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NEET • PHYSICS • ATOMS

Atoms practice · Mixed difficulty

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Showing 61-90 of 130 questions

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61 Hard
61 of 130
Application +4 | -1
A 100eV100 \mathrm{eV} electron collides with a stationary helium ion (He+)\left(\mathrm{He}^{+}\right)in its ground state and excites to a higher level. After the collision, He+\mathrm{He}^{+}ions emits two photons in succession with wavelength 1085A∘1085\mathop {\text{A}}\limits^ \circ and 304A∘304\mathop {\text{A}}\limits^ \circ. Also the energy of the electron after the collision is 6×……eV6 \times \ldots \ldots \mathrm{eV} (approximately). Given h=6.63×10−34Js\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}.
View answer and explanation
Correct option: A
8
The correct answer is A (8) because after the collision and subsequent photon emissions, the remaining energy of the electron is approximately 8 eV.
62 Medium
62 of 130
Application +4 | -1
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number ZZ of hydrogen like ion is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the Rydberg formula equates the wavelengths, leading to Z=2.
63 Medium
63 of 130
Understanding +4 | -1
An electron moving around the nucleus with an angular momentum ll has a magnetic moment
View answer and explanation
Correct option: B
e2ml\frac{e}{{2m}}l
Option B (e2ml\frac{e}{{2m}}l) is correct because the magnetic moment is directly proportional to the angular momentum and inversely proportional to twice the mass.
64 Easy
64 of 130
Application +4 | -1
The number of different wave lengths may be observed in the spectrum from a hydrogen sample if the atoms are excited to fourth excited state is
View answer and explanation
Correct option: C
10
Option C (10) is correct because the number of different wavelengths is given by the formula n(n-1)/2, where n is the energy level.
65 Medium
65 of 130
Analyzing +4 | -1
Which of the following parameters is same for electron in all hydrogen like atoms and ions in their ground states?
View answer and explanation
Correct option: D
(Speed) (Radius)
Option D ((Speed) (Radius)) is correct because the product of speed and radius is proportional to n/Z, which is the same for all hydrogen-like atoms and ions in their ground states (n=1).
66 Hard
66 of 130
Application +4 | -1
A hydrogen atom moves with a velocity uu and makes a head on inelastic collision with another stationary H\mathrm{H}-atom. Both atoms are in ground state before collision. The minimum value of uu if one of them is to be given a minimum excitation energy is
View answer and explanation
Correct option: B
6.24×104 ms−16.24 \times 10^4 \mathrm{~ms}^{-1}
Option B (6.24×104 ms−16.24 \times 10^4 \mathrm{~ms}^{-1}) is correct because it is the minimum velocity required for one of the hydrogen atoms to reach the first excited state after an inelastic collision, calculated using conservation of momentum and energy.
67 Medium
67 of 130
Application +4 | -1
In hydrogen atom, when electron jumps from second to first orbit, then energy emitted is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the energy emitted when an electron jumps from the second to the first orbit in a hydrogen atom is 10.2 eV, which is not among the given options.
68 Hard
68 of 130
Application +4 | -1
An electron rotates in a circle around a nucleus having positive charge Ze.\text{Ze}. Correct relation between total energy (E)\text{(E)} of electron to its potential energy (U)\text{(U)} is:
View answer and explanation
Correct option: D
2E=U2 \mathrm{E}=\mathrm{U}
Option D (2E=U2E = U) is correct because the total energy (E) of an electron in orbit is half of its potential energy (U) and has the opposite sign.
69 Medium
69 of 130
Remembering +4 | -1
In Davisson and Germer experiment intensity of scattered beam of electron was maximum at 50∘50^{\circ} scattering angle and at
View answer and explanation
Correct option: C
54 V54 \mathrm{~V} accelerating potential
Option C (54 V54 \mathrm{~V} accelerating potential) is correct because the maximum intensity of the scattered electron beam in the Davisson-Germer experiment occurs at this voltage when the scattering angle is 50∘50^{\circ}.
70 Medium
70 of 130
Remembering +4 | -1
The order of the size of nucleus and Bohr radius of an atom respectively are
View answer and explanation
Correct option: A
10−14  m,  10−10  m{10^{ - 14}}\,\,m,\,\,{10^{ - 10}}\,\,m
Option A (10−14 m, 10−10 m{10^{ - 14}}\,m,\,{10^{ - 10}}\,m) is correct because the typical size of a nucleus is about 10−14{10^{ - 14}} m and the Bohr radius is about 10−10{10^{ - 10}} m.
