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NEET • PHYSICS • MAGNETISM AND MATTER

Magnetism and matter practice · Medium

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Showing 31-60 of 128 questions

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31 Medium
31 of 128
Application +4 | -1
The radius of the coil of a tangent galvanometer which has 10 turns is 0.1 m. The current required to produce a deflection of 60∘  (BH=4×10−5  T)60^\circ \;\left( {{B_H} = 4 \times {{10}^{ - 5}}\mathrm{\;T}} \right) is
View answer and explanation
Correct option: B
1.1 A
Option B (1.1 A) is correct because it is the current calculated using the tangent galvanometer formula with the given parameters.
32 Medium
32 of 128
Understanding +4 | -1
When the N- pole of a bar magnet points
towards the south and S- pole towards the
north, the null point are at the
View answer and explanation
Correct option: A
magnetic axis
Option A (magnetic axis) is correct because when the poles are reversed relative to Earth's magnetic field, the null points lie along the magnetic axis.
33 Medium
33 of 128
Remembering +4 | -1
If a diamagnetic substance is brought near north or south pole of a bar magnet, it is
View answer and explanation
Correct option: B
Repelled by the poles
The correct answer is B (Repelled by the poles) because diamagnetic substances are repelled by magnetic fields.
34 Medium
34 of 128
Remembering +4 | -1
The magnetic field due to a small magnetic dipole of magnetic moment MM, at distance rr from the centre on the equatorial line is given by (in M.K.S system)
View answer and explanation
Correct option: B
μ04π×Mr3\frac{{{\mu _0}}}{{4\pi }} \times \frac{M}{{{r^3}}}
Option B (μ04π×Mr3\frac{{{\mu _0}}}{{4\pi }} \times \frac{M}{{{r^3}}}) is correct because it represents the magnetic field due to a small magnetic dipole at a distance r on the equatorial line.
35 Medium
35 of 128
Application +4 | -1
The effective length of a magnet is 31.4 cm and its pole strength is 0.5 Am. Calculate its magnetic moment. If it is bent in form of semicircle, then magnetic moment will be
View answer and explanation
Correct option: A
0.157  Am2,  0.01  Am20.157\mathrm{\;A}{\mathrm{m}^2},\mathrm{\;}0.01\mathrm{\;A}{\mathrm{m}^2}
Option A (0.157  Am2,  0.01  Am20.157\mathrm{\;A}{\mathrm{m}^2},\mathrm{\;}0.01\mathrm{\;A}{\mathrm{m}^2}) is correct because the magnetic moment is calculated as M=m×lM = m \times l initially and then M′=m×(2r)M' = m \times (2r) where r=l/πr = l/\pi when bent into a semicircle.
36 Medium
36 of 128
Application +4 | -1
A paramagnetic substance of susceptibility 3×10−43\mathrm{ } \times \mathrm{ }{10^{ - 4}} is placed in a magnetic intensity of 4×10−4Am−14\mathrm{ } \times \mathrm{ }{10^{ - 4}}A{m^{ - 1}} . Then the intensity of magnetization (in the units of Am−1A{m^{ - 1}}) is
View answer and explanation
Correct option: C
12×10−812 \times {10^{ - 8}}
Option C (12×10−812 \times {10^{ - 8}}) is correct because the intensity of magnetization is the product of susceptibility and magnetic intensity.
37 Medium
37 of 128
Remembering +4 | -1
The intensity of magnetic field due to an isolated pole of strength mm at a point distance rr from it will be
View answer and explanation
Correct option: A
mr2\frac{m}{{{r^2}}}
Option A (mr2\frac{m}{{{r^2}}}) is correct because the intensity of the magnetic field due to an isolated pole is inversely proportional to the square of the distance.
38 Medium
38 of 128
Application +4 | -1
A short bar magnet experiences a torque of magnitude 0.64 J. When it is placed in a uniform magnetic field of 0.32 T, taking an angle of  with the direction of the field. The magnetic moment of the magnet is
View answer and explanation
Correct option: B
4  Am24\mathrm{\;A}{\mathrm{m}^2}
Option B is correct because the magnetic moment is calculated using the formula τ = MBsinθ, and substituting the given values yields 4 Am².
