Which reagent would enable you to remove ${\rm{SO}}_4^{2 - }$ ions from solution containing both ${\rm{SO}}_4^{2 - }$ and ${\rm{C}}{{\rm{l}}^ - }$ ions?

${\rm{Ba}}{\left( {{\rm{OH}}} \right)_2}$

An alloy of ${\rm{Na}} + {\rm{K}}$ is:

Used in specially designed thermometers

Which of the following statements is correct for ${\rm{CsB}}{{\rm{r}}_3}$ ?

It contains ${\rm{C}}{{\rm{s}}^ + }$ and ${\rm{Br}}_3^ - $ ions

It contains ${\rm{C}}{{\rm{s}}^{2 + }}$ and ${\rm{B}}{{\rm{r}}^ - }$ ions

It contains ${\rm{C}}{{\rm{s}}^ + },{\rm{B}}{{\rm{r}}^ - }{\rm{and B}}{{\rm{r}}_2}$ lattice molecules

${\rm{KCl }}{\rm{. MgC}}{{\rm{l}}_2}.6{{\rm{H}}_2}{\rm{O}}$

${\rm{MgC}}{{\rm{O}}_3}{\rm{. CaC}}{{\rm{O}}_3}$

${\rm{MgS}}{{\rm{O}}_4}.7{{\rm{H}}_2}{\rm{O}}$

${\rm{KAlS}}{{\rm{i}}_3}{{\rm{O}}_8}$

${\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3} + {\rm{CaS}}$

${\rm{NaHC}}{{\rm{O}}_3} + {\rm{CoS}}$

${\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3} + {\rm{CoS}}$

${\rm{Ca}}{\left( {{\rm{OH}}} \right)_2}$

${\rm{CaS}}{{\rm{O}}_4} \cdot 2{{\rm{H}}_2}{\rm{O}}$

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NEET • CHEMISTRY • S-BLOCK ELEMENTS

S-block elements practice · Easy

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1 Easy

1 of 38

Application +4 | -1

If 5 moles of

\mathrm{BaCl}_{2}

is mixed with 2 moles of

\mathrm{Na}_{3} \mathrm{PO}_{4}

, the maximum number of moles of

\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}

formed is ________ (Nearest integer)

View answer and explanation

Correct option: A

Option A (1) is correct because the reaction stoichiometry and limiting reactant determine the maximum moles of Ba3(PO4)2 formed.

2 Easy

2 of 38

Understanding +4 | -1

When sodium chloride solution is electrolysed, the gas that is liberated at the cathode is

View answer and explanation

Correct option: C

Hydrogen

Option C is correct because during the electrolysis of aqueous sodium chloride, water is reduced at the cathode to produce hydrogen gas and hydroxide ions.

3 Easy

3 of 38

Understanding +4 | -1

Which among the following elements has the tendency to form covalent compounds.

View answer and explanation

Correct option: B

Be

The correct answer is B (

Be

) because Beryllium, due to its small size and high polarizing power, has a greater tendency to form covalent compounds compared to other alkaline earth metals.

4 Easy

4 of 38

Remembering +4 | -1

The non-metal which is not affected by

\mathrm{NaOH}

View answer and explanation

Correct option: A

\mathrm{C}

Option A (

\mathrm{C}

) is correct because carbon is generally unreactive with NaOH under normal conditions.

5 Easy

5 of 38

Application +4 | -1

Which reagent would enable you to remove

\mathrm{SO}_4^{2 - }

ions from solution containing both

\mathrm{SO}_4^{2 - }

and

\mathrm{C}{\mathrm{l}^ - }

ions?

View answer and explanation

Correct option: C

\mathrm{Ba}{\left( {\mathrm{OH}} \right)_2}

Option C is correct because

Ba(OH)_2

will precipitate

SO_4^{2-}

ions as

BaSO_4

, which is insoluble, while not reacting with

Cl^-

ions.

6 Easy

6 of 38

Remembering +4 | -1

An alloy of

\mathrm{Na} + \mathrm{K}

is:

View answer and explanation

Correct option: C

Both (1) and (2)

Option C (Zero, 1) is correct because electrolysis of

H_2SO_5

gives

H_2O_2

at the anode, and

H_2SO_5

has zero peroxy bonds while

H_2O_2

has one.

7 Easy

7 of 38

Analyzing +4 | -1

Which possesses highest lattice energy?

