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NEET • CHEMISTRY • CO-ORDINATION COMPOUNDS
Co-ordination compounds practice · Mixed difficulty
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271
Medium
271 of 320
Analyzing
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Consider the following statements
I. Chain and position isomerism are not possible together between two isomers
II. Tautomerism is a chemical phenomenon which is catalysed by acid as well as base
III. Tautomers are always metamers
IV. Tautomers are always functional isomers
Select the correct answer by using the codes given below
I. Chain and position isomerism are not possible together between two isomers
II. Tautomerism is a chemical phenomenon which is catalysed by acid as well as base
III. Tautomers are always metamers
IV. Tautomers are always functional isomers
Select the correct answer by using the codes given below
View answer and explanation
Correct option: D
I, II and IV are correct
Option D (I, II and IV are correct) is correct because chain and position isomerism are mutually exclusive, tautomerism is acid/base catalyzed, and tautomers are functional isomers.
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Remembering
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The common name of is
View answer and explanation
Correct option: B
Zeise's salt
Option B (Zeise's salt) is correct because is the chemical formula for Zeise's salt, a classic example of an organometallic compound.
273
Hard
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Analyzing
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A certain complex ion has the formula where is the metal ion and en ethylene diamine. How many isomers are possible for this ?
View answer and explanation
Correct option: A
3
Option A (3) is correct because the complex can exist as cis, trans, and mer isomers due to the arrangement of the ligands around the metal center.
274
Hard
274 of 320
Understanding
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In an octahedral geometry, the pair of orbitals involved in hybridization is:
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Correct option: A
The correct answer is A (). In hybridization, the orbitals involved are and because they point directly along the axes.
275
Easy
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Remembering
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Chromium carbonyl is:
View answer and explanation
Correct option: C
Option C is correct because chromium carbonyl has the formula Cr(CO)6, where chromium is bonded to six carbonyl ligands.
276
Medium
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Application
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The EAN of platinum in potassium hexachloroplatinate (IV) is:
View answer and explanation
Correct option: B
86
Option B (86) is correct because the EAN is calculated by adding the number of electrons in the metal ion and the number of electrons donated by the ligands.
277
Hard
277 of 320
Understanding
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is diamagnetic. Which of the following reasons is correct?
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Correct option: C
Metal-metal () bond in molecule
Option C (Metal-metal () bond in molecule) is correct because the presence of an Fe-Fe bond allows for the pairing of electrons between the two iron atoms, resulting in a diamagnetic complex.
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Application
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Spin only magnetic moment value of ion is
View answer and explanation
Correct option: A
2.83 BM
Option A (2.83 BM) is correct because has a ion with a configuration. Since is a strong field ligand, it will pair up the electrons, resulting in 2 unpaired electrons and a magnetic moment of approximately 2.83 BM.
279
Easy
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Understanding
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possesses:
View answer and explanation
Correct option: D
Octahedral geometry
The correct answer is D (Octahedral geometry) because the complex has a coordination number of 6, leading to an octahedral shape.
280
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Remembering
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Which of the following is colorless?
View answer and explanation
Correct option: A
Option A is correct because Ni(CO)4 is a tetrahedral complex with a d10 configuration, resulting in no d-d transitions and thus is colorless.
281
Medium
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Application
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Which one of the following has a square planar geometry?
View answer and explanation
Correct option: D
Option D ([PtCl4]2-) is correct because Pt(II) complexes with strong field ligands like Cl- tend to form square planar geometries due to dsp² hybridization.
282
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Understanding
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The IUPAC name of is
View answer and explanation
Correct option: B
Dichloro bis (triphenylphosphine)nickel(II)
Option B (Dichloro bis (triphenylphosphine)nickel(II)) is correct because it correctly names the compound, indicating the dichloro and bis(triphenylphosphine) ligands, and the oxidation state of nickel.
283
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Remembering
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Dimethyl glyoxime forms a coloured complex with
View answer and explanation
Correct option: B
Option B () is correct because dimethyl glyoxime (DMG) forms a characteristic red-colored complex with Nickel(II) ions.
284
Easy
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Remembering
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Wilkinson’s catalyst, is used for
View answer and explanation
Correct option: C
Hydrogenation of alkenes
Option C (Hydrogenation of alkenes) is correct because Wilkinson's catalyst is primarily used for the hydrogenation of alkenes.
285
Hard
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Understanding
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Arrange the following cobalt complexes in the order of increasing crystal field stabilization energy (CFSE) value. Complexes
Choose the correct option.
