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NEET • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Mixed difficulty

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301 Medium
301 of 407
Analyzing +4 | -1
The first ionization energy of magnesium is smaller as compared to that of elements XX and YY, but higher than that of ZZ. The elements XX, YY and ZZ, respectively, are
View answer and explanation
Correct option: C
argon, chlorine and sodium
Option C is correct because ionization energy generally increases across a period and decreases down a group. Argon and chlorine have higher ionization energies than magnesium, while sodium has a lower ionization energy.
302 Medium
302 of 407
Remembering +4 | -1
In Mendleev's periodic table some pairs of elements do not follow increasing order of atomic weight known as anomolous pair. The correct example of anomolous pair is
View answer and explanation
Correct option: B
Th,PaTh, Pa
Option B (Th,PaTh, Pa) is the correct anomalous pair because Thorium and Protactinium's positions were not strictly based on increasing atomic weight in Mendeleev's table.
303 Easy
303 of 407
Understanding +4 | -1
The order of stability of metal oxides is
View answer and explanation
Correct option: C
Fe2O3<Cr2O3<Al2O3<MgO\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} < C{\mathrm{r}_2}{\mathrm{O}_3} < A{\mathrm{l}_2}{\mathrm{O}_3} < MgO
Option C (Fe2O3<Cr2O3<Al2O3<MgO\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} < C{\mathrm{r}_2}{\mathrm{O}_3} < A{\mathrm{l}_2}{\mathrm{O}_3} < MgO) is correct because the stability of metal oxides generally increases with the electropositivity of the metal.
304 Easy
304 of 407
Application +4 | -1
In which block does 106th element belong?
View answer and explanation
Correct option: C
d-block
Option C (d-block) is correct because the 106th element, Seaborgium (Sg), is a transition metal and belongs to the d-block.
305 Easy
305 of 407
Analyzing +4 | -1
Statement I: FF is more electronegative than Cl.Cl.

Statement II: FF has high electron affinity than Cl.Cl.
View answer and explanation
Correct option: C
If statement 1 is true but statement 2 is false
Option C is correct. Fluorine is more electronegative than chlorine, but chlorine has a higher electron affinity than fluorine due to fluorine's small size and strong interelectronic repulsions.
306 Medium
306 of 407
Remembering +4 | -1
According to the Periodic Law of elements, the variation in properties of elements is related to their
View answer and explanation
Correct option: C
atomic numbers
Option C (atomic numbers) is correct because the modern periodic law states that the properties of elements are periodic functions of their atomic numbers.
307 Medium
307 of 407
Understanding +4 | -1
Which one of the following has maximum ionisation potential?
View answer and explanation
Correct option: B
Be
Option B (Be) is correct because Be has a smaller atomic size and a higher effective nuclear charge compared to the other elements.
308 Medium
308 of 407
Analyzing +4 | -1
Among the statements (I-IV), the correct ones are:
I) BeBe has smaller atomic radius compared to MgMg
II) BeBe has higher ionisation enthalpy than AlAl
III) Charge/radius ratio of BeBe is greater than that of AlAl
IV) Both BeBe and AlAl form mainly covalent compounds.
View answer and explanation
Correct option: B
(I), (II) and (IV)
Option B ((I), (II) and (IV)) is correct because Be has a smaller atomic radius than Mg, higher ionization enthalpy than Al, and both form mainly covalent compounds.
309 Medium
309 of 407
Analyzing +4 | -1
The electronic configuration of four elements are

(i) [Xe]5s1[\mathrm{Xe}] 5 s^1

(ii) [Xe]4f14,5d1,6s2[\mathrm{Xe}] 4 f^{14}, 5 d^1, 6 s^2

(iii) [Ar]4s24p5[\mathrm{Ar}] 4 s^2 4 p^5

(iv) [Ar]3d7,4s2[\mathrm{Ar}] 3 d^7, 4 s^2

Select the incorrect statement about these elements.
View answer and explanation
Correct option: B
(ii) is a dd-block element
Option B is the incorrect statement. (ii) is an f-block element because the last electron enters the 4f orbital.
310 Medium
310 of 407
Analyzing +4 | -1
Electronic configurations of four elements A, B, C\mathrm{C} and D\mathrm{D} are given below :