View answer and explanation

Correct option: B

\mathrm{LiF}

Option B (LiF) is correct because lattice energy is inversely proportional to the size of the ions and directly proportional to the charge. LiF has the smallest ions among the given options, leading to the highest lattice energy.

8 Easy

8 of 38

Remembering +4 | -1

On heating washing soda, we get:

View answer and explanation

Correct option: D

{\mathrm{H}_2}\mathrm{O}\left( v \right)

Option D (

{\mathrm{H}_2}\mathrm{O}\left( v \right)

) is correct because washing soda (Na2CO3.10H2O) loses water molecules upon heating.

9 Easy

9 of 38

Understanding +4 | -1

Gypsum is added to clinker during cement manufacture to:

View answer and explanation

Correct option: A

Decrease the rate of setting of cement

Option A is correct because Gypsum (

CaSO_4 \cdot 2H_2O

) is added to cement to slow down the hydration process of cement compounds, preventing flash setting.

10 Easy

10 of 38

Analyzing +4 | -1

A sudden large jump between the values of second and third ionization energies of an element would be associated with the electronic configuration:

View answer and explanation

Correct option: D

1{s^2},2{s^2}2{p^6},3{s^2}

Option D (1s2,2s22p6,3s2) is correct because removing the third electron requires significantly more energy as it comes from a stable noble gas core.

11 Easy

11 of 38

Understanding +4 | -1

Which one of the following on hydrolysis gives the corresponding metallic hydroxide,

{H_2}{O_2}\,\,and\,\,{O_2}

View answer and explanation

Correct option: C

K{O_2}

The correct answer is C (

KO_2

) because potassium superoxide reacts with water to produce potassium hydroxide, hydrogen peroxide, and oxygen.

12 Easy

12 of 38

Remembering +4 | -1

Metallic hydride among the following is

View answer and explanation

Correct option: C

CrH

CrH (Option C) is the correct answer because transition metals form metallic hydrides due to their ability to accommodate hydrogen in their lattice structure.

13 Easy

13 of 38

Remembering +4 | -1

The element with strong electropositive nature is:

View answer and explanation

Correct option: B

\mathrm{Cs}

Option D (

{H_2}{O_2}\,oxidises\mathrm{ }PbS\mathrm{ }into\mathrm{ }S{O_2}

) is correct because

{H_2}{O_2}

oxidizes

PbS

into

PbSO_4

, not

SO_2

14 Easy

14 of 38

Analyzing +4 | -1

A white solid reacts with dil.

\mathrm{HCl}

to give colourless gas that decolourises aqueous bromine. The solid is most likely to be:

View answer and explanation

Correct option: D

Sodium thiosulphate

Option D (Sodium thiosulphate) is correct because it reacts with dilute HCl to produce sulfur dioxide, which decolorizes aqueous bromine.

15 Easy

15 of 38

Analyzing +4 | -1

Be Shows diagonal relationship with

Al

. Which of the following similarity incorrect?

View answer and explanation

Correct option: B

Be

Al

rendered passive by Con.

HN{O_3}

Option C (Be(OH)2 like Al(OH)3 is basic) is incorrect because both Be(OH)2 and Al(OH)3 are amphoteric, not basic.

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16 Easy

16 of 38

Understanding +4 | -1

The correct order of density of following elements is :- (Be, Mg, Ca, Sr)

View answer and explanation

Correct option: C

Ca < Mg < Be < Sr

The correct answer is C (Ca < Mg < Be < Sr) because density generally increases down the group, but Calcium is an exception due to its larger atomic size and weaker metallic bonding compared to Magnesium.

17 Easy

17 of 38

Understanding +4 | -1

Which is most basic in character?

View answer and explanation

Correct option: A

\mathrm{CsOH}

Option A (

\mathrm{CsOH}

) is correct because Cesium hydroxide is the most basic among the given options due to Cesium's lowest ionization energy and largest size, leading to the weakest bond with hydroxide.

18 Easy

18 of 38

Understanding +4 | -1

Which of the following statements is correct for

\mathrm{CsB}{\mathrm{r}_3}

View answer and explanation

Correct option: D

It contains

\mathrm{C}{\mathrm{s}^ + }

and

\mathrm{Br}_3^ -

ions

Option D is correct because

\mathrm{CsBr}_3

is an ionic compound containing

\mathrm{Cs}^+

cations and tribromide

\mathrm{Br}_3^-

anions.

