Biomolecules practice · Easy

Option D is false because SDS denatures proteins and coats them with a negative charge, it does not maintain the 3D structure.

Option A (Glucose) is correct because glucose is commonly referred to as grape sugar due to its abundance in grapes.

Option D (Lecithin) is correct because it is a phospholipid, containing a phosphate group in its structure.

Option D (All of the above) is the correct answer because living steady state involves homeostasis, energy flow follows thermodynamics, and metabolism involves energy exchange.

Option A (Dehydrogenase) is correct because dehydrogenases are oxidoreductases, not hydrolases. Hydrolases catalyze hydrolysis reactions.

Option C (Allosteric inhibition) is correct because it involves a reversible modification of the enzyme's active site structure by a molecule binding at a site other than the active site.

Option B (Amino and carboxyl groups) is correct because the relative number of amino (-NH2) and carboxyl (-COOH) groups determines whether an amino acid is acidic, basic, or neutral.

Option B (Adenine and guanine) is correct because both adenine and guanine are purines, which are nitrogenous bases with a two-ring structure.

Option C is correct because the aggregation of various biomolecules in a cell is referred to as the cellular pool.

Option D (All are correct) is correct because the living state is indeed a non-equilibrium steady state to perform work, the constant flow of material prevents equilibrium, and living state and metabolism are closely linked.

Option C (Enzyme – Lipopolysaccharide) is correct because enzymes are proteins, not lipopolysaccharides. Lipopolysaccharides are components of bacterial cell walls.

Option A (A-Endergonic; B-Exergonic) is correct because the formation of ATP from ADP and Pi (A) requires energy input (endergonic), while the breakdown of ATP into ADP and Pi (B) releases energy (exergonic).

Option A (Galactose) is correct because galactose is a monosaccharide with a free aldehyde or ketone group, allowing it to act as a reducing agent.

Option A (Monosaccharide) is correct because lactose is a disaccharide composed of two monosaccharides (glucose and galactose).

Option D (Cellulose – Heteropolymer) is correct because cellulose is a homopolymer, not a heteropolymer. It is made up of only glucose monomers.

Option C (4 subunits (2α,2β)) is correct because adult human hemoglobin consists of two alpha and two beta subunits.

Option B (Glycogen) is correct because glycogen is a polysaccharide, a polymer of glucose monomers.

Option C (Nitrogen bases) is correct because nitrogenous bases (adenine, guanine, cytosine, thymine, and uracil) contain heterocyclic rings.

Option A (Deamination) is correct because deamination is the process of removing an amino group from a molecule, specifically an amino acid in this context.

Option B (II and III) is correct because lipids are hydrophobic (water insoluble) and dissolve in non-polar organic solvents.

Option D (Zwitterionic form) is correct because a zwitterion is a molecule with both positive and negative electrical charges, resulting in a net neutral charge.

Option C (It is a simple lipid called trihydroxypropane) is correct because glycerol is a three-carbon alcohol with three hydroxyl groups, which is chemically trihydroxypropane.

Option D (Source of many vertebrate hormones and other steroids) is correct because cholesterol is a precursor for steroid hormones and other essential steroids in vertebrates.

Option D (Photosynthesis) is correct because photosynthesis is the process by which plants and other organisms convert light energy into chemical energy in the form of glucose, which serves as the starting point for food production.

Option C (Lysine is a neutral amino acid) is the wrong statement because Lysine is a basic amino acid due to the presence of an additional amino group.

Option D (Molecular weight of glycine and glucose is less than 800 Dalton) is correct because both glycine (an amino acid) and glucose (a monosaccharide) have molecular weights significantly less than 800 Daltons.

Option A is correct because β-pleated sheets are formed by hydrogen bonds between polypeptide chains, linking them together.

Option D (Catalysed reactions) is correct because metabolic reactions are facilitated by enzymes, which act as biological catalysts.

Option C (30°-50°C) is correct because this temperature range is generally optimal for enzyme function in many organisms.

Option D (Fischer) is correct because Emil Fischer proposed the \'lock and key\' model to explain enzyme specificity.