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NEET • PHYSICS • MAGNETISM AND MATTER

Magnetism and matter practice · Mixed difficulty

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Showing 91-120 of 164 questions

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91 Medium
91 of 164
Remembering +4 | -1
The relative permeability (μr)(\mu_r) of a substance is related to its susceptibility (χ)(\chi) as
View answer and explanation
Correct option: B
μr=1+χ\mu_r=1+\chi
Option B (μr=1+χ\mu_r=1+\chi) is correct because it represents the relationship between relative permeability and susceptibility.
92 Hard
92 of 164
Application +4 | -1
A sample of cast iron exhibits a magnetic field B=0.5T,B=0.5 T, when intensity of magnetizing field (H)(H) is 10Am.10 \frac{\mathrm{A}}{\mathrm{m}}. Relative permeability of iron is 
View answer and explanation
Correct option: C
125000π\frac{125000}{\pi}
Option C (125000π\frac{125000}{\pi}) is correct because the relative permeability is calculated using the formula μr=Bμ0H\mu_r = \frac{B}{\mu_0 H}.
93 Easy
93 of 164
Application +4 | -1
A bar magnet of length 0.2m and with a magnetic moment of 10 Am210\,A{m^2} is placed in a uniform magnetic field of intensity 0.8 T, with is axis making an angle of 30∘30^\circ with the field. What is the torque on the magnet?
View answer and explanation
Correct option: C
4 N-m
Option D is correct because the torque is calculated using the formula τ = MBsinθ, and substituting the given values yields 4 N-m.
94 Easy
94 of 164
Application +4 | -1
The vertical component of the earth's magnetic field is 6×10−5 T6 \times 10^{-5} \mathrm{~T} at any place where the angle of dip is 37∘37^{\circ}. The earth's resultant magnetic field at that place will be
(\left(\right. Given tan⁡37∘=34)\left.\tan 37^{\circ}=\frac{3}{4}\right)
View answer and explanation
Correct option: D
1×10−4 T1 \times 10^{-4} \mathrm{~T}
Option D (1×10−4 T1 \times 10^{-4} \mathrm{~T}) is correct because it's calculated using the relationship between the vertical component, angle of dip, and the earth's resultant magnetic field.
95 Medium
95 of 164
Application +4 | -1
Susceptibility of MgMg at 300  K300\;K is 1.2×10−51.2 \times {10^{ - 5}}. The temperature at which susceptibility will be 1.8×10−51.8 \times {10^{ - 5}}is
View answer and explanation
Correct option: B
200 KK
Option B is correct. Using Curie's law, susceptibility is inversely proportional to temperature, so T2=T1∗(χ1/χ2)T_2 = T_1 * (\chi_1 / \chi_2).
96 Medium
96 of 164
Understanding +4 | -1
A dip circle is at right angles to the magnetic meridian.
View answer and explanation
Correct option: B
90∘^ \circ
Option B (90∘^ \circ) is correct because when a dip circle is at right angles to the magnetic meridian, it is aligned with the vertical plane perpendicular to the magnetic field, showing a dip angle of 90 degrees.
97 Easy
97 of 164
Understanding +4 | -1
The area enclosed by a hysteresis loop is a measure of
View answer and explanation
Correct option: D
Energy loss per cycle
Option D (Energy loss per cycle) is correct because the area enclosed by the hysteresis loop represents the energy dissipated as heat during each magnetization-demagnetization cycle.
98 Easy
98 of 164
Remembering +4 | -1
The magnet can be completely demagnetized by
View answer and explanation
Correct option: D
A reverse field of appropriate strength
Option D (A reverse field of appropriate strength) is correct because applying a reverse magnetic field of sufficient strength can randomize the magnetic domains, leading to complete demagnetization.
99 Hard
99 of 164
Understanding +4 | -1
Given below are two statement:

Statement-I: Susceptibilities of paramagnetic
substances incerase with decrease in temperature.

Statement-II: Diamagnetism is a result of orbital
motions of electrons developing magnetic
moments opposite to the applied magnetic field.

