$A{\rm{and}}B$ are two salts. $A$ with dilute ${\rm{HCl}}$ and $B$ with conc. ${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$ react to give reddish brown vapours, hence $A$ and $B$ respectively are:

${\rm{NaN}}{{\rm{O}}_2},{\rm{NaBr}}$

${\rm{NaBr}},{\rm{NaN}}{{\rm{O}}_3}$

${\rm{NaN}}{{\rm{O}}_3},{\rm{NaBr}}$

${\rm{NaBr}},{\rm{NaN}}{{\rm{O}}_2}$

Which reagent would enable you to remove ${\rm{SO}}_4^{2 - }$ ions from solution containing both ${\rm{SO}}_4^{2 - }$ and ${\rm{C}}{{\rm{l}}^ - }$ ions?

${\rm{Ba}}{\left( {{\rm{OH}}} \right)_2}$

An alloy of ${\rm{Na}} + {\rm{K}}$ is:

Used in specially designed thermometers

${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_2}{{\rm{O}}_3}$ is reduced by ${{\rm{I}}_2}$ to

${\rm{N}}{{\rm{a}}_2}{{\rm{S}}_4}{{\rm{O}}_6}$

${\rm{N}}{{\rm{a}}_2}{\rm{S}}{{\rm{O}}_4}$

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NEET • CHEMISTRY • S-BLOCK ELEMENTS

S-block elements practice · Mixed difficulty

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Showing 1-30 of 113 questions

1 Medium

1 of 113

Understanding +4 | -1

Which of the following exists in polymeric form?

View answer and explanation

Correct option: B

\mathrm{BeC}{\mathrm{l}_2}

Option B is correct because

BeCl_2

exists in a polymeric form in the solid state, with chlorine atoms bridging between beryllium atoms.

2 Easy

2 of 113

Application +4 | -1

If 5 moles of

\mathrm{BaCl}_{2}

is mixed with 2 moles of

\mathrm{Na}_{3} \mathrm{PO}_{4}

, the maximum number of moles of

\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}

formed is ________ (Nearest integer)

View answer and explanation

Correct option: A

Option A (1) is correct because the reaction stoichiometry and limiting reactant determine the maximum moles of Ba3(PO4)2 formed.

3 Hard

3 of 113

Remembering +4 | -1

Alkali metal superoxides are obtained by the reaction of

View answer and explanation

Correct option: A

Oxygen with alkali metal in liquid ammonia

Option A (Oxygen with alkali metal in liquid ammonia) is correct because alkali metal superoxides are obtained by reacting alkali metals with excess oxygen in liquid ammonia.

4 Hard

4 of 113

Remembering +4 | -1

Pearl ash and caustic potash are chemically:

View answer and explanation

Correct option: A

{\mathrm{K}_2}\mathrm{C}{\mathrm{O}_3}\mathrm{and KOH}

Option A (

{\mathrm{K}_2}\mathrm{C}{\mathrm{O}_3}\mathrm{and KOH}

) is correct because pearl ash is potassium carbonate (

{\mathrm{K}_2}\mathrm{C}{\mathrm{O}_3}

) and caustic potash is potassium hydroxide (KOH).

5 Easy

5 of 113

Understanding +4 | -1

When sodium chloride solution is electrolysed, the gas that is liberated at the cathode is

View answer and explanation

Correct option: C

Hydrogen

Option C is correct because during the electrolysis of aqueous sodium chloride, water is reduced at the cathode to produce hydrogen gas and hydroxide ions.

6 Medium

6 of 113

Application +4 | -1

What is product of reaction :

\underset {\text{(dilute)}}{Ba(OH)_2}+H_2O_2+ClO_2 \longrightarrow

View answer and explanation

Correct option: D

Ba\left(ClO_2\right)_2

Option D (

Ba(ClO_2)_2

) is correct because the reaction of barium hydroxide, hydrogen peroxide, and chlorine dioxide produces barium chlorite and other products.

7 Easy

7 of 113

Understanding +4 | -1

Which among the following elements has the tendency to form covalent compounds.

View answer and explanation

Correct option: B

Be

The correct answer is B (

Be

) because Beryllium, due to its small size and high polarizing power, has a greater tendency to form covalent compounds compared to other alkaline earth metals.

8 Easy

8 of 113

Remembering +4 | -1

The non-metal which is not affected by

\mathrm{NaOH}

View answer and explanation

Correct option: A

\mathrm{C}

Option A (

\mathrm{C}

) is correct because carbon is generally unreactive with NaOH under normal conditions.

9 Hard

9 of 113

Application +4 | -1

Reaction of

\mathrm{BeO}

with ammonia and hydrogen fluoride gives

A

which on thermal decomposition gives

\mathrm{BeF}_{2}

and

\mathrm{NH}_{4} \mathrm{F}

. What is '

{A}

View answer and explanation

Correct option: D

\left(\mathrm{NH}_{4}\right)_{2} \mathrm{BeF}_{4}

Option D ((

\mathrm{NH}_{4}

)

_{2} \mathrm{BeF}_{4}

) is correct because the reaction sequence and products indicate the formation of ammonium tetrafluoroberyllate.