(i) 1s22s22p61 s^2 2 s^2 2 p^6

(ii) 1s22s22p41 s^2 2 s^2 2 p^4

(iii) 1s22s22p63s11 s^2 2 s^2 2 p^6 3 s^1

(iv) 1s22s22p51 s^2 2 s^2 2 p^5

Which of the following is the correct order of increasing tendency to gain electron?
View answer and explanation
Correct option: A
(i) << (iii) << (ii) << (iv)
Option A ((i) << (iii) << (ii) << (iv)) is correct because the electron gain enthalpy becomes more negative as we move towards a more stable electronic configuration.
311 Easy
311 of 407
Analyzing +4 | -1
Anomalous pair among the following is
View answer and explanation
Correct option: D
Cobalt – Nickel
Option D (Cobalt – Nickel) is correct because Cobalt and Nickel have nearly the same atomic masses, which is an anomaly in the periodic trends.
312 Medium
312 of 407
Application +4 | -1
An element, which belongs to third period and group 16 in the periodic table has electronic configuration.
View answer and explanation
Correct option: B
1 s2,2 s22p6,3 s23p41 {~s}^2, 2 {~s}^2 2 {p}^6, 3 {~s}^2 3 {p}^4
Option B (1 s2,2 s22p6,3 s23p41 {~s}^2, 2 {~s}^2 2 {p}^6, 3 {~s}^2 3 {p}^4) is correct because it represents an element in the third period (3 energy levels) and group 16 (6 valence electrons).
313 Medium
313 of 407
Application +4 | -1
If ionization potential for hydrogen atom is 13.6 eV, then ionization potential for Li+2L{i^{ + 2}} will be:
View answer and explanation
Correct option: D
122.4 eV
Option D (122.4 eV) is correct because the ionization potential is proportional to Z² for hydrogen-like species, where Z is the atomic number.
314 Medium
314 of 407
Analyzing +4 | -1
Assertion (A): Be\mathrm{Be} and Al\mathrm{Al} show some similar properties.
Reason (R): The metallic radius of Be\mathrm{Be} is less than the metallic radius of Al\mathrm{Al}.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct; and Reason is not the correct explanation of Assertion
Option B is correct. Beryllium (Be) and Aluminum (Al) exhibit diagonal relationship due to similar polarizing power, but the reason given about metallic radii is true but not the correct explanation for the similarity in properties.
315 Easy
315 of 407
Analyzing +4 | -1
Assertion (A): In a triad, the three elements present have different gaps of atomic masses.

Reason (R): Elements in a triad have different properties.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C is correct because the assertion about triads having different gaps in atomic masses is true, but the reason that elements in a triad have different properties is not the correct explanation for the assertion.
316 Hard
316 of 407
Understanding +4 | -1
The correct electronegativity order is:
View answer and explanation
Correct option: C
Si,P,C,N\mathrm{Si},\mathrm{P},\mathrm{C},\mathrm{N}
Option C (Si, P, C, N) is the correct electronegativity order. Electronegativity increases across a period and decreases down a group. N is the most electronegative among the given elements.
317 Medium
317 of 407
Analyzing +4 | -1
The ionisation energy will be maximum for the process:
View answer and explanation
Correct option: B
Be→Be2+\mathrm{Be} \to \mathrm{B}{\mathrm{e}^{2 + }}
Option B (Be→Be2+\mathrm{Be} \to \mathrm{B}{\mathrm{e}^{2 + }}) is correct because removing two electrons from Be requires significantly more energy due to its small size and relatively high nuclear charge compared to removing electrons from Cs, Li, or Ba.
318 Easy
318 of 407
Remembering +4 | -1
Eka aluminum and Eka silicon are known as
View answer and explanation
Correct option: A
Ga and Ge
Option A is correct. Eka-aluminum was predicted by Mendeleev to be Gallium (Ga), and Eka-silicon was predicted to be Germanium (Ge).
319 Easy
319 of 407
Understanding +4 | -1
Periodic classification of elements is used to examine the
View answer and explanation
Correct option: C
Both (1) and (2)
The correct answer is C (Both (1) and (2)) because the periodic classification is used to examine both physical and chemical properties of elements.
320 Easy
320 of 407
Understanding +4 | -1
Which of the following is general electronic configuration of representative elements
View answer and explanation
Correct option: A
ns1−2np1−5n{s^{1 - 2}}n{p^{1 - 5}}
Option C is correct because representative elements are those in the s and p blocks, excluding noble gases. Their general electronic configuration reflects partially filled s and p orbitals in the outermost shell.
321 Easy
321 of 407
Remembering +4 | -1
The general electronic configuration of the transition elements is
View answer and explanation
Correct option: D
(n−1)d1−10,  ns1−2\left( {n - 1} \right){d^{1 - 10}},\;n{s^{1 - 2}}
Option D ((n - 1)d(1-10), ns(1-2)) is correct because it accurately represents the filling of d orbitals and s orbitals in transition elements.
322 Easy
322 of 407
Remembering +4 | -1
Which one of the following is not a transition metal
View answer and explanation
Correct option: D
Cd
Option D is correct. Cadmium (Cd) is not considered a typical transition metal because it has a completely filled d-orbital in its common oxidation states.
323 Easy
323 of 407
Remembering +4 | -1
Atomic radii of fluorine and neon in angstrom unit are respectively given by:
View answer and explanation
Correct option: A
0.72,1.60
Option A (0.72,1.60) is correct because atomic radii decrease across a period, and noble gases have larger van der Waals radii.
324 Medium
324 of 407
Analyzing +4 | -1
S-I: The second ionisation energy of 'OO' is greater than that of 'NN'.

