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NEET • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Medium

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61 Medium
61 of 92
Analyzing +4 | -1
Two point charges QQ each are placed at a distance dd apart. A third point charge qq is placed at a distance xx from mid-point on the perpendicular bisector. The value of xx at which charge qq will experience the maximum Coulombs force is :
View answer and explanation
Correct option: D
x=d22x=\frac{d}{2 \sqrt{2}}
The maximum Coulomb force occurs at x=d22x=\frac{d}{2 \sqrt{2}}. This is found by differentiating the force expression with respect to x and setting it to zero to find the maximum.
62 Medium
62 of 92
Understanding +4 | -1
A particle of ′m′'m' and charge ′q′'q' is accelerated through a potential difference of V  volt,V\;volt, its energy will be
View answer and explanation
Correct option: A
qVqV
The correct answer is qV because the energy gained by a charge accelerated through a potential difference is the product of the charge and the potential difference.
63 Medium
63 of 92
Analyzing +4 | -1
For a uniformly charged ring of radius R,R, the electric field on its axis has the largest magnitude at a distance hh from its centre. Then, value of hh is
View answer and explanation
Correct option: A
R2\frac{R}{{\sqrt 2 }}
Option A (R2\frac{R}{{\sqrt 2 }}) is correct because the electric field on the axis of a ring is maximum at a distance of R/sqrt(2) from the center.
64 Medium
64 of 92
Understanding +4 | -1
If a unit positive charge is taken from one point to another over an equipotential surface, then
View answer and explanation
Correct option: D
No work is done
Option D is correct because the potential difference between any two points on an equipotential surface is zero, hence no work is done.
65 Medium
65 of 92
Remembering +4 | -1
The maximum electric field that a dielectric medium of a capacitor can withstand without break
down (of its insulating property) is called its :
View answer and explanation
Correct option: C
dielectric strength
Option C (dielectric strength) is correct because it defines the maximum electric field a dielectric can withstand before breakdown.
66 Medium
66 of 92
Application +4 | -1
Force acting upon a charged particle kept between the plates of a charged condenser is F.F. If one plate of the condenser is removed, then the force acting on the same particle will become
View answer and explanation
Correct option: B
F/2F/2
Option B (F/2F/2) is correct because removing one plate halves the electric field strength, and thus halves the force on the charged particle.
67 Medium
67 of 92
Application +4 | -1
A sphere of radius R has a uniform distribution of electric charge (q) in its volume. At a distance x from its centre, the electric field (at x=R2x = \frac{R}{2}) will be
View answer and explanation
Correct option: B
q8πε0R2\frac{q}{{8\pi {\varepsilon _0}{R^2}}}
Option B (q8πε0R2\frac{q}{{8\pi {\varepsilon _0}{R^2}}}) is correct because it is derived from Gauss's law considering the charge enclosed within the Gaussian surface at x = R/2.
68 Medium
68 of 92
Analyzing +4 | -1
Statement-I: A charge qq is lying at the centre of the line joining two similar charges QQ each. The system will be in equilibrium if q=Q/4q=Q / 4

Statement-II: For QQ to be in equilibrium, sum of the forces on QQ due to rest of the two charges must zero.
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Statement-I is false, Statement-II is true. The system will be in equilibrium if q = -Q/4. Statement II is true because the sum of forces on Q due to other charges must be zero for equilibrium.
69 Medium
69 of 92
Application +4 | -1
Charge q2{q_2} of mass mm revolves around a stationary charge q1{q_1} in a circular orbit of radius rr The orbital periodic time of q2{q_2} would be
View answer and explanation
Correct option: A
[4π3mr2kq1q2]1/2{\left[ {\frac{{4{\pi ^3}m{r^2}}}{{k{q_1}{q_2}}}} \right]^{1/2}}
Option A ([4π3mr2kq1q2]1/2{\left[ {\frac{{4{\pi ^3}m{r^2}}}{{k{q_1}{q_2}}}} \right]^{1/2}}) is correct because the centripetal force is provided by the electrostatic force, and equating them allows solving for the period.
