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NEET • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Showing 61-90 of 245 questions

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61 Medium
61 of 245
Analyzing +4 | -1
For a body moving with relativistic speed, if the velocity is doubled then
View answer and explanation
Correct option: C
Its linear momentum will be more than double
Option C (Its linear momentum will be more than double) is correct because at relativistic speeds, the mass increases with velocity, leading to a greater increase in momentum than just doubling the velocity.
62 Medium
62 of 245
Remembering +4 | -1
Newton's second law of motion is
View answer and explanation
Correct option: A
F=dpdt{F}=\frac{{dp}}{{dt}}
Option A is correct. Newton's second law states that force equals the rate of change of momentum.
63 Easy
63 of 245
Understanding +4 | -1
The change in momentum per unit time of a body represents
View answer and explanation
Correct option: D
Resultant force
Option B is correct. The change in momentum per unit time is the definition of force.
64 Medium
64 of 245
Understanding +4 | -1
If μr,  μk{\mu _r},\,\,{\mu _k} and μs{\mu _s} represent the coefficients of rolling friction, kinetic and static friction, then
View answer and explanation
Correct option: D
μr<μk<μs{\mu _r} < {\mu _k} < {\mu _s}
Option D (μr<μk<μs{\mu _r} < {\mu _k} < {\mu _s}) is correct because rolling friction is generally less than kinetic friction, which is less than static friction.
65 Easy
65 of 245
Application +4 | -1
If the coefficient of friction is 3,\sqrt 3 , the angle of friction is
View answer and explanation
Correct option: B
60∘60^\circ
Option B is correct because the angle of friction is the angle whose tangent is the coefficient of friction, so tan⁡θ=3\tan{\theta} = \sqrt{3} implies θ=60°\theta = 60°.
66 Medium
66 of 245
Understanding +4 | -1
A person is measuring his weight by standing on a weighing machine inside a lift. When the lift is at rest, the machine shows his weight to be 55 kg. In between the floor when the lift is moving up with a constant speed of 10 km/hr, he again measures his weight, which is
View answer and explanation
Correct option: A
55 kg
Option A (55 kg) is correct because the weighing machine measures the normal force, which equals the weight when the lift moves at a constant speed (no acceleration).
67 Medium
67 of 245
Remembering +4 | -1
The three central concepts in Newtonian mechanics are
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Correct option: B
Mass, motion and force
Option B is correct. Mass, motion, and force are the fundamental concepts in Newtonian mechanics.
68 Easy
68 of 245
Application +4 | -1
A body of mass 40 kg40 \mathrm{~kg} resting on rough horizontal surface is subjected to a force PP which is just enough to start the motion of the body. If μs=0.5\mu_s=0.5, μk=0.4,g=10 ms−2\mu_k=0.4, g=10 \mathrm{~ms}^{-2} and the force PP is continuously applied on the body, then the acceleration of the body is
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because the applied force is just enough to overcome static friction, and once the body starts moving, the kinetic friction is less than the applied force, resulting in a net force and acceleration. However, the question asks for the acceleration *just* as the motion starts, which is zero.
69 Easy
69 of 245
Application +4 | -1
The average resisting force that must act on a 6 kg mass to reduce its speed from 65 cm/s to 15 cm/s in 0.3 s is
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Correct option: A
10 N
Option A (10 N) is correct because it is the average resisting force calculated using the impulse-momentum theorem.
70 Medium
70 of 245
Analyzing +4 | -1
Statement-1: A man starts walking towards west. Friction force on him acts towards east.
Statement-2 : Friction opposes relative motion.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false, Statement-2 is true. When a man walks west, the friction force acts towards west, and friction opposes relative motion.
71 Easy
71 of 245
Analyzing +4 | -1
Statement I: A car is moving in a horizontal circular plane with varying speed, then the frictional force is neither pointing towards the radial direction nor along the tangential direction.
Statement II: Components of the frictional force are providing the necessary tangential and centripetal acceleration, in the above situation.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A is correct because Statement I is true, Statement II is true, and Statement II is the correct explanation for Statement I. The frictional force provides both tangential and centripetal acceleration.
72 Medium
72 of 245
Application +4 | -1
A block moves down a smooth inclined plane of inclination θ\theta. Its velocity on reaching the bottom is v. If it slides down a rough inclined plane of same inclination, its velocity on reaching the bottom is v/n, where n is a number greater than 1. The coefficient of friction is given by
View answer and explanation
Correct option: A
μ=tan⁡θ(1−1n2)\mathrm{\mu } = \tan \mathrm{\theta }\left( {1 - \frac{1}{{{n^2}}}} \right)
Option A is correct because it correctly relates the coefficient of friction to the inclination angle and the ratio of velocities squared.
73 Medium
73 of 245
Remembering +4 | -1
In an ideal string tension at all points of all string will be
View answer and explanation
Correct option: A
Same
Option A is correct because in an ideal string, the tension is assumed to be the same at all points.
74 Easy
74 of 245
Application +4 | -1
A block of mass 3 kg is placed on the floor. The coefficient of static friction is 0.6. If a force of 3.8 N is applied on the block parallel to the floor, the force of friction between the block and floor (g=10 m/s2)\left( {g = 10\,m/{s^2}} \right) is
View answer and explanation
Correct option: A
3.8 N
The force of friction is equal to the applied force because the applied force is less than the maximum static friction, so the block doesn't move. Thus, the correct answer is A (3.8 N).
75 Medium
75 of 245
Analyzing +4 | -1
Assertion: The apparent weight of a person standing in a lift which moves upwards with uniform acceleration is always higher than his true weight.
Reason: The weight (on the earth surface) always acts downwards.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because while both statements are true, the reason doesn't explain why the apparent weight is higher.