10 Medium

10 of 113

Understanding +4 | -1

Solution of sodium metal in liquid

\mathrm{N}{\mathrm{H}_3}

is strongly reducing due to the presence of :

View answer and explanation

Correct option: B

Solvated electrons

Option B is correct because the blue color and reducing properties of the solution are due to the presence of solvated electrons, which are free electrons surrounded by ammonia molecules.

11 Medium

11 of 113

Application +4 | -1

A doctor by mistake administers a

\mathrm{Ba}\left(\mathrm{NO}_3\right)_2

solution to a patient for radiography investigations. Which of the following should be given as the best to prevent the absorption of soluble barium?

View answer and explanation

Correct option: B

\mathrm{Na}_2 \mathrm{SO}_4

Option B (Na2SO4) is correct because it will react with Ba(NO3)2 to form insoluble BaSO4, preventing the absorption of soluble barium.

12 Medium

12 of 113

Analyzing +4 | -1

A\mathrm{and}B

are two salts.

A

with dilute

\mathrm{HCl}

and

B

with conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

react to give reddish brown vapours, hence

A

and

B

respectively are:

View answer and explanation

Correct option: D

\mathrm{NaN}{\mathrm{O}_2},\mathrm{NaBr}

Option D (

\mathrm{NaN}{\mathrm{O}_2},\mathrm{NaBr}

) is correct because

\mathrm{NaBr}

with conc.

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

and

\mathrm{NaN}{\mathrm{O}_2}

with dilute

\mathrm{HCl}

produce reddish-brown vapors.

13 Easy

13 of 113

Application +4 | -1

Which reagent would enable you to remove

\mathrm{SO}_4^{2 - }

ions from solution containing both

\mathrm{SO}_4^{2 - }

and

\mathrm{C}{\mathrm{l}^ - }

ions?

View answer and explanation

Correct option: C

\mathrm{Ba}{\left( {\mathrm{OH}} \right)_2}

Option C is correct because

Ba(OH)_2

will precipitate

SO_4^{2-}

ions as

BaSO_4

, which is insoluble, while not reacting with

Cl^-

ions.

14 Easy

14 of 113

Remembering +4 | -1

An alloy of

\mathrm{Na} + \mathrm{K}

is:

View answer and explanation

Correct option: C

Both (1) and (2)

Option C (Zero, 1) is correct because electrolysis of

H_2SO_5

gives

H_2O_2

at the anode, and

H_2SO_5

has zero peroxy bonds while

H_2O_2

has one.

15 Easy

15 of 113

Analyzing +4 | -1

Which possesses highest lattice energy?

View answer and explanation

Correct option: B

\mathrm{LiF}

Option B (LiF) is correct because lattice energy is inversely proportional to the size of the ions and directly proportional to the charge. LiF has the smallest ions among the given options, leading to the highest lattice energy.

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16 Hard

16 of 113

Understanding +4 | -1

Following statements regarding the periodic trends of chemical reactivity of the alkali metals and the halogens are given. Which of these statements gives the correct picture?

View answer and explanation

Correct option: D

In alkali metals the reactivity increases but in the halogens it decreases with increase in atomic number down the group.

Option D is correct because the reactivity of alkali metals increases down the group due to decreasing ionization energy, while the reactivity of halogens decreases down the group due to decreasing electronegativity and electron affinity.

17 Medium

17 of 113

Understanding +4 | -1

\mathrm{N}{\mathrm{a}_2}{\mathrm{S}_2}{\mathrm{O}_3}

is reduced by

{\mathrm{I}_2}

View answer and explanation

Correct option: D

\mathrm{N}{\mathrm{a}_2}{\mathrm{S}_4}{\mathrm{O}_6}

Option D is correct because sodium thiosulphate (

\mathrm{Na}_2\mathrm{S}_2\mathrm{O}_3

) reacts with iodine (

{\mathrm{I}_2}

) to form sodium tetrathionate (

\mathrm{Na}_2\mathrm{S}_4\mathrm{O}_6

) and sodium iodide.

18 Hard

18 of 113

Analyzing +4 | -1

Two metals ‘x’ and ‘y’ belong to the same group of S – block. ‘x’ forms a soluble sulphate but insoluble oxide, ‘y’ forms soluble oxide but insoluble sulphate x and y are respectively

View answer and explanation

Correct option: A

Mg and Ba

Option A (Mg and Ba) is correct because Magnesium forms a soluble sulfate but an insoluble oxide, while Barium forms a soluble oxide but an insoluble sulfate.

19 Easy

19 of 113

Remembering +4 | -1

On heating washing soda, we get:

View answer and explanation

Correct option: D

{\mathrm{H}_2}\mathrm{O}\left( v \right)

Option D (

{\mathrm{H}_2}\mathrm{O}\left( v \right)

) is correct because washing soda (Na2CO3.10H2O) loses water molecules upon heating.