S-II: The half filled p-orbitals cause greater stability.
View answer and explanation
Correct option: A
Both I and II are correct
Option A is correct because both statements are true: the second ionization energy of O is greater than N, and half-filled p-orbitals contribute to greater stability.
325 Easy
325 of 407
Remembering +4 | -1
Which of the scientists given below discovered that periodic table should be based on the atomic number?
View answer and explanation
Correct option: C
Moseley
Option C (Moseley) is correct because Moseley discovered that the periodic table should be based on atomic number.
326 Medium
326 of 407
Application +4 | -1
The electron affinity of chlorine is 3.7eV.13.7 \mathrm{eV} .1 gram of chlorine is completely converted to Cl−\mathrm{Cl}^{-}ion in a gaseous state. (1eV=23.06 kcal mol−1)\left(1 \mathrm{eV}=23.06 \mathrm{~kcal} \mathrm{~mol}^{-1}\right).
Energy released in the process is
View answer and explanation
Correct option: D
2.4 kcal2.4 \mathrm{~kcal}
Option A (2.4 kcal) is correct because it calculates the energy released when 1 gram of chlorine is converted to chloride ions using the given electron affinity and conversion factor.
327 Easy
327 of 407
Analyzing +4 | -1
Identify the least stable ion amongst the following:
View answer and explanation
Correct option: B
Be−\mathrm{B}{\mathrm{e}^ - }
Option B (Be−\mathrm{B}{\mathrm{e}^ - }) is the least stable ion because adding an electron to Beryllium (Be) disrupts its stable, completely filled s-orbital configuration.
328 Easy
328 of 407
Analyzing +4 | -1
In which of the following options the order of arrangement does not agree with the variation of property indicated against it?
View answer and explanation
Correct option: B
B<C<N<OB\mathrm{ } < \mathrm{ }C\mathrm{ } < \mathrm{ }N\mathrm{ } < \mathrm{ }O (increasing first ionization enthalpy)
Option D is correct because Mg2+Mg^{2+} has a noble gas configuration, making it extremely difficult to remove another electron.
329 Medium
329 of 407
Analyzing +4 | -1
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The ionic radii of O2−{O^{2 - }} and Mg2+M{g^{2 + }} are same.
Reason: Both O2−{O^{2 - }} and Mg2+M{g^{2 + }} are isoelectronic species.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: D
(A) is false but (R) is true.
Option D ((A) is false but (R) is true) is correct because while both ions are isoelectronic, their ionic radii are different.
330 Medium
330 of 407
Understanding +4 | -1
Which of the following transitions involves maximum amount of energy?
View answer and explanation
Correct option: D
M2+(g)→M3+(g){M^{2 + }}\left( \mathrm{g} \right) \to {M^{3 + }}\left( \mathrm{g} \right)
Option D (M2+(g)→M3+(g){M^{2 + }}\left( \mathrm{g} \right) \to {M^{3 + }}\left( \mathrm{g} \right)) is correct because the ionization energy increases with each successive ionization due to increased nuclear attraction on the remaining electrons.
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