70 Medium
70 of 92
Analyzing +4 | -1
Assertion (A): The basic difference between magnetic lines of force and electric lines of force is electric lines of force are discontinuous and magnetic lines of force are continuous.
Reason (R): Magnetic lines of force exist in a magnet but no electric lines of force exists in a charged body.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Option A is correct because electric lines of force are discontinuous due to the existence of isolated charges, while magnetic lines of force are continuous as magnetic monopoles do not exist. The reason correctly explains this difference.
71 Medium
71 of 92
Analyzing +4 | -1
The bob of simple pendulum is hanging vertically down from a fixed identical bob by means of string of length ll. If both bobs are charged with a charge with a charge qq each, time period of the pendulum is (ignore the radii of the bobs)
View answer and explanation
Correct option: C
2πlg2\pi \sqrt {\frac{l}{\mathrm{g}}}
The time period remains 2πlg2\pi \sqrt{\frac{l}{g}} because the electrostatic force is horizontal and does not affect the vertical component of gravity, which determines the pendulum's period.
72 Medium
72 of 92
Understanding +4 | -1
Which of the following is deflected by electric field
View answer and explanation
Correct option: D
α\alpha-particles
The correct answer is D because alpha particles are charged particles and experience a force in an electric field, causing them to be deflected.
73 Medium
73 of 92
Analyzing +4 | -1
Statement-I: Acceleration of charged particle in non uniform electric field does not depend on veloicty of charged particle

Statement-II: charge is an invariant quantity, that is, amount of charge on particle doesn't depend on frame of referenced
View answer and explanation
Correct option: A
Statement-I is True, statement-II is True
Both statements are true. The acceleration of a charged particle in an electric field depends on the electric field and the charge, not the velocity. Charge is also an invariant quantity, meaning it doesn't change with the frame of reference.
74 Medium
74 of 92
Remembering +4 | -1
The force on qq charge is placed in an uniform electric field EE will be
View answer and explanation
Correct option: B
qE{qE}
The correct answer is qE because the force on a charge in an electric field is given by the product of the charge and the electric field strength.
75 Medium
75 of 92
Analyzing +4 | -1
Point charges +4q,  −q  and+4q+ 4q,\,\, - q\;\mathrm{ and } + 4q are kept on the x−axis\mathrm{x - axis} at points x=0,  x=a  and   x=2ax = 0,\,\,x = a\mathrm{ \,\,and}\,\,\,\mathrm{ }x = 2a respectively, for displacement along x−axis\mathrm{x - axis} :-
View answer and explanation
Correct option: C
all the charges are in unstable equilibrium
Option C (all the charges are in unstable equilibrium) is correct because any small displacement from their positions will result in a force that pushes them further away.
76 Medium
76 of 92
Remembering +4 | -1
The electric field created by a point charge falls with distance rr from the point charge as
View answer and explanation
Correct option: B
1r2\frac{1}{{{r^2}}}
Option B is correct because the electric field due to a point charge is inversely proportional to the square of the distance from the charge, as described by Coulomb's Law.
77 Medium
77 of 92
Remembering +4 | -1
Dielectric constant for metal is
View answer and explanation
Correct option: B
Infinite
The dielectric constant for a metal is infinite because metals allow free movement of charge, effectively canceling out any applied electric field.
78 Medium
78 of 92
Understanding +4 | -1
An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct
View answer and explanation
Correct option: C
Electric flux entering into sphere and leaving the sphere are same
Option C Electric flux entering into sphere and leaving the sphere are same is correct because the net charge of the dipole is zero, so the net flux is zero.
79 Medium
79 of 92
Analyzing +4 | -1
A neutron, a proton and an electron are placed in a uniform electric field.
View answer and explanation
Correct option: D
Magnitude of acceleration will be different.
The magnitude of acceleration will be different because the force on each particle depends on its charge, and the acceleration depends on both the force and the mass, which are different for each particle.
