The bond order in $NO$ is 2.5 while that in ${\rm{N}}{{\rm{O}}^ + }$ is 3. Which of the following statements is true for these two species?

Bond length in $NO$ is greater than in ${\rm{N}}{{\rm{O}}^ + }$

Bond length in ${\rm{N}}{{\rm{O}}^ + }$ is greater than in $NO$

Bond length in ${\rm{N}}{{\rm{O}}^ + }$ is equal to than in $NO$

The correct order of increasing bond length of ${\rm{C}} - {\rm{H}},{\rm{C}} - {\rm{O}},{\rm{C}} - {\rm{C}}$ and ${\rm{C}} = {\rm{C}}$ is:

${\rm{C}} - {\rm{H}} < C = C < C - O < C - C$

${\rm{C}} - {\rm{H}} < C - O < C - C < C = C$

${\rm{C}} - {\rm{C}} < C = C < C - O < C - H$

${\rm{C}} - {\rm{O}} < C - H < C - C < C = C$

Molecular shape of ${\rm{S}}{{\rm{F}}_4},{\rm{C}}{{\rm{F}}_4}$ and ${\rm{Xe}}{{\rm{F}}_4}$ are:

Different with $1,{\rm{ }}0{\rm{ }} and {\rm{ }}2$ lone pairs of electrons respectively.

The same with $2,{\rm{ }}0{\rm{ }} and {\rm{ }}1$ lone pair of electrons respectively

The same with $1,{\rm{ }}1{\rm{ }} and {\rm{ }}1$lone pair of electrons respectively.

Different with $0,{\rm{ }}1{\rm{ }} and {\rm{ }}2$ lone pairs of electrons respectively.

A compound contains $X,{\rm{ }}Y\,and\,Z$ atoms. The oxidation states of $X,{\rm{ }}Y\,and\,Z$ are $ + 2$, $ + 2$ and $ - 2$ respectively. The possible formula of the compound is

${Y_2}{\left( {X{Z_3}} \right)_2}$

${X_3}{\left( {{Y_4}Z} \right)_2}$

${X_3}{\left( {Y{Z_4}} \right)_3}$

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Chemical bonding & molecular structure practice · Mixed difficulty

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541 Easy

541 of 579

Analyzing +4 | -1

Which of the following contains atleast one lone pair of electrons in all of its halides?

View answer and explanation

Correct option: A

{Xe}

Option A (

{Xe}

) is correct because Xenon forms halides such as

XeF_2

XeF_4

, and

XeF_6

, all of which have at least one lone pair of electrons on the central Xe atom.

542 Easy

542 of 579

Understanding +4 | -1

During the formation of a chemical bond

View answer and explanation

Correct option: D

Energy decreases

Option D (Energy decreases) is correct because the formation of a chemical bond is an exothermic process, resulting in a decrease in the energy of the system.

543 Medium

543 of 579

Analyzing +4 | -1

On comparison with

{H}-{C}-{H}

bond angle of methane, the

{C}-{N}-{C}

bond angle of trimethylamine is

View answer and explanation

Correct option: B

No change

Option A (Higher) is correct because the lone pair repulsion in trimethylamine is less than in methane, leading to a slightly larger C-N-C bond angle.

544 Easy

544 of 579

Understanding +4 | -1

Which has zero dipole moment?

View answer and explanation

Correct option: C

\mathrm{Si}{\mathrm{F}_4}

Option C is correct because SiF4 has a symmetrical tetrahedral structure, causing the bond dipoles to cancel out, resulting in a zero dipole moment.

545 Medium

545 of 579

Understanding +4 | -1

The bond order in

NO

is 2.5 while that in

\mathrm{N}{\mathrm{O}^ + }

is 3. Which of the following statements is true for these two species?

View answer and explanation

Correct option: B

Bond length in

NO

is greater than in

\mathrm{N}{\mathrm{O}^ + }

Option B (Bond length in

NO

is greater than in

\mathrm{N}{\mathrm{O}^ + }

) is correct because a higher bond order indicates a stronger and shorter bond, so

\mathrm{N}{\mathrm{O}^ + }

with a bond order of 3 has a shorter bond length than

NO

with a bond order of 2.5.

546 Hard

546 of 579

Understanding +4 | -1

Which of the following geometry is not possible when the central atom is having

s p^3 d

-hybridization?

View answer and explanation

Correct option: B

Trigonal planar

Option B (Trigonal planar) is correct because

sp^3d

hybridization typically leads to geometries such as trigonal bipyramidal, linear, T-shaped, or seesaw, but not trigonal planar.