Choose the correct answer from the options given
below.
View answer and explanation
Correct option: A
Both Statement-I and Statement-II are true
Option A is correct. Paramagnetic susceptibility increases as temperature decreases, and diamagnetism arises from orbital motions opposing the applied field.
100 Easy
100 of 164
Application +4 | -1
A magnet is suspended in such a way that it oscillates in the horizontal plane. It makes 20  oscillations  per  minute20\;oscillations\;per\;minute at a place where dip angle is 30∘30^\circ and 15  oscillations  per15\;oscillations\;per minuteminute at a place where dip angle 60∘60^\circ. The ratio of total earth’s magnetic field at the two places is
View answer and explanation
Correct option: B
16  :9316\;:9\sqrt 3
Option B is correct because in equilibrium, the torques due to both magnetic fields must be equal and opposite, leading to the given relationship.
101 Medium
101 of 164
Understanding +4 | -1
A compass needle which is allowed to move in a horizontal plane is taken to a geomagnetic pole. It
View answer and explanation
Correct option: B
Will stay in any position
Option B (Will stay in any position) is correct because at the geomagnetic pole, the horizontal component of the Earth's magnetic field is zero, so the compass needle is free to rotate in any direction.
102 Medium
102 of 164
Remembering +4 | -1
Magnetic susceptibility for a paramagnetic and diamagnetic material is respectively
View answer and explanation
Correct option: C
Small, positive and small, negative
Option C is correct. Paramagnetic materials have a small positive susceptibility, while diamagnetic materials have a small negative susceptibility.
103 Medium
103 of 164
Remembering +4 | -1
Hysteresis loss is minimized by using
View answer and explanation
Correct option: D
Mu metal
Option D (Mu metal) is correct because Mu-metal is a special nickel-iron alloy with very high permeability and low hysteresis, making it ideal for minimizing hysteresis loss.
104 Easy
104 of 164
Application +4 | -1
Two magnets of magnetic moments 4 Am24\,A{m^2} and 3 Am23\,A{m^2} are joined to form a cross (+)\left( + \right) then the magnetic moment of the combination is [Am2]\left[ {A{m^2}} \right]
View answer and explanation
Correct option: A
5
Option A (5) is correct because the magnetic moments are perpendicular, so the resultant is found using the Pythagorean theorem.
105 Medium
105 of 164
Analyzing +4 | -1
A magnetic needle suspended by a silk thread is vibrating in the earth's magnetic field. if the temperature of the needle is increased by 700∘C700^{\circ} \mathrm{C}, then
View answer and explanation
Correct option: D
the needle stops vibrating
Option D (the needle stops vibrating) is correct because increasing the temperature significantly can demagnetize the needle, causing it to lose its magnetic properties and stop vibrating.
106 Medium
106 of 164
Understanding +4 | -1
If a piece of metal was thought to be magnet, which one of the following observations would offer conclusive evidence
View answer and explanation
Correct option: B
It repels a known magnet
Option B is correct because repulsion is the definitive test for a magnet, as attraction can be caused by induced magnetism.
107 Medium
107 of 164
Analyzing +4 | -1
Assertion: If a compass needle be kept at magnetic north pole of the earth, the compass needle may stay in any direction
Reason: Dip needle will stay vertical at the north pole of earth.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and the reason are correct, but the reason does not explain the assertion.
108 Medium
108 of 164
Understanding +4 | -1
Magnetic field strength due to a short bar magnet on its axial line at a distance x is B. Its value at the same distance on the equatorial line is
View answer and explanation
Correct option: D
B/2
Option D is correct. The magnetic field on the equatorial line is half the magnetic field on the axial line at the same distance for a short bar magnet.
109 Medium
109 of 164
Application +4 | -1
At a place the angle of dip is 30∘.30^\circ . If the horizontal component of earth’s magnetic field is BH,{B_H}, then the total field intensity is
View answer and explanation
Correct option: B
2BH3\frac{{2{B_H}}}{{\sqrt 3 }}
Option B (2BH3\frac{{2{B_H}}}{{\sqrt 3 }}) is correct because the total field intensity is related to the horizontal component by B=BHcos⁡δB = \frac{B_H}{\cos{\delta}}.
110 Medium
110 of 164
Remembering +4 | -1
A diamagnetic material in a magnetic field moves
View answer and explanation
