Skip to main content
Back to PRACTICAL CHEMISTRY

Your Progress

0 / 95 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 1-30 of 95 questions
1 Hard
1 of 95
Analyzing +4 | -1
A pale green crystalline inorganic salt (A) dissolves freely in water. It gives a brown precipitate on addition of aqueous NaOH.\mathrm{NaOH}. The solution of (A) also gives a black precipitate on bubbling H2S\mathrm{H}_2 \mathrm{S} in alkaline medium. An aqueous solution of the (A) decolorizes the pink colour of the permanganate solution. The metal in the salt solution is
View answer and explanation
Correct option: D
Iron
Option D (Iron) is correct because ferrous salts are pale green, form brown precipitates with NaOH, black precipitates with H2S, and decolorize permanganate solutions.
2 Hard
2 of 95
Application +4 | -1
100 ml100 \mathrm{~ml} of NaHC2O4\mathrm{NaHC}_2 \mathrm{O}_4 required 50 ml50 \mathrm{~ml} of 0.1 M KMnO40.1 \mathrm{~M} \, \mathrm{KMnO}_4 solution in acidic medium. Volume of 0.1 M NaOH0.1 \mathrm{~M} \mathrm{~NaOH} required by 100 ml100 \mathrm{~ml} of NaHC2O4\mathrm{NaHC}_2 \mathrm{O}_4 is
View answer and explanation
Correct option: C
125 ml125 \mathrm{~ml}
Option D (150 ml) is correct because the reaction with KMnO4 involves 5 electrons, while the reaction with NaOH involves 1 equivalent of NaOH per mole of NaHC2O4.
3 Medium
3 of 95
Analyzing +4 | -1
The ion that cannot be precipitated by both HCl{HCl} and H2S{H}_2 {S} is
View answer and explanation
Correct option: C
Ag+{Ag}^{+}
Option B (Cu+{Cu}^{+}) is correct because Ag+{Ag}^{+} can be precipitated by both HCl{HCl} and H2S{H}_2 {S}, Pb2+{Pb}^{2+} can be precipitated by HCl{HCl} and H2S{H}_2 {S}, Sn2+{Sn}^{2+} can be precipitated by H2S{H}_2 {S} but not always by HCl{HCl}, while Cu+{Cu}^{+} is not readily precipitated by either.
4 Hard
4 of 95
Understanding +4 | -1
The rapid change of pH near the stoichiometric point of an acid-base titration in the basis of indicator detection. pH of the solution is related to ratio of the concentrations of the conjugated acid (HIn)(HIn) and the base (In)(In) forms of the indicator by the expression.
View answer and explanation
Correct option: A
log⁡[In−][HIn]=pH−pHIn\log \frac{\left[{In}^{-}\right]}{[H I n]}=p H-p H_{I n}
Option A (log⁡[In−][HIn]=pH−pHIn\log \frac{\left[{In}^{-}\right]}{[H I n]}=p H-p H_{I n}) is correct because it represents the Henderson-Hasselbalch equation applied to acid-base indicators, relating pH to the ratio of the conjugate base and acid forms of the indicator.
5 Medium
5 of 95
Analyzing +4 | -1
On heating colourless solid A,A, gas BB (liquid at room temp.) and gas CC are formed. AA is decomposed by NaOH\mathrm{NaOH} on heating to form gas DD giving white fumes with HCl.\mathrm{HCl}. Gas C{C} occupies 800 ml/g800 \mathrm{~ml} / \mathrm{g} at N.T.P. Hence AA is
View answer and explanation
Correct option: D
NH4NO2\mathrm{NH}_4 \mathrm{NO}_2
Option D (NH4NO2\mathrm{NH}_4 \mathrm{NO}_2) is correct because ammonium nitrite decomposes upon heating to give nitrogen gas and water, and reacts with NaOH to produce ammonia gas.
6 Medium
6 of 95
Application +4 | -1
Standard HClHCl solution is titrated to a pink phenolphthalein endpoint by adding a NaOH\mathrm{NaOH} solution while stirring. If a solution becomes pink throughout but loses its color upon standing for a short time, what should be done to restore the color?
View answer and explanation
Correct option: B
Add an additional drop of NaOH\mathrm{NaOH} solution
The correct answer is B because the pink color fading indicates the solution is becoming less basic, so adding NaOH will restore the basic conditions needed for phenolphthalein to be pink.
7 Hard
7 of 95
Application +4 | -1
How many moles of KMnO4\mathrm{KMnO}_4 are needed to oxidised a mixture of 1 mole of each FeSO4\mathrm{FeSO}_4 & FeC2O4\mathrm{FeC}_2 \mathrm{O}_4 in acidic medium