547 Medium

547 of 579

Application +4 | -1

The structure of

\mathrm{ICl}_2^ -

is:

View answer and explanation

Correct option: D

Distorted trigonal bipyramid

Option D (Distorted trigonal bipyramid) is correct because

\mathrm{ICl}_2^ -

has 2 bond pairs and 3 lone pairs around the central iodine atom, leading to a linear shape derived from a trigonal bipyramidal arrangement.

548 Medium

548 of 579

Understanding +4 | -1

The correct order of increasing bond length of

\mathrm{C} - \mathrm{H},\mathrm{C} - \mathrm{O},\mathrm{C} - \mathrm{C}

and

\mathrm{C} = \mathrm{C}

is:

View answer and explanation

Correct option: B

\mathrm{C} - \mathrm{H} < C = C < C - O < C - C

Option B (

\mathrm{C} - \mathrm{H} < C = C < C - O < C - C

) is correct because single bonds are longer than double bonds, and bond length increases with the size of the atoms involved.

549 Medium

549 of 579

Application +4 | -1

Molecular shape of

\mathrm{S}{\mathrm{F}_4},\mathrm{C}{\mathrm{F}_4}

and

\mathrm{Xe}{\mathrm{F}_4}

are:

View answer and explanation

Correct option: D

Different with

1,\mathrm{ }0\mathrm{ } and \mathrm{ }2

lone pairs of electrons respectively.

Option D (Different with

1,\mathrm{ }0\mathrm{ } and \mathrm{ }2

lone pairs of electrons respectively) is correct because the shapes and lone pairs differ:

SF_4

(see-saw, 1 lone pair),

CF_4

(tetrahedral, 0 lone pairs), and

XeF_4

(square planar, 2 lone pairs).

550 Easy

550 of 579

Analyzing +4 | -1

Which one species has the longest bond length?

View answer and explanation

Correct option: B

\mathrm{O}_2^ -

Option B (

\mathrm{O}_2^ -

) is correct because it has the lowest bond order among the given species, leading to the longest bond length.

551 Easy

551 of 579

Remembering +4 | -1

Bond angle in

{H}_2 {O}

is:

View answer and explanation

Correct option: C

104.5^0

Option C (

104.5^0

) is correct because the bond angle in water is approximately 104.5 degrees due to the two lone pairs on the oxygen atom repelling the bonding pairs.

552 Easy

552 of 579

Analyzing +4 | -1

Which of the following sets of species does not follow octet rule?

View answer and explanation

Correct option: C

\mathrm{AlCl}_3, \mathrm{BF}_3, \mathrm{PCl}_5, \mathrm{SF}_6

Option C (

\mathrm{AlCl}_3, \mathrm{BF}_3, \mathrm{PCl}_5, \mathrm{SF}_6

) is correct because in these molecules, Al and B have less than 8 electrons, while P and S have more than 8 electrons around the central atom.

553 Easy

553 of 579

Remembering +4 | -1

Which of the following silver salts is insoluble in water?

View answer and explanation

Correct option: B

\mathrm{A}{\mathrm{g}_2}\mathrm{S}{\mathrm{O}_4}

Option B (

\mathrm{A}{\mathrm{g}_2}\mathrm{S}{\mathrm{O}_4}

) is correct because silver sulfate is known to be sparingly soluble in water, while the other options are generally soluble.

554 Medium

554 of 579

Application +4 | -1

The bond order of

\mathrm{N}_2^ +

View answer and explanation

Correct option: C

2.5

Option C (2.5) is correct because

\mathrm{N}_2^ +

has 13 electrons, resulting in a bond order of 2.5.

555 Hard

555 of 579

Understanding +4 | -1

Choose the correct sequence of

{T}

and

{F}

for following statements. Here

{T}

stands for true statement and

{F}

stands for false statement.

(i) Formal charge in the Lewis structure helps in keeping track of the valence electrons in the molecule.

(ii) Formal charge indicates the actual charge separation within the molecule.

(iii) Formal charges help in the selection of the lowest energy structure from a number of possible Lewis structures.

View answer and explanation

Correct option: B

{T} F {T}

Option B (T F T) is correct because formal charge helps track valence electrons and select the lowest energy structure, but it doesn't represent actual charge separation.

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556 Hard

556 of 579

Application +4 | -1

\mathrm{PO}_4^{3 - }

, the formal charge on each on each oxygen atom and the

\mathrm{P} - \mathrm{O}

bond order respectively are

View answer and explanation

Correct option: C

- 0.75,1.25

Option C (-0.75, 1.25) is correct because the formal charge on each oxygen is -0.75 and the P-O bond order is 1.25.

557 Medium

557 of 579

Remembering +4 | -1

Among the following, which is water insoluble?

View answer and explanation

Correct option: D

Magnesium fluoride

Option D (Magnesium fluoride) is correct because magnesium fluoride (

MgF_2

) has a relatively low solubility in water compared to the other alkali metal fluorides due to its higher lattice energy and lower hydration energy.