71 Medium
71 of 130
Remembering +4 | -1
The angular momentum of electron in nth{n^{\mathrm{th}}} orbit is given by
View answer and explanation
Correct option: C
nh2πn\frac{h}{{2\pi }}
Option B (Statement I is true; Statement II is true; Statement II is not the correct explanation for Statement I) is correct because Bohr's postulate was to avoid the problem of radiating electrons, but not directly explained by classical physics.
72 Easy
72 of 130
Understanding +4 | -1
E1E_1 is energy of KαK_\alpha photon of aluminium, E2E_2 is energy of KβK_\beta photon of aluminium and E3E_3 is energy of KαK_\alpha photon from sodium, then the correct order of energies is given:
View answer and explanation
Correct option: D
E2>E1>E3E_2 > E_1 > E_3
Option D (E2>E1>E3E_2 > E_1 > E_3) is correct because KβK_\beta photons have higher energy than KαK_\alpha for the same element, and energy increases with atomic number.
73 Easy
73 of 130
Application +4 | -1
According to Bohr model, magnetic field at the centre (at the nucleus) of a hydrogen atom due to the motion of the electron in nnth orbit is proportional to:
View answer and explanation
Correct option: B
1/n51 / n^5
Option B (1/n51 / n^5) is correct because the magnetic field at the center of a hydrogen atom is proportional to 1n5\frac{{1}}{{n^5}}.
74 Medium
74 of 130
Remembering +4 | -1
The transition of an electron from n2=5,6,……{n_2} = 5,6, \ldots \ldots to n1=4{n_1} = 4 gives rise to
View answer and explanation
Correct option: D
Brackett series
Option D (Brackett series) is correct because the Brackett series corresponds to transitions where electrons fall to the n=4 energy level.
75 Medium
75 of 130
Understanding +4 | -1
Assertion: For the scattering of α\alpha-particles at large angles, only the nucleus of the atom is responsible.
Reason: Nucleus is very heavy in comparison to electrons.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A (If both assertion and reason are true and reason is the correct explanation of assertion) is correct because the nucleus is much heavier than electrons, so alpha particles interacting at large angles are primarily influenced by the nucleus.
76 Medium
76 of 130
Remembering +4 | -1
The Rydberg constant RR for hydrogen is
View answer and explanation
Correct option: D
R=(14πε0)2.2π2me4ch3R = {\left( {\frac{1}{{4\pi {\varepsilon _0}}}} \right)^2}.\frac{{2{\pi ^2}m{e^4}}}{{c{h^3}}}
Option A (6) is correct because the maximum number of photons emitted corresponds to all possible transitions from n=4 to lower energy levels.
77 Easy
77 of 130
Analyzing +4 | -1
In Bohr's theory for hydrogen-like atoms:
View answer and explanation
Correct option: C
In hypothetical condition if mass of the revolving electron is increased, electron velocity in the orbit will remain exactly same
Option D (None of the above) is incorrect. Option C is correct because velocity is independent of mass if angular momentum is quantized.
78 Easy
78 of 130
Application +4 | -1
Taking the wavelength of first Balmer line in the hydrogen spectrum (n=3(n=3 ton =2)=2) as 660 nm660 \mathrm{~nm}, then the wavelength of 2nd 2^{\text {nd }} balmer line in the same spectrum (n=4(n=4 ton =2)=2) will be
View answer and explanation
Correct option: A
488.9 nm488.9 \mathrm{~nm}
Option A (488.9 nm488.9 \mathrm{~nm}) is correct because it is calculated using the Rydberg formula for the Balmer series, considering the transition from n=4 to n=2.
79 Medium
79 of 130
Understanding +4 | -1
If the ionization potential of helium atom is 24.6 volt, the energy required to ionize it will be
View answer and explanation
Correct option: A
24.6  eV24.6\,\,eV
Option A (24.6  eV24.6\,\,eV) is correct because the ionization potential in volts is numerically equal to the ionization energy in electron volts.
80 Medium
80 of 130
Understanding +4 | -1
The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true
View answer and explanation
Correct option: A
Its kinetic energy increases and its potential and total energies decrease
Option A (Its kinetic energy increases and its potential and total energies decrease) is correct because as the electron transitions to a lower energy level, its velocity increases (kinetic energy increases), and its potential and total energies become more negative (decrease).
