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NEET • CHEMISTRY • HALOALKANES AND HALO ARENES

Haloalkanes and halo arenes practice · Mixed difficulty

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31 Hard
31 of 110
Remembering +4 | -1
Which of the following is not inflammable?
View answer and explanation
Correct option: D
Carbon tetrachloride
Option D (Carbon tetrachloride) is correct because carbon tetrachloride (CCl4CCl_4) is non-flammable due to the complete halogenation, which makes it unable to support combustion.
32 Easy
32 of 110
Remembering +4 | -1
For the carbylamine reaction we need hot alcoholic KOH and:
View answer and explanation
Correct option: D
Any monoalkyl amine and trichloro methane
Option D is correct because the carbylamine reaction requires a primary amine, chloroform (trichloromethane), and hot alcoholic KOH.
33 Hard
33 of 110
Application +4 | -1
In the reaction:

CH3−CH   CH3∣−CH2−O−CH2−CH3+HI→product isC{H_3} - \mathop {CH}\limits^{\mathop {\,\,\,C{H_3}}\limits_| } - C{H_2} - O - C{H_2} - C{H_3} + HI \to {\text{product}}\,{\text{is}}
View answer and explanation
Correct option: C
CH3−CH  CH3∣−CH2−OH+CH3−CH2−IC{H_3} - \mathop {CH}\limits_{\mathop {\,\,C{H_3}}\limits^| } - C{H_2} - OH + C{H_3} - C{H_2} - I
Option D is correct because HI cleaves ethers via SN1 or SN2 mechanism, depending on the structure of the ether, leading to an alcohol and an alkyl iodide.
34 Hard
34 of 110
Application +4 | -1
A reaction of benzo nitrile with one equivalent CH3MgBrC{H_3}MgBr followed by hydrolysis produces a yellow liquid P.P.
The compound PP will give positive
View answer and explanation
Correct option: A
iodoform test
Option A (iodoform test) is correct because the product P is acetophenone, which contains the CH3CO−CH_3CO- group and gives a positive iodoform test.
35 Medium
35 of 110
Remembering +4 | -1
General formula for arenes is:
View answer and explanation
Correct option: D
CnH2n−6y{\mathrm{C}_n}{\mathrm{H}_{2n - 6y}}
Option D (CnH2n−6y{\mathrm{C}_n}{\mathrm{H}_{2n - 6y}}) is correct because arenes contain benzene rings, and the general formula accounts for the unsaturation caused by the rings, where 'y' represents the number of benzene rings.
36 Medium
36 of 110
Analyzing +4 | -1
Assertion : 4-Nitrochlorobenzene undergoes nucleophilic substitution more readily than chlorobenzene.

Reason : Chlorobenzene undergoes nucleophilic substitution by elimination-addition mechanism while 4-nitrochlorobenzene undergoes nucleophilic substitution by addition-elimination mechanism.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because while both statements are true, the reason provided doesn't accurately explain the enhanced reactivity of 4-nitrochlorobenzene.
37 Hard
37 of 110
Analyzing +4 | -1
Which of the following statements is correct for four isomeric bromobutanes?
View answer and explanation
Correct option: A
Of the two 1∘1^{\circ} bromides, the carbocation intermediate derived from (CH3)2CHCH2Br\left(\mathrm{CH}_3\right)_2 \mathrm{CHCH}_2 \mathrm{Br} is more stable than derived from CH3CH2CH2CH2Br\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}
Option A (Of the two 1∘1^{\circ} bromides, the carbocation intermediate derived from (CH3)2CHCH2Br\left(CH_3\right)_2 CHCH_2 Br is more stable than derived from CH3CH2CH2CH2BrCH_3 CH_2 CH_2 CH_2 Br) is correct because the isopropyl group provides more hyperconjugative stabilization to the developing positive charge in the transition state compared to the n-propyl group.
38 Hard
38 of 110
Understanding +4 | -1
Read the following statements and choose the correct code

(i) SN2{SN}^2 reaction proceed with complete stereochemical inversion.

