Electric potential and capacitance practice · Mixed difficulty

To increase the resonant frequency in series LCR
circuit,

A condenser is charged to a p.d. of 240 volts, its energy is $2 \times {10^{ - 5}}\,\,{\text{joule}}{\text{.}}$ If the battery is there and the space between the plates is filled up with a dielectric medium $\left( {{\varepsilon _r} = 10} \right),$ its new energy is

To store electric charge, we use

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and work done by the battery will be

A sphere P of radius 6 cm is charged to a potential of 12 V and is connected to an uncharged sphere Q of radius 3 cm. Determine the loss energy during the process.

The energy stored in a condenser of capacity $C$ which has been raised to a potential $V$ is given by

The dielectric constant of a perfect conductor is

The ratio of electric fields due to an electric dipole on the axis and equatorial line at equal distance will be

A hollow conducting sphere of radius $R$ has a charge $\left( { + Q} \right)$ on its surface. What is the electric potential within the sphere at a distance $r = R/3$ from its centre

The capacitance of an isolated conducting sphere of radius $R$ is proportional to

The combined capacity of the parallel combination of two capacitors is four times their combined capacity when connected in series. This means that

The magnetic potential at a point on the axial line of a bar magnet of dipole moment M is V. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point?

Two charges $+ 3.2 \times {10^{ - 19}}C$ and $- 3.2 \times {10^{ - 19}}C$ kept $2.4\mathrm{\;}\mathop A\limits^ \circ$ apart forms a dipole. If it is kept in uniform electric field of intensity $4 \times {10^5}\;volt/m$ then what will be its electrical energy in equilibrium

A condenser having a capacity of $6\mu F$ is charged to $100V$ and is then joined to an uncharged condenser of $14\mu F$ and then removed. The ratio of the charges on $6\mu F$ and $14\mu F$ and the potential of 6μF will be

A parallel plate condenser is immersed in an oil of dielectric constant 3. The field between the plates is

Assertion: In the absence of an external electric field, the dipole moment per unit volume of polar dielectric is zero.

Reason: The dipoles of a polar dielectric are randomly oriented.

An oil condenser has a capacity of $200\,\,\mu F.$ The oil has a dielectric constant 5. When the oil leaks out its new capacity is

The potential at a point $x$ (measured in $\mu m$) due to some charges situated on the x-axis is given by
$V\left( x \right) = 20/\left( {{x^2} - 4} \right)Volts.$ The electric field $E$ at $x = 4\mu m$ is given by

A spherical equipotential surface is not possible

The electric potential at a point distant $\text{r}$ from an electric dipole is proportional to

Assertion (A): Electric potential on the surface of a charged sphere of radius $R$ is $V$. Then electric field at a distance $r=\frac{R}{2}$ from centre is $\frac{V}{2 R}$. Charge is distributed uniformly over the volume.

Reason (R) : From centre to surface, electric field varies linearly with $r$. Here, $r$ is distance from centre.

Two identical capacitors are joined in parallel, charged to a potential $V$ and then separated and then connected in series $i.e.$ the positive plate of one is connected to negative of the other

Value of potential at a point due to a point charge is

The energy stored in a capacitor of capacitance $\text{C}$ having a charge $\text{Q}$ under a potential $\text{V}$ is

A positive charge is moved from low potential point A to a high potential point B. Then the electric potential energy

If the plates of a parallel plate capacitor connected to a battery are moved close to each other, then

A. the charge stored in it, increases.

B. the energy stored in it, decreases.

C. its capacitance increases.

D. the ratio of charge to its potential remains the same.

E. the product of charge and voltage increases.

Choose the most appropriate answer from the options given below:

Two particles of charges 4 nC and Q are kept in air with a separation of 10 cm between them. If the electrostatic potential energy of the system is $1.8 \, \mu \mathrm{J},$ then Q =

An air filled parallel plate capacitor the capacity $C.$ If distance between plates is doubled and it is immersed in a liquid then capacity becomes twice. Dielectric constant of the liquid is

The electric field due to a dipole at a distance $r$ on its axis is

An uncharged capacitor is connected to a battery. On charging the capacitor