correct option: B
(stress)2  ×  volume2 Y\frac{{{{\left( {\mathrm{stress}} \right)}^2}\,\, \times \,\,\mathrm{volume}}}{{2\,Y}}
Option B ((stress)2×,volume2,Y\frac{{{{\left( {\mathrm{stress}} \right)}^2}\times \\,\mathrm{volume}}}{{2\\,Y}}) is correct because it represents the elastic energy stored in a wire in terms of stress, volume, and Young's modulus.
62 Medium
62 of 177
Application +4 | -1
A wire of Young’s modulus 1.5×1012  Nm−21.5 \times {10^{12}}\;\mathrm{N}{\mathrm{m}^{ - 2}} is stretched by a force so as to produce a strain of 2×104.2 \times {10^4}. The energy stored per unit volume is
View answer and explanation
Correct option: D
3  ×104  Jm−33\mathrm{\;} \times {10^4}\mathrm{\;J}{\mathrm{m}^{ - 3}}
Option D (3  ×104  Jm−33\mathrm{\;} \times {10^4}\mathrm{\;J}{\mathrm{m}^{ - 3}}) is correct because the energy stored per unit volume is calculated using the formula 12×Y×(strain)2\frac{1}{2} \times Y \times (\text{{strain}})^2.
63 Hard
63 of 177
Application +4 | -1
The maximum stress that can be applied to the material of a wire used to suspend an elevator is 1.3×108 Nm−21.3 \times 10^8 \mathrm{~Nm}^{-2}. If the mass of the elevator is 900 kg900 \mathrm{~kg} and it moves up with an acceleration of 2.2 ms−22.2 \mathrm{~ms}^{-2}, what is the minimum diameter of the wire?
View answer and explanation
Correct option: A
1.0284×10−2 m1.0284 \times 10^{-{2}} \mathrm{~m}
Option A (1.0284×10−2 m1.0284 \times 10^{-{2}} \mathrm{~m}) is correct because it is the minimum diameter of the wire calculated based on the maximum stress, mass, and acceleration of the elevator.
64 Hard
64 of 177
Application +4 | -1
A cable is replaced by another one of the same length and material but of twice the diameter. The maximum load that the new wire can support without exceeding the elastic limit, as compared to the load that the original wire could support, is
View answer and explanation
Correct option: C
four times
Option C (four times) is correct because the maximum load a wire can support is proportional to its cross-sectional area, which is proportional to the square of the diameter.
65 Easy
65 of 177
Application +4 | -1
If the ratio of lengths, radii and Young's moduli of steel and copper are 4, 3 and 2 respectively. The ratio of their increase in lengths would be (same force FF is applied to them)
View answer and explanation
Correct option: A
29\frac{2}{9}
Option A (29\frac{2}{9}) is correct because the ratio of increase in lengths is derived from Young's modulus formula, considering the ratios of lengths, radii, and Young's moduli.
66 Medium
66 of 177
Application +4 | -1
Two wires of the same material and same mass are stretched by the same force. Their lengths are in the ratio 2 : 3. Then their elongations are in the ratio
View answer and explanation
Correct option: C
4:94\mathrm{ }:\mathrm{ }9
Option C (4:94\mathrm{ }:\mathrm{ }9) is correct because elongation is proportional to the square of the length when the material, mass, and force are the same.
67 Medium
67 of 177
Remembering +4 | -1
The expression of force constant for a spring following Hooke's law is given by:
View answer and explanation
Correct option: A
k=YAlk=\frac{Y A}{l}
Option B (k=YAΔlk=\frac{Y A}{\Delta l}) is correct because it represents the force constant derived from Young's modulus, area, and change in length.
68 Medium
68 of 177
Application +4 | -1
Longitudinal stress of 1N/mm21N/m{m^2} is applied on a wire. The percentage increase in length is (Y=1011N/m2)\left( {Y = {{10}^{11}}N/{m^2}} \right)
View answer and explanation
Correct option: B
0.0010.001
Option B (0.0010.001) is correct because the percentage increase in length is calculated using the formula relating stress, Young's modulus, and strain.
69 Medium
69 of 177
Understanding +4 | -1
The Young’s modulus of a wire of length LL and radius rr is YN/m2Y\mathrm{ }N/{m^2}. If the length and radius are reduced to L/2L/2 and r/2r/2, then its Young’s modulus will be
View answer and explanation
Correct option: B
YY
Option B (YY) is correct because Young's modulus is a material property and does not depend on the dimensions of the wire.