View answer and explanation
Correct option: A
45\frac{4}{5}
Option A (45\frac{4}{5}) is correct because KMnO4 oxidizes FeSO4 to Fe3+ (1 electron) and FeC2O4 to Fe3+ and CO2 (3 electrons), requiring a total of 4 electrons from KMnO4.
8 Medium
8 of 95
Understanding +4 | -1
In V group, (NH4)2CO3\left(\mathrm{NH}_4\right)_2 \mathrm{CO}_3 is added to precipitate out the carbonates. We do not add Na2CO3\mathrm{Na}_2 \mathrm{CO}_3 because
View answer and explanation
Correct option: C
MgCO3\mathrm{MgCO}_3 will be precipitated out in V\mathrm{V} group
Option C (MgCO3\mathrm{MgCO}_3 will be precipitated out in V\mathrm{V} group) is correct because Na2CO3\mathrm{Na}_2\mathrm{CO}_3 would increase the concentration of carbonate ions, leading to the precipitation of MgCO3\mathrm{MgCO}_3 along with the group V carbonates, interfering with the analysis.
9 Medium
9 of 95
Remembering +4 | -1
As2S3\mathrm{As}_2 \mathrm{S}_3 dissolves in a solution of yellow ammonium sulphide to give:
View answer and explanation
Correct option: A
(NH4)3AsS4\left(\mathrm{NH}_4\right)_3 \mathrm{AsS}_4
Option A ((NH4)3AsS4\left(\mathrm{NH}_4\right)_3 \mathrm{AsS}_4) is correct because As2S3\mathrm{As}_2\mathrm{S}_3 reacts with yellow ammonium sulfide to form ammonium thioarsenate.
10 Medium
10 of 95
Understanding +4 | -1
Which is the safest method for performing a
flame test?
View answer and explanation
Correct option: C
Soak a wooden splint in an aqueous solution
of the metal salt, then burn the splint in the
flame from a Bunsen burner
Option C (Soak a wooden splint in an aqueous solution of the metal salt, then burn the splint in the flame from a Bunsen burner) is the safest method because it avoids the use of flammable solvents like methanol and provides a controlled way to introduce the metal salt into the flame.
11 Easy
11 of 95
Remembering +4 | -1
Lassaigne’s test is used in qualitative analysis to detect
View answer and explanation
Correct option: D
All
The correct answer is D (All) because Lassaigne's test is used to detect nitrogen, sulfur, and halogens in organic compounds.
12 Medium
12 of 95
Remembering +4 | -1
When bismuth chloride is poured into a large volume of water the white precipitate produced is
View answer and explanation
Correct option: C
BiOCl\mathrm{BiOCl}
Option C (BiOCl\mathrm{BiOCl}) is correct because bismuth chloride reacts with water to form bismuth oxychloride as a white precipitate.
13 Medium
13 of 95
Analyzing +4 | -1
In which of the following solvents, AgBr\mathrm{AgBr} will have the highest solubility
View answer and explanation
Correct option: B
10−3 M NH4OH10^{-3} \mathrm{~M} \mathrm{~NH}_4 \mathrm{OH}
Option B (10−3 M NH4OH10^{-3} \mathrm{~M} \mathrm{~NH}_4 \mathrm{OH}) is correct because AgBr\mathrm{AgBr} forms a complex with ammonia, increasing its solubility.
14 Medium
14 of 95
Analyzing +4 | -1
Which one among the following pairs of ions cannot be separated by H2S{H}_2 {S} in dilute HCl?{HCl}?
View answer and explanation
Correct option: A
Bi3+,Sn4+\mathrm{Bi}^{3+}, \mathrm{Sn}^{4+}
Option A (Bi3+,Sn4+\mathrm{Bi}^{3+}, \mathrm{Sn}^{4+}) is correct because both Bi3+\mathrm{Bi}^{3+} and Sn4+\mathrm{Sn}^{4+} form sulfide precipitates in dilute HCl{HCl}, so they cannot be separated using H2S{H}_2{S} in dilute HCl{HCl}.
15 Hard
15 of 95
Analyzing +4 | -1
A NaOH\mathrm{NaOH} solution is to be standardized by titrating it against a known mass of potassium hydrogen phthalate. Which procedure will give a molarity of NaOH\mathrm{NaOH} that is too low?
View answer and explanation
Correct option: C
Neglecting to fill the tip of the buret with
NaOH\text{NaOH} solution before titrating
Option C (Neglecting to fill the tip of the buret with NaOH\text{NaOH} solution before titrating) is correct because it results in a smaller volume of NaOH being used than recorded.

