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NEET • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Showing 241-245 of 245 questions
241 Medium
241 of 245
Application +4 | -1
A body sliding on a smooth inclined plane required 4s to reach the bottom, starting from rest at the top. How much time does it takes to cover one-fourth the distance starting from rest at top?
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Correct option: B
2s
Option B (2s) is correct because the time taken is proportional to the square root of the distance covered in uniformly accelerated motion.
242 Easy
242 of 245
Application +4 | -1
On the horizontal surface of a truck (μ=0.6)\left( {\mu = 0.6} \right), a block of mass 1 kg is placed. If the truck is accelerating at the rate of 5m/sec25m/se{c^2} then frictional force on the block will be
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Correct option: A
5 N
Option A (5 N) is correct because the frictional force is equal to the product of the mass and the acceleration of the truck, as long as this value is less than the maximum static friction.
243 Medium
243 of 245
Analyzing +4 | -1
Statement-I: When a person walks on a rough surface, the frictional force exerted by surface on the person is opposite to the direction of his motion.
Statement-II: It is the force exerted by the road on the person that causes the motion.
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Correct option: C
Statement-I is false and statement-II is true
Option C is correct because the frictional force exerted by the surface on the person is in the direction of motion, and the force exerted by the road causes the motion.
244 Medium
244 of 245
Remembering +4 | -1
A force produces an acceleration of 1 m/s in a body of mass 1 kg. This form is defined as?
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Correct option: A
Newton
Option A is correct. A Newton is defined as the force required to accelerate a 1 kg mass at 1 m/s².
245 Medium
245 of 245
Application +4 | -1
A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration of 4.9m/s−24.9\mathrm{ }m/{s^{ - 2}} and then lowered with an acceleration of 4.9m/s−24.9\mathrm{ }m/{s^{ - 2}}. The ratio of tensions in first case to second cases is (g=9.8ms−2)\left( {g = 9.8\mathrm{ }m{s^{ - 2}}} \right)
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Correct option: C
3:13\mathrm{ }:\mathrm{ }1
Option C (3:13\mathrm{ }:\mathrm{ }1) is correct because the tension is greater when lifting up with acceleration than when lowering with the same acceleration.
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