70 Medium
70 of 177
Understanding +4 | -1
The increases in length is ll of a wire of length LL by the longitudinal stress. Then the stress is proportional to
View answer and explanation
Correct option: B
l/Ll/L
Option B is correct because stress is proportional to strain, and strain is defined as the change in length divided by the original length (l/Ll/L).
71 Hard
71 of 177
Understanding +4 | -1
If Poisson's ratio σ\sigma for a material is −12-\frac{1}{2}, then the material is
View answer and explanation
Correct option: B
incompressible
Option B is correct. A Poisson's ratio of -1/2 indicates that the material's volume remains constant under deformation, which is the definition of incompressibility.
72 Medium
72 of 177
Understanding +4 | -1
The bulk modulus of an ideal gas at constant temperature
View answer and explanation
Correct option: C
Is equal to its pressure pp
Option C (Is equal to its pressure pp) is correct because the bulk modulus at constant temperature is equal to the pressure of the ideal gas.
73 Medium
73 of 177
Application +4 | -1
A cube is shifted to a depth of 100 m in a lake. The change in volume is 0.1%0.1\%. The bulk modulus of the material is nearly
View answer and explanation
Correct option: D
106  Pa  {10^6}\mathrm{\;Pa\;}
Option D (106  Pa  {10^6}\mathrm{\;Pa\;}) is correct because the bulk modulus is calculated using the formula relating pressure change to fractional volume change.
74 Easy
74 of 177
Understanding +4 | -1
Given below are two statements: one is labelled as
Assertion (A) and the other is labelled as Reason
(R).

Assertion (A): The property of body, by virtue of
which it tends to regain its original shape when the
external force is removed, is Elasticity.

Reason (R): The restoring force depends upon the
bonded inter atomic and inter molecular force of
solid.

In the light of the above statements, choose the
correct answer from the options given below:
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct
explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because elasticity is the property to regain original shape, and this property arises from interatomic forces.
75 Easy
75 of 177
Understanding +4 | -1
The breaking stress for a wire of radius r\mathrm{r} of given material is F N/m2\mathrm{F} \mathrm{~N} / \mathrm{m}^2. The breaking stress for the wire of same material of radius 2r2 \mathrm{r} is:
View answer and explanation
Correct option: C
F\mathrm{F}
Option C (F) is correct because breaking stress is a material property and depends only on the material, not the dimensions of the wire.
76 Easy
76 of 177
Application +4 | -1
For steel Y=2×1011Nm−2Y=2 \times 10^{11} \mathrm{Nm}^{-2}. The force required to double the length of a steel wire of area 1 cm21 \mathrm{~cm}^2 is
View answer and explanation
Correct option: A
2×107 N2 \times 10^7 \mathrm{~N}
Option A (2×107 N2 \times 10^7 \mathrm{~N}) is correct because doubling the length means strain is 1, and force is calculated using Young's modulus formula.
77 Easy
77 of 177
Application +4 | -1
An elongation of 0.4% in a wire of cross-sectional area is 10−6 m2{10^{ - 6}}\,{m^2} causes a tension of 100 N. Y for the wire is [in  N/m2][\mathrm{in }\,\,N/{m^2}]
View answer and explanation
Correct option: D
25×10925 \times {10^9}
Option D (25×10925 \times {10^9}) is correct because Young's modulus is calculated by dividing stress by strain.
78 Medium
78 of 177
Understanding +4 | -1
A wire is stretched under a force. If the wire suddenly snaps the temperature of the wire
View answer and explanation
Correct option: C
Increase
Option C (Increase) is correct because when a wire snaps, the elastic potential energy is converted into heat, increasing the temperature.
79 Medium
79 of 177
Understanding +4 | -1
Statement I: Lead is more elastic than rubber.
Statement II: If the same load is attached to lead and rubber wires of the same cross-sectional area, the strain of lead is very much less than that of rubber.
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A is correct because Statement I is true as lead is more elastic than rubber, and Statement II is true because lead experiences less strain than rubber under the same load.
80 Easy
80 of 177
Application +4 | -1
What is the formula for force when a rod fixed between two rigid support at both end. A temperature is changed by ΔT,Y\Delta {T}, {Y}-young modulus, α=\boldsymbol{\alpha}= coefficient of linear expension :
View answer and explanation
Correct option: A
F=YAαΔTF=Y A \alpha \Delta T
Option A (F=YAαΔTF=Y A \alpha \Delta T) is correct because it represents the thermal stress formula for a rod fixed between two rigid supports.