558 Medium

558 of 579

Application +4 | -1

A compound contains

X,\mathrm{ }Y\,and\,Z

atoms. The oxidation states of

X,\mathrm{ }Y\,and\,Z

are

+ 2

+ 2

and

- 2

respectively. The possible formula of the compound is

View answer and explanation

Correct option: A

XY{Z_2}

Option A (

XY{Z_2}

) is correct because the sum of oxidation states in a neutral compound must be zero.

559 Easy

559 of 579

Understanding +4 | -1

Higher is the bond order, greater is:

View answer and explanation

Correct option: A

Bond dissociation energy

Option A (Bond dissociation energy) is correct because a higher bond order indicates a stronger bond, which requires more energy to break.

560 Medium

560 of 579

Application +4 | -1

Two elements

X

and

Y

have following electronic configuration

X = 1{s^2}\,2{s^2}2{p^6}\,\,3{s^2}3{p^6}\,\,4{s^2}

Y = 1{s^2}\,2{s^2}2{p^6}\,\,3{s^2}3{p^5}\,

The expected compound formed by combination of

X

and

Y

will be expressed as

View answer and explanation

Correct option: A

X{Y_2}

Option A (

X{Y_2}

) is correct because X has a +2 charge and Y has a -1 charge, thus requiring two Y atoms to balance the charge of one X atom.

561 Medium

561 of 579

Analyzing +4 | -1

Which of the following is paramagnetic with bond order 0.5?

View answer and explanation

Correct option: B

\mathrm{H}_2^ +

Option B (

{\mathrm{H}_2^ + }

) is correct because it has one electron, resulting in a bond order of 0.5 and is paramagnetic due to the unpaired electron.

562 Easy

562 of 579

Understanding +4 | -1

S - P

overlapping is present in

View answer and explanation

Correct option: D

HF

Option D (

HF

) is correct because hydrogen uses its s orbital and fluorine uses its p orbital to form the bond.

563 Medium

563 of 579

Analyzing +4 | -1

Among the following which has the highest cation to anion size ratio?

View answer and explanation

Correct option: B

\mathrm{CsF}

Option B (CsF) is correct because Cs has the largest cation size and F has the smallest anion size among the given options, maximizing the ratio.

564 Easy

564 of 579

Remembering +4 | -1

Which type of compounds show high melting and boiling points

View answer and explanation

Correct option: A

Electrovalent compounds

Option A (Electrovalent compounds) is correct because electrovalent compounds have strong electrostatic forces of attraction between ions, leading to high melting and boiling points.

565 Medium

565 of 579

Application +4 | -1

Which of the following species has four lone pairs in its outer shell?

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{l}^ - }

Option C (

\mathrm{C}{\mathrm{l}^ - }

) is correct because a chloride ion has 7 valence electrons plus one from the negative charge, giving it 8 electrons, which is 4 lone pairs.

566 Easy

566 of 579

Application +4 | -1

Which of the following is diamagnetic?

View answer and explanation

Correct option: C

\mathrm{L}{\mathrm{i}_2}

Option C (

\mathrm{L}{\mathrm{i}_2}

) is correct because it has all its electrons paired in its molecular orbital configuration, resulting in no net magnetic moment.

567 Medium

567 of 579

Remembering +4 | -1

The energy of hydrogen bond is of the order of

View answer and explanation

Correct option: A

40 \mathrm{~kJ} \mathrm{~mol}^{-1}

Option A (

40 \mathrm{~kJ} \mathrm{~mol}^{-1}

) is correct because the energy of a hydrogen bond typically falls in the range of 5 to 40 kJ/mol.

568 Easy

568 of 579

Application +4 | -1

The bond order in

{O}_2^{+}

View answer and explanation

Correct option: B

2.5

Option B (2.5) is correct because the bond order is calculated using molecular orbital theory, and for

O_2^+

, it is 2.5.

569 Easy

569 of 579

Application +4 | -1

The hybridization of phosphorus in

\mathrm{POC}{\mathrm{l}_3}

is same as in:

View answer and explanation

Correct option: A

\mathrm{P in PC}{\mathrm{l}_3}

Option A (

\mathrm{P in PCl_3}

) is correct because both

POCl_3

and

PCl_3

have phosphorus as the central atom with three bonding pairs and one lone pair (or a double bond and two single bonds in

POCl_3

), resulting in

sp^3

hybridization.

570 Medium

570 of 579

Understanding +4 | -1

The molecule having smallest bond angle is

View answer and explanation

Correct option: D

{\mathrm{H}_2}\mathrm{Te}

Option D (

{\mathrm{H}_2}\mathrm{Te}

) is correct because as we go down the group, the bond angle decreases due to the increasing size and decreasing electronegativity of the central atom.

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