Skip to main content
Back to STRUCTURE OF ATOM

Your Progress

0 / 492 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 61-90 of 492 questions

Preparing practice and saved progress…

61 Easy
61 of 492
Remembering +4 | -1
Cathode-ray tube is used in:
View answer and explanation
Correct option: C
A television set
Option C (A television set) is correct because cathode-ray tubes (CRTs) were historically used as the display component in television sets.
62 Easy
62 of 492
Application +4 | -1
Which of the following ions has electronic configuration [Ar]3d6:\left[ {\mathrm{Ar}} \right]3{d^6}:
View answer and explanation
Correct option: D
  27Co3+{\mathrm{\;}_{27}}\mathrm{C}{\mathrm{o}^{3 + }}
Option D (  27Co3+){\mathrm{\;}_{27}}\mathrm{C}{\mathrm{o}^{3 + }}) is correct because Cobalt (Co) has an atomic number of 27. Co³⁺ loses 3 electrons, resulting in the electronic configuration [Ar]3d⁶.
63 Easy
63 of 492
Remembering +4 | -1
The minimum energy required to eject an electron from an atom is called :
View answer and explanation
Correct option: D
Work function
Option D (Work function) is correct because the work function is defined as the minimum energy required to eject an electron from an atom.
64 Medium
64 of 492
Application +4 | -1
Wavelength of a photon is 2.0×10−11m,h=6.6×10−34  Js.2.0 \times {10^{ - 11}}\mathrm{m},h = 6.6 \times {10^{ - 34}}\;\mathrm{Js}.. The momentum of photon is:
View answer and explanation
Correct option: A
3.3×10−23  kg  m  s−13.3 \times {10^{ - 23}}\mathrm{\;kg\;m\;}{\mathrm{s}^{ - 1}}
Option A (3.3×10−23  kg  m  s−13.3 \times {10^{ - 23}}\mathrm{\;kg\;m\;}{\mathrm{s}^{ - 1}}) is correct because it is calculated using the formula relating momentum and wavelength of a photon.
65 Hard
65 of 492
Application +4 | -1
The nucleus and an atom can be assumed to be spherical. The radius of the nucleus of mass no. A is given by 1.25×10−13×A1/3cm.1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.. The atomic radius of atom is 1 Å. If the mass no. is 64, the fraction of the atomic volume that is occupied by nucleus is:
View answer and explanation
Correct option: D
1.25×10−131.25 \times {10^{ - 13}}
Option D (1.25×10−131.25 \times {10^{ - 13}}) is correct because it represents the ratio of the volume of the nucleus to the volume of the atom, calculated using the given radii and the formula for the volume of a sphere.
66 Medium
66 of 492
Application +4 | -1
When the frequency of light incident on a metallic plate is doubled, the KE of the emitted photoelectrons will be:
View answer and explanation
Correct option: C
Increased but more than doubled of the previous KE
Option C (Increased but more than doubled of the previous KE) is correct because the kinetic energy is related to the frequency by KE=hf−WKE = hf - W, where W is the work function. Doubling the frequency does not simply double the kinetic energy.
67 Hard
67 of 492
Analyzing +4 | -1
Which of the following energy change is less than third balmer transition in He+\mathrm{He}^{+} ion:
View answer and explanation
Correct option: B
Third separation energy of Li+2\mathrm{Li}^{+2} ion
The correct answer is B (Third separation energy of Li+2\mathrm{Li}^{+2} ion) because its energy is less than the third Balmer transition in He+\mathrm{He}^{+} ion.
68 Easy
68 of 492
Understanding +4 | -1
Mg2+\mathrm{M}{\mathrm{g}^{2 + }} is isoelectrionic with
View answer and explanation
Correct option: C
