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NEET • CHEMISTRY • HALOALKANES AND HALO ARENES

Haloalkanes and halo arenes practice · Mixed difficulty

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91 Medium
91 of 110
Analyzing +4 | -1


Bottles containing C6H5I{C}_6 {H}_5 {I} and C6H5CH2I{C}_6 {H}_5 {CH}_2 {I} lost their original labels. They were labelled AA and BB for testing. AA and BB were separately taken in test tubes and boiled with NaOH{NaOH} solution. The end solution in each tube was made acidic with dilute HNO3{HNO}_3 and then some AgNO3{AgNO}_3 solution was added. Substance B{B} gave a yellow precipitate. Which one of the following statements is true for this experiment ?
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Correct option: D
AA was C6H5I{C}_6 {H}_5 {I}
Option D (AA was C6H5I{C}_6 {H}_5 {I}) is correct because phenyl iodide will react with NaOH to produce iodide ions, which will then precipitate with silver nitrate as yellow AgI.
92 Medium
92 of 110
Understanding +4 | -1
Which of the following does not react with benzene in presence of anhydrous AlCl3\mathrm{AlC}{\mathrm{l}_3}?
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Correct option: A
C6H5Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{Cl}
Option A (C6H5Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{Cl}) does not react with benzene in the presence of anhydrous AlCl3AlCl_3 because the resulting phenyl cation is highly unstable and does not readily form.
93 Medium
93 of 110
Application +4 | -1
Ethyl chloride on heating with AgCN forms a compound X. The functional isomer of X is
View answer and explanation
Correct option: C
C2H5CN{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{CN}
Option C (C2H5CN{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{CN}) is correct because ethyl chloride reacts with AgCN to form ethyl isocyanide (C2H5NCC_2H_5NC), and the functional isomer of ethyl isocyanide is ethyl cyanide (C2H5CNC_2H_5CN).
94 Easy
94 of 110
Understanding +4 | -1
SN1  {\mathrm{S}_\mathrm{N}}1\mathrm{\;} reaction on optically active substrates mainly gives :
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Correct option: C
Racemic product
Option C (Racemic product) is correct because S\N1 reactions proceed through a carbocation intermediate, which is planar and can be attacked from either side, leading to racemization.
95 Easy
95 of 110
Remembering +4 | -1
The substance employed as tear gas is:
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Correct option: B
Chloropicrin
Option B (Chloropicrin) is correct because chloropicrin (CCl3NO2CCl_3NO_2) is a known lachrymatory agent used as tear gas.
96 Hard
96 of 110
Application +4 | -1
The major product formed in the following reaction is
CH3−CH3∣C∣H−CH2I→CH3OHC{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ H \end{array} - C{H_2}I\xrightarrow{{C{H_3}OH}}
View answer and explanation
Correct option: D
CH3−CH3∣C∣OCH3−CH3C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {OC{H_3}} \end{array} - C{H_3}
Option D is correct because the reaction proceeds via SN1 mechanism due to the formation of a stable tertiary carbocation, leading to the substitution of iodine with methoxy group.
97 Hard
97 of 110
Understanding +4 | -1
Given below are two statements:

Statement I : Ethane at 333 to 343 K343 \mathrm{~K} and 6-7 atm pressure in the presence of AlEt3\mathrm{AlEt}_3 and TiCl4\mathrm{TiCl}_4 undergoes addition polymerization to give LDP.

Statement II : Caprolactam at 533-543K in H2O\mathrm{H}_2 \mathrm{O} through step growth polymerizes to give Nylon 6.

In the light of the above statements, choose the correct answer from the options given below:
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Correct option: A
Statement I is false but Statement II is true
Option A (Statement I is false but Statement II is true) is correct because ethane does not undergo addition polymerization to give LDP, and caprolactam does polymerize to Nylon 6.
98 Hard
98 of 110
Application +4 | -1
In the following sequence of reactions

C2H5Br→AgCNX  →ReductionY;Y{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Br}\xrightarrow{{\mathrm{AgCN}}}X\;\xrightarrow{{\mathrm{Reduction}}}Y;Y is
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Correct option: D
ethylmethyl amine
Option D (ethylmethyl amine) is correct because the reaction of ethyl bromide with AgCN forms ethyl cyanide, which upon reduction gives ethylmethyl amine.
99 Easy
99 of 110
Application +4 | -1
The number of stereoisomers of compound

