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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 616 questions

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211 Medium
211 of 616
Understanding +4 | -1
A length is measured as 2500 m2500 \mathrm{~m} by a meter scale. Which of the following statement is correct:
View answer and explanation
Correct option: C
Number of significant figure in given data is 4 but it should be written as 2.500×103 m2.500 \times 10^3 \mathrm{~m}
Option C (Number of significant figure in given data is 4 but it should be written as 2.500×103m2.500 \times 10^3 \mathrm{{m}}) is correct because trailing zeros are significant when a decimal point is present or implied, and scientific notation clarifies the significant figures.
212 Medium
212 of 616
Remembering +4 | -1
What is the SI unit of surface tension?
View answer and explanation
Correct option: A
Nm−1{Nm}^{-1}
Option A (Nm−1{Nm}^{-1}) is correct because surface tension is defined as force per unit length.
213 Medium
213 of 616
Application +4 | -1
If velocity (v), time (T) and mass (M) are taken as fundamental quantities, then dimensional formula for gravitational potential would be.
View answer and explanation
Correct option: C
[M0v2T0]\left[ {{M^0}{v^2}{T^0}} \right]
Option C ([M0v2T0][{M^0}{v^2}{T^0}]) is correct because gravitational potential is energy per unit mass, which has dimensions of velocity squared when velocity and mass are fundamental.
214 Medium
214 of 616
Application +4 | -1
If muscle times speed equals power, what is the ratio of the SI units and the CGS unit of muscle?
View answer and explanation
Correct option: A
10510^5
Option A (10510^5) is correct because the ratio of SI to CGS units of muscle (which is force) is 10510^5.
215 Medium
215 of 616
Remembering +4 | -1
If μ0\mu_0 and ε0\varepsilon_0 are the permeability and permittivity of free space, respectively, then the dimension of (1μ0ε0)\left(\frac{1}{\mu_0 \varepsilon_0}\right) is:
View answer and explanation
Correct option: B
L2/T2\mathrm{L}^2 / \mathrm{T}^2
Option B (L2/T2\mathrm{L}^2 / \mathrm{T}^2) is correct because 1μ0ε0\frac{1}{\mu_0 \varepsilon_0} represents the square of the speed of light, which has dimensions of length squared divided by time squared.
216 Medium
216 of 616
Understanding +4 | -1
Which of the following sets cannot enter into the list of fundamental quantities in any system of units?
View answer and explanation
Correct option: B
length, time, velocity
Option B (length, time, velocity) is the correct answer because velocity can be expressed in terms of length and time, making it a derived quantity, not a fundamental one.
217 Medium
217 of 616
Analyzing +4 | -1
Which one of the following does not have the same dimensions
View answer and explanation
Correct option: D
Planck constant and energy
Option D is correct. Planck's constant and energy have different dimensions. Planck's constant has dimensions of [ML²T⁻¹], while energy has dimensions of [ML²T⁻²].
218 Easy
218 of 616
Remembering +4 | -1
Which of the following is not the unit of energy
View answer and explanation
Correct option: D
Kilowatt
Option D (Kilowatt) is correct because kilowatt is a unit of power, while calorie, joule, and electron volt are units of energy.
219 Medium
219 of 616
Application +4 | -1
Error in the measurement of radius of a sphere is 1%. Then
error in the measurement of volume is
View answer and explanation
Correct option: C
0.03
Option C (3%) is correct because the percentage error in volume is three times the percentage error in radius, according to the formula for the volume of a sphere.
220 Medium
220 of 616
Understanding +4 | -1
Which one of the following represents the correct dimensions of the coefficient of viscosity?
View answer and explanation
Correct option: C
[ML−1T−1]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 1}}} \right]
Option C [ML−1T−1]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 1}}} \right] is correct because it represents the correct dimensional formula for the coefficient of viscosity derived from Newton's formula.
221 Medium
221 of 616
Understanding +4 | -1
Dimensional equation cannot be used
View answer and explanation
Correct option: C
To find out constant of proportionality which
may be a pure number
Option C (To find out constant of proportionality which may be a pure number) is correct because dimensional analysis cannot determine dimensionless constants in physical equations.