Correct option: A
from stronger to weaker parts of the field
Option A (from stronger to weaker parts of the field) is correct because diamagnetic materials are repelled from regions of high magnetic field strength.
111 Easy
111 of 164
Understanding +4 | -1
When a ferromagnetic substance is heated to a temperature above its Curie temperature, it:
View answer and explanation
Correct option: A
Behaves like a paramagnetic substance
Option A is correct. Above the Curie temperature, the thermal energy disrupts the alignment of magnetic domains, causing the ferromagnetic substance to behave like a paramagnetic substance.
112 Medium
112 of 164
Understanding +4 | -1
Consider a short magnetic dipole of magnetic length 10 cm. Its geometric length is
View answer and explanation
Correct option: A
12 cm
Option A (12 cm) is correct because the geometric length is approximately 6/5 times the magnetic length for a short dipole.
113 Medium
113 of 164
Remembering +4 | -1
At which place, earth’s magnetism becomes horizontal
View answer and explanation
Correct option: D
Magnetic equator
Option D (Magnetic equator) is correct because at the magnetic equator, the Earth's magnetic field lines are parallel to the surface, making the field horizontal.
114 Easy
114 of 164
Application +4 | -1
At a certain place the angle of dip is 30∘30^{\circ} and the horizontal component of earth's magnetic field is 0.5 G0.5 \,\mathrm{G}. The earth's total magnetic field (in G), at that certain place, is :
View answer and explanation
Correct option: A
13\frac{1}{\sqrt{3}}
Option A (13\frac{1}{\sqrt{3}}) is correct because it represents the total magnetic field calculated from the horizontal component and the angle of dip.
115 Medium
115 of 164
Remembering +4 | -1
The magnetic induction in air at a distance dd from an isolated point pole of strength mm unit will be
View answer and explanation
Correct option: B
md2\frac{m}{{{d^2}}}
Option B is correct because the magnetic induction due to a point pole is inversely proportional to the square of the distance.
116 Medium
116 of 164
Application +4 | -1
A long magnet is cut into two equal parts, such that the length of each half is same as that of original magnet. If the period of original magnetic is TT, the period of new magnet is
View answer and explanation
Correct option: A
TT
Option B is correct because the frequency of oscillation is related to the magnetic field intensity, and using the given information, the magnetic field at the second place is approximately 0.36×10−6T0.36 \times 10^{-6} T.
117 Medium
117 of 164
Remembering +4 | -1
If M\mathrm{M} is magnetic moment and B\mathrm{B} is the magnetic field, then the torque is given by
View answer and explanation
Correct option: C
M→×B→\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}
Option C (M→×B→\overrightarrow{\mathrm{M}} \times \overrightarrow{\mathrm{B}}) is correct because the torque on a magnetic dipole in a magnetic field is given by the cross product of the magnetic moment and the magnetic field.
118 Easy
118 of 164
Understanding +4 | -1
The magnetic induction and magnetising field intensity in a sample of magnetic material are B\mathrm{B} and H\mathrm{H} respectively. The magnetic susceptibility of the material is:
View answer and explanation
Correct option: B
Bμ0H−1\frac{\mathrm{B}}{\mu_0 \mathrm{H}}-1
Option B (Bμ0H−1\frac{\mathrm{B}}{\mu_0 \mathrm{H}}-1) is correct because it represents the formula for magnetic susceptibility, χm=Bμ0H−1\chi_m = \frac{B}{\mu_0 H} - 1.
119 Hard
119 of 164
Application +4 | -1
Two bar magnets having same geometry with magnetic moments MM and 2M2 M are first placed in such a way that their similar poles are same side then its time period of oscillation is T1T_1. Now the polarity of one of the magnet is reversed then the time period of oscillation is T2T_2, so
View answer and explanation
Correct option: A
T1<T2T_1 < T_2
Option A (T1<T2T_1 < T_2) is correct because when similar poles are on the same side, the effective magnetic moment is higher, leading to a smaller time period.
120 Easy
120 of 164
Application +4 | -1
The period of oscillation of a freely suspended bar magnet is 4 s. If it is cut into two equal parts in length, then the time period of each part will be
View answer and explanation
Correct option: B
2 s
Option B is correct because the current required to produce a deflection in a tangent galvanometer is calculated using the tangent law, and the given values lead to approximately 1.1 A.
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