39 Medium
39 of 128
Application +4 | -1
A magnetised wire is bent into an arc of a circle subtending an angle 60∘60^\circ at its centre. Then its magnetic moment is X. If the same wire is bent into an arc of a circle subtending an angle 90∘90^\circ at its centre then its magnetic moment will be
View answer and explanation
Correct option: C
(22)x3\frac{{\left( {2\sqrt 2 } \right)x}}{3}
Option C is correct because the magnetic moment is proportional to sin(θ\theta/2), and the ratio of magnetic moments for 60° and 90° arcs is (2√2)/3.
40 Medium
40 of 128
Understanding +4 | -1
Which of the following properties is 'False' for
a bar magnet ?
View answer and explanation
Correct option: A
It doesn't produce magnetic field
Option A (It doesn't produce magnetic field) is the false statement because a bar magnet inherently produces a magnetic field.
41 Medium
41 of 128
Understanding +4 | -1
Which of the following is represented by the area enclosed by a hysteresis loop (B−HB - H curve)?
View answer and explanation
Correct option: C
Heat energy lost per unit volume in the sample
Option C is correct. The area enclosed by the hysteresis loop represents the energy lost as heat per unit volume during each magnetization cycle.
42 Medium
42 of 128
Application +4 | -1
A magnetic dipole is placed in two perpendicular magnetic fields B⃗{\mathrm{\vec B}} and H⃗{\mathrm{\vec H}} and is in equilibrium taking angle θ\mathrm{\theta } with B⃗{\mathrm{\vec B}}. Then
View answer and explanation
Correct option: C
Bsin⁡θ=Hcos⁡θB\sin \mathrm{\theta } = H\cos \mathrm{\theta }
Option C (Bsin⁡θ=Hcos⁡θB\sin \mathrm{\theta } = H\cos \mathrm{\theta }) is correct because the torques due to the two magnetic fields must balance for equilibrium.
43 Medium
43 of 128
Understanding +4 | -1
The effect due to uniform magnetic field on a freely suspended magnetic needle is as follows
View answer and explanation
Correct option: B
Torque is present but no net force
Option B is correct because a uniform magnetic field exerts a torque on a magnetic needle to align it with the field, but the net force is zero due to the uniformity of the field.
44 Medium
44 of 128
Understanding +4 | -1
Relative permittivity and permeability of a material are εr{\mathrm{\varepsilon }_r} and μr,{\mathrm{\mu }_r}, respectively. Which of the following values of these quantities are allowed for a diamagnetic material?
View answer and explanation
Correct option: B
εr=1.5,  μr=0.5{\varepsilon _r} = 1.5,\;{\mathrm{\mu }_r} = 0.5
Option B is correct. For a diamagnetic material, the relative permittivity can be greater than 1, and the relative permeability must be less than 1.
45 Medium
45 of 128
Remembering +4 | -1
Magnetic intensity for an axial point due to a short bar magnet of magnetic moment MM is given by
View answer and explanation
Correct option: C
μ02π×Md3\frac{{{\mu _0}}}{{2\pi }} \times \frac{M}{{{d^3}}}
Option C (μ02π×Md3\frac{{{\mu _0}}}{{2\pi }} \times \frac{M}{{{d^3}}}) is correct because it represents the magnetic field intensity for an axial point due to a short bar magnet.
46 Medium
46 of 128
Understanding +4 | -1
The time period of a bar magnet suspended horizontally in the earth’s magnetic field and allowed to oscillate
View answer and explanation
Correct option: A
Is directly proportional to the square root of its mass
Option A is correct because the time period of a bar magnet is directly proportional to the square root of its moment of inertia, which is related to its mass.
47 Medium
47 of 128
Understanding +4 | -1
A magnetic dipole is placed in a uniform magnetic field. The net magnetic force on the dipole
View answer and explanation
Correct option: A
Is always zero
Option A (Is always zero) is correct because in a uniform magnetic field, the forces on the north and south poles of the dipole are equal and opposite, resulting in a net force of zero.
48 Medium
48 of 128
Understanding +4 | -1
Curie-Weiss law is obeyed by iron
View answer and explanation
Correct option: D
Above Curie temperature
Option D is correct. The Curie-Weiss law describes the behavior of magnetic susceptibility above the Curie temperature, where the material transitions from ferromagnetic to paramagnetic.
49 Medium
49 of 128
Understanding +4 | -1
A magnetic needle is kept in a non-uniform magnetic field. It experiences force and torque both due to unequal forces acting on poles.
View answer and explanation
Correct option: C
A force and a torque
Option C (A force and a torque) is correct because in a non-uniform magnetic field, a magnetic needle experiences both a force and a torque due to the unequal forces acting on its poles.
