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NEET • PHYSICS • KINETIC THEORY OF GASES

Kinetic theory of gases practice · Medium

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31 Medium
31 of 69
Application +4 | -1
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure (CP)\left( {{C_P}} \right) and at constant volume (CV)\left( {{C_V}} \right) is:
View answer and explanation
Correct option: D
7/57/5
Option D (7/57/5) is correct because the ratio of specific heats is calculated using the formula γ=1+2f\gamma = 1 + \frac{2}{f}, where f is the degrees of freedom.
32 Medium
32 of 69
Application +4 | -1
The diameter of oxygen atom is 3A∘3\mathop A\limits^ \circ. The fraction of molecular volume to the actual volume occupied by oxygen at STP is
View answer and explanation
Correct option: B
8×10−48 \times {10^{ - 4}}
Option B (8×10−48 \times {10^{ - 4}}) is correct because it represents the ratio of the volume occupied by oxygen molecules to the total volume at STP, considering the diameter of the oxygen atom.
33 Medium
33 of 69
Understanding +4 | -1
The absolute temperature of a gas is determined by
View answer and explanation
Correct option: D
The mean square velocity of the molecules
Option D (The mean square velocity of the molecules) is correct because the absolute temperature of a gas is directly related to the average kinetic energy, which is proportional to the mean square velocity of the molecules.
34 Medium
34 of 69
Application +4 | -1
If the mean free path of atoms is doubled then the pressure of gas will become
View answer and explanation
Correct option: B
P2\frac{P}{2}
Option B (P2\frac{P}{2}) is correct because the pressure is inversely proportional to the mean free path.
35 Medium
35 of 69
Understanding +4 | -1
At O K which of the following properties of a gas will be zero
View answer and explanation
Correct option: A
Kinetic energy
Option A (Kinetic energy) is correct because at 0 K, all molecular motion ceases, resulting in zero kinetic energy.
36 Medium
36 of 69
Understanding +4 | -1
Supposing the distance between the atoms of a diatomic gas to be constant, its specific heat at constant volume per mole (gram mole) is
View answer and explanation
Correct option: A
52R\frac{5}{2}R
Option A (52R\frac{5}{2}R) is correct because a diatomic gas with constant distance between atoms has 3 translational and 2 rotational degrees of freedom, leading to Cv=52RC_v = \frac{5}{2}R.
37 Medium
37 of 69
Remembering +4 | -1
The relation between the gas pressure PP and average kinetic energy per unit volume EE is
View answer and explanation
Correct option: D
P=23EP = \frac{2}{3}E
The correct answer is D because the relation between gas pressure and average kinetic energy per unit volume is P = (2/3)E, derived from kinetic theory of gases.
38 Medium
38 of 69
Understanding +4 | -1
Relation between the ratio of specific heats (γ)\left( \gamma \right) of gas and degree of freedom 'f' will be
View answer and explanation
Correct option: C
f=2/(γ−1)f = 2/\left( {\gamma - 1} \right)
Option C (f=2/(γ−1)f = 2/(\gamma - 1)) is correct because it represents the correct relationship between degrees of freedom and the ratio of specific heats.
39 Medium
39 of 69
Understanding +4 | -1
Consider a gas with density ρ\rho and cˉ{\bar c} as the root mean square velocity of its molecules contained in a volume. If the system moves as whole with velocity v,  v,\; then the pressure exerted by the gas is
View answer and explanation
Correct option: A
13ρcˉ2\frac{1}{3}\rho {{\bar c}^2}
Option A (13ρcˉ2\frac{1}{3}\rho {\bar c}^2) is correct because the pressure exerted by a gas depends on the root mean square velocity of its molecules, not the bulk velocity of the system.
40 Medium
40 of 69
Application +4 | -1
A monoatomic gas is kept at room temperature 300K. Calculate the average kinetic energy of gas molecule (Use k=1.38×10−23MKSk = 1.38 \times {10^{ - 23}}MKS units)
View answer and explanation
Correct option: C
0.039eV0.039eV
Option C (0.039eV0.039eV) is correct because it is the average kinetic energy of a monoatomic gas molecule at 300K, calculated using the formula KE=32kTKE = \frac{3}{2}kT.
41 Medium
41 of 69
Analyzing +4 | -1
Read the given statements and decide which is/are correct on the basis of kinetic theory of gases
(I) Energy of one molecule at absolute temperature is zero
(II) r.m.s.r.m.s.speeds of different gases are same at same temperature
(III) For one gram of all ideal gas kinetic energy is same at same temperature
(IV) For one mole of all ideal gases mean kinetic energy is same at same temperature
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because all the given statements are incorrect based on the kinetic theory of gases.
42 Medium
42 of 69
Analyzing +4 | -1
Given below are two statements :

Statement I : The temperature of a gas is −73∘C-73^{\circ} \mathrm{C}. When the gas is heated to 527∘C527^{\circ} \mathrm{C}, the root mean square speed of the molecules is doubled.

Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is true but statement II is false
Option D is correct because Statement I is true (RMS speed doubles when temperature quadruples in Kelvin), but Statement II is false (PV = 2/3 * Translational KE).
43 Medium
43 of 69
Understanding +4 | -1
Water is used to cool radiators of engines, because
View answer and explanation
Correct option: D
It has high specific heat
Option D (It has high specific heat) is correct because water's high specific heat allows it to absorb a large amount of heat with a small temperature change.
44 Medium
44 of 69
Understanding +4 | -1
Molecules of a gas behave like
View answer and explanation
Correct option: C
Perfectly elastic rigid sphere
Option C (Perfectly elastic rigid sphere) is correct because the kinetic theory of gases assumes that gas molecules undergo perfectly elastic collisions and are rigid.
45 Medium
45 of 69
Application +4 | -1
The Molecules of a given mass of a gas have r.m.s. Velocity of 200ms−1 at 270C200ms_{}^{ - 1}\,at\,{27^0}C and 1.0×105Nm−21.0 \times {10^5}N{m^{ - 2}} pressure. When the temperature and pressure of the gas are respectively, 1270C  and  0.05×105Nm−2{127^0}C{\mkern 1mu} {\mkern 1mu} and{\mkern 1mu} {\mkern 1mu} 0.05 \times {10^5}N{m^{ - 2}} , The r.m.s velocity of its molecule in   ms−1\;ms_{}^{ - 1} is
View answer and explanation
Correct option: B
4003\frac{{400}}{{\sqrt 3 }}
Option B (4003\frac{{400}}{{\sqrt 3 }}) is correct because it is the calculated rms velocity based on the given temperature and pressure changes.
46 Medium
46 of 69
Application +4 | -1
The speeds of 5 molecules of a gas (in arbitary units) are as follows : 2,3,4,5,6. The r.m.s speed for these molecules is
View answer and explanation
Correct option: D
4:244:24
Option D (4:244:24) is correct because it is the calculated root mean square speed for the given set of molecular speeds.
47 Medium
47 of 69
Application +4 | -1
For a gas molecule with a 6 degrees of freedom the law of equipartition of energy gives the following relation between the molar specific heat (Cv)\left( {Cv} \right) and gas constant (R)\left( R \right)
View answer and explanation
Correct option: D
Cv=3R{C_v} = 3R
Option D (Cv=3R{C_v} = 3R) is correct because, according to the equipartition theorem, each degree of freedom contributes R/2 to the molar specific heat at constant volume, and with 6 degrees of freedom, Cv=6∗(R/2)=3RC_v = 6 * (R/2) = 3R.
48 Medium
48 of 69
Analyzing +4 | -1
Same gas is filled in two vessels of the same volume at the same temperature. If the ratio of the number of molecules is 1:41: 4, then
A. The r.m.s. velocity of gas molecules in two vessels will be the same.
B. The ratio of pressure in these vessels will be 1:41 : 4.
C. The ratio of pressure will be 1:11 : 1.
D. The r.m.s. velocity of gas molecules in two vessels will be in the ratio of 1:41 : 4.
Choose the correct answer from the options given
below
View answer and explanation
Correct option: C
A and B only
Option A (A and B only) is correct because the r.m.s. velocity depends only on temperature, and the pressure ratio is directly proportional to the number of molecules.
49 Medium
49 of 69
Remembering +4 | -1
The translational kinetic energy of gas molecule for one mole of the gas is equal to
View answer and explanation
Correct option: A
32RT\frac{3}{2}RT
Option A (32RT\frac{3}{2}RT) is correct because the translational kinetic energy of one mole of gas is given by this formula.
50 Medium
50 of 69
Analyzing +4 | -1
Assertion (A) : If a gas container is placed in a moving train, the temperature of gas will increase.