80 Medium
80 of 92
Understanding +4 | -1
A ring of radius rr carries a charge QQ uniformly distributed over its length. A charge qq is placed at its centre will experience a force equal to
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because the net force on a charge at the center of a uniformly charged ring is zero due to symmetry.
81 Medium
81 of 92
Remembering +4 | -1
Electric charges under action of electric forces is called
View answer and explanation
Correct option: A
electrostatic
Option A is correct because electrostatics deals with electric charges at rest or in slow motion under the influence of electric forces.
82 Medium
82 of 92
Analyzing +4 | -1
Which of the following statement is correct?
View answer and explanation
Correct option: B
Electric field is non-zero on the axis of hollow current carrying wire
Option B (Electric field is non-zero on the axis of hollow current carrying wire) is correct because while the magnetic field is zero inside, the electric field due to the charges on the wire is not necessarily zero.
83 Medium
83 of 92
Analyzing +4 | -1
Two identical conducting spheres carrying different charges attract each other with a force FF when placed in air medium at a distance dd apart. The spheres are brought into contact and then taken to their original positions. Now the two spheres repel each other with a force whose magnitude is equal to that of the initial attractive force. The ratio between initial charges on the spheres is
View answer and explanation
Correct option: C
−3(3+√8)or(−3+√8)- 3\left( {3 + \surd 8} \right)\mathrm{or}\left( { - 3 + \surd 8} \right)
Option A is correct because it correctly sets up and solves the equations for the forces before and after contact, leading to the correct ratio of initial charges.
84 Medium
84 of 92
Understanding +4 | -1
Two parallel metal plates having charges +Q+ Q and −Q- Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will
View answer and explanation
Correct option: C
Decrease
Option C is correct because the electric field between the plates decreases when a dielectric (kerosene oil) is introduced.
85 Medium
85 of 92
Application +4 | -1
Force between two identical charges placed at a distance of rr in vacuum is FF. Now a slab of dielectric of dielectric constant 4 is inserted between these two charges. If the thickness of the slab is r/2,r/2, then the force between the charges will become
View answer and explanation
Correct option: D
F4\frac{F}{4}
Option D (F/4) is correct because the introduction of a dielectric slab effectively reduces the electric field and hence the force between the charges.
86 Medium
86 of 92
Application +4 | -1
An electron enters in high potential region V2{V_2} from lower potential region V1{V_1} then its velocity
View answer and explanation
Correct option: A
Will increase
Option A (Will increase) is correct because an electron moving from a lower potential to a higher potential region gains kinetic energy, thus increasing its velocity.
87 Medium
87 of 92
Understanding +4 | -1
A comb run through one’s dry hair attracts small bits of paper. This is due to
View answer and explanation
Correct option: C
The atoms in the paper get polarised by the charged comb
Option C (The atoms in the paper get polarised by the charged comb) is correct because the charged comb induces a polarization in the paper, leading to an attractive force.
88 Medium
88 of 92
Analyzing +4 | -1
Statement-I: A positive point charge is brought in an electric field, the electric field at neary by point will increase

Statement-II: Electric field produced by charge may favour the existing electric filed
View answer and explanation
Correct option: D
Statement-I is false, Statement-II is false
Both statements are false. Bringing a positive charge nearby can either increase or decrease the electric field depending on the direction of the existing field. Also, the electric field produced by a charge can either favor or oppose the existing electric field.
89 Medium
89 of 92
Analyzing +4 | -1
Consider E1→=xi^+j^\overrightarrow {{E_1}} = x\hat i + \hat j and E2→=xy2i^+x2y  j^;\overrightarrow {{E_2}} = x{y^2}\hat i + {x^2}y\;\hat j; then
View answer and explanation
Correct option: C
Both are electrostatic
Option C (Both are electrostatic) is correct because both electric fields satisfy the condition for being electrostatic: ∇×E⃗=0\nabla \times \vec{E} = 0.
90 Medium
90 of 92
Remembering +4 | -1
The force per unit charge is known as_____.
View answer and explanation
Correct option: B
Electric field
The correct answer is Electric field because the electric field is defined as the force per unit charge.
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