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NEET • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Mixed difficulty

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271 Medium
271 of 579
Remembering +4 | -1
The bond formed as a result of the electrostatic attraction between the positive and negative ions is termed as …
View answer and explanation
Correct option: B
Electrovalent bond
Option B (Electrovalent bond) is correct because an electrovalent bond is formed due to the electrostatic attraction between positive and negative ions.
272 Easy
272 of 579
Analyzing +4 | -1
The correct order of strength of H-bond
View answer and explanation
Correct option: B
HF>H2O2>H2O>H2sHF > {H_2}{O_2} > {H_2}O > {H_2}s
Option D (HF>H2O>H2O2>H2sHF > {H_2}O > {H_2}{O_2} > {H_2}s) is correct because the strength of hydrogen bonding depends on the electronegativity of the atom bonded to hydrogen and the number of hydrogen bonds that can be formed.
273 Medium
273 of 579
Understanding +4 | -1
H−B−H\mathrm{H} - \mathrm{B} - \mathrm{H} bond angle in BH4−\mathrm{BH}_4^ - is:
View answer and explanation
Correct option: C
109∘109^\circ
Option C (109∘109^\circ) is correct because BH4−\mathrm{BH}_4^ - has a tetrahedral geometry, and the bond angle in a tetrahedron is approximately 109.5 degrees.
274 Medium
274 of 579
Application +4 | -1
In which of the following molecules/ions BF3,NO2−,NH2−\mathrm{B}{\mathrm{F}_3},\mathrm{NO}_2^ - ,\mathrm{NH}_2^ -, and H2O{\mathrm{H}_2}\mathrm{O} the central atom is sp2s{p^2} hybridized?
View answer and explanation
Correct option: A
BF3andNO2−\mathrm{B}{\mathrm{F}_3}\mathrm{and NO}_2^ -
Option A (BF3andNO2−\mathrm{B}{\mathrm{F}_3}\mathrm{and NO}_2^ -) is correct because both BF3BF_3 and NO2−NO_2^- have central atoms with three sp2sp^2 hybrid orbitals.
275 Easy
275 of 579
Understanding +4 | -1
In H2−{H_2}^ - ion, the bond order is
View answer and explanation
Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct because H2−{H_2}^- has a bond order of 0.5, calculated from its electronic configuration.
276 Easy
276 of 579
Understanding +4 | -1
H2O{\mathrm{H}_2}\mathrm{O} has a net dipole moment, while BeF2\mathrm{Be}{\mathrm{F}_2} has zero dipole moment, because:
View answer and explanation
Correct option: B
BeF2\mathrm{Be}{\mathrm{F}_2} molecule is linear, while H2O{\mathrm{H}_2}\mathrm{O} is bent
Option B is correct because BeF2 is linear, causing the bond dipoles to cancel out, while H2O is bent, resulting in a net dipole moment.
277 Medium
277 of 579
Analyzing +4 | -1
The molecule having smallest bond angle is:
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Correct option: A
AsCl3\mathrm{AsC}{\mathrm{l}_3}
Option A (AsCl3\mathrm{AsC}{\mathrm{l}_3}) is correct because as you go down the group, the bond angle decreases due to increased bond pair repulsion.
278 Hard
278 of 579
Understanding +4 | -1
Which of the following molecules has three fold axis of symmetry?
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Correct option: A
NH3\mathrm{N}{\mathrm{H}_3}
Option A (NH3\mathrm{N}{\mathrm{H}_3}) is correct because ammonia has a three-fold rotational axis of symmetry along the N-H bonds.
279 Medium
279 of 579
Analyzing +4 | -1
Which of the following pairs of compounds is isoelectronic and isostructural?
View answer and explanation
Correct option: D
IBr2−,XeF2\mathrm{IBr}_2^ - \mathrm{,Xe}{\mathrm{F}_\mathrm{2}}
Option D (IBr2−,XeF2\mathrm{IBr}_2^ - \mathrm{,Xe}{\mathrm{F}_\mathrm{2}}) is correct because both are linear with 2 bond pairs and 3 lone pairs on the central atom, and they have the same number of electrons.
280 Medium
280 of 579
Application +4 | -1
NO+{NO}^{+}has bond order
View answer and explanation
Correct option: C
3
Option C (3) is correct because the bond order of NO+{NO}^{+} is 3, calculated from its molecular orbital configuration.