50 Medium
50 of 128
Understanding +4 | -1
Keeping dissimilar poles of two magnets of equal pole strength and length same side, their time period will be
View answer and explanation
Correct option: C
Infinity
Option C (Infinity) is correct because when dissimilar poles are kept together, the net magnetic moment is nearly zero, leading to an infinite time period.
51 Medium
51 of 128
Analyzing +4 | -1
Assertion(A): Steel is attracted by a magnet.

Reason (R): Steel is not a magnetic substance.
View answer and explanation
Correct option: C
If (A) is true but the (R) is false
Option C is correct because steel is attracted by a magnet, but it is a ferromagnetic substance, meaning it *is* a magnetic substance.
52 Medium
52 of 128
Remembering +4 | -1
The magnetic susceptibility of paramagnetic materials is
View answer and explanation
Correct option: D
Positive, but small
Option D (Positive, but small) is correct because paramagnetic materials have a small positive susceptibility, indicating they are weakly attracted to magnetic fields.
53 Medium
53 of 128
Understanding +4 | -1
Intensity of magnetic field due to earth at a point inside a hollow steel box is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because a hollow steel box acts as a magnetic shield, preventing the external magnetic field from penetrating inside.
54 Medium
54 of 128
Application +4 | -1
At a certain place the horizontal component of the earth’s magnetic field is B0{B_0} and the angle of dip is 45∘^ \circ. The total intensity of the field at that place will be
View answer and explanation
Correct option: B
2\sqrt 2 B0{B_0}
Option B (2\sqrt 2 B0{B_0}) is correct because the total intensity is related to the horizontal component and the angle of dip by B=B0cos⁡δB = \frac{B_0}{\cos{\delta}}.
55 Medium
55 of 128
Application +4 | -1
The magnetic susceptibility of a material of a rod is 499. The absolute permeability of vacuum is 4π×10−7  Hm−14\pi \times {10^{ - 7}}\;\mathrm{H}{\mathrm{m}^{ - 1}}. The absolute permeability of the material of a rod is
View answer and explanation
Correct option: B
2π×10−4  Hm−12\pi \times {10^{ - 4}}\;\mathrm{H}{\mathrm{m}^{ - 1}}
Option B (2π×10−4  Hm−12\pi \times {10^{ - 4}}\;\mathrm{H}{\mathrm{m}^{ - 1}}) is correct because it is calculated using the formula for absolute permeability: μ=μ0(1+χm)\mu = \mu_0(1 + \chi_m).
56 Medium
56 of 128
Remembering +4 | -1
Magnetic field intensity is defined as
View answer and explanation
Correct option: B
Magnetic induction force acting on a unit magnetic pole
The correct answer is Magnetic induction force acting on a unit magnetic pole because magnetic field intensity (H) is defined as the force experienced by a unit north pole placed in the magnetic field.
57 Medium
57 of 128
Remembering +4 | -1
The field due to a magnet at a distance RR from the centre of the magnet is proportional to
View answer and explanation
Correct option: D
1/R3{R^3}
Option D (1/R3{R^3}) is correct because the magnetic field due to a dipole falls off as the inverse cube of the distance.
58 Medium
58 of 128
Understanding +4 | -1
A vertical pillar of soft iron partially embedded in earth, at south pole, is found to be magnetized by the earth's magnetic field. The polarity at the top end of the pillar will be
View answer and explanation
Correct option: B
North pole
Option B is correct. The top end of the soft iron pillar will be a North pole because the Earth's magnetic field lines enter the Earth at the North pole and exit at the South pole. The pillar acts as a temporary magnet.
59 Medium
59 of 128
Application +4 | -1
Two magnets held together in earth’s magnetic field with same polarity together make 12 vib−min⁡−1and\mathrm{vib } - {\min ^{ - 1}}\mathrm{and} when opposite poles together make 4 vib−min⁡−1.The\mathrm{vib } - {\min ^{ - 1}}.\mathrm{The} ratio of magnetic moments is
View answer and explanation
Correct option: D
10:810\mathrm{ }:\mathrm{ }8
Option D (10:810\mathrm{ }:\mathrm{ }8) is correct because the frequency of vibration is related to the magnetic moments and the earth's magnetic field.
60 Medium
60 of 128
Remembering +4 | -1
If the magnetic susceptibility of a specimen is small and positive, then the specimen is
View answer and explanation
Correct option: B
Paramagnetic
Option B (Paramagnetic) is correct because paramagnetic materials have a small, positive magnetic susceptibility.
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