81 Medium
81 of 130
Remembering +4 | -1
In Davisson - Germer experiment maximum intensity is observed at
View answer and explanation
Correct option: B
54∘{54^ \circ } and 50 V
Option C (54∘{54^ \circ } and 50 V) is correct because the maximum intensity in the Davisson-Germer experiment is observed at this angle and voltage due to constructive interference of electron waves.
82 Medium
82 of 130
Remembering +4 | -1
Intensity of XX-rays depends upon the number of
View answer and explanation
Correct option: A
Electrons
Option A (Electrons) is correct because the intensity of X-rays is directly related to the number of electrons striking the target in the X-ray tube.
83 Medium
83 of 130
Understanding +4 | -1
Statement-I: In the experiment of alpha particle scattering, extremely thin gold foils are preferred over other metals.

Statement-II: Gold is a ductile material.
View answer and explanation
Correct option: A
Statement-I and Statement-II are true
Option A (Statement-I and Statement-II are true) is correct because gold foils are preferred due to their ductility, allowing them to be made extremely thin, which is essential for single-layer scattering in Rutherford's experiment.
84 Medium
84 of 130
Application +4 | -1
The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 A∘6561\,\mathop \mathrm{A}\limits^ \circ. The wavelength of the second spectral line in the Balmer series of singly ionized helium atom is
View answer and explanation
Correct option: A
1215 A∘1215\,\mathop \mathrm{A}\limits^ \circ
Option A (1215A∘1215 \mathop \mathrm{A}\limits^ \circ) is correct because the wavelength is calculated using the Rydberg formula, considering the change in Z and n values.
85 Easy
85 of 130
Application +4 | -1
A moving hydrogen atom makes a head-on collision with another stationary hydrogen atom. Before collision both atoms are in their ground states, and after collision they move together. The mininum value of the kinetic energy of the moving hydrogen atom (in eV)\mathrm{eV}), such that one of the atom reaches the 1st excited state will be:
View answer and explanation
Correct option: A
10.210.2
Option A (10.210.2) is correct because the minimum kinetic energy required is equal to the energy difference between the ground state and the first excited state, which is 10.2 eV.
86 Easy
86 of 130
Application +4 | -1
The energy necessary to remove the electron from n=10n = 10 state in hydrogen atom will be
View answer and explanation
Correct option: B
0.136 eV0.136\,eV
Option B (0.136 eV0.136\,eV) is correct because the energy required to remove an electron from the n=10n=10 state is En=−13.6n2eV=13.6100eV=0.136eVE_n = \frac{{-13.6}}{{n^2}} eV = \frac{{13.6}}{{100}} eV = 0.136 eV.
87 Medium
87 of 130
Understanding +4 | -1
In an XX-rays tube, the intensity of the emitted XX-rays beam is increased by
View answer and explanation
Correct option: A
Increasing the filament current
Option A (Increasing the filament current) is correct because increasing the filament current increases the number of electrons emitted, thus increasing the intensity of the X-ray beam.
88 Easy
88 of 130
Understanding +4 | -1
The angular momentum of electron is J. Its magnetic moment will be
View answer and explanation
Correct option: A
eJ2m\frac{{eJ}}{{2m}}
Option A (eJ2m\frac{{eJ}}{{2m}}) is correct because the magnetic moment is related to the angular momentum by the formula μ=eJ2m\mu = \frac{{eJ}}{{2m}}.
89 Easy
89 of 130
Understanding +4 | -1
The maximum number of photons emitted by an H-atom, if atom is excited to states with principal quantum number four is
View answer and explanation
Correct option: A
6
Option B (Paschen series is a line spectrum in the infrared) is correct because the Paschen series involves transitions to the n=3 energy level, which results in infrared photons and a line spectrum.
90 Medium
90 of 130
Analyzing +4 | -1
Which of the following statements about the Bohr model of the hydrogen atom is false
View answer and explanation
Correct option: D
Potential energy of electron in n=2n = 2 orbit is less than that in n=1n = 1 orbit
Option D (Potential energy of electron in n=2n = 2 orbit is less than that in n=1n = 1 orbit) is false because potential energy is less negative (higher) in the n=2 orbit than in the n=1 orbit.
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