Choose the correct option.
View answer and explanation
Correct option: A
Option A () is correct because the spectrochemical series dictates the ligand field strength order: , hence the increasing CFSE order is .
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286
Hard
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Analyzing
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The equation which is balanced and represents the correct product(s) is
View answer and explanation
Correct option: B
Option B () is correct because it represents a balanced chemical equation with correct products formed when the complex reacts with acid.
287
Hard
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Analyzing
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Assertion : If in is replaced by , same wave1ength will be absorbed by the complex :
Reason : It is a high spin species.
Reason : It is a high spin species.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because replacing NH3 with H2O will change the ligand field strength and hence the wavelength absorbed, and [Co(NH3)6]+3 is a low spin complex, not high spin.
288
Easy
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Application
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A complex of platinum, ammonia and chlorine produces four ions per molecule in the solution. The structure consistent with the observation is:
View answer and explanation
Correct option: C
Option C ([Pt(NH3)5Cl]Cl3) is correct because it dissociates into one complex ion [Pt(NH3)5Cl]3+ and three chloride ions, resulting in a total of four ions.
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Application
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The magnetic moment (in B.M.) of complex is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because in a weak field ligand like water undergoes pairing and becomes diamagnetic, resulting in zero unpaired electrons and thus zero magnetic moment.
290
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Application
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The oxidation state of in its oxo-complex species
View answer and explanation
Correct option: B
3
The correct answer is 3 because the oxidation state of Mo in is +3.
291
Easy
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Remembering
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In the ligands are:
View answer and explanation
Correct option: C
Both
Option B (Chelates) is correct because complexes formed with bidentate or polydentate ligands are called chelates.
292
Easy
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Understanding
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The coordination number of in
View answer and explanation
Correct option: C
6
Option C (6) is correct because the coordination number is the number of ligands directly attached to the central metal ion, which in this case is 3 NH3 and 3 H2O, totaling 6.
293
Easy
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Analyzing
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The complex ion which has no ‘d’-electron in the central metal atom is:
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Correct option: A
Option A () is correct because Mn in MnO4- has a +7 oxidation state, resulting in a d0 configuration, meaning no d-electrons.
294
Medium
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Analyzing
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Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity?
View answer and explanation
Correct option: D
Trichloro triammine platinum (IV) chloride
Option D (Trichloro triammine platinum (IV) chloride) is correct because it has the fewest ions in solution, leading to the lowest electrical conductivity.
295
Medium
295 of 320
Understanding
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When ammonia is added to green aqueous solution of nickel(II) sulphate, the colour of the solution changes to blue violet. This is caused by:
View answer and explanation
Correct option: B
Ammonia molecules replacing water molecules surrounding nickel
The correct answer is B. The blue-violet color arises because ammonia molecules replace water molecules in the coordination sphere of nickel, leading to a different complex with a different color.
296
Easy
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Understanding
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Which of the following statements is correct?
View answer and explanation
Correct option: C
In the ligand has satisfied only the secondary valency of ferric ion
The correct answer is C. In , the ligand (CN-) satisfies only the secondary valency (coordination number) of the ferric ion (Fe3+).
297
Hard
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Application
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Which of the following compound is not colored?
View answer and explanation
Correct option: B
Option B () is correct because compounds with filled d-orbitals are generally colorless.
298
Hard
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Application
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The magnetic moment is measured in Bohr Magneton (BM).
Spin only magnetic moment of in and complexes respectively is:
Spin only magnetic moment of in and complexes respectively is:
View answer and explanation
Correct option: C
5.92 B.M. and 1.732 B.M.
Option C (5.92 B.M. and 1.732 B.M.) is correct because it accurately calculates the spin-only magnetic moment based on the number of unpaired electrons in each complex.
299
Medium
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Analyzing
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Which of the following complexes will show geometrical as well as optical isomerism? (en ethylene diamine)
View answer and explanation
Correct option: D
Option D () is correct because it can exist as cis and trans isomers, and the cis isomer is chiral, exhibiting optical isomerism.
300
Easy
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Analyzing
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Which statement is not correct in the case of complex?
View answer and explanation
Correct option: B
It involves - hybridization
Option B (It involves - hybridization) is not correct because involves hybridization.
Revision notes and key takeaways
Review CO-ORDINATION COMPOUNDS in your textbook or class notes, then use this set to check your understanding.
Showing 271-300 of 320 questions
