Which compound will liberate ${\rm{C}}{{\rm{O}}_2}$ from ${\rm{NaHC}}{{\rm{O}}_3}$ solution?

${\rm{C}}{{\rm{H}}_3}{{\rm{N}}^ + }{{\rm{H}}_3}{\rm{C}}{{\rm{L}}^ - }$

${\rm{C}}{{\rm{H}}_3}{\rm{CON}}{{\rm{H}}_2}$

${\rm{C}}{{\rm{H}}_3}{\rm{N}}{{\rm{H}}_2}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_4}{{\rm{N}}^ + }{\rm{O}}{{\rm{H}}^ - }$

From the following compounds which does not react with ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{S}}{{\rm{O}}_2}{\rm{CI}}$?

${\rm{C}}{{\rm{H}}_3}.{\rm{N}}{{\rm{H}}_2}$

${{\rm{C}}_2}{{\rm{H}}_5}.{\rm{N}}{{\rm{H}}_2}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{NH}}$

${\left( {{{\rm{C}}_2}{{\rm{H}}_5}} \right)_3}{\rm{N}}$

The product $A$ and $B$ in the reaction are: ${{\rm{C}}_2}{{\rm{H}}_5}{\rm{N}}{{\rm{H}}_2} + {\rm{CHC}}{{\rm{l}}_3} + 3{\rm{KOH\;}} \to A + B + 3{{\rm{H}}_2}{\rm{O}}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{NC}} + 3{\rm{KCl}}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{CN}} + 3{\rm{KCl}}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{CON}}{{\rm{H}}_2} + 3{\rm{KCl}}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{NC}} + {{\rm{K}}_2}{\rm{C}}{{\rm{O}}_3}$

Back to AMINES

Your Progress

0 / 33 Answered

Correct

Incorrect

Accuracy

NEET • CHEMISTRY • AMINES

Amines practice · Easy

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →

Showing 1-30 of 33 questions

1 Easy

1 of 33

Understanding +4 | -1

Which statement is not correct regarding aniline?

View answer and explanation

Correct option: D

It is soluble in water

Option D (It is soluble in water) is the incorrect statement because aniline is only slightly soluble in water due to the large hydrophobic phenyl group.

2 Easy

2 of 33

Understanding +4 | -1

The amine which is most basic in aqueous solution is

View answer and explanation

Correct option: A

{\left( {C{H_3}} \right)_2}NH

Option A (

{\left( {C{H_3}} \right)_2}NH

) is correct because secondary amines are generally more basic than primary or tertiary amines in aqueous solution due to a combination of inductive effect and solvation effects.

3 Easy

3 of 33

Understanding +4 | -1

The reduction of which of the following compound would yield secondary amine?

View answer and explanation

Correct option: B

Carbylamine

Option B (Carbylamine) is correct because the reduction of carbylamines (isocyanides) yields secondary amines.

4 Easy

4 of 33

Understanding +4 | -1

Which one of the following methods is neither meant for the synthesis nor for separation of amines?

View answer and explanation

Correct option: B

Wurtz reaction

Option B (Wurtz reaction) is correct because the Wurtz reaction is used for the synthesis of alkanes, not amines, and is not used for separating amines.

5 Easy

5 of 33

Understanding +4 | -1

The correct order of the basic strength of methyl substituted amines in aqueous solution is:

View answer and explanation

Correct option: A

{(C{H_3})_2}NH\, > \,C{H_3}N{H_2}\, > \,{(C{H_3})_3}N

Option A (

{(C{H_3})_2}NH\, > \,C{H_3}N{H_2}\, > \,{(C{H_3})_3}N

) is correct because in aqueous solution, the basic strength is influenced by both the +I effect of methyl groups and solvation effects. Secondary amines are generally more basic than primary amines due to better solvation, while tertiary amines are less basic due to steric hindrance and reduced solvation.

6 Easy

6 of 33

Remembering +4 | -1

R - N{H_2} + CHC{l_3} + 3KOH\xrightarrow{{{\text{Heat}}}}R - NC + 3KCl + 3{H_2}O

Above reaction is known as:

View answer and explanation

Correct option: B

Carbylamine reaction

Option B (Carbylamine reaction) is correct because the reaction of a primary amine with chloroform and a base (KOH) to form an isocyanide (R-NC) is the defining characteristic of the Carbylamine reaction.

7 Easy

7 of 33

Analyzing +4 | -1

Which of the following is more basic than aniline?

View answer and explanation

Correct option: B

Benzylamine

Option B (Benzylamine) is correct because the lone pair on the nitrogen in benzylamine is not delocalized into the aromatic ring, making it more available for protonation than aniline and its derivatives.