CH3−CH=CH−CHBr−CH3\mathrm{C}{\mathrm{H}_3}-\mathrm{CH} = \mathrm{CH}-\mathrm{CHBr}-\mathrm{C}{\mathrm{H}_3} would be:
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Correct option: D
4
Option D (4) is correct because the compound has one chiral center and exhibits cis/trans isomerism due to the double bond, resulting in 2 x 2 = 4 stereoisomers.
100 Medium
100 of 110
Remembering +4 | -1
Chloroform on reaction with conc. HNO3\mathrm{HN}{\mathrm{O}_3} gives an insecticide and war gas known as:
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Correct option: A
Chloropicrin
Option A (Chloropicrin) is correct because chloroform reacts with concentrated nitric acid to produce chloropicrin, which is both an insecticide and a war gas.
101 Medium
101 of 110
Application +4 | -1
Which of the following will not form a yellow precipitate on heating with an alkaline solution of iodine?
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Correct option: C
CH3OH\mathrm{C}{\mathrm{H}_3}\mathrm{OH}
Option C (CH3OH\mathrm{C}{\mathrm{H}_3}\mathrm{OH}) is correct because it does not contain either the CH3CO−CH_3CO- or CH3CH(OH)−CH_3CH(OH)- group required for a positive iodoform test.
102 Hard
102 of 110
Analyzing +4 | -1
Identify Z{Z} in

CH3CH2CH2Br→Aq. NaOHX→Al2O3Y→Cl2/H2oZ\begin{aligned} C{H_3}C{H_2}C{H_2}Br\xrightarrow{{{\text{Aq}}{\text{. NaOH}}}}X\xrightarrow{{{\text{A}}{{\text{l}}_2}{{\text{O}}_3}}}Y\xrightarrow{{{\text{C}}{{\text{l}}_2}/{H_2}o}}Z \end{aligned}
View answer and explanation
Correct option: B
CH3CHOHCH2Cl{CH}_3 {CHOHCH}_2 {Cl}
Option B (CH3CHOHCH2Cl{CH}_3 {CHOHCH}_2 {Cl}) is correct because the reaction sequence involves hydrolysis of the bromide, dehydration to propene, and then addition of hypochlorous acid (HOCl) following Markovnikov's rule.
103 Medium
103 of 110
Understanding +4 | -1
In a SN2S{N^2} Substitution reaction, which of the following has the highest relative rate
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Correct option: D
CH3CH2BrC{H_3}C{H_2}Br
Option D (CH3CH2BrC{H_3}C{H_2}Br) is correct because S\N2 reactions are favored by less steric hindrance, and ethyl bromide is the least sterically hindered among the given options.
104 Hard
104 of 110
Understanding +4 | -1
Positive Beilstein test for halogen shows that:
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Correct option: B
a halogen may be present
Option B (a halogen may be present) is correct because the Beilstein test indicates the presence of a halogen but is not definitive due to possible interferences.
105 Hard
105 of 110
Application +4 | -1
Maximum number of molecules of CH3I\mathrm{C}{\mathrm{H}_3}\mathrm{I} that can react with a molecule of CH3NH2  \mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}\mathrm{\;} are
View answer and explanation
Correct option: A
3
Option A (3) is correct because methylamine (CH3NH2\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}) has two replaceable hydrogen atoms on the nitrogen and can react with three molecules of methyl iodide (CH3I\mathrm{C}{\mathrm{H}_3}\mathrm{I}) to form a quaternary ammonium salt.
106 Easy
106 of 110
Analyzing +4 | -1
Chlorine is most reactive towards NaOH in:
View answer and explanation
Correct option: D
C6H5CH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{Cl}
Option D is correct because benzyl halides are more reactive towards NaOH due to the stability of the benzylic carbocation formed during the reaction.
107 Easy
107 of 110
Application +4 | -1
A mixture of 1-chloropropane and 2-chloropropane when treated with alcoholic KOH, it gives:
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Correct option: A
1-propene
Option A (1-propene) is correct because alcoholic KOH promotes dehydrohalogenation, leading to the formation of the most stable alkene, which is 1-propene in this case.
108 Medium
108 of 110
Understanding +4 | -1
Aryl halides are less reactive towards electrophiles than alkyl halides due to:
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Correct option: A
Resonance
Option A (Resonance) is correct because aryl halides exhibit resonance, which stabilizes the molecule and makes the carbon-halogen bond stronger, thus less reactive towards electrophiles.
109 Medium
109 of 110
Understanding +4 | -1
CH3CH2CH2Br+NaCN→CH3CH2CH2CN+NaBrC{H_3}C{H_2}C{H_2}Br + NaCN \to C{H_3}C{H_2}C{H_2}CN + NaBr
The above reaction will occur at fastest rate in
View answer and explanation
Correct option: D
DMF
Option D (DMF) is correct because DMF is a polar aprotic solvent, which favors SN2 reactions by solvating the cation but not the anion, thus increasing the nucleophilicity of CN-.
110 Medium
110 of 110
Remembering +4 | -1
Polymerization of alkenes takes place through
View answer and explanation
Correct option: D
S N2S\,{N^2} mechanism
Option A (free radical mechanism) is correct because the polymerization of alkenes typically proceeds through a free radical mechanism, especially when initiated by peroxides or high temperatures.
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