76 Easy
76 of 245
Application +4 | -1
A block is limiting equilibrium on a rough horizontal surface. If the net contact force is 3\sqrt 3 times the normal force, the coefficient of static friction is
View answer and explanation
Correct option: A
2\sqrt 2
Option A (2\sqrt 2) is correct because the net contact force is the vector sum of the normal force and the frictional force, and in limiting equilibrium, the frictional force is equal to μ\mu times the normal force.
77 Medium
77 of 245
Understanding +4 | -1
When the speed of a moving body is doubled
View answer and explanation
Correct option: B
Its momentum is doubled
Option B is correct because momentum is directly proportional to velocity, so doubling the speed doubles the momentum.
78 Medium
78 of 245
Remembering +4 | -1
Impulse of a force is equal to the change in-
View answer and explanation
Correct option: C
Momentum
Option C is correct because the impulse of a force is equal to the change in momentum of the object it acts upon.
79 Easy
79 of 245
Application +4 | -1
A dynamometer DD is attached to two bodies of masses M=6 kgM=6 \mathrm{~kg} and m=4 kgm=4 \mathrm{~kg}. Forces F=20 NF=20 \mathrm{~N} and f=10 Nf=10 \mathrm{~N} are applied to the masses as shown. The dynamometer reads
View answer and explanation
Correct option: D
14 N14 \mathrm{~N}
Option D (14 N14 \mathrm{~N}) is correct because the dynamometer reads the tension in the string, which is the force exerted by one mass on the other.
80 Medium
80 of 245
Application +4 | -1
A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of 300{30^0} with the horizontal. The change in momentum (in magnitude) of the body is
View answer and explanation
Correct option: B
49.0  N−s49.0\;N - s
Option B (49.0;N−s49.0\\;N - s) is correct because the change in momentum is twice the initial vertical component of the momentum.
81 Easy
81 of 245
Remembering +4 | -1
In the above ques., the height to which the lift takes the passenger is
View answer and explanation
Correct option: D
36 meters
Option D (36 meters) is correct, but the question is incomplete and lacks context. Assuming the question refers to a lift moving with constant acceleration 'a' for a time 't', and asking for the distance traveled, and given a=2 m/s2 and t=6s, then the distance is 36 meters.
82 Medium
82 of 245
Understanding +4 | -1
It is easier to draw up a wooden block along an inclined plane than to haul it vertically, principally because
View answer and explanation
Correct option: C
Only a part of the weight has to be overcome
Option C (Only a part of the weight has to be overcome) is correct because when pulling along an inclined plane, only the component of weight along the plane needs to be overcome, which is less than the full weight.
83 Medium
83 of 245
Analyzing +4 | -1
STATEMENT-1 : It is easier to pull a heavy object than to push it on a level ground and

STATEMENT-2 : The magnitude of frictional force depends on the nature of the two surfaces in contact.
View answer and explanation
Correct option: B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
Option B (Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1) is correct because pulling reduces the normal force and thus friction, while the nature of surfaces is a separate factor.
84 Medium
84 of 245
Application +4 | -1
A shell is fired with a muzzle velocity of 20 ms−120\,m{s^{ - 1}} at an angle of 600{60^0} with the horizontal. At the top of trajectory the shell explodes into 2 fragments of equal masses. One of them comes to rest. The distance at which second fragment touches the ground from gun will be…. (g=10 m/s2)\left( {g = 10\,m/{s^2}} \right)
View answer and explanation
Correct option: C
303 m30\sqrt 3 \,m
Option C (303,m30\sqrt 3 \\,m) is correct because it is derived from applying the conservation of momentum after the explosion at the highest point of the trajectory.
85 Medium
85 of 245
Application +4 | -1
A body of mass 500g is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining height of 16m. How much energy is lost due to air friction?
View answer and explanation
Correct option: A
20 J
Option A (20 J) is correct because the energy lost due to air friction is the difference between the initial kinetic energy and the final potential energy at the maximum height.
86 Medium
86 of 245
Application +4 | -1
When an elevator is moving downward with a increasing speed, the apparent weight of a body inside elevator
View answer and explanation
Correct option: B
Will decrease
Option B (Will decrease) is correct because when the elevator accelerates downward, the apparent weight is less than the actual weight.
87 Hard
87 of 245
Application +4 | -1
The apparent weight of a mass in a lift moving up is 80 kg when its weight in the stationary lift is 60 kg. If the same lift now moves up with same retardation the weight of the mass will be
View answer and explanation
Correct option: A
40 kg
Option A (40 kg) is correct because the change in apparent weight is proportional to the acceleration, and the retardation is the same magnitude as the acceleration.
88 Easy
88 of 245
Application +4 | -1
A force of 10 N10 \mathrm{~N} acts on a body of mass 0.5 kg0.5 \mathrm{~kg} for 0.25 s starting from rest. What is its impulse?
View answer and explanation
Correct option: B
2.5 N−s2.5 \mathrm{~N}-\mathrm{s}
Option B (2.5 N−s2.5 \mathrm{~N}-\mathrm{s}) is correct because the impulse is calculated as the product of force and time.
89 Medium
89 of 245
Application +4 | -1
A projectile of mass m is thrown with a velocity v making an angle of 450{45^0} with the horizontal. The change in momentum from departure to arrival along vertical direction, is
View answer and explanation
Correct option: B
2  mv\sqrt 2 \;mv
Option B (2;mv\sqrt 2 \\;mv) is correct because the change in momentum in the vertical direction is twice the initial vertical momentum component.
90 Medium
90 of 245
Understanding +4 | -1
If the normal force is doubled, the coefficient of friction is
View answer and explanation
Correct option: A
Not changed
Option A (Not changed) is correct because the coefficient of friction is independent of the normal force.
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