20 Medium

20 of 113

Remembering +4 | -1

In a sodium chloride crystal, each chloride ion is surrounded by:

View answer and explanation

Correct option: B

6\mathrm{N}{\mathrm{a}^ + }\mathrm{ions}

Option B (

6\mathrm{N}{\mathrm{a}^ + }\mathrm{ions}

) is correct because in the NaCl crystal structure, each chloride ion is surrounded by six sodium ions in an octahedral arrangement.

21 Medium

21 of 113

Analyzing +4 | -1

Which order is NOT correct

View answer and explanation

Correct option: C

Melting point :

LiCl > NaCl > KCl > RbCl > CsCl

Option C (Melting point :

LiCl > NaCl > KCl > RbCl > CsCl

) is NOT correct because as the size of the cation increases, the lattice energy decreases, and hence the melting point decreases.

22 Easy

22 of 113

Understanding +4 | -1

Gypsum is added to clinker during cement manufacture to:

View answer and explanation

Correct option: A

Decrease the rate of setting of cement

Option A is correct because Gypsum (

CaSO_4 \cdot 2H_2O

) is added to cement to slow down the hydration process of cement compounds, preventing flash setting.

23 Easy

23 of 113

Analyzing +4 | -1

A sudden large jump between the values of second and third ionization energies of an element would be associated with the electronic configuration:

View answer and explanation

Correct option: D

1{s^2},2{s^2}2{p^6},3{s^2}

Option D (1s2,2s22p6,3s2) is correct because removing the third electron requires significantly more energy as it comes from a stable noble gas core.

24 Hard

24 of 113

Analyzing +4 | -1

A metal

'M'

reacts with

{\mathrm{N}_2}

to give a compound

'A'\left( {{M_3}N} \right).\mathrm{ }'A'

on heating at high temperature gives back

'M'\mathrm{and '}A'

on reacting with

{\mathrm{H}_2}\mathrm{O}

gives a gas

B.\mathrm{ }'B'

turns

\mathrm{CuS}{\mathrm{O}_4}

solution blue on passing through it.

M\mathrm{and}B

can be

View answer and explanation

Correct option: B

\mathrm{Li and N}{\mathrm{H}_3}

Option B (

\mathrm{Li and N}{\mathrm{H}_3}

) is correct because Lithium reacts with nitrogen to form Lithium nitride (

\mathrm{L}{\mathrm{i}_3}\mathrm{N}

), which reacts with water to produce ammonia (

\mathrm{N}{\mathrm{H}_3}

), and ammonia turns

\mathrm{CuS}{\mathrm{O}_4}

solution blue.

25 Medium

25 of 113

Analyzing +4 | -1

Which of the following has minimum values of cation-anion size ratio?

View answer and explanation

Correct option: C

\mathrm{MgC}{\mathrm{l}_2}

Option C (

\mathrm{MgC}{\mathrm{l}_2}

) is correct because Mg has the smallest cation size and Cl has a relatively large anion size compared to the other options, resulting in the smallest cation-anion size ratio.

26 Medium

26 of 113

Remembering +4 | -1

Manufacture of

\mathrm{NaOH}

is done by:

View answer and explanation

Correct option: A

Castner- Kellner process

Option A (Castner- Kellner process) is correct because this process is specifically used for the manufacture of NaOH.

27 Medium

27 of 113

Application +4 | -1

Zinc carbonate can be obtained from a solution of zinc chloride by adding:

View answer and explanation

Correct option: A

\mathrm{NaHC}{\mathrm{O}_3}

Option A (

\mathrm{NaHC}{\mathrm{O}_3}

) is correct because sodium bicarbonate reacts with zinc chloride to form zinc carbonate precipitate, sodium chloride, and carbon dioxide.

28 Easy

28 of 113

Understanding +4 | -1

Which one of the following on hydrolysis gives the corresponding metallic hydroxide,

{H_2}{O_2}\,\,and\,\,{O_2}

View answer and explanation

Correct option: C

K{O_2}

The correct answer is C (

KO_2

) because potassium superoxide reacts with water to produce potassium hydroxide, hydrogen peroxide, and oxygen.

29 Easy

29 of 113

Remembering +4 | -1

Metallic hydride among the following is

View answer and explanation

Correct option: C

CrH

CrH (Option C) is the correct answer because transition metals form metallic hydrides due to their ability to accommodate hydrogen in their lattice structure.

30 Hard

30 of 113

Analyzing +4 | -1

Which of the following acts as reducing agent as well as oxidising agent?

View answer and explanation

Correct option: B

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

Option B (

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

) is correct because in

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

, oxygen has an oxidation state of -1, which can be both increased (oxidation) and decreased (reduction).

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 113 single-correct-answer MCQs on S-BLOCK ELEMENTS.
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