81 Easy
81 of 177
Application +4 | -1
The length of a wire is 4 m. Its length is increased by 2 mm when a force acts on it. The strain is
View answer and explanation
Correct option: A
5×10−45 \times {10^{ - 4}}
Option A (5×10−45 \times {10^{ - 4}}) is correct because strain is the change in length divided by the original length.
82 Medium
82 of 177
Analyzing +4 | -1
Statement-I: Spring balances show correct readings even after they had been used for a long time.
Statement-II: On using for long time, spring balances losses its elastic strength.
View answer and explanation
Correct option: C
Statement I is false and statement II is true
Option C is correct because Statement I is false as spring balances lose accuracy over time due to elastic fatigue, and Statement II is true because spring balances do lose their elastic strength with prolonged use.
83 Medium
83 of 177
Remembering +4 | -1
The value of Poisson’s ratio lies between
View answer and explanation
Correct option: A
−1  to  12- 1\,\,\mathrm{to}\,\,\frac{1}{2}
Option A (−1  to  12-1\,\,\mathrm{to}\,\,\frac{1}{2}) is correct because Poisson's ratio is defined as the negative ratio of transverse strain to axial strain, and for most materials, it lies between -1 and 0.5.
84 Medium
84 of 177
Application +4 | -1
If Young’s modulus of elasticity YY for a material is one and half times its rigidity coefficient η\eta, the Poisson’s ratio σ\sigma will be
View answer and explanation
Correct option: B
−14- \frac{1}{4}
Option C is correct. Using the relationship between Young's modulus, rigidity coefficient, and Poisson's ratio, we can solve for the Poisson's ratio when Y = 1.5η.
85 Medium
85 of 177
Analyzing +4 | -1
Statement I: Identical springs of steel and copper are equally stretched. More work will be done on the steel spring.
Statement II: Steel is more elastic than copper.
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A is correct because Statement I is true as steel requires more work due to its higher Young's modulus, and Statement II is true because steel is indeed more elastic than copper.
86 Easy
86 of 177
Application +4 | -1
A steel wire of 6 mm diameter is stretched by applying a stress in the wire is 3×106 N/m2.3 \times {10^6}\,N/{m^2}. Find the applied force in stretched wire
View answer and explanation
Correct option: D
84.8 N
Option D (84.8 N) is correct because the applied force is calculated by multiplying the stress by the area of the wire's cross-section.
87 Medium
87 of 177
Understanding +4 | -1
For a constant hydraulic stress on an object, the fractional change in the object’s volume (ΔVV)\left( {\frac{{\Delta V}}{V}} \right) and its bulk modulus (BB) are related as
View answer and explanation
Correct option: B
ΔVV∝1B\frac{{\Delta V}}{V} \propto \frac{1}{B}
Option B (ΔVV∝1B\frac{{\Delta V}}{V} \propto \frac{1}{B}) is correct because the fractional change in volume is inversely proportional to the bulk modulus under constant hydraulic stress.
88 Medium
88 of 177
Understanding +4 | -1
Statement I: Stress is the internal force per unit area of the body.
Statement II: Rubber is more elastic than steel.
View answer and explanation
Correct option: B
Statement I is true and statement II is false
Option B (Statement I is true and statement II is false) is correct because stress is internal force per unit area, and steel is more elastic than rubber.
89 Medium
89 of 177
Application +4 | -1
A force of 200 N is applied at one end of a wire of length 2m2m and having area of cross-section 10−2cm2{10^{ - 2}}c{m^2}. The other end of the wire is rigidly fixed. If coefficient of linear expansion of the wire α=8×10−6/ 0C\alpha = 8 \times {10^{ - 6}}/{\,^0}C and Young’s modulus Y=2.2×1011  N/m2Y = 2.2 \times {10^{11}}\;N/{m^2} and its temperature is increased by 50C{5^0}C, then the increase in the tension of the wire will be
View answer and explanation
Correct option: D
8.8 N
Option D (8.8 N) is correct because the increase in tension is calculated considering both the applied force and the thermal stress due to temperature change.
90 Medium
90 of 177
Application +4 | -1
An elastic material of Young’s modulus YY is subjected to a stress SS. The elastic energy stored per unit volume of the material is
View answer and explanation
Correct option: B
S22Y\frac{{{S^2}}}{{2Y}}
Option B (S22Y\frac{{{S^2}}}{{2Y}}) is correct because it represents the elastic energy stored per unit volume, derived from the formula involving stress and Young's modulus.
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