Skip to main content
Back to UNITS & MEASUREMENTS

Your Progress

0 / 616 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 451-480 of 616 questions

Preparing practice and saved progress…

451 Medium
451 of 616
Application +4 | -1
A quantity ff is given by f=hc5G,f = \sqrt {\frac{{h{c^5}}}{G}} , where cc is speed of light, GG universal gravitational constant and hh is the Planck’s constant.
Dimension of ff is that of
View answer and explanation
Correct option: D
energy
Option D (energy) is correct because the dimensions of the given quantity match the dimensions of energy.
452 Medium
452 of 616
Application +4 | -1
If error in measurement of volume of a cube is 6%6 \% then percentage error in the measurement of its surface area is
View answer and explanation
Correct option: C
4%4 \%
Option C (4%4 \%) is correct because the percentage error in surface area is 2/3 times the percentage error in volume.
453 Medium
453 of 616
Understanding +4 | -1
Assertion: Mass, length and time are fundamental physical quantities.

Reason: They are independent of each other.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because mass, length, and time are fundamental quantities and are independent of each other, which is the reason for them being fundamental.
454 Medium
454 of 616
Application +4 | -1
The area of a square is 5.29  cm25.29\mathrm{ }\,\,c{m^2}. The area of 7 such squares taking into account the significant figures is
View answer and explanation
Correct option: B
37.0  cm237.0\mathrm{ }\,\,c{m^2}
Option B (37.0 cm237.0\mathrm{ }\,c{m^2}) is correct because it is the area of 7 squares, taking into account significant figures.
455 Easy
455 of 616
Application +4 | -1
A force is represented by F=ax2+bt12F=a x^2+b t^{\frac{1}{2}}
Where x=x= distance and t=t= time. The dimensions of b2/ab^2 / a are:
View answer and explanation
Correct option: A
[ML3 T−3]\left[\mathrm{ML}^3 \mathrm{~T}^{-3}\right]
Option A ([ML3 T−3\mathrm{ML}^3 \mathrm{~T}^{-3}]) is correct because it is derived by finding the dimensions of a and b from the given force equation and then calculating the dimensions of b2/ab^2/a.
456 Medium
456 of 616
Analyzing +4 | -1
If a book with many printing errors contains four different formulae for the displacement yy of a particle undergoing a certain periodic motion.
(1) y=asin⁡2πtTy=a \sin \frac{2 \pi t}{T}
(2) y=asin⁡vTy=a \sin v T
(3) y=aTsin⁡tay=\frac{a}{T} \sin \frac{t}{a}
(4) y=(a2)(sin⁡2πtT+cos⁡2πtT)y=(a \sqrt{2})\left(\sin \frac{2 \pi t}{T}+\cos \frac{2 \pi t}{T}\right)
where aa is the maximum displacement of the particle, vv is the speed of particle, TT is the time period of motion. Then dimensionally
View answer and explanation
Correct option: B
(2) and (3) are wrong
Option B is correct because formulas (2) and (3) are dimensionally incorrect. The arguments of trigonometric functions must be dimensionless, and the dimensions of y must be length.
457 Medium
457 of 616
Understanding +4 | -1
μ0\mu_0 and ε0\varepsilon_0 denote the magnetic permeability and electrical permittivity of free space, then the dimensions of 1μ0ε0\frac{1}{\sqrt{\mu_0 \varepsilon_0}} are similar to
View answer and explanation
Correct option: B
velocity
Option B (velocity) is correct because the dimensions of 1μ0ε0\frac{{1}}{{\sqrt{{\mu_0 \varepsilon_0}}}} are [LT−1][LT^{-1}], which is the dimension of velocity.
458 Medium
458 of 616
Remembering +4 | -1
Oersted is a unit of
View answer and explanation
Correct option: B
Magnetic intensity
Option B (Magnetic intensity) is correct because Oersted is a unit of magnetic field strength, also known as magnetic intensity or H-field.
459 Medium
459 of 616
Application +4 | -1
The dimensions of   ab\;\frac{a}{b} in the equation p=a  −  t2bxp = \frac{{a\; - \;{t^2}}}{{bx}} where p is pressure, x is distance and t is time, are
View answer and explanation
Correct option: B
[MT−2]\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right]
Option B [MT−2]\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right] is correct because it is derived from dimensional analysis using the principle of homogeneity.
460 Medium
460 of 616
Application +4 | -1
How many amu would make up 1 kg?1 \mathrm{~kg}?
View answer and explanation
Correct option: A
6.024×1026amu6.024 \times 10^{26} \mathrm{amu}
Option A (6.024×1026amu6.024 \times 10^{26} \mathrm{amu}) is correct because 1 amu is approximately 1.66×10−271.66 \times 10^{-27} kg, so 1 kg is approximately 6.024×10266.024 \times 10^{26} amu.
461 Medium
461 of 616
Remembering +4 | -1
Lumen is the unit of
View answer and explanation
Correct option: A
luminous flux
Option A (luminous flux) is correct because the lumen is the SI unit specifically designed to measure luminous flux, which quantifies the total amount of visible light emitted by a source.
462 Medium
462 of 616
Remembering +4 | -1
What is the dimension of Luminous flux?
View answer and explanation
Correct option: A
[cd1][\mathrm{cd^1}]
Option A ([cd¹]) is correct because luminous flux is measured in lumens, and the dimension of luminous intensity (candela) is [cd], and luminous flux is directly related to luminous intensity.
463 Medium
463 of 616
Analyzing +4 | -1
If xx and aa stand for distance, then for what value of nn is the given equation dimensionally correct? The equation is ∫dxa2−xn=sin⁡−1xa\int \frac{d x}{\sqrt{a^2-x^n}}=\sin ^{-1} \frac{x}{a}
View answer and explanation
Correct option: B
2
Option B is correct. For the equation to be dimensionally correct, the term inside the square root must have dimensions of a2a^2. Thus, xnx^n must have the same dimensions as a2a^2, implying n=2n=2.
464 Medium
464 of 616
Understanding +4 | -1
The number of significant figures in q=1.6×10−19q = 1.6 \times {10^{ - 19}} coulomb are
View answer and explanation
Correct option: B
2
Option B (2) is correct because only the digits 1 and 6 are significant in the given number; the power of 10 does not affect the number of significant figures.
465 Medium
465 of 616
Understanding +4 | -1
Which of the following is not a dimensionless quantity?
View answer and explanation
Correct option: C
Permeability of free space (μ0)({\mu _0})
Option C (Permeability of free space (μ0)({\mu _0})) is correct because it has units and dimensions, unlike the other dimensionless quantities.
466 Medium
466 of 616
Understanding +4 | -1
Which is dimensionless?
View answer and explanation
Correct option: D
Energy/work
Option D (Energy/work) is correct because energy and work have the same dimensions, making their ratio dimensionless.
467 Medium
467 of 616
Understanding +4 | -1
Statement-I: Dimensional analysis can give us the numerical value of proportionality constants that may appear in an algebraic expression.
Statement-II: Dimensional analysis make use of the fact that dimensions can be treated as algebraic quantities.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C (Statement-I is false and statement-II is true) is correct because dimensional analysis cannot determine the numerical values of dimensionless constants, but it does rely on the fact that dimensions can be treated algebraically.
468 Medium
468 of 616
Understanding +4 | -1
If e is the charge, V the potential difference, T the temperature, then the units of eVT\frac{{eV}}{T} are the same as that of
View answer and explanation
Correct option: C
Boltzmann's constant
Option C (Boltzmann's constant) is correct because eVT\frac{{eV}}{T} has the same units as energy per temperature, which is the unit of Boltzmann's constant.
469 Hard
469 of 616
Remembering +4 | -1
To determine refractive index of glass also using
a travelling microscope, minimum number of
readings required are
View answer and explanation
Correct option: C
Three
Option C (Three) is correct because three readings are needed: one for the real depth, one for the apparent depth with the glass slab, and one as a reference point.
470 Medium
470 of 616
Application +4 | -1
If ee is the electronic charge, cc is the speed of light in free space and hh is Planck’s constant, the quantity 14π∈0∣e∣2hc\frac{1}{{4\pi { \in _0}}}\frac{{{{\left| e \right|}^2}}}{{hc}} has dimensions of
View answer and explanation
Correct option: C
[M0L0T0]\left[ {{M^0}{L^0}{T^0}} \right]
Option A (π6\frac{\pi}{6}) is correct because the phase difference is calculated by converting both SHMs to sine functions and then subtracting their phase angles.
471 Easy
471 of 616
Application +4 | -1
A physical quantity A is related to four observables a,b,c and d as follows   A=a2b3cd\;A = \frac{{{a^2}{b^3}}}{{c\sqrt d }} The percentage errors of measurement in a,b,c and d are 1%, 3%, 2% and 2% respectively. What is the percentage error in the quantity A?
View answer and explanation
Correct option: D
14%14\%
Option D (14%14\%) is correct because the percentage error in A is calculated by summing the percentage errors in a, b, c, and d, each multiplied by its respective power.
472 Medium
472 of 616
Remembering +4 | -1
Parsec is a unit of
View answer and explanation
Correct option: A
Distance
Option A (Distance) is correct because a parsec is a unit of length used to measure large distances to astronomical objects outside the solar system.
473 Medium
473 of 616
Analyzing +4 | -1
If E,M,L and G denote energy, mass, angular momentum and gravitational constant respectively, then the quantity (EL2/M5G2)\left( {E{L^2}/{M^5}{G^2}} \right) has the dimensions of
View answer and explanation
Correct option: A
Angle
Option A (Angle) is correct because the expression (EL2/M5G2)\left( {E{L^2}/{M^5}{G^2}} \right) is dimensionless, representing an angle.
474 Medium
474 of 616
Analyzing +4 | -1
The entropy of any system is given by S=α2β  ln[μkRJβ2 + 3]\mathrm{S = }{\mathrm{\alpha }^\mathrm{2}}\mathrm{\beta\,\, ln}\left[ {\frac{{\mathrm{\mu kR}}}{{\mathrm{J}{\mathrm{\beta }^\mathrm{2}}}}\, + \,3} \right] where, α\alpha and β\beta are the constants; μ, J, k  and  R\mu ,\,J,\,k\,\,\mathrm{and}\,\,R are number of moles, mechanical equivalent of heat, Boltzmann constant and gas constant, respectively.
[Take,  S=dQT    ]\left[ {\mathbf{Take},\,\,\mathrm{S = }\frac{{\mathrm{dQ}}}{\mathrm{T}}\;\;} \right]
Choose the incorrect option.
View answer and explanation
Correct option: D
  α  and  k\,\,\alpha \,\,\mathrm{and}\,\,k have the same dimension
Option D is correct because α\alpha and kk have different dimensions. After dimensional analysis, it's found that α\alpha is dimensionless while kk has dimensions of energy per temperature.
475 Medium
475 of 616
Understanding +4 | -1
The ratio of the volume of the atom to the volume of the nucleus is of the order of
View answer and explanation
Correct option: A
101510^{15}
Option A (101510^{15}) is correct because the ratio of the volume of the atom to the volume of the nucleus is approximately 101510^{15}, based on their respective radii.
476 Medium
476 of 616
Application +4 | -1
If force is proportional to square of velocity, then the dimensions of proportionality constant are
View answer and explanation
Correct option: B
[ML−1T0]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}} \right]
Option B ([ML−1T0]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}} \right]) is correct because the proportionality constant's dimensions are derived from the force divided by the square of velocity.
477 Medium
477 of 616
Remembering +4 | -1
Unit of Stefan's constant is
View answer and explanation
Correct option: B
Jm−2s−1K−4{Jm}^{-2} {s}^{-1} K^{-4}
Option B is correct because Stefan's constant has units of Watts per square meter per Kelvin to the fourth power, which is equivalent to J m-2 s-1 K-4.
478 Medium
478 of 616
Understanding +4 | -1
SI unit of permittivity is
View answer and explanation
Correct option: B
C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}
Option B (C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}) is correct because it is derived from Coulomb's law and represents the units of permittivity.
479 Medium
479 of 616
Understanding +4 | -1
Planck’s constant has the dimensions (unit) of
View answer and explanation
Correct option: D
Angular momentum
Option D (Angular momentum) is correct because Planck's constant has the dimensions of energy multiplied by time, which is equivalent to angular momentum.
480 Medium
480 of 616
Remembering +4 | -1
The quantity having the same units in all systems of units is
View answer and explanation
Correct option: B
time
Option B (time) is correct because the unit of time (seconds) is the same in all systems of units (SI, CGS, FPS).
Revision notes and key takeaways

Review UNITS & MEASUREMENTS in your textbook or class notes, then use this set to check your understanding.

Showing 451-480 of 616 questions

Your practice

0 / 616 answered · 616 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.