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NEET • CHEMISTRY • ALDEHYDES & KETONES & CARBOXYLIC ACIDS

Aldehydes & ketones & carboxylic acids practice · Mixed difficulty

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Showing 121-137 of 137 questions
121 Easy
121 of 137
Analyzing +4 | -1
CH3COOH  and  C6H5COOH\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}\;\mathrm{and}\;{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{COOH} can be distinguished by:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because CH3COOHCH_3COOH and C6H5COOHC_6H_5COOH differ in flame test, solubility in water, and physical state.
122 Medium
122 of 137
Application +4 | -1
The product formed in the following ozonalysis is CH2BrCH=CHCH3→O3C{H_2}BrCH = CHC{H_3}\xrightarrow{{{O_3}}}
View answer and explanation
Correct option: B
CH3CHOC{H_3}CHO
Option D (CH3CHOC{H_3}CHO) is correct because ozonolysis cleaves the double bond, forming aldehydes or ketones. In this case, it forms acetaldehyde.
123 Medium
123 of 137
Remembering +4 | -1
Reaction of formaldehyde and ammonia gives
View answer and explanation
Correct option: A
Hexamethylene tetramine
Option A (Hexamethylene tetramine) is correct because formaldehyde reacts with ammonia to form hexamethylenetetramine.
124 Hard
124 of 137
Understanding +4 | -1
A mixture of benzaldehyde and formaldehyde on heating with aqueous NaOH\mathrm{NaOH} solution gives
View answer and explanation
Correct option: A
Benzyl alcohol and sodium formate
Option A (Benzyl alcohol and sodium formate) is correct because benzaldehyde and formaldehyde undergo Cannizzaro reaction in presence of NaOH.
125 Hard
125 of 137
Analyzing +4 | -1
A compound ‘A’ having the molecular formula C5H12O{\mathrm{C}_5}{\mathrm{H}_{12}}\mathrm{O}, on oxidation gives a compound ‘B’with molecular formula C5H12O{\mathrm{C}_5}{\mathrm{H}_{12}}\mathrm{O}. Compound ‘B’ gave a 2, 4-dinitrophenylhydrazine derivative but did not answer haloform test or silver mirror test. The structure of compound ‘A’
View answer and explanation
Correct option: C
CH3−CH2−CH−CH2−CH3                                            ∣                                      OH\begin{array}{l} \mathrm{C}{\mathrm{H}_3} - \mathrm{C}{\mathrm{H}_2} - \mathrm{CH} - \mathrm{C}{\mathrm{H}_2} - \mathrm{C}{\mathrm{H}_3}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;OH \end{array}
Option C is correct because the compound 'A' is a secondary alcohol that gets oxidized to a ketone, which gives a positive 2,4-DNP test but negative haloform and silver mirror tests.
126 Medium
126 of 137
Remembering +4 | -1
What is the formula of adipic acid?
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Correct option: A
COOH(CH2)4COOH\mathrm{COOH}{\left( {\mathrm{C}{\mathrm{H}_2}} \right)_4}\mathrm{COOH}
Option A (COOH(CH2)4COOH\mathrm{COOH}{\left( {\mathrm{C}{\mathrm{H}_2}} \right)_4}\mathrm{COOH}) is correct because it represents the chemical formula of adipic acid, a dicarboxylic acid with six carbon atoms.
127 Hard
127 of 137
Application +4 | -1
Calcium propanoate on refluxing yields:
View answer and explanation
Correct option: C
Pentanone-3
Option C (Pentanone-3) is correct because calcium propanoate undergoes dry distillation to form a symmetrical ketone, pentanone-3.
128 Hard
128 of 137
Understanding +4 | -1
Which factor/s will increase the reactivity of >C=O group?