8 Easy

8 of 33

Application +4 | -1

Which compound will liberate

\mathrm{C}{\mathrm{O}_2}

from

\mathrm{NaHC}{\mathrm{O}_3}

solution?

View answer and explanation

Correct option: D

\mathrm{C}{\mathrm{H}_3}{\mathrm{N}^ + }{\mathrm{H}_3}\mathrm{C}{\mathrm{L}^ - }

Option D (

\mathrm{C}{\mathrm{H}_3}{\mathrm{N}^ + }{\mathrm{H}_3}\mathrm{C}{\mathrm{L}^ - }

) is correct because it is a salt of a weak base (methylammonium chloride) and will react with

\mathrm{NaHC}{\mathrm{O}_3}

to release

\mathrm{C}{\mathrm{O}_2}

9 Easy

9 of 33

Analyzing +4 | -1

From the following compounds which does not react with

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{S}{\mathrm{O}_2}\mathrm{CI}

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_3}.\mathrm{N}{\mathrm{H}_2}

Option D (

{{\left( {{\mathrm{C}_2}{\mathrm{H}_5}} \right)}_3}\mathrm{N}

) is correct because it is a tertiary amine and does not have any replaceable hydrogen atoms on the nitrogen, thus it cannot react with Hinsberg's reagent.

10 Easy

10 of 33

Understanding +4 | -1

Aniline, chloroform and alc.

\mathrm{KOH}

on heating give:

View answer and explanation

Correct option: A

Phenyl isocyanide

Option A (Phenyl isocyanide) is correct because the reaction of aniline with chloroform and alcoholic KOH is the carbylamine reaction, which produces phenyl isocyanide.

11 Easy

11 of 33

Application +4 | -1

Major product,

\mathrm{P}

of the reaction is

\mathrm{ArN}_2 \mathrm{Cl}+\mathrm{HBF}_4 \longrightarrow \mathrm{Q} \stackrel{\Delta}{\longrightarrow} \mathrm{P}

View answer and explanation

Correct option: A

\mathrm{Ar}-\mathrm{F}

Option A (Ar-F) is correct because the reaction sequence represents the Balz-Schiemann reaction, which converts an aryl diazonium salt to an aryl fluoride.

12 Easy

12 of 33

Analyzing +4 | -1

The value of

{K_b}

is highest in case of:

View answer and explanation

Correct option: A

p -

methoxy aniline

Option A (

p -

methoxy aniline) is correct because the methoxy group is an electron-donating group, which increases the electron density on the nitrogen atom, making it more basic and thus increasing the

K_b

value.

13 Easy

13 of 33

Application +4 | -1

A colourless, odourless and non-combustible gas is liberated when ethylamine reacts with:

View answer and explanation

Correct option: C

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

Option C (

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

) is correct because ethylamine reacts with nitrous acid (

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

) to produce ethanol and nitrogen gas, which is colorless, odorless, and non-combustible.

14 Easy

14 of 33

Remembering +4 | -1

Nitrobenzene is generally used for:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because nitrobenzene can be used as a solvent in shoe polish, floor polish, and is a precursor to aniline production.

15 Easy

15 of 33

Remembering +4 | -1

Schiff’s bases are formed when aniline is condensed with:

View answer and explanation

Correct option: B

Aromatic aldehydes

Option B (Aromatic aldehydes) is correct because Schiff's bases are formed by the condensation reaction between primary amines (like aniline) and aldehydes, especially aromatic aldehydes.

Explore Other Chapters in CHEMISTRY

View All →

CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs THERMODYNAMICS 583 MCQs STRUCTURE OF ATOM 499 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs Equilibrium 412 MCQs STATES OF MATTER 410 MCQs

16 Easy

16 of 33

Understanding +4 | -1

The most basic compound among the following is:

View answer and explanation

Correct option: A

Benzylamine

Option A (Benzylamine) is the most basic compound because the nitrogen's lone pair is not delocalized into a ring, unlike aniline, acetanilide, and p-nitroaniline.

17 Easy

17 of 33

Remembering +4 | -1

The reagent used for conversion of benzene diazonium chloride to benzene is:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because

{\mathrm{H}_3}\mathrm{P}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{N}{\mathrm{a}_2}\mathrm{Sn}{\mathrm{O}_2} + \mathrm{NaOH}

, and

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

can all reduce benzene diazonium chloride to benzene.