222 Easy
222 of 616
Analyzing +4 | -1
Statement-I: If a physical quantity has a unit, it must not be dimensionless.
Statement-II: No physical quantity exists which has dimension but no unit.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C (Statement-I is false and statement-II is true) is correct because a physical quantity can have a unit and still be dimensionless, and there are no known physical quantities with dimension but no unit.
223 Medium
223 of 616
Analyzing +4 | -1
The relation tan⁡θ=v2/rg\tan \theta=v^2 / r g gives the angle of banking of the cyclist going round the curve. Here vv is the speed of the cyclist, rr is the radius of the curve, and gg is the acceleration due to gravity. Which of the following statements about the relation is true?
View answer and explanation
Correct option: A
It is both dimensionally as well as numerically correct.
Option A (It is both dimensionally as well as numerically correct) is correct because the expression tan⁡θ=v2/rg\tan \theta = v^2 / rg is dimensionally consistent and matches the standard formula for the angle of banking.
224 Medium
224 of 616
Analyzing +4 | -1
A rectangular beam which is supported at its two ends and leaded in the middle with weight w sags by an amount δ such that δ=wl34Yd3,  \delta = \frac{{w{l^3}}}{{4Y{d^3}}},\;, where l,dl,d and Y represent length, depth and elasticity respectively. Guess the unknown factor using dimensional considerations
View answer and explanation
Correct option: A
Breadth
The correct answer is A (Breadth) because dimensional analysis shows the unknown factor must have dimensions of length, which corresponds to breadth.
225 Medium
225 of 616
Understanding +4 | -1
[ML2T−2]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right] are dimensions of
View answer and explanation
Correct option: B
Moment of force
Option B (Moment of force) is correct because the dimensions of moment of force (torque) are [ML2T−2]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right].
226 Medium
226 of 616
Understanding +4 | -1
Assertion : Avogadro’s number is the number of atoms
in one gram mole.
Reason : Avogadro’s number is a dimensionless constant.
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect
The correct answer is C (Assertion is correct, reason is incorrect) because Avogadro's number has units of mol-1, making the reason incorrect.
227 Medium
227 of 616
Application +4 | -1
The dimensions of resistivity in terms of M,L,T and Q where Q stands for the dimensions of charge, is
View answer and explanation
Correct option: A
ML3T−1Q−2M{L^3}{T^{ - 1}}{Q^{ - 2}}
Option A (ML3T−1Q−2M{L^3}{T^{ - 1}}{Q^{ - 2}}) is correct because it is derived from the definition of resistivity using Ohm's law and the dimensions of resistance, area, length, and charge.
228 Medium
228 of 616
Understanding +4 | -1
If e\mathrm{e} is charge, V\mathrm{V} is potential difference, T\mathrm{T} is temperature, then units of eVT\frac{\mathrm{eV}}{\mathrm{T}} are same as of
View answer and explanation
Correct option: C
Boltzman  constant(Energytemperature){\text{Boltzman}}\,\,{\text{constant}}\left( {\frac{{{\text{Energy}}}}{{{\text{temperature}}}}} \right)
The units of eV/T are the same as Boltzmann's constant because eV represents energy and T represents temperature, so eV/T is energy per temperature.
229 Medium
229 of 616
Application +4 | -1
A physical quantity is represented by X=MαLbT−c.X = {\mathrm{M}^\alpha }{\mathrm{L}^b}{\mathrm{T}^{ - c}}.. If percentage errors in the measurements of M,L and T are α%,β%\alpha \% ,\beta \% and γ%\gamma \% respectively, then total, percentage error is
View answer and explanation
Correct option: B
(αa+βb+γc)%\left( {\alpha a + \beta b + \gamma c} \right)\%
Option B ((αa+βb+γc)%\left( {\alpha a + \beta b + \gamma c} \right)\%) is correct because the percentage error is the sum of the absolute values of the errors multiplied by their respective powers.
230 Hard
230 of 616
Application +4 | -1
A wire has mass (0.3 ± 0.003) gm,(0.3\, \pm \,0.003)\,gm, radius (0.5± 0.005) cm (0.5 \pm \,0.005)\,cm\, and length (6± 0.06) cm (6 \pm \,0.06)\,cm\,. The maximum percentage error in the measurement of its density is:-
View answer and explanation
Correct option: D
4%
Option D (4%) is correct because the maximum percentage error in density is the sum of the percentage errors in mass, length, and twice the percentage error in radius.
231 Medium
231 of 616
Analyzing +4 | -1
[ML−2T−2]\left[ {\mathrm{M}{\mathrm{L}^{ - 2}}{\mathrm{T}^{ - 2}}} \right] represents dimensional formula of which of the following physical quantities?
View answer and explanation
Correct option: D
Pressure gradient
Option D (Pressure gradient) is correct because the dimensional formula of pressure gradient is force per unit volume per unit length, which matches the given formula.
232 Medium
232 of 616
Application +4 | -1
The ratio of SI. Unit of the CGS unit of Planck’s constant is
View answer and explanation
Correct option: A
107:1{10^7}:1
Option A (107:1{10^7}:1) is correct because the SI unit of Planck's constant is JsJs and the CGS unit is erg⋅serg \cdot s, and 1J=107erg1 J = 10^7 erg.
233 Easy
233 of 616
Understanding +4 | -1
Which of the following quantities has the same dimensions as that of energy
View answer and explanation
Correct option: D
Work
Option D (Work) is correct because work and energy are dimensionally equivalent, both representing the capacity to do work.
234 Easy
234 of 616
Remembering +4 | -1
Unit of stress is
View answer and explanation
Correct option: C
N/m2N/{m^2}
Option C (N/m2N/{m^2}) is correct because stress is defined as force per unit area, and the unit of force is Newton (N) and area is square meter (m2m^2).
235 Easy
235 of 616
Understanding +4 | -1
Statement I: The order of accuracy of measurement depends on the least count of the measuring instrument.

Statement II: The smaller the least count, the greater is the number of significant figures in the measured value.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I
Option B (Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I) is correct because both statements are true, but Statement II does not explain Statement I.
236 Medium
236 of 616
Understanding +4 | -1
We can reduce random errors by
View answer and explanation
Correct option: A
Taking large number of observations
Option A (Taking large number of observations) is correct because averaging multiple measurements reduces the impact of random fluctuations.
237 Medium
237 of 616
Analyzing +4 | -1
Statement-1 : Angular momentum and Plank constant have same dimensions.
Statement-2 : Moment of force and linear momentum have same dimensions.
View answer and explanation
Correct option: C
) Statement 1 is true and 2nd is false
Option C is correct. Angular momentum and Planck's constant have the same dimensions, while moment of force (torque) and linear momentum do not.
238 Medium
238 of 616
Application +4 | -1
A body travels uniformly a distance of (20±0.1)  m\left( {20 \pm 0.1} \right)\,\,m in time (2.0±0.02)  s.\left( {2.0 \pm 0.02} \right)\,\,s. The velocity of the body is
View answer and explanation
Correct option: D
(10±0.1)  ms−1\left( {10 \pm 0.1} \right)\,\,m{s^{ - 1}}
Option D ((10±0.1) ms−1\left( {10 \pm 0.1} \right)\,m{s^{ - 1}}) is the closest to the correct answer because it correctly calculates the velocity and its associated uncertainty using error propagation.
239 Medium
239 of 616
Understanding +4 | -1
The dimensions of angular impulse is equal to
View answer and explanation
Correct option: A
[M1L2T−1]\left[\mathrm{M}^1 \mathrm{L}^2 \mathrm{T}^{-1}\right]
Option A (M1L2T−1\mathrm{M}^1 \mathrm{L}^2 \mathrm{T}^{-1}) is correct because angular impulse is the change in angular momentum, which has the dimensions of mass * velocity * radius.
240 Medium
240 of 616
Understanding +4 | -1
The dimensions of pressure are:
View answer and explanation
Correct option: C
[ML−1T−2]\left[ {M{L^{ - 1}}{T^{ - 2}}} \right]
Option C ([ML−1T−2]\left[ {M{L^{ - 1}}{T^{ - 2}}} \right]) is correct because pressure is force per unit area, and its dimensions are derived accordingly.
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