I. Presence of a group with positive inductive effect.

II. Presence of a group with negative inductive effect.

III. Presence of large alkyl group.
View answer and explanation
Correct option: B
Only (ii)
Option B (Only (ii)) is correct because the presence of a group with a negative inductive effect increases the partial positive charge on the carbonyl carbon, making it more susceptible to nucleophilic attack.
129 Medium
129 of 137
Remembering +4 | -1
Formalin is the commercial name of
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Correct option: C
40% aqueous solution of methanal
Option C (40% aqueous solution of methanal) is correct because formalin is the commercial name for a 40% aqueous solution of methanal (formaldehyde).
130 Hard
130 of 137
Application +4 | -1
The end product ‘C’ in the following sequence of chemical reactions is

CH3COOH→CaCo3A→HeatB→NH2OHC\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}\xrightarrow{{\mathrm{CaC}{\mathrm{o}_3}}}A\xrightarrow{{\mathrm{Heat}}}B\xrightarrow{{\mathrm{N}{\mathrm{H}_2}\mathrm{OH}}}C
View answer and explanation
Correct option: D
Acetoxime
Option D (Acetoxime) is correct because the sequence of reactions leads to the formation of acetoxime.
131 Hard
131 of 137
Application +4 | -1
Which one of the following can produce hydrogen when treated with metallic sodium?
View answer and explanation
Correct option: D
CH3CONH2\mathrm{C}{\mathrm{H}_3}\mathrm{CON}{\mathrm{H}_2}
Option D (CH3CONH2\mathrm{C}{\mathrm{H}_3}\mathrm{CON}{\mathrm{H}_2}) is correct because amides have an acidic hydrogen that can react with metallic sodium to produce hydrogen gas.
132 Easy
132 of 137
Understanding +4 | -1
Benzaldehyde can be obtained by the hydrolysis of:
View answer and explanation
Correct option: B
Benzal chloride
Option B (Benzal chloride) is correct because hydrolysis of benzal chloride (C6H5CHCl2\mathrm{C_6H_5CHCl_2}) yields benzaldehyde (C6H5CHO\mathrm{C_6H_5CHO}).
133 Medium
133 of 137
Remembering +4 | -1
Which one of the following is not a fatty acid?
View answer and explanation
Correct option: D
Phenyl acetic acid
Option D (Phenyl acetic acid) is correct because it is an aromatic acid, not a fatty acid, which are typically long-chain aliphatic carboxylic acids.
134 Medium
134 of 137
Understanding +4 | -1
Which one of the following is reduced with zinc and hydrochloric acid to give the corresponding hydrocarbon?
View answer and explanation
Correct option: D
Butan-2-one
Option D (Butan-2-one) is correct because ketones are reduced to corresponding hydrocarbons by zinc and hydrochloric acid (Clemmensen reduction).
135 Medium
135 of 137
Application +4 | -1
.HCHO+XC6H5−CH2OH.    X  isHCHO + X{C_6}{H_5} - C{H_2}OH.\,\,\,\,X\,\,is
View answer and explanation
Correct option: A
C6H5−MgBr{C_6}{H_5} - MgBr
Option A (C6H5−MgBr{C_6}{H_5} - MgBr) is correct because Grignard reagents react with formaldehyde to form primary alcohols after hydrolysis.
136 Hard
136 of 137
Analyzing +4 | -1
What is the end product in the following sequences of operations;

Acetamide→P2O5A→4HB?\mathrm{Acetamide}\xrightarrow{{{\mathrm{P}_2}{\mathrm{O}_5}}}A\xrightarrow{{4\mathrm{H}}}B?
View answer and explanation
Correct option: B
C2H5NH2{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}
Option B (C2H5NH2{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}) is correct because acetamide undergoes dehydration with P2O5 to form acetonitrile, which is then reduced to ethylamine.
137 Hard
137 of 137
Understanding +4 | -1
Which one of following can be oxidised to the corresponding carbonyl compound?
View answer and explanation
Correct option: A
2-hydroxypropane
Option A (2-hydroxypropane) is correct because secondary alcohols can be oxidized to ketones.
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