Gravitation practice · Easy

The weight of the body at the centre of the earth is

A mass of $3 \times {10^{24}}\,kg$ is to be compressed in a sphere in such a way that the escape velocity from the sphere is $9 \times {10^8}\,m/s.$ Radius of the sphere should be $\left[ {G = 6.67 \times {{10}^{ - 11}}\,N{m^2}/k{g^2}} \right]$

A body of mass 60 g experiences a gravitational force of 3.0 N, when placed at a particular point. The magnitude of the gravitational field intensity at that point is:

When a body is taken from the equator to the poles, its weight

The velocity with which a projectile must be fired so that it escapes Earth's gravitation does not depend on

The gravitational field due to a uniform solid sphere of mass $M$ and radius $a$ at the centre of the sphere is

What should be the period of rotation of earth so as to make any object on the equator weigh half of its present value?

Assertion: For a satellite revolving very near to earth's surface the time period of revolution is given by $1 \mathrm{~h} \, 24 \mathrm{~min}$.
Reason: The period of revolution of a satellite depends only upon its height above the earth's surface.

Earth orbiting satellite will escape, if