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products and are respectively
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NEET • CHEMISTRY • d & f- BLOCK ELEMENTS
D & f- BLOCK ELEMENTS practice · Mixed difficulty
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181
Easy
181 of 213
Understanding
+4 | -1
Most basic compound among the following is
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Correct option: A
Option A () is the most basic because the basicity of lanthanide hydroxides decreases as the ionic size decreases from La to Lu.
182
Hard
182 of 213
Understanding
+4 | -1
In chromyl chloride test for confirmation of ion, a yellow solution is obtained. Acidification of the solution and addition of amyl alcohol and turns organic layer blue indicating formation of chromium pentoxide. The oxidation state of chromium in that is
View answer and explanation
Correct option: A
6
The oxidation state of chromium in chromium pentoxide is 6 because chromium pentoxide has a butterfly structure with two peroxide linkages.
183
Easy
183 of 213
Application
+4 | -1
The +3 ion of which one of the following has half-filled sunshell?
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Correct option: C
Gd
Option C is correct because Gd3+ has 7 electrons in its 4f subshell, resulting in a half-filled configuration (4f7).
184
Easy
184 of 213
Remembering
+4 | -1
Most common oxidation state of vanadium is
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Correct option: D
Option D () is correct because the most stable and common oxidation state of Vanadium is +5, found in compounds like .
185
Easy
185 of 213
Analyzing
+4 | -1
Which of the following compounds has colour but no unpaired electrons?
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Correct option: A
Option A () is correct because it exhibits color due to charge transfer transitions, even though it has no unpaired d-electrons in the traditional sense.
186
Easy
186 of 213
Remembering
+4 | -1
The magnetic moment , of transition metals is related to the number of unpaired elelctrnos as
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Correct option: D
Option D is correct because the magnetic moment is calculated using the spin-only formula involving the number of unpaired electrons.
187
Easy
187 of 213
Understanding
+4 | -1
Which will reduce acidified potassium dichromate solution?
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Correct option: B
Mohr’s salt
Option B (Mohr’s salt) is correct because Mohr's salt (ferrous ammonium sulfate) contains ions, which can be oxidized to by potassium dichromate, thus reducing the dichromate.
188
Medium
188 of 213
Application
+4 | -1
Ferrous ion changes to ion, on reacting with acidified hydrogen peroxide. The number of -electrons present in and its magnetic moment (in BM) are, respectively
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Correct option: B
5 and 5.92
Option B (5 and 5.92) is correct because ferrous ion () is oxidized to ferric ion (), which has 5 d-electrons and a magnetic moment of approximately 5.92 BM.
189
Easy
189 of 213
Remembering
+4 | -1
Brass is an alloy of:
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Correct option: A
Zn and Cu
Option A (Zn and Cu) is correct because brass is an alloy primarily composed of zinc and copper.
190
Hard
190 of 213
Analyzing
+4 | -1
products and are respectively
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Correct option: A
Option A () is the correct answer because iodide is oxidized to iodine in acidic medium, to iodate in neutral or weakly basic medium, and is reduced to and respectively. and react to form .
191
Medium
191 of 213
Analyzing
+4 | -1
Identify the incorrect statement among the following
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Correct option: D
and -orbitals are equally shielded.
Option D is correct because 4f orbitals are shielded more effectively than 5f orbitals due to their spatial distribution.
192
Easy
192 of 213
Application
+4 | -1
Which of the following in its oxidation state shows the paramagnetism?
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Correct option: A
Option A () is correct because has unpaired electrons, making it paramagnetic.
193
Easy
193 of 213
Analyzing
+4 | -1
The correct order of spin only magnetic moments for the following complex ions is
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Correct option: C
Option C () is correct because it arranges the complexes in increasing order of their spin-only magnetic moments, which depends on the number of unpaired electrons.
194
Medium
194 of 213
Application
+4 | -1
reacts with oxalic acid according to the equation
Here 20 ml of 0.1 M will react with
Here 20 ml of 0.1 M will react with
View answer and explanation
Correct option: A
50 ml of 0.1 M
The correct answer is 50 ml of 0.1 M because the stoichiometry of the reaction dictates that 2 moles of react with 5 moles of oxalic acid.
195
Medium
195 of 213
Understanding
+4 | -1
on heating gives a gas which is also given by
View answer and explanation
Correct option: A
Heating
Option A (Heating ) is correct because it also produces nitrogen gas upon heating, similar to the given reaction.
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196
Medium
196 of 213
Analyzing
+4 | -1
View answer and explanation
Correct option: D
All are correct properties of
Option D (All are correct properties of ) is correct because is diamagnetic, it's a salt of dibasic acid , and it oxidizes to .
197
Medium
197 of 213
Application
+4 | -1
Which of the following ions has the highest magnetic moment?
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Correct option: C
Option C () is correct because it has the highest number of unpaired electrons, leading to the highest magnetic moment.