Explore Other Chapters in CHEMISTRY

View All →
CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs THERMODYNAMICS 583 MCQs STRUCTURE OF ATOM 499 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs Equilibrium 412 MCQs STATES OF MATTER 410 MCQs
16 Hard
16 of 95
Understanding +4 | -1
A purple coloured solution is added from a burette to FeSO4\mathrm{FeSO}_4 solution kept in the flask. After sometime, the purple colour changes to light pink. The ion formed from that solution is
View answer and explanation
Correct option: D
Mn2+\mathrm{Mn}^{2+}
Option D (Mn2+\mathrm{Mn}^{2+}) is correct because the purple permanganate ion (MnO4−\mathrm{MnO}_4^−) is reduced to the nearly colorless manganese(II) ion (Mn2+\mathrm{Mn}^{2+}) when it reacts with FeSO4\mathrm{FeSO}_4.
17 Medium
17 of 95
Understanding +4 | -1
In the precipitation of the iron group (III) in qualitative analysis, ammonium chloride is added before adding ammonium hydroxide to:
View answer and explanation
Correct option: B
Decrease concentration of −OH{ }^{-} \mathrm{OH} ions
Option B (Decrease concentration of −OH{ }^{-} \mathrm{OH} ions) is correct because ammonium chloride decreases the hydroxide ion concentration through the common ion effect, preventing the precipitation of group III hydroxides before group IV sulfides.
18 Medium
18 of 95
Remembering +4 | -1
A solution of a salt of which metal produces
bright red colour in a flame test?
View answer and explanation
Correct option: A
Lithium
The correct answer is A (Lithium) because lithium salts produce a bright red color in a flame test.
19 Medium
19 of 95
Understanding +4 | -1
A gas is obtained by addition of dil. H2SO4\mathrm{H}_2 \mathrm{SO}_4 to a mixture which turns lead acetate paper black. It is
View answer and explanation
Correct option: A
H2S\mathrm{H}_2 \mathrm{S}
Option A (H2S\mathrm{H}_2 \mathrm{S}) is correct because hydrogen sulfide gas reacts with lead acetate to form lead sulfide, which is a black precipitate.
20 Medium
20 of 95
Understanding +4 | -1
The acidic solution of a salt produced a deep blue colour with starch iodine solution. The salt may be
View answer and explanation
Correct option: B
Nitrite
Option B (Nitrite) is correct because nitrites can oxidize iodide ions in the presence of acid to form iodine, which gives a blue color with starch.
21 Medium
21 of 95
Remembering +4 | -1
Mark the correct statement:
View answer and explanation
Correct option: D
All the above statement are correct
Option D (All the above statement are correct) is correct because all the statements accurately describe the precipitation of basic radicals in different groups.
22 Medium
22 of 95
Remembering +4 | -1
Which of the following give white precipitate when HCl\mathrm{HCl} is added to its aqueous solution
View answer and explanation
Correct option: A
Hg+\mathrm{Hg}^{+}
The correct answer is A (Hg+\mathrm{Hg}^{+}) because mercurous ions (Hg+\mathrm{Hg}^{+}) react with HCl\mathrm{HCl} to form insoluble mercurous chloride (Hg2Cl2\mathrm{Hg_2Cl_2}), which precipitates as a white solid.
23 Medium
23 of 95
Remembering +4 | -1
Soda-lime test is used to detect _______ element of organic compound.
View answer and explanation
Correct option: C
N
The correct answer is C (N) because the soda-lime test is used to detect the presence of nitrogen in an organic compound.
24 Medium
24 of 95
Remembering +4 | -1
Nitrogen in the organic compound can be
determined by
View answer and explanation
Correct option: B
Kjeldhal method
The correct answer is B (Kjeldhal method) because the Kjeldahl method is specifically designed for the quantitative determination of nitrogen in organic compounds.
25 Medium
25 of 95
Remembering +4 | -1
Which of the following does not give NH3{NH}_3 on heating with NaOHNaOH solution?
View answer and explanation
Correct option: B
Aniline
The correct answer is B (Aniline) because aniline does not have an amide or imide group that can be hydrolyzed by NaOH to release ammonia.
26 Medium
26 of 95
Remembering +4 | -1
A reagent which gives brilliant red precipitate with Nickel ions in basic medium is
View answer and explanation
Correct option: A
Dimethyl glyoxime
Option A (Dimethyl glyoxime) is correct because it forms a bright red precipitate with Nickel(II) ions in a basic medium.
27 Medium
27 of 95
Understanding +4 | -1
Given below are two statements:

