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NEET • PHYSICS • GRAVITATION

Gravitation practice · Medium

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Showing 121-135 of 135 questions
121 Medium
121 of 135
Application +4 | -1
Determine the energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 3R.
View answer and explanation
Correct option: D
7GMm8R\frac{{7GMm}}{{8R}}
Option D (7GMm8R\frac{{7GMm}}{{8R}}) is correct because it represents the total energy required, which is the sum of the change in potential energy and the kinetic energy in the orbit.
122 Medium
122 of 135
Analyzing +4 | -1
Assertion: If value of acceleration due to gravity of a planet is lesser than earth then escape velocity from planet is lesser too.
Reason: Escape velocity just depends only on acceleration due to gravity.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. Escape velocity depends on both acceleration due to gravity and the radius of the planet.
123 Medium
123 of 135
Analyzing +4 | -1
Average density of the earth
View answer and explanation
Correct option: B
is a complex function of gg
Option B (is a complex function of gg) is correct because the average density of the Earth is related to the gravitational constant GG and the acceleration due to gravity gg, which are interconnected through the Earth's mass and radius.
124 Medium
124 of 135
Application +4 | -1
A particle of mass m is moving in a horizontal circle of radius r,under a centripetal force =kr2′  where  k  is  a  constant.= \frac{k}{{{r^2}'}}\;\mathrm{where\;}k\mathrm{\;is\;a\;constant}.
View answer and explanation
Correct option: A
The potential energy of the particle is zero
The potential energy is usually defined to be zero at infinity, and since the force is centripetal, it's directed towards the center, and we are not given any information to calculate the potential energy, so Option A (The potential energy of the particle is zero) is the most appropriate.
125 Medium
125 of 135
Understanding +4 | -1
Where will it be profitable to purchase 1 kilogram sugar
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Correct option: B
At equator
The correct answer is B (At equator) because the weight of sugar is least at the equator due to the Earth's shape and rotation, making it profitable to purchase there.
126 Medium
126 of 135
Application +4 | -1
The radius of earth is 6400 km. At what depth below the surface of earth the acceleration due to gravity decreases by 2% than on surface of earth.
View answer and explanation
Correct option: B
128 km
Option B (128 km) is correct because the acceleration due to gravity decreases linearly with depth, and a 2% decrease corresponds to a specific depth calculated using the formula.
127 Medium
127 of 135
Analyzing +4 | -1
Assertion: If gravitational force is proportional to 1R3\frac{1}{\mathrm{R}^3} then Keplar's second law would not be affected.
Reason: For Keplar's second law, central nature of force is the only condition.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because Kepler's second law is based on the conservation of angular momentum, which is a consequence of the central nature of the force, regardless of its specific dependence on distance.
128 Medium
128 of 135
Analyzing +4 | -1
Kepler's third law states that the square of period of revolution (TT) of a planet around the sun is proportional to the third power of average distance, rr between the sun and the planet i.e. T2=Kr3{T}^2={Kr}^3. Here, K{K} is constant. If masses of the sun and the planet are M{M} and m{m} respectively, then as per Newton's law of gravitation force of attraction between them is F=GMmr2F=\frac{G M m}{r^2}, where G{G} is gravitational constant. The relation between G{G} and K{K} is described as
View answer and explanation
Correct option: B
GMK=4π2G M K=4 \pi^2
Option B (GMK=4π2G M K=4 \pi^2) is correct because Kepler's third law relates the period of revolution to the orbital radius and the gravitational constant.
129 Medium
129 of 135
Understanding +4 | -1
If the earth rotates faster than its present speed, the weight of an object will
View answer and explanation
Correct option: B
Decrease at the equator but remain unchanged at the poles
Option B (Decrease at the equator but remain unchanged at the poles) is correct because the effective weight decreases at the equator due to increased centrifugal force, but remains unchanged at the poles.
130 Medium
130 of 135
Application +4 | -1
Radius of orbit of satellite of earth is R. Its kinetic energy is proportional to
View answer and explanation
Correct option: A
1R\frac{1}{R}
Option A (1R\frac{1}{R}) is correct because the kinetic energy of a satellite is inversely proportional to the radius of its orbit.
131 Medium
131 of 135
Understanding +4 | -1
A small satellite is in elliptical orbit around Earth as shown. If L denotes the magnitude of its angular momentum and K denotes kinetic energy
View answer and explanation
Correct option: D
L2=L1 and K2>K1{L_2} = {L_1}\,and\,{K_2} > {K_1}
Option D (L2=L1 and K2>K1{L_2} = {L_1}\,and\,{K_2} > {K_1}) is correct because angular momentum is conserved in an elliptical orbit, and kinetic energy is greater at the point closest to Earth.
132 Medium
132 of 135
Analyzing +4 | -1
A clock S is based on oscillation of a spring and a clock P is based on pendulum motion. Both clocks run at the same rate on earth. On a planet having the same density as earth but twice the radius
View answer and explanation
Correct option: B
PP will run faster than SS
Option B (PP will run faster than SS) is correct because the time period of a spring clock is independent of gravity, while the time period of a pendulum clock depends on gravity, which changes on the new planet.
133 Medium
133 of 135
Application +4 | -1
If earth were to suddenly contract to half its present size, without change in its mass, the duration of the day will be
View answer and explanation
Correct option: C
6 hours
Option C (6 hours) is correct because the duration of the day is inversely proportional to the square of the radius.
134 Medium
134 of 135
Understanding +4 | -1
The centripetal force acting on a satellite orbiting round the earth and the gravitational force of earth acting on the satellite both equal FF. The net force on the satellite is
View answer and explanation
Correct option: B
FF
Option B (FF) is correct because the net force is the gravitational force, which provides the centripetal force.
135 Medium
135 of 135
Understanding +4 | -1
For a body to escape from earth, angle at which it should be fired is?
View answer and explanation
Correct option: D
any angle
Option D is correct because the escape velocity is independent of the angle at which the body is projected. The body needs to have sufficient kinetic energy to overcome the gravitational potential energy, regardless of the angle.
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