198
Medium
198 of 213
Application
+4 | -1
Which of the following electronic configuration represents the maximum magnetic moment?
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Correct option: D
The correct answer is because it has the maximum number of unpaired electrons (4) when considering Hund's rule, leading to the highest magnetic moment.
199
Hard
199 of 213
Understanding
+4 | -1
Arrange and in increasing order of their ionic radii
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Correct option: A
Option A () is correct because ionic radii decrease with increasing atomic number across the lanthanide series due to lanthanide contraction.
200
Hard
200 of 213
Analyzing
+4 | -1
Assertion : does not affect iodometric titration of Solution
Reason : is formed.
Reason : is formed.
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Correct option: D
If both Assertion & Reason are false.
Option D (If both Assertion & Reason are false) is correct because *does* affect the iodometric titration of solution, and the reason is incomplete. can oxidize to , interfering with the titration.
201
Medium
201 of 213
Application
+4 | -1
Correct outer electronic configuration of trivalent cationic form of (Neptunium, atomic number of 93 ) is
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Correct option: C
Option C () is correct because Neptunium (Np) has an atomic number of 93. After losing 3 electrons to form , the resulting electronic configuration is .
202
Medium
202 of 213
Analyzing
+4 | -1
In which of the following cases, the stability of two oxidation states is correctly represented
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Correct option: B
Option B () is correct because has a stable half-filled configuration, making it more stable than .
203
Easy
203 of 213
Remembering
+4 | -1
The nitrate of which metal leaves metallic globule on heating strongly?
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Correct option: B
Option B () is correct because silver nitrate decomposes upon heating to produce metallic silver, nitrogen dioxide, and oxygen.
204
Easy
204 of 213
Analyzing
+4 | -1
Which of the following is most stable?
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Correct option: D
Option D () is the most stable because it has a half-filled orbital configuration.
205
Medium
205 of 213
Understanding
+4 | -1
When excess of is added to a solution of , a white ppt. turning to grey is obtained. This grey colour is due to the formation of:
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Correct option: D
The grey color is due to the formation of mercury () because reduces to metallic mercury.
206
Medium
206 of 213
Remembering
+4 | -1
A hard and resistant alloy generally used in tip of nib of pen is:
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Correct option: B
Pt, Cr
Option A (Os, Ir) is correct because an alloy of Osmium and Iridium is very hard and resistant, making it suitable for pen nibs.
207
Hard
207 of 213
Understanding
+4 | -1
Pick out the correct statements from the following.
I. Cobalt (III) is more stable in octahedral complexes.
II. Zinc forms coloured ions or complexes.
III. Most of the -block elements and their compounds are ferromagnetic.
IV. Osmium shows (VIII) oxidation state.
V. Cobalt (II) is more stable in octahedral complexes.
I. Cobalt (III) is more stable in octahedral complexes.
II. Zinc forms coloured ions or complexes.
III. Most of the -block elements and their compounds are ferromagnetic.
IV. Osmium shows (VIII) oxidation state.
V. Cobalt (II) is more stable in octahedral complexes.
View answer and explanation
Correct option: D
1 and 4
Cobalt (III) is more stable in octahedral complexes due to crystal field stabilization energy, and Osmium shows (VIII) oxidation state, making statements I and IV correct.
208
Easy
208 of 213
Understanding
+4 | -1
In the above reaction, is
View answer and explanation
Correct option: C
Option C () is correct because when potassium dichromate is heated, it decomposes to form potassium chromate, oxygen, and chromium(III) oxide.
209
Easy
209 of 213
Analyzing
+4 | -1
The set of correct statements is:
(i) Manganese exhibits +7 oxidation state in its oxide.
(ii) Ruthenium and Osmium exhibit +8 oxidation in their oxides.
(iii) Sc shows +4 oxidation state which is oxidizing in nature.
(iv) Cr shows oxidising nature in +6 oxidation state.
(i) Manganese exhibits +7 oxidation state in its oxide.
(ii) Ruthenium and Osmium exhibit +8 oxidation in their oxides.
(iii) Sc shows +4 oxidation state which is oxidizing in nature.
(iv) Cr shows oxidising nature in +6 oxidation state.
View answer and explanation
Correct option: B
(i), (ii) and (iv)
Option B ((i), (ii) and (iv)) is correct because Manganese exhibits +7 in its oxide, Ruthenium and Osmium exhibit +8 in their oxides, and Cr shows oxidizing nature in +6 oxidation state.
210
Medium
210 of 213
Understanding
+4 | -1
Transition elements exhibit positive oxidation states only. This is because of:
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Correct option: B
Their electropositive nature
Option B (Their electropositive nature) is correct because transition elements readily lose electrons due to their relatively low ionization energies, leading to positive oxidation states.
Revision notes and key takeaways
Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.
Showing 181-210 of 213 questions
