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products and are respectively
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NEET • CHEMISTRY • d & f- BLOCK ELEMENTS
D & f- BLOCK ELEMENTS practice · Hard
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31
Hard
31 of 46
Analyzing
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Metallic bonds do not play a role in:
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Correct option: A
Brass
Option C (Germanium) is correct because Germanium is a metalloid and forms covalent bonds, not metallic bonds.
32
Hard
32 of 46
Analyzing
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A solution when diluted with and boiled gives a white ppt. On addition of excess , the volume of precipitate decreases due to dissolution leaving behind a white gelatinous precipitate. The precipitate which dissolves in is:
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Correct option: A
Option A () is correct because zinc hydroxide is amphoteric and dissolves in excess ammonium hydroxide due to the formation of a complex, while aluminum hydroxide forms a gelatinous precipitate.
33
Hard
33 of 46
Remembering
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Which of the following compounds is used as the starting material for the preparation of potassium dichromate?
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Correct option: C
(Chromite)
Option C ( (Chromite)) is correct because chromite ore is the primary source from which potassium dichromate is produced.
34
Hard
34 of 46
Understanding
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A blue colouration is not obtained when:
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Correct option: B
Copper sulphate solution reacts with ]
A blue coloration is not obtained when copper sulphate solution reacts with because it forms a chocolate brown precipitate of copper ferrocyanide.
35
Hard
35 of 46
Analyzing
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Which of the following reagents does not convert copper sulphate to cuprous state?
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Correct option: D
Option D () is correct because it does not have the reducing power to convert Cu2+ to Cu+.
36
Hard
36 of 46
Understanding
+4 | -1
In the equation,
Identify the metal (M)
Identify the metal (M)
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Correct option: A
Option A () is correct because gold is extracted by leaching with cyanide, forming a complex ion.
37
Hard
37 of 46
Application
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In order to oxidise a mixture of one mole of each of and in acidic medium, the number of moles of required is
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Correct option: A
2
Option A (2) is correct because the total number of moles of required to oxidize the mixture is calculated based on the stoichiometry of the redox reactions involved.
38
Hard
38 of 46
Understanding
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The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because
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Correct option: D
The -orbitals extend further from the nucleus than the -orbitals.
Option D (The -orbitals extend further from the nucleus than the -orbitals) is correct because the greater extension of 5f orbitals in actinoids allows for more effective shielding and participation in bonding, leading to variable oxidation states.
39
Hard
39 of 46
Understanding
+4 | -1
Which of the following statements regarding copper salts is not true?
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Correct option: C
Copper(I) oxide is red powder
Option A (Copper(I) Disproportionates into Cu and Cu(II) in aqueous solution) is not true because Copper(I) disproportionates into Cu and Cu(II) in aqueous solution is a true statement. Copper(I) oxide is actually a red powder.
40
Hard
40 of 46
Analyzing
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The colour of is yellow. The expected colour of is
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Correct option: A
Yellow
Option A (Yellow) is correct because Dy3+ and Sm3+ are complementary and exhibit similar colors due to similar electronic transitions.
41
Hard
41 of 46
Application
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reacts with , in weakly basic medium to form and . When of solution reacts with of in basic medium, what is the number of moles of formed?
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Correct option: B
Option B () is correct because it represents the number of moles of formed based on the stoichiometry of the reaction between and in a weakly basic medium.
42
Hard
42 of 46
Understanding
+4 | -1
In chromyl chloride test for confirmation of ion, a yellow solution is obtained. Acidification of the solution and addition of amyl alcohol and turns organic layer blue indicating formation of chromium pentoxide. The oxidation state of chromium in that is
View answer and explanation
Correct option: A
6
The oxidation state of chromium in chromium pentoxide is 6 because chromium pentoxide has a butterfly structure with two peroxide linkages.
43
Hard
43 of 46
Analyzing
+4 | -1
products and are respectively
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Correct option: A
Option A () is the correct answer because iodide is oxidized to iodine in acidic medium, to iodate in neutral or weakly basic medium, and is reduced to and respectively. and react to form .
44
Hard
44 of 46
Understanding
+4 | -1
Arrange and in increasing order of their ionic radii
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Correct option: A
Option A () is correct because ionic radii decrease with increasing atomic number across the lanthanide series due to lanthanide contraction.
45
Hard
45 of 46
Analyzing
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Assertion : does not affect iodometric titration of Solution
Reason : is formed.
Reason : is formed.
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Correct option: D
If both Assertion & Reason are false.
Option D (If both Assertion & Reason are false) is correct because *does* affect the iodometric titration of solution, and the reason is incomplete. can oxidize to , interfering with the titration.
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46
Hard
46 of 46
Understanding
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Pick out the correct statements from the following.
I. Cobalt (III) is more stable in octahedral complexes.
II. Zinc forms coloured ions or complexes.
III. Most of the -block elements and their compounds are ferromagnetic.
IV. Osmium shows (VIII) oxidation state.
V. Cobalt (II) is more stable in octahedral complexes.
I. Cobalt (III) is more stable in octahedral complexes.
II. Zinc forms coloured ions or complexes.
III. Most of the -block elements and their compounds are ferromagnetic.
IV. Osmium shows (VIII) oxidation state.
V. Cobalt (II) is more stable in octahedral complexes.
View answer and explanation
Correct option: D
1 and 4
Cobalt (III) is more stable in octahedral complexes due to crystal field stabilization energy, and Osmium shows (VIII) oxidation state, making statements I and IV correct.
Revision notes and key takeaways
Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.
Showing 31-46 of 46 questions
