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NEET • CHEMISTRY • ELECTRO CHEMISTRY

Electro chemistry practice · Mixed difficulty

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Showing 361-381 of 381 questions
361 Easy
361 of 381
Remembering +4 | -1
The apparatus in which electrical energy is converted into chemical energy is known as :
View answer and explanation
Correct option: C
Both (a) and (b)
Option C (Both (a) and (b)) is correct because both voltameters and coulometers are devices used to convert electrical energy into chemical energy through electrolysis.
362 Medium
362 of 381
Application +4 | -1
For the electrochemical cell, M∣M+∣∣X−∣X,M\left| {{M^ + }||{X^ - }} \right|X,

E∘(M+∣M)=0.44V,E∘=(X∣X−)=0.33V{E^ \circ }({M^ + }|M) = 0.44V,{E^ \circ } = (X|{X^ - }) = 0.33V . From this data one can deduce that
View answer and explanation
Correct option: B
M++X−→M+X{M^ + } + {X^ - } \to M + X is the spontaneous reaction
Option C (M+X→M++X−M + X \to {M^ + } + {X^ - } is the spontaneous reaction) is correct because the cell potential is positive, indicating a spontaneous reaction in the direction written.
363 Medium
363 of 381
Analyzing +4 | -1
During electrolysis of sulphuric acid, which of the following processes is possible at anode?

A. 2H2O(l)⟶O2( g)+4H+(aq)+4e−Ecell ⊖=+1.23 V2 {H}_2 {O}({l}) \longrightarrow {O}_2({~g})+4 {H}^{+}({aq})+4 {e}^{-} \stackrel{\ominus}{{E}_{\text {cell }}}=+1.23 {~V}

B. 2SO42−(aq)⟶S2O82−(aq)+2e−Ecell ⊖=1.96 V2 {SO}_4^{2-}({aq}) \longrightarrow {S}_2 {O}_8^{2-}({aq})+2 {e}^{-} \stackrel{\ominus}{{E}_{\text {cell }}}= 1.96 {~V}

Choose the correct option based on following statements.

(i) Process A is preferred at higher concentration of sulphuric acid.

(ii) Process B is preferred at higher concentration of sulphuric acid.

(iii) Process A is preferred for dilute sulphuric acid.

(iv) Process B is preferred for dilute sulphuric acid.

(v) Both A and B are equally possible at higher concentration.
View answer and explanation
Correct option: B
(iii) and (ii)
Option B ((iii) and (ii)) is correct because at higher concentrations of sulphuric acid, process B is preferred, and for dilute sulphuric acid, process A is preferred.
364 Easy
364 of 381
Remembering +4 | -1
An apparatus used for the measurement of quantity of electricity is known as a :
View answer and explanation
Correct option: C
Coulometer
Option C is correct because a coulometer is specifically designed to measure the quantity of electricity (charge) passed during an electrochemical process.
365 Easy
365 of 381
Analyzing +4 | -1
Assertion: The degree of dissociation of a weak electrolyte depends on the nature of the electrolyte as well as on the concentration of the electrolyte.

Reason: The degree of dissociation of a weak electrolyte is directly proportional to the square root of the concentration of the electrolyte.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B (Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion) is correct because both statements are true, but the reason doesn't fully explain the assertion.
366 Medium
366 of 381
Analyzing +4 | -1
Assertion: Conductivity of metals decreases with increase of temperature whereas that of electrolytic solution increases.

Reason:Electrons in metals are very tightly held by the nucleus and are not free to move.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is incorrect.
Option C is correct because the assertion is true (metals' conductivity decreases with temperature, while electrolytic solutions' increases), but the reason is false (electrons in metals are free to move, not tightly held).
367 Medium
367 of 381
Application +4 | -1
For the reduction of silver ions with copper metal, the standard cell potential is 0.46 V at 25∘C{25^ \circ }C. The value of standard Gibbs energy ΔG∘\Delta {G^ \circ } will be :
View answer and explanation
Correct option: A
−89.0kJ- 89.0{\kern 1pt} {\kern 1pt} \mathrm{kJ}
Option A (−89.0kJ- 89.0{\kern 1pt} {\kern 1pt} \mathrm{kJ}) is correct because it is the result of correctly applying the formula ΔG∘=−nFE∘\Delta G^\circ = -nFE^\circ with the correct number of electrons transferred.
368 Medium
368 of 381
Application +4 | -1
10−2{10^{ - 2}} g atom of Ag can be oxidised to Ag+\mathrm{A}{\mathrm{g}^ + } during the electrolysis of AgNO3\mathrm{AgN}{\mathrm{O}_3} solution using silver electrode by :
View answer and explanation
Correct option: A
965 coulomb
Option A (965 coulomb) is correct because the charge required is directly proportional to the number of gram atoms oxidized, based on Faraday's laws.
369 Medium
369 of 381
Application +4 | -1
The conductivity of N/50N/50 solution of KCl\mathrm{KCl} in a cell at 250C is 0.002765mhocm−10.002765{\kern 1pt} {\kern 1pt} {\rm{mho {\kern 1pt}{\kern 1pt} c}}{\mathrm{m}^{ - 1}} . If the resistance of a cell containing this solution is 400 ohm, the cell constant is :
View answer and explanation
Correct option: B
1.106cm−11.106{\kern 1pt} {\kern 1pt} \mathrm{c}{\mathrm{m}^{ - 1}}
Option B (1.106cm−11.106{\kern 1pt} {\kern 1pt} \mathrm{c}{\mathrm{m}^{ - 1}}) is correct because the cell constant is calculated by multiplying conductivity and resistance.
370 Medium
370 of 381
Understanding +4 | -1
Which substance is obtained in the solution on electrolysis of aqueous CuSO4\mathrm{CuS}{\mathrm{O}_4} solution using graphite electrodes?
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Correct option: A
H2O{\mathrm{H}_2}\mathrm{O}
Option B (H2SO4H_2SO_4) is correct because during the electrolysis of aqueous CuSO4 using graphite electrodes, water is oxidized at the anode to produce oxygen gas and sulfuric acid remains in the solution.
371 Medium
371 of 381
Remembering +4 | -1
Which of the following electrolytes is used in lead storage battery?
View answer and explanation
Correct option: C
38 % solution of H2SO4{H_2}S{O_4}
Option C (38 % solution of H2SO4{H_2}S{O_4}) is correct because dilute sulfuric acid is the electrolyte used in lead storage batteries.
372 Hard
372 of 381
Understanding +4 | -1
Statement-I: The voltage of mercury cell remains constant for long period of time.

