Hydrocarbons practice · Mixed difficulty

Which of the following would not give 2phenylbutane as the major product in a FriedelCrafts alkylation reaction?

A hydrocarbon containing 2 carbon atoms give Sabatier and Senderen’s reaction but does not give precipitate with ammoniacal silver nitrate solution. The hydrocarbon in question is:

Which alkane (molecular mass = 72) would yield only three mono chlorinated derivates

S-I: Alkenes with Bayer's reagent give vicinal diols
S-II: Bayer's test is useful to detect the presence of unsaturation

The angle strain in cyclobutane is

Hex-4-ene-2-ol on treatment with PCC gives 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is

Alkanes mainly show reactions involving:

Given below are two statements.
Statement-I 2-methylbutane on oxidation with $KMn{O_4}$ gives 2-methylbutan -2-ol.
Statement-II $n$-alkanes can be easily oxidised to corresponding alcohols with $KMn{O_4}$.
Choose the correct option.

2-methylpropene is isomeric with butane-1. They can be distinguished by:

2-Hexyne gives trans-2-hexene on treatment with:

When $HBr$ adds to 1 – butyne in presence of peroxide

Kolbe’s synthesis of sodium salt of butanoic acid gives:

Ethylene is used in making:

Which of the following compound is not prepared by Kolbe’s electrolytic method

${R_2}Cu\,\,Li$ is the intermediate formed in the Corey-House synthesis. It is called

A hydrocarbon has the formula ${\mathrm{C}_3}{\mathrm{H}_4}$. To find out whether it contains two double bonds or triple bonds, the following test is performed:

A mixture of $\mathrm{C}{\mathrm{S}_2}$ and ${\mathrm{H}_2}\mathrm{S}$ on passing over heated $Cu$ gives:

Intermediate of Wurtz reaction is $C{H_3}C{H_2}Br\xrightarrow{{Na/ether}}$

Consider the following reaction,

$\mathrm{CH}_4+\mathrm{O}_2 \xrightarrow[\Delta]{\stackrel{ }{ } X^{\prime}} \mathrm{HCHO}+\mathrm{H}_2 \mathrm{O}$; Here, ' $X$ ' is

In the following sequence of reactions, the alkene affords the compound 'B' The compound B is
$C{H_3}CH = CHC{H_3}AB$

S-I: Both Benzene $\&$ ethyne give same product on ozonolysis.
S-II: Ethyne $\&$ benzene possess same emperical formula.

Which of the following can be used for preparation of propane?

Butyne on oxidation with hot. alk $KMn{O_4}$ gives

An Alkene, on ozonalysis gives formaldehyde, and acetaldehyde. The alkene is

1-butyne on oxidation with hot alkaline ${KMnO}_4$ would yield. Which of the following as end product?

Treatment of 2 – methyl but–2–ene with $HBr$ in the presence of a peroxide yields

$C{H_3}C \equiv CC{H_2}C{H_3}\xrightarrow[{ii)\,{H_2}O}]{{i)\,{O_3}}}$ products are

S-I: Bromo benzene when treated with $\mathrm{Br}_2 / \mathrm{Fe}$ gives 1,4-dibromobenzene as major product
S-II: In bromobenzene, the inductive effect of the bromo group is more dominant than the mesomeric effect in directing the incoming electrophile.

The olefin which on ozonolysis gives $\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CHO}\;and\;\mathrm{C}{\mathrm{H}_3}\mathrm{CHO}$ is:

Which compound will react with an aqueous solution of $\mathrm{Ag}\left( {\mathrm{N}{\mathrm{H}_3}} \right)_2^ + \mathrm{O}{\mathrm{H}^ - }$?