18 Easy

18 of 33

Application +4 | -1

The product

A

and

B

in the reaction are:

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2} + \mathrm{CHC}{\mathrm{l}_3} + 3\mathrm{KOH\;} \to A + B + 3{\mathrm{H}_2}\mathrm{O}

View answer and explanation

Correct option: A

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{NC} + 3\mathrm{KCl}

Option A (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{NC} + 3\mathrm{KCl}

) is correct because this reaction is the carbylamine reaction (or isocyanide test), where a primary amine reacts with chloroform and a base to form an isocyanide, which has a foul odor.

19 Easy

19 of 33

Understanding +4 | -1

The reaction of aniline with acetyl chloride in presence of

\mathrm{NaOH}

gives:

View answer and explanation

Correct option: A

Acetanilide

Option A (Acetanilide) is correct because the reaction of aniline with acetyl chloride in the presence of NaOH is an acylation reaction, forming acetanilide.

20 Easy

20 of 33

Understanding +4 | -1

Reduction of alkyl nitriles, produces

View answer and explanation

Correct option: B

Primary amine

Option B (Primary amine) is correct because the reduction of alkyl nitriles results in the formation of primary amines.

21 Easy

21 of 33

Remembering +4 | -1

Pure aniline is a:

View answer and explanation

Correct option: B

Colourless liquid

Option B (Colourless liquid) is correct because pure aniline is a colorless liquid that turns brown upon exposure to air and light due to oxidation.

22 Easy

22 of 33

Remembering +4 | -1

Pyridine possesses:

View answer and explanation

Correct option: A

Aromatic nature

Option A (Aromatic nature) is correct because pyridine follows Huckel's rule and has a cyclic, planar structure with a delocalized pi electron system.

23 Easy

23 of 33

Remembering +4 | -1

Sulphonic acid is used in the manufacture of:

View answer and explanation

Correct option: D

Dyes

Option D (Dyes) is correct because sulfonic acids are used as intermediates in the synthesis of many dyes due to their ability to impart water solubility and reactivity.

24 Easy

24 of 33

Application +4 | -1

Which one of the following compounds will dissolve in an alkali solution after it has undergone reaction with Hinsberg reagent?

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}

Option A (

\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}

) is correct because primary amines react with Hinsberg's reagent to form a sulfonamide that has an acidic hydrogen and is therefore soluble in alkali.

25 Easy

25 of 33

Understanding +4 | -1

A nitrogen containing organic compound on heating with chloroform and alcoholic

\mathrm{KOH}

evolved very unpleasant smelling vapours. The compound could be:

View answer and explanation

Correct option: D

Aniline

Option D (Aniline) is correct because the reaction with chloroform and alcoholic KOH is the carbylamine reaction, which is a test for primary amines like aniline.

26 Easy

26 of 33

Analyzing +4 | -1

The weakest base among the following is

View answer and explanation

Correct option: B

aniline

Option B (aniline) is correct because the lone pair of electrons on the nitrogen atom in aniline is delocalized into the benzene ring, making it less available for protonation and thus less basic.

27 Easy

27 of 33

Understanding +4 | -1

Urea when heated slowly, product formed is:

View answer and explanation

Correct option: C

biuret

Option C (biuret) is correct because heating urea slowly leads to the formation of biuret through a condensation reaction.

28 Easy

28 of 33

Analyzing +4 | -1

Which of the following is not correct?

View answer and explanation

Correct option: D

Ethylamine and aniline both react with

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

to give hydroxyl compounds in cold

Option D (Ethylamine and aniline both react with

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

to give hydroxyl compounds in cold) is not correct because while ethylamine reacts to form an alcohol, aniline forms a diazonium salt which requires different conditions to form a hydroxyl compound.

29 Easy

29 of 33

Application +4 | -1

Alkyl halide

(RX)

on treatment with

KCN

followed by reduction leads to formation of:

View answer and explanation

Correct option: B

R\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

Option B (

R\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

) is correct because the reaction sequence involves converting an alkyl halide to an alkyl cyanide, followed by reduction to a primary amine with one additional carbon.

30 Easy

30 of 33

Remembering +4 | -1

Which one of the following is not an explosive?

View answer and explanation

Correct option: B

o-aminotoluene

Option B (o-aminotoluene) is correct because it is not commonly used as an explosive, unlike trinitroglycerin, dynamite, and TNT.

Revision notes and key takeaways

Review AMINES in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 33 single-correct-answer MCQs on AMINES.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Showing 1-30 of 33 questions

Continue Your Practice

📚 Switch Set (EASY)

Chapter Sets

ALL 104 MCQs EASY 33 MCQs HARD 23 MCQs MEDIUM 48 MCQs

0 /33

0✓ 0✗

0% Accuracy