281 Medium
281 of 579
Analyzing +4 | -1
In [Ag(CN)2]−1{\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}, the number of π\pi -bonds is
View answer and explanation
Correct option: C
44
Option C (4) is correct because each CN- ion has two pi bonds, and there are two CN- ions coordinated to the Ag+ ion, resulting in a total of 4 pi bonds.
282 Hard
282 of 579
Understanding +4 | -1
Statement-1: The ionic character exist in H2H_2 molecule but no dipole moment or bond moment exists permanently.
Statement-2: It arises so, as the two ionic forms having bond moments in opposite directions contribute equally to nullify the effect.
View answer and explanation
Correct option: A
Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1.
Option A (Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1) is correct because while the H2H_2 molecule is non-polar overall, there are instantaneous fluctuations in electron density that create temporary dipoles, and these can be thought of as arising from equally contributing ionic forms with opposing bond moments that cancel out.
283 Easy
283 of 579
Analyzing +4 | -1
Which of the following statements are not correct?
A. The electron gain enthalpy of FF is more negative than that of Cl.Cl.
B. Ionization enthalpy decreases in a group of periodic table.
C. The electronegativity of an atom depends upon the atoms bonded to it.
D. Al2O3Al_2O_3 and NONO are examples of amphoteric oxides.
Choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: D
A, C and D only
Option D is the correct answer because statements A, C, and D are incorrect regarding electron gain enthalpy, electronegativity, and amphoteric oxides, respectively.
284 Medium
284 of 579
Remembering +4 | -1
The bond energies of F2,Cl2,Br2\mathrm{F}_2, \mathrm{Cl}_2, \mathrm{Br}_2 and I2\mathrm{I}_2 are 155 , 244,193 and 151 kJ/mol151 \mathrm{~kJ} / \mathrm{mol}. The weakest bond will be in
View answer and explanation
Correct option: B
I2\mathrm{I}_2
Option B (I2\mathrm{I}_2) is correct because it has the lowest bond energy (151 kJ/mol) among the given options, indicating the weakest bond.
285 Medium
285 of 579
Analyzing +4 | -1
Out of the following which has highest dipole moment
View answer and explanation
Correct option: C
Cis - 3 - hexene
Option C (Cis - 3 - hexene) is correct because the cis isomer has a net dipole moment due to the alkyl groups being on the same side of the double bond, while the other options are either symmetrical or have very small dipole moments.
286 Easy
286 of 579
Application +4 | -1
Elements whose electronegativities are 1.21.2 and 3.03.0 form:
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Correct option: A
Ionic bond
Option A (Ionic bond) is correct because a large electronegativity difference (greater than 1.7) between two elements typically results in the formation of an ionic bond.
287 Medium
287 of 579
Understanding +4 | -1
When an element of very low ionisation potential is allowed to react with an element of very high electron affinity, we get:
View answer and explanation
Correct option: B
A strong ionic bond
Option B (A strong ionic bond) is correct because the large difference in electronegativity between the two elements leads to a complete transfer of electrons and the formation of a strong electrostatic attraction.
288 Medium
288 of 579
Application +4 | -1
The bond angle between two hybrid orbitalsis 105°. The percentage of s-character of hybrid orbital is between
View answer and explanation
Correct option: C
22−23%22 - 23\%
Option C (22−23%22 - 23\%) is correct because the percentage of s-character can be estimated using the formula % s-character = (1/(1+cot2(theta/2))) * 100.
289 Hard
289 of 579
Application +4 | -1
Suppose that AA and BB form the compounds B2A3B_2 A_3 and B2AB_2 A. If 0.05 mole of B2A3B_2 A_3 weighs 9g9 g and 0.1 mole of B2AB_2 A weighs 10 g10 {~g}, the atomic weight of AA and BB respectively are
View answer and explanation
Correct option: B
40 and 30
Option B (40 and 30) is correct because it can be found by setting up and solving a system of two equations based on the given molar masses of the compounds.
290 Medium
290 of 579
Application +4 | -1
It is thought that atoms combine with each other such that the outermost orbit acquires a stable configuration of 88 electrons. If stability were attained with 66 electrons rather than with 88, what would be the formula of the stable fluoride ions?
View answer and explanation
Correct option: B
F+{\mathrm{F}^ + }
Option B (F+{\mathrm{F}^ + }) is correct because fluorine has 7 valence electrons, and if stability were achieved with 6 electrons, it would need to lose one electron to form F+F^+.