(ii) SN1{SN}^1 reaction proceed with recimisation.

(iii) A dextrorotatory compound rotate the plane polarised light to the left.

(iv) A laevorotatory compound rotate the plane polarised light to the right
View answer and explanation
Correct option: B
TTFF
Option B (TTFF) is correct because S\N2 reactions proceed with inversion, S\N1 with racemization, dextrorotatory compounds rotate light to the right, and levorotatory to the left.
39 Medium
39 of 110
Application +4 | -1
1-phenyl, 2-chloropropane on treatment with aqueous KOH\mathrm{KOH} gives mainly:
View answer and explanation
Correct option: C
1-phenylpropan-2-ol
Option C (1-phenylpropan-2-ol) is correct because the reaction of 1-phenyl, 2-chloropropane with aqueous KOH results in a nucleophilic substitution (SN1SN_1 or SN2SN_2) where the chlorine atom is replaced by a hydroxyl group at the 2nd carbon.
40 Medium
40 of 110
Application +4 | -1
At higher temperature, iodoform reaction is given by:
View answer and explanation
Correct option: B
CH3COOC2H5\mathrm{C}{\mathrm{H}_3}\mathrm{COO}{\mathrm{C}_2}{\mathrm{H}_5}
Option B (CH3COOC2H5\mathrm{C}{\mathrm{H}_3}\mathrm{COO}{\mathrm{C}_2}{\mathrm{H}_5}) is correct because esters with the structure CH3COORCH_3COOR or RCOCH3RCOCH_3 give a positive iodoform test at higher temperatures.
41 Medium
41 of 110
Understanding +4 | -1
Although chlorobenzene does not give Ulmann’s reaction. However, presence of…group in chlorobenzene at o−,p−o - ,p -position enables it to give Ulmann’s reaction.
View answer and explanation
Correct option: A
NO2\mathrm{N}{\mathrm{O}_2}
Option A (NO2\mathrm{N}{\mathrm{O}_2}) is correct because the presence of a nitro group at the ortho- or para- position activates chlorobenzene towards nucleophilic substitution reactions like the Ullmann reaction.
42 Easy
42 of 110
Understanding +4 | -1
Assertion : Exposure of ultraviolet rays to human causes the skin cancer, disorder and disrupt the immune system.