Reason (R) : Kinetic energy of gas molecules will increase.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct because the assertion is false (temperature doesn't necessarily increase), but the reason is true (kinetic energy of the gas molecules will increase due to the train's motion).
51 Medium
51 of 69
Analyzing +4 | -1
Assertion: An ideal gas has infinitely many molar specific heats.
Reason: Specific heat is amount of heat needed to raise the temperature of 1 mole of gas by 1 K1 \mathrm{~K}.
View answer and explanation
Correct option: B
If both Assertion and reason are true and the Reason is not a correct explanation of the Assertion
Option B is correct because while both the assertion and reason are true, the reason doesn't explain why an ideal gas has infinitely many molar specific heats.
52 Medium
52 of 69
Analyzing +4 | -1
Let V\mathrm{V} denote the root mean square speed of the molecules in an ideal diatomic gas at absolute temperature T\mathrm{T}. The mass of a molecule is ' mm '. Neglecting vibrational energy terms, which is false?
View answer and explanation
Correct option: C
The average rotational kinetic energy of a molecule is mv2/4\mathrm{mv}^2 / 4
The statement that is false is C (The average rotational kinetic energy of a molecule is mv2/4\mathrm{mv}^2 / 4) because for a diatomic molecule, the average rotational kinetic energy is kT\mathrm{kT}, which is equivalent to mv2/6\mathrm{mv}^2 / 6.
53 Medium
53 of 69
Application +4 | -1
A sample of gas is 00C{0^0}C. To what temperature it must be raised in order to double the r.m.s. speed
of the molecule
View answer and explanation
Correct option: B
8190C{819^0}C
Option B (8190C{819^0}C) is correct because the RMS speed is proportional to the square root of the absolute temperature, so doubling the RMS speed requires quadrupling the absolute temperature.
54 Medium
54 of 69
Analyzing +4 | -1
The specific heats, Cp  and  CV{C_p}\mathrm{ \,\,and }\,\,{C_V} of a gas of diatomic molecules, A are given (in units of Jmol−1K−1\mathrm{J mo}{\mathrm{l}^{ - 1}}{K^{ - 1}}) by 29 and 22, respectively. Another gas of diatomic molecules B, has the corresponding values 30 and 21. If they are treated as ideal gases, then
View answer and explanation
Correct option: A
A has a vibrational mode but B has none
The correct answer is A (A has a vibrational mode but B has none) because the experimental value of Cp for gas A is greater than the theoretical value without vibration, indicating the presence of a vibrational mode.
55 Medium
55 of 69
Understanding +4 | -1
If the rms velocity of a gas is vv ,then
View answer and explanation
Correct option: B
v2/T=constant{v^2}/T = \mathrm{constant}
Option B (v2/T=constant{v^2}/T = \mathrm{constant}) is correct because the rms velocity squared is directly proportional to the temperature.
56 Medium
56 of 69
Application +4 | -1
The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K, the root mean square velocity of the gas molecule is V. at 480 K it becomes
View answer and explanation
Correct option: B
3 V
Option A (4 V) is incorrect. The correct answer is 2V. The rms velocity is proportional to the square root of the temperature. If the temperature is increased by a factor of 4, the rms velocity increases by a factor of 2.
57 Medium
57 of 69
Analyzing +4 | -1
Given below are two statements :
Statement I : The average momentum of a molecule in a sample of an ideal gas depends on temperature.
Statement II : The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v.2v.
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is false but Statement II is true
Option D (Statement I is false but Statement II is true) is correct because the average momentum is zero, and the rms speed doubles when temperature doubles and molecules dissociate.
58 Medium
58 of 69
Remembering +4 | -1
The ratio of the molar heat capacities of a diatomic gas at constant pressure to that at constant volume is
View answer and explanation
Correct option: D
75\frac{7}{5}
Option D (75\frac{7}{5}) is correct because for a diatomic gas, Cp=72RC_p = \frac{7}{2}R and Cv=52RC_v = \frac{5}{2}R, so the ratio Cp/Cv=7/5C_p/C_v = 7/5.
59 Medium
59 of 69
Analyzing +4 | -1
The minimum attainable pressure of ideal gas in the process T=T0+αV2T=T_0+\alpha V^2, where T0T_0 and α\alpha are positive constants and VV is the volume of one mole of gas is xRαT0x R \sqrt{\alpha T_0}. Find the value of xx.
View answer and explanation
Correct option: A
2
The correct answer is 2 because the minimum pressure is found by minimizing the pressure function derived from the ideal gas law and the given temperature-volume relationship.
60 Medium
60 of 69
Remembering +4 | -1
At a given temperature the r.m.s.r.m.s. velocity of molecules of the gas is
View answer and explanation
Correct option: D
Inversely proportional to square root of molecular weight
Option D (Inversely proportional to square root of molecular weight) is correct because the RMS velocity is inversely proportional to the square root of the molar mass (molecular weight).
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