Na+\mathrm{N}{\mathrm{a}^ + }
Option C (Na+\mathrm{N}{\mathrm{a}^ + }) is correct because both Mg2+\mathrm{M}{\mathrm{g}^{2 + }} and Na+\mathrm{N}{\mathrm{a}^ + } have 10 electrons, making them isoelectronic.
69 Medium
69 of 492
Remembering +4 | -1
The ratio of specific charge of an electron to that of proton is
View answer and explanation
Correct option: B
76.54236111
The correct answer is B (76.54236111) because the specific charge (charge/mass) of an electron is much greater than that of a proton.
70 Medium
70 of 492
Application +4 | -1
Which of the following particles moving with same velocity would be associated with smaller de-Broglie wavelength?
View answer and explanation
Correct option: B
Oxygen molecule
Option B (Oxygen molecule) is correct because the de Broglie wavelength is inversely proportional to the mass, and oxygen molecule has the largest mass among the given options.
71 Easy
71 of 492
Application +4 | -1
According to (n+l) rule after completing 'np' level the electron enters to:
View answer and explanation
Correct option: B
(n+1)s\left( {n + 1} \right)s
Option B ((n+1)s(n + 1)s) is correct because according to the (n+l) rule, after filling the 'np' level, the next orbital to be filled is the (n+1)s orbital, as it has the lowest (n+l) value.
72 Easy
72 of 492
Understanding +4 | -1
Isoelectronic pair among the following is
View answer and explanation
Correct option: B
Ar and Ca2+\mathrm{C}{\mathrm{a}^{2 + }}
Option B (Ar and Ca2+\mathrm{C}{\mathrm{a}^{2 + }}) is correct because both species have the same number of electrons (18).
73 Hard
73 of 492
Understanding +4 | -1
The angular momentum of electron of H-atom is proportional to:
View answer and explanation
Correct option: C
r\sqrt r
Option C (r\sqrt r) is correct because the angular momentum is proportional to r\sqrt r based on Bohr's quantization condition and the relationship between velocity and radius.
74 Medium
74 of 492
Remembering +4 | -1
Which one of the following has unit positive charge and 1 u mass?
View answer and explanation
Correct option: C
Proton
Option C (Proton) is correct because a proton has a unit positive charge and a mass of approximately 1 atomic mass unit (1 u).
75 Hard
75 of 492
Application +4 | -1
The correct set of four 517 the electron of Rubedium atom (Z=37) is
View answer and explanation
Correct option: C
5,0,0,+125,0,0, + \frac{1}{2}
Option C (5,0,0,+125,0,0, + \frac{1}{2}) is correct because it represents the quantum numbers for the last electron of Rubidium (Z=37), which is in the 5s orbital.
76 Medium
76 of 492
Application +4 | -1
The energy levels for   zA(+z−1){\;_z}{A^{\left( { + z - 1} \right)}} can be given by:
View answer and explanation
Correct option: A
En for  A(+Z−1)=Z2×En for  H{E_n}\,for\,\,{A^{\left( { + Z - 1} \right)}} = {Z^2} \times {E_n}\,for\,\,H
Option A is correct because the energy levels for a hydrogen-like species are proportional to Z squared times the energy levels of hydrogen.
77 Easy
77 of 492
Application +4 | -1
Magnetic quantum number for the last electron in sodium is:
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the last electron in sodium (1s² 2s² 2p⁶ 3s¹) occupies the 3s orbital, which has an azimuthal quantum number (l) of 0. Therefore, the magnetic quantum number (m) is also 0.
78 Medium
78 of 492
Understanding +4 | -1
Which of the following statement(s) is/are incorrect regarding photoelectric effect?