291 Medium
291 of 579
Understanding +4 | -1
The IClICl molecule is:
View answer and explanation
Correct option: C
Polar with negative end on chlorine
Option D is correct because chlorine is more electronegative than iodine, so the chlorine end of the ICl molecule will have a partial negative charge.
292 Hard
292 of 579
Analyzing +4 | -1
Which of the following has highest bond angle?
View answer and explanation
Correct option: C
NH3\mathrm{N}{\mathrm{H}_3}
Option C is correct because NH3\mathrm{N}{\mathrm{H}_3} has the largest bond angle due to the higher electronegativity of N compared to P, and the presence of a lone pair.
293 Easy
293 of 579
Understanding +4 | -1
Which of the following has covalent bond?
View answer and explanation
Correct option: B
AlCl3\mathrm{AlC}{\mathrm{l}_3}
Option B (AlCl3\mathrm{AlCl}_3) is correct because aluminum chloride has a significant degree of covalent character due to the small size and high charge of the aluminum ion, leading to polarization of the chloride ions.
294 Medium
294 of 579
Analyzing +4 | -1
Which of the following species has only π\pi bonds according to MOT?
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Correct option: A
C2{C_2}
Option A (C2{C_2}) is correct because, according to MOT, C2{C_2} has only π\pi bonds and no σ\sigma bonds.
295 Medium
295 of 579
Application +4 | -1
The bond order of N2+N_2^{+}on the basis of molecular orbital theory is [At. number of N={N}= 7]
View answer and explanation
Correct option: B
2.5
Option B (2.5) is correct because the molecular orbital configuration of N2+N_2^+ results in a bond order of 2.5.
296 Medium
296 of 579
Analyzing +4 | -1
In which of the following, unpaired electrons are present? KO2,AlO2−,BaO2,NO2+\mathrm{K}{\mathrm{O}_2},\mathrm{AlO}_2^ - ,\mathrm{Ba}{\mathrm{O}_2},\mathrm{NO}_2^ +
View answer and explanation
Correct option: C
only KO2\mathrm{K}{\mathrm{O}_2}
Option C (only KO2\mathrm{K}{\mathrm{O}_2}) is correct because KO2\mathrm{K}{\mathrm{O}_2} is a superoxide containing the O2−\mathrm{O}_2^ - ion, which has one unpaired electron.
297 Medium
297 of 579
Understanding +4 | -1
Each of the followings has non-zero dipole moment, except:
View answer and explanation
Correct option: A
C6H6{\mathrm{C}_6}{\mathrm{H}_6}
Option A (C6H6{\mathrm{C}_6}{\mathrm{H}_6}) is correct because benzene is a symmetrical molecule with the dipole moments of the C-H bonds canceling each other out, resulting in a zero net dipole moment.
298 Easy
298 of 579
Analyzing +4 | -1
In which of the process the bond order increases and magnetic behaviour changes
View answer and explanation
Correct option: D
O2→O2+2{O_2} \to {O_2}^{ + 2}
Option D (O2→O2+2{O_2} \to {O_2}^{ + 2}) is correct because the bond order increases from 2 to 3 and the magnetic behavior changes from paramagnetic to diamagnetic.
299 Hard
299 of 579
Application +4 | -1
B10C2H12{\mathrm{B}_{10}}{\mathrm{C}_2}{\mathrm{H}_{12}} is isoelectronic with
View answer and explanation
Correct option: A
B12H122−{\mathrm{B}_{12}}\mathrm{H}_{12}^{2 - }
Option A (B12H122−{\mathrm{B}_{12}}\mathrm{H}_{12}^{2 - }) is correct because it has the same number of valence electrons as B10C2H12{\mathrm{B}_{10}}{\mathrm{C}_2}{\mathrm{H}_{12}}.
300 Medium
300 of 579
Analyzing +4 | -1
Statement-1: Ag2SAg_2S is much less soluble in water than Ag2OAg_2O.

Statement-2: S2−S^{2-} is much larger than O2−O^{2-}; so polarization of S2−S^{2-} is higher than O2−O^{2-}.
View answer and explanation
Correct option: A
Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1.
Option A (Statement-1 is true, statement-2 is true and statement- 2 is correct explanation for statement-1) is correct because larger size of S2- leads to more polarization and hence lower solubility.
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