19 Easy

19 of 38

Analyzing +4 | -1

A metal

M

forms water soluble

M\mathrm{S}{\mathrm{O}_4}

and inert

MO.MO

in aqueous solution forms insoluble

M{\left( {\mathrm{OH}} \right)_2}

soluble in NaOH. Metal

M

View answer and explanation

Correct option: A

Option A (Be) is correct because Beryllium forms a water-soluble sulfate, an inert oxide, and an amphoteric hydroxide.

20 Easy

20 of 38

Remembering +4 | -1

Carnallite is

View answer and explanation

Correct option: D

\mathrm{KCl }\mathrm{. MgC}{\mathrm{l}_2}.6{\mathrm{H}_2}\mathrm{O}

Carnallite (Option D) is a hydrated double chloride of potassium and magnesium, with the formula

KCl \cdot MgCl_2 \cdot 6H_2O

21 Easy

21 of 38

Analyzing +4 | -1

Which substance gives a different flame colouration from the others?

View answer and explanation

Correct option: D

Table salt

Option D (Table salt) is correct because table salt (NaCl) contains sodium, which imparts a yellow color to the flame, while the others contain potassium which imparts a violet/lilac color.

22 Easy

22 of 38

Analyzing +4 | -1

\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_3}

and

\mathrm{NaHC}{\mathrm{O}_3}

may be distinguished by treating their aqueous solution with:

View answer and explanation

Correct option: D

\mathrm{MgS}{\mathrm{O}_4}

Option D (

\mathrm{MgS}{\mathrm{O}_4}

) is correct because

Na_2SO_3

reacts with

MgSO_4

to form a precipitate of

MgS{O_3}

, while

NaHCO_3

does not form a precipitate.

23 Easy

23 of 38

Remembering +4 | -1

Magnesia is:

View answer and explanation

Correct option: A

\mathrm{MgO}

Magnesia (Option A) is the common name for magnesium oxide, MgO.

24 Easy

24 of 38

Understanding +4 | -1

The outermost electron is most loosely held in:

View answer and explanation

Correct option: D

\mathrm{Cs}

Option D (Cs) is correct because Cesium has the lowest ionization energy among the alkali metals, meaning its outermost electron is most loosely held.

25 Easy

25 of 38

Remembering +4 | -1

Black ash is:

View answer and explanation

Correct option: C

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{CaS}

Option C (

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{CaS}

) is the correct composition of black ash, a byproduct in the Leblanc process.

26 Easy

26 of 38

Analyzing +4 | -1

Chemical

A

is used for water softening to remove temporary hardness.

A

reacts with sodium carbonate to generate caustic soda. When

\mathrm{C}{\mathrm{O}_2}

is bubbled through

A

, it turns cloudy. What is

A

View answer and explanation

Correct option: C

\mathrm{Ca}{\left( {\mathrm{OH}} \right)_2}

Option C (Ca(OH)2) is correct because it is used for water softening, reacts with sodium carbonate to produce caustic soda, and forms a cloudy solution with CO2.

27 Easy

27 of 38

Analyzing +4 | -1

Which can undergo both oxidation and reduction?

View answer and explanation

Correct option: C

\mathrm{B}{\mathrm{a}^ + }

Option C (Ba+) is correct because it can be oxidized to Ba2+ or reduced to Ba0, thus undergoing both oxidation and reduction.

28 Easy

28 of 38

Application +4 | -1

A colourless salt gives violet colour to Bunsen flame and also turns moisture litmus paper blue. It is:

View answer and explanation

Correct option: C

{\mathrm{K}_2}\mathrm{C}{\mathrm{O}_3}

Option C (

{\mathrm{K}_2}\mathrm{C}{\mathrm{O}_3}

) is correct because potassium salts impart a violet color to the flame, and carbonates turn litmus paper blue due to hydrolysis.

29 Easy

29 of 38

Remembering +4 | -1

Milk of lime is:

View answer and explanation

Correct option: C

\mathrm{Ca}{\left( {\mathrm{OH}} \right)_2}

Milk of lime (Option C) is a suspension of calcium hydroxide,

Ca(OH)_2

, in water.

30 Easy

30 of 38

Analyzing +4 | -1

The decreasing order of second ionization energy of K, Ca and Ba is:

View answer and explanation

Correct option: C

\mathrm{K} > Ca > Ba

Option C (K > Ca > Ba) is correct because after the first ionization, K+ has a noble gas configuration, requiring much more energy to remove the second electron.

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 38 single-correct-answer MCQs on S-BLOCK ELEMENTS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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