Statement - II: The net cell reaction does not involve active species(ions) .
View answer and explanation
Correct option: A
Both Statements-I and II are correct and Statement - II is correct explanation for Statement - I.
Option A is correct because the voltage of a mercury cell remains constant due to the net cell reaction not involving ions in solution, which means the concentration of the active species remains constant.
373 Easy
373 of 381
Understanding +4 | -1
The correct order of electro chemical equivalent (e) of Sodium, Magnesium and Aluminium is
View answer and explanation
Correct option: A
Na > Mg > Al
Option A is correct because the electrochemical equivalent (e) is directly proportional to the molar mass and inversely proportional to the number of electrons involved in the half-cell reaction. For Na, Mg, and Al, the molar masses are approximately 23, 24, and 27 g/mol, and the number of electrons involved are 1, 2, and 3, respectively. Therefore, the order of electrochemical equivalents is Na > Mg > Al.
374 Hard
374 of 381
Application +4 | -1
The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4cm25.4\mathrm{c}{\mathrm{m}^2} in area was formed to be 32 ohm. The specific and equivalent conductivity respectively in their proper units are :
View answer and explanation
Correct option: C
0.0104 and 104.0
Option C (0.0104 and 104.0) is correct because it calculates specific conductivity using the formula and equivalent conductivity by multiplying with 1000.
375 Easy
375 of 381
Remembering +4 | -1
The laws of electrolysis ware proposed by
View answer and explanation
Correct option: B
Faraday
Option B is correct because Michael Faraday proposed the laws of electrolysis.
376 Hard
376 of 381
Application +4 | -1
Resistance of 0.2 M solution of an electrolyte is 50Ω50{\kern 1pt} {\kern 1pt} \Omega . The specific conductance of the solution is 1.3 S m−1{\mathrm{m}^{ - 1}}.
If resistance of the 0.4 M solution of the same electrolyte is 260Ω , its molar conductivity is
View answer and explanation
Correct option: B
6.25×10−4Sm2mol−16.25 \times {10^{ - 4}}\mathrm{S}{\kern 1pt} {\kern 1pt} {\mathrm{m}^2}\mathrm{mo}{\mathrm{l}^{ - 1}}
Option B (6.25×10−4Sm2mol−16.25 \times {10^{ - 4}}\mathrm{S}{\kern 1pt} {\kern 1pt} {\mathrm{m}^2}\mathrm{mo}{\mathrm{l}^{ - 1}}) is correct because it correctly calculates the molar conductivity using the given resistance and specific conductance.
377 Easy
377 of 381
Understanding +4 | -1
The electrolysis of a solution resulted in the formation of H2{\mathrm{H}_2} at the cathode and Cl2\mathrm{C}{\mathrm{l}_2} at the anode. The liquid is:
View answer and explanation
Correct option: C
NaCl\mathrm{NaCl} solution in water
Option C (NaCl solution in water) is correct because electrolysis of NaCl(aq) produces H2 at the cathode and Cl2 at the anode.
378 Easy
378 of 381
Remembering +4 | -1
Anode in the Leclanche cell is
View answer and explanation
Correct option: B
Zinc container
Option B is correct because in a Leclanche cell (dry cell), the anode is the zinc container, which gets oxidized during the cell's operation.
379 Easy
379 of 381
Understanding +4 | -1
In a galvanic cell, which is wrong?
View answer and explanation
Correct option: C
Reduction takes place at anode
Option C (Reduction takes place at anode) is correct because reduction always occurs at the cathode, while oxidation occurs at the anode in a galvanic cell.
380 Easy
380 of 381
Understanding +4 | -1
Specific conductivity of a solution
View answer and explanation
Correct option: B
Decreases with dilution
Option B (Decreases with dilution) is correct because specific conductivity is the conductance of a unit volume of solution, and the number of ions per unit volume decreases upon dilution.
381 Easy
381 of 381
Analyzing +4 | -1
Statement (S): Conductivity of weak electrolytic solution decreases with dilution whereas equivalent conductivity, molar conductivity increases with dilution.
Explanation (E): On dilution, the ionic mobility and number of ions present in solution increases but number of ions per mL decreases.
View answer and explanation
Correct option: C
Both S and E are correct and E is correct explanation of S.
Option C (Both S and E are correct and E is correct explanation of S) is correct because both the statement and explanation are true, and the explanation correctly describes why conductivity decreases while equivalent and molar conductivity increase with dilution.
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