(i) The number of electrons ejected is proportional to the intensity of light.

(ii) There is some time lag between the striking of light beam on the metal surface and the ejection of electrons.

(iii) The kinetic energy of ejected electrons depends upon the brightness of light.

(iv) The kinetic energy of the ejected electron is proportional to the frequency of the incident radiation.
View answer and explanation
Correct option: B
(ii) and (iii)
Option B is correct. There is no time lag in the photoelectric effect, and the kinetic energy depends on the frequency, not the brightness, of the light.
79 Medium
79 of 492
Application +4 | -1
Wavelengths of different radiations are given below, arrange in increasing order of energies
λ(A)=300 nm, λ(B)=30μm, λ(C)=3 nm, λ(D)=30A∘\lambda \left( A \right) = 300\,nm,\,\lambda \left( B \right) = 30\mu m,\,\lambda \left( C \right) = 3\,nm,\,\lambda \left( D \right) = 30{A^ \circ }
View answer and explanation
Correct option: A
B<A<C=DB < A < C = D
Option A (B<A<C=DB < A < C = D) is correct because energy is inversely proportional to wavelength. Shorter wavelengths correspond to higher energy.
80 Easy
80 of 492
Remembering +4 | -1
Different lines in Lyman series of hydrogen spectrum lie in …. Region
View answer and explanation
Correct option: A
Ultraviolet
Option A (Ultraviolet) is correct because the Lyman series corresponds to transitions to the n=1 energy level, which results in the emission of ultraviolet photons.
81 Hard
81 of 492
Analyzing +4 | -1
Based on equation E=−2.178×10−18 J(Z2n2)\mathrm{E}=-2.178 \times 10^{-18} \mathrm{~J}\left(\frac{Z^2}{n^2}\right), certain conclusions are written. Which of them is not correct ?
View answer and explanation
Correct option: C
For n=1\mathrm{n}=1, the electron has a more negative energy than it does for n=6\mathrm{n}=6 which mean that the electron is more loosely bound in the smallest allowed orbit.
Option C (For n=1\mathrm{n}=1, the electron has a more negative energy than it does for n=6\mathrm{n}=6 which mean that the electron is more loosely bound in the smallest allowed orbit) is not correct because a more negative energy indicates a *stronger* binding to the nucleus, not a looser one.
82 Easy
82 of 492
Remembering +4 | -1
When an electron moves from higher orbit to a lower orbit … is produced
View answer and explanation
Correct option: B
Emission spectra
Option B (Emission spectra) is correct because when an electron moves from a higher to a lower energy level, it emits energy in the form of photons, creating an emission spectrum.
83 Easy
83 of 492
Application +4 | -1
The frequency of a green light is 6×1014Hz.6 \times {10^{14}}\mathrm{Hz}. Its wavelength is:
View answer and explanation
Correct option: A
500 nm
Option A (500 nm) is correct because wavelength is the speed of light divided by the frequency, and using the given frequency yields a wavelength of 500 nm.
84 Easy
84 of 492
Application +4 | -1
The ratio of ionization energy of H-and Be+3B{e^{ + 3}} is
View answer and explanation
Correct option: D
1:161:16
Option D (1:16) is correct because ionization energy is proportional to Z2Z^2, where Z is the atomic number. For H, Z=1, and for Be+3, Z=4, so the ratio is 12 : 42 = 1:16.
85 Easy
85 of 492
Understanding +4 | -1
The de-Broglie equation applies
View answer and explanation
Correct option: C
All the material objects in motion
Option C (All the material objects in motion) is correct because the de Broglie equation applies to all matter, relating wavelength to momentum.
86 Medium
86 of 492
Remembering +4 | -1
Compared to mass of lightest nucleus the mass of an electron is only:
View answer and explanation
Correct option: C
1/18001/1800
Option C is correct because the mass of an electron is approximately 1/1800th the mass of the lightest nucleus (Hydrogen).
87 Easy
87 of 492
Remembering +4 | -1
The quantum levels upto n=3 has:
View answer and explanation
Correct option: C
s,p,d-levels
Option C (s,p,d-levels) is correct because for n=3, the possible values of l are 0, 1, and 2, corresponding to s, p, and d orbitals, respectively.
88 Hard
88 of 492
Analyzing +4 | -1
A single electron species in energy level (orbit number nn ) with energy XX was provided with excess of energy so that it jumps to higher energy level with energy YY. If it can emit radiations of six different wavelengths on de-excitement between these two energy levels, then the correct relation is
View answer and explanation
Correct option: C
XY=1+3n\sqrt{\frac{X}{Y}}=1+\frac{3}{n}
Option C (XY=1+3n\sqrt{\frac{X}{Y}}=1+\frac{3}{n}) is correct. The number of spectral lines emitted relates to the initial and final energy levels, and the energy is inversely proportional to the square of the energy level.
89 Easy
89 of 492
Remembering +4 | -1
What is the ration of mass of an electron to the mass of a proton?
View answer and explanation
Correct option: C
1:18371:1837
Option C (1:18371:1837) is correct because the mass of an electron is approximately 1/1837th the mass of a proton.
90 Medium
90 of 492
Remembering +4 | -1
The three quantum numbers &nbsp;n,ln,l and mm&nbsp;are the outcome of:
View answer and explanation
Correct option: B
Solution of Schr&ouml;dinger principle
Option B (Solution of Schr\"odinger principle) is correct because the three quantum numbers n,l,n, l, and mm arise from solving the Schr\"odinger equation for the hydrogen atom.
Revision notes and key takeaways

Review STRUCTURE OF ATOM in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 492 questions

Your practice

0 / 492 answered · 492 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.