Reason : Carbon tetrachloride is released into air it rises to atmosphere and deplets the ozone layer.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because both statements are true, but the reason does not explain the assertion.
43 Medium
43 of 110
Analyzing +4 | -1
2-chlorobutane obtained by chlorination of butane, will be:
View answer and explanation
Correct option: B
Racemic form
Option B is correct because chlorination of butane at the 2nd carbon creates a chiral center, and since the reaction is not stereospecific, it results in a racemic mixture (equal amounts of both enantiomers).
44 Medium
44 of 110
Application +4 | -1
CH3−CH−CH2−CH3→UVCl2A (major), AC{H_3} - CH - C{H_2} - C{H_3}\xrightarrow[{UV}]{{C{l_2}}}A\,\left( {\mathrm{major}} \right),\,A is
View answer and explanation
Correct option: B
CH3−C∣Cl∣CH3−CH2−CH3C{H_3} - \mathop {\mathop C\limits_{\mathop |\limits_{Cl} } }\limits^{\mathop |\limits^{C{H_3}} } - C{H_2} - C{H_3}
Option B (CH3−C∣Cl∣CH3−CH2−CH3C{H_3} - \mathop {\mathop C\limits_{\mathop |\limits_{Cl} } }\limits^{\mathop |\limits^{C{H_3}} } - C{H_2} - C{H_3}) is correct because chlorination of alkanes under UV light follows a free radical mechanism, and the most stable radical is formed at the most substituted carbon.
45 Easy
45 of 110
Understanding +4 | -1
Which of the following undergoes nucleophilic substitution exclusively SN1{\mathrm{S}_\mathrm{N}}1 mechanism?
View answer and explanation
Correct option: A
Benzyl chloride
Option A (Benzyl chloride) is correct because benzyl carbocations are stabilized by resonance with the benzene ring, favoring the S\N1 mechanism.
46 Medium
46 of 110
Application +4 | -1
What mass of isobutylene is obtained from 37 g of tertiary butyl alcohol by heating with 20% H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} at 363 K, if the yield is 65%?
View answer and explanation
Correct option: B
18.2 g
Option B (18.2 g) is correct because the reaction involves the dehydration of tertiary butyl alcohol to isobutylene, and the yield is calculated based on the given percentage.
47 Medium
47 of 110
Understanding +4 | -1
In SN1S{N^1} reaction, the racemization takes place it is due to
View answer and explanation
Correct option: D
Both (1) & (2)
Option D (Both (1) & (2)) is correct because in an S\N1 reaction, the carbocation intermediate is planar and can be attacked from either side, leading to both inversion and retention of configuration, resulting in racemization.
48 Medium
48 of 110
Understanding +4 | -1
Which can be hydrolysed most easily?
View answer and explanation
Correct option: A
(C6H5)3CCl{\left( {{\mathrm{C}_6}{\mathrm{H}_5}} \right)_3}\mathrm{CCl}
Option A ((C6H5)3CCl\mathrm{C}_6{\mathrm{H}_5})_3\mathrm{CCl}) is correct because the resulting carbocation is highly stabilized by resonance with three phenyl groups, making it more susceptible to hydrolysis via an S\N1 mechanism.
49 Hard
49 of 110
Remembering +4 | -1
Statement I: CCl2F2CC{l_2}{F_2} is called Freon 12

Statement II: Freon 12 is manufactured from tetra-chloromethane by Swarts reaction.