Statement (I): Kjeldahl method is applicable to
estimate nitrogen in pyridine.

Statement (II): The nitrogen present in pyridine
can easily be converted into ammonium sulphate in
Kjeldahl method.

In the light of the above statements, choose the
correct answer from the options given below.
View answer and explanation
Correct option: A
Both Statement I and Statement II is false
The correct answer is A (Both Statement I and Statement II is false) because Kjeldahl method is not applicable to estimate nitrogen in pyridine, and the nitrogen present in pyridine cannot be easily converted into ammonium sulphate in Kjeldahl method.
28 Hard
28 of 95
Application +4 | -1
0.2475 g0.2475\,g of an organic compound gave 0.495 g0.495\,g of CO2C{O_2} and 0.2025 g0.2025\,g of H2O{H_2}O on combustion. The percentage of carbon is
View answer and explanation
Correct option: A
54.54%54.54\%
Option A (54.54%54.54\%) is correct because the percentage of carbon is calculated using the mass of CO2 formed and the mass of the organic compound.
29 Easy
29 of 95
Analyzing +4 | -1
[x]+H2SO4→[y][x]+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow[y] a colourless gas with irritating smell, [y]+K2Cr2O7+H2SO4→[{y}]+\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow green solution. [x][{x}] and [y][y] are
View answer and explanation
Correct option: A
SO32−,SO2\mathrm{SO}_3^{2-}, \mathrm{SO}_2
Option A (SO32−,SO2\mathrm{SO}_3^{2-}, \mathrm{SO}_2) is correct because sulfite ions react with sulfuric acid to produce sulfur dioxide, which has an irritating smell and can reduce dichromate ions to a green solution of chromium(III) ions.
30 Hard
30 of 95
Remembering +4 | -1
The principal reason that solid sodium hydroxide is not used as a primary standard for acid-base titrations is that it
View answer and explanation
Correct option: A
Absorbs water from air
The correct answer is A (Absorbs water from air) because solid sodium hydroxide is hygroscopic and readily absorbs moisture and carbon dioxide from the air, making it difficult to obtain a precise weight.
Revision notes and key takeaways

Review PRACTICAL CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 95 single-correct-answer MCQs on PRACTICAL CHEMISTRY.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
Showing 1-30 of 95 questions

Continue Your Practice

📚 More Sets in This Chapter

Try different difficulty levels to master this topic

→ NEET CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Easy) 18 MCQs → NEET CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Hard) 25 MCQs → NEET CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Medium) 52 MCQs
🎯 Next Chapters to Practice

Continue building your subject mastery

→ CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs → THERMODYNAMICS 583 MCQs → STRUCTURE OF ATOM 499 MCQs → CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs
📚 Switch Set (ALL)
Chapter Sets
ALL 95 MCQs EASY 18 MCQs HARD 25 MCQs MEDIUM 52 MCQs
0 /95
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →