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JEE • PHYSICS • THERMAL PROPERTIES OF MATTER

Thermal properties of matter practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 553 questions

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1 Medium
1 of 553
Remembering +4 | -1
In the relation n=PVRT,n=n = \frac{{PV}}{{RT}},n =
View answer and explanation
Correct option: D
Number of Moles
Option D (Number of Moles) is correct because in the ideal gas law equation, 'n' represents the number of moles.
2 Medium
2 of 553
Understanding +4 | -1
Mud houses are cooler in summer and warmer in winter because
View answer and explanation
Correct option: C
Mud is bad conductor of heat
Option C (Mud is bad conductor of heat) is correct because mud's poor conductivity prevents heat transfer, keeping houses cooler in summer and warmer in winter.
3 Hard
3 of 553
Understanding +4 | -1
For cooking the food, which of the following type of utensil is most suitable
View answer and explanation
Correct option: D
Low specific heat and high conductivity
Option D (Low specific heat and high conductivity) is correct because utensils should heat up quickly (low specific heat) and transfer heat efficiently (high conductivity).
4 Medium
4 of 553
Understanding +4 | -1
Which of the following statements is correct?
View answer and explanation
Correct option: D
When fully inflated balloon is immersed in cold water, it will contract
Option D (When fully inflated balloon is immersed in cold water, it will contract) is correct because cooling the air inside the balloon reduces its volume.
5 Medium
5 of 553
Application +4 | -1
300 gm of water at 250{25^0} is added to 100 g of ice at 00C{0^0}C. The final temperature of the mixture is
View answer and explanation
Correct option: D
00C{0^0}C
Option D (00C{0^0}C) is correct because the heat released by the water cooling down to 0°C is not enough to melt all the ice, so the final temperature is 0°C.
6 Medium
6 of 553
Application +4 | -1
A black body radiates energy at the rate of E  Wm−2E\,\,W{m^{ - 2}} at a high temperature T K. When the temperature is reduced to (T2)K\left( {\frac{T}{2}} \right)K the radiant energy is
View answer and explanation
Correct option: D
E16\frac{E}{16}
Option D (E16\frac{E}{16}) is correct because according to Stefan's law, the radiant energy is proportional to the fourth power of the temperature, so when the temperature is halved, the energy becomes 1/16th.
7 Medium
7 of 553
Remembering +4 | -1
A perfectly black body has absorptivity a equal to
View answer and explanation
Correct option: D
a=1a=1
Option D (a=1a=1) is correct because a perfectly black body absorbs all incident radiation, meaning its absorptivity is 1.
8 Medium
8 of 553
Application +4 | -1
Suppose that one early morning when the temperature is 10∘C10^{\circ} \mathrm{C}, a driver of an automobile gets his gasoline tank which is made of steel, filled with 75 litre of gasoline, which is also at 10∘C10^{\circ} \mathrm{C}. During the day, the temperature rises to 30∘C30^{\circ} \mathrm{C}. How much gasoline will overflow? Given α\alpha for steel =1.2×10−5∘C−1=1.2 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1} and γ\gamma for gasoline =9.5×10−4∘C−1=9.5 \times 10^{-4}{ }^{\circ} \mathrm{C}^{-1}.
View answer and explanation
Correct option: A
1.37 litre
Option A (1.37 litre) is correct because it is calculated by finding the difference between the change in volume of gasoline and the change in volume of the steel tank due to thermal expansion.
9 Easy
9 of 553
Remembering +4 | -1
On Which of the following scales of temperature, the temperature is never negative
View answer and explanation
Correct option: D
Kelvin
Option D (Kelvin) is correct because the Kelvin scale starts at absolute zero, and all temperatures are positive relative to that.
10 Medium
10 of 553
Application +4 | -1
One litre glass flask contains some mercury. It is found that at different temperatures the volume of air inside the flask remains the same. What is the volume of mercury in this flask if coefficient of linear expansion of glass is 9×10−6/∘C9 \times {10^{ - 6}}/^\circ C while volume expansion of mercury is 1.8×10−4/∘C.1.8 \times {10^{ - 4}}/^\circ C.
View answer and explanation
Correct option: C
150 cc
Option C (150 cc) is correct because it is the volume of mercury calculated using the condition that the volume of air remains the same.
11 Medium
11 of 553
Application +4 | -1
A body at 500C{50^0}C cools in a surroundings maintained at 300C{30^0}C the temperature at which the rate of cooling is half that of the beginning is
View answer and explanation
Correct option: C
400C{40^0}C
Option C (400C{40^0}C) is correct because it is derived from Newton's law of cooling, where the rate of cooling is proportional to the temperature difference.
12 Medium
12 of 553
Understanding +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion (A) When a rod lying freely is heated, no thermal stress is developed in it.
Reason (R) On heating, the length of rod increases.
In the light of the above statements, choose the correct answer from the options given below
View answer and explanation
Correct option: A
Both A and R are true but R is not the correct explanation of A.
Option A is correct because while heating a rod increases its length, thermal stress only develops if the rod is constrained.
13 Medium
13 of 553
Remembering +4 | -1
The reflectance and emittance of a perfectly black body are respectively
View answer and explanation
Correct option: A
0, 1
Option A (0, 1) is correct because a perfectly black body absorbs all incident radiation (reflectance = 0) and emits radiation perfectly (emittance = 1).
14 Medium
14 of 553
Understanding +4 | -1
The quantity PVKT\frac{P V}{K T} represents:
View answer and explanation
Correct option: D
Number of molecules in the gas
Option D (Number of molecules in the gas) is correct because using the ideal gas law, PV = nRT, and R = N_A * K, we can derive PV/KT = nN_A, which represents the number of molecules.
15 Medium
15 of 553
Application +4 | -1
An amount of water of mass 20 g at 00C{0^0}C is mixed with 40 g of water 100C{10^0}C final temperature of the mixture
View answer and explanation
Correct option: D
6.660C{6.66^0}C
Option D (6.660C{6.66^0}C) is correct because it represents the final temperature calculated using the principle of heat exchange between the two water masses.
16 Medium
16 of 553
Understanding +4 | -1
On a clear sunny day, an object at temperature T is placed on the top of a high mountain. An identical object at the same temperature is placed at the foot of mountain. If both the objects are exposed to sun-rays for two hours in an identical manner, the object at the top of the mountain will register a temperature
View answer and explanation
Correct option: B
Lower than the object at the foot
Option B is correct because the object at the top of the mountain will generally register a lower temperature due to factors like thinner air, more shadows, and less direct sunlight.
17 Medium
17 of 553
Remembering +4 | -1
Psychrometer is used to measure
View answer and explanation
Correct option: A
Relative humidity
Option A (Relative humidity) is correct because a psychrometer measures relative humidity by comparing the readings of a dry-bulb thermometer and a wet-bulb thermometer.
18 Medium
18 of 553
Understanding +4 | -1
The specific heat capacity of a substance depends on which of following and why?
View answer and explanation
Correct option: D
The material of the substance
Option D (The material of the substance) is correct because specific heat capacity is an intrinsic property of a substance, determined by its molecular structure and composition.
19 Medium
19 of 553
Application +4 | -1
A normal diet furnishes 2000 kcal2000 \mathrm{~kcal} to a 60 kg60 \mathrm{~kg} person in a day. If this energy was used to heat the person with no losses to the surroundings, how much would the person's temperature increase? The specific heat of the human body =0.83 cal g−1∘C−1=0.83 \mathrm{~cal} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}^{-1}.
View answer and explanation
Correct option: A
40.16∘C40.16^{\circ} \mathrm{C}
Option A (40.16∘C40.16^{\circ} \mathrm{C}) is correct because it is calculated using the formula ΔT=Qmc\Delta T = \frac{Q}{mc}, where Q is the heat energy, m is the mass, and c is the specific heat.
20 Medium
20 of 553
Remembering +4 | -1
Pure substance would freeze or solidify at its:
View answer and explanation
Correct option: A
Melting Point
Option A (Melting Point) is correct because freezing and melting points are the same temperature for a pure substance.
21 Medium
21 of 553
Remembering +4 | -1
Which of the following law states that "good absorbers of heat are good emitters"?
View answer and explanation
Correct option: B
Kirchhoff’s law
Option B (Kirchhoff’s law) is correct because it directly states that good absorbers of heat are good emitters.
22 Medium
22 of 553
Application +4 | -1
Compare the rate of loss of heat from a metal sphere of temperature 827∘C827^{\circ} \mathrm{C}, with the rate of loss of heat from the same sphere at 427∘C427^{\circ} \mathrm{C}, if the temperature of surroundings is 27∘C27^{\circ} \mathrm{C}.
View answer and explanation
Correct option: A
6.276:16.276: 1
Option A (6.276:16.276: 1) is correct because it is calculated using the Stefan-Boltzmann law of radiation.
23 Medium
23 of 553
Application +4 | -1
The ends of 2 different materials with their thermal conductivities, radii of cross section and length all in the ratio of 1  :21\;:2 maintained at temperature difference. If the rate of the flow of heat in the longer rod is 4 cals−1{\mathrm{s}^{ - 1}}, that in the shorter rod in cals−1{\mathrm{s}^{ - 1}} will be
View answer and explanation
Correct option: A
1
Option A (1) is correct because the rate of heat flow is directly proportional to thermal conductivity and area, and inversely proportional to length. Considering the ratios, the heat flow in the shorter rod is 1 cal/s.
24 Medium
24 of 553
Application +4 | -1
The temperature of a thin uniform rod increases by Δt\Delta t . If moment of inertia I about an axis perpendicular to its length then its moment of inertia increases by
View answer and explanation
Correct option: C
2αI Δt2\alpha I\,\Delta t
Option C (2αI Δt2\alpha I\,\Delta t) is correct because the moment of inertia increases proportionally to the square of the length, and the length increases linearly with temperature.
25 Medium
25 of 553
Application +4 | -1
The quantities of heat required to raise the temperatures of two copper spheres of radii r1andr2(r1=1.5r2){r_1}\mathrm{and}{r_2}\left( {{r_1} = 1.5{r_2}} \right) through 1 K are in the ratio of
View answer and explanation
Correct option: C
94\frac{9}{4}
Option C (94\frac{{9}}{{4}}) is correct because the heat required is proportional to the volume (and thus the cube of the radius), but since the temperature change is the same, it simplifies to the ratio of the volumes, which is the cube of the ratio of the radii.
26 Medium
26 of 553
Remembering +4 | -1
Newton’s law of cooling holds good only, if the temperature difference between the body and the surroundings is
View answer and explanation
Correct option: A
Less than 100C{10^0}C
Option A (Less than 100C{10^0}C) is correct because Newton's Law of Cooling is an approximation that works best when the temperature difference is small.
27 Medium
27 of 553
Remembering +4 | -1
Amount of energy required to change liquid to gas and vice versa without any change in temperature is termed as:
View answer and explanation
Correct option: D
Latent heat of vaporization
Option D (Latent heat of vaporization) is correct because the latent heat of vaporization is the energy required to change a substance from a liquid to a gas (or vice versa) at a constant temperature.
28 Medium
28 of 553
Understanding +4 | -1
Statement 1: Specific heat of a substance during change of state is infinite.
Statement 2: During change of state ΔQ=mL\Delta Q=m L, specific heat does not come in.
View answer and explanation
Correct option: A
Statement 1 is true and statement 2 is true
Statement 1 is true because during a change of state, the temperature remains constant, leading to infinite specific heat. Statement 2 is also true as the heat involved is given by Q=mLQ = mL, independent of specific heat.
29 Easy
29 of 553
Application +4 | -1
A wire of cross sectional area 4 mm24\,m{m^2} is fixed between two points at 30∘C.Y=2×1011pa{30^ \circ }C.Y = 2 \times {10^{11}}pa and α=10−5/  ∘C\alpha = {10^{ - 5}}/\,{\,^ \circ }C ; When the temperature falls to 20∘C{20^ \circ }C , the tension in the string in (newton) is
View answer and explanation
Correct option: C
80
Option D (80) is correct because it is the tension calculated using the formula involving Young's modulus, area, coefficient of linear expansion, and temperature difference.
30 Medium
30 of 553
Analyzing +4 | -1
On heating a liquid of coefficient of cubical expansion γ\gamma in a container having coefficient of linear expansion γ/3, the level of liquid in the container will
View answer and explanation
Correct option: C
Will remain almost stationary
Option C (Will remain almost stationary) is correct because if the cubical expansion of the liquid equals the cubical expansion of the container, the liquid level remains constant.
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Key Takeaways

  • ✓ This set contains 553 single-correct-answer MCQs on THERMAL PROPERTIES OF MATTER.
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