In the light of the above statements, choose the correct answer
View answer and explanation
Correct option: A
Both statement I and statement II are correct
Option A (Both statement I and statement II are correct) is correct because CCl2F2CC{l_2}{F_2} is indeed called Freon 12, and it is manufactured from tetrachloromethane (carbon tetrachloride) by Swarts reaction.
50 Hard
50 of 110
Understanding +4 | -1
Which one of the following possess highest m.pt. ?
View answer and explanation
Correct option: D
p- dichlorobenzene
Option D (p- dichlorobenzene) is correct because para-dichlorobenzene has a symmetrical structure, allowing for better packing in the crystal lattice, leading to higher melting point.
51 Medium
51 of 110
Application +4 | -1
20% aqueous solution of sodium chloride containing ethyl alcohol on electrolysis gives:
View answer and explanation
Correct option: D
Chloroform
Option D (Chloroform) is correct because the electrolysis of a sodium chloride solution containing ethyl alcohol can lead to the formation of chloroform through a series of reactions involving chlorination and oxidation.
52 Easy
52 of 110
Remembering +4 | -1
Iodoform is obtained when ethanol is heatd with
View answer and explanation
Correct option: B
I2{\mathrm{I}_2} and aq. KOH
Option B (I2{\mathrm{I}_2} and aq. KOH ) is correct because iodoform is produced when ethanol reacts with iodine and aqueous KOH in the iodoform reaction.
53 Medium
53 of 110
Understanding +4 | -1
Best reagent for preparing a chloro alkane from an alcohol is
View answer and explanation
Correct option: A
SOCl2/C2H5NSOC{l_2}/{C_2}{H_5}N
Option A (SOCl2/C2H5NSOC{l_2}/{C_2}{H_5}N) is correct because thionyl chloride (SOCl2SOC{l_2}) with pyridine (C2H5N{C_2}{H_5}N) provides a clean and efficient method for converting alcohols to chloroalkanes with inversion of configuration, and the byproducts are gaseous, making purification easier.
54 Medium
54 of 110
Understanding +4 | -1
Which of the following compound shows greater reactivity towards SN1S{N^1} reaction
View answer and explanation
Correct option: D
CH2=CHCH2ClC{H_2} = CHC{H_2}Cl
Option D (CH2=CHCH2ClC{H_2} = CHC{H_2}Cl) is correct because the carbocation formed after the leaving group departs is allylic and stabilized by resonance, favoring the S\N1 mechanism.
55 Hard
55 of 110
Understanding +4 | -1
Which of the following statements is/are true for geminal halide?
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Correct option: A
Ethylidine chloride is one of the examples of it
Option A (Ethylidine chloride is one of the examples of it) is correct because geminal halides have both halogens on the same carbon, and ethylidine chloride (CH3CHCl2CH_3CHCl_2) fits this description.
56 Hard
56 of 110
Analyzing +4 | -1
Among the following, the most reactive towards alcoholic KOH{KOH} is :
View answer and explanation
Correct option: B
CH3COCH2CH2Br{CH}_3 {COCH}_2 {CH}_2 {Br}
Option B (CH3COCH2CH2Br{CH}_3 {COCH}_2 {CH}_2 {Br}) is the most reactive towards alcoholic KOH{KOH} because the carbonyl group activates the adjacent carbon, making the leaving group departure easier.
57 Easy
57 of 110
Analyzing +4 | -1
Arrange decreasing order of reactivity of these compounds for nucleophilic substitution reaction.
(I)   CH3CH2−O−O∣∣S∣∣O−CF3\left( {\text{I}} \right)\,\,\,C{H_3}C{H_2} - O - \begin{array}{cccccccccccccccccccc} O \\ {||} \\ S \\ {||} \\ O \end{array} - C{F_3}
(II)   CH3−CH2−OTs\left( {{\text{II}}} \right)\,\,\,C{H_3} - C{H_2} - OTs
(III)   CH3−CH∣OH−CH3\left( {{\text{III}}} \right)\,\,\,C{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {OH} \end{array}} - C{H_3}
(IV)   CH3−CH∣C6H5−OH\left( {{\text{IV}}} \right)\,\,\,C{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{C_6}{H_5}} \end{array}} - OH
View answer and explanation
Correct option: D
I >> II >> IV >> III
Option D is correct because the reactivity order in nucleophilic substitution depends on the leaving group ability and steric hindrance. I and II have better leaving groups than III and IV, and I is better than II.
58 Medium
58 of 110
Remembering +4 | -1
Which one of the following pairs is the strongest pesticide?
View answer and explanation
Correct option: B
DDT and 666
Option B (DDT and 666) is correct because both DDT (dichlorodiphenyltrichloroethane) and 666 (benzene hexachloride) are well-known and potent pesticides.
59 Hard
59 of 110
Analyzing +4 | -1
Which of the following is not correct?
View answer and explanation
Correct option: A
PhCH2Br>PhChBrCH3>PhCBr(CH3)2(SN1){PhCH}_2 {Br}>{PhChBrCH}_3>{PhCBr}\left({CH}_3\right)_2\left({S}_{{N}} 1\right)
Option A is not correct because the stability of carbocations formed in SN1 reactions is not accurately represented by the given order. The correct order should consider the stability of the carbocation intermediate.
60 Hard
60 of 110
Analyzing +4 | -1
Arrange the following carbonyl compounds in increasing order of their reactivity in nucleophilic addition reaction

i) Benaldehyde \quad ii) P-Tolualdehyde
iii) P-Nitro benzaldehyde \quad iv) Acetophenone
View answer and explanation
Correct option: C
iv < ii < i < iii
Option C is correct because electron-withdrawing groups increase the reactivity of carbonyl compounds towards nucleophilic addition, while electron-donating groups decrease it. Steric hindrance also plays a role.
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