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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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241 Medium
241 of 451
Understanding +4 | -1
Two equal and opposite forces act on a rigid body at a certain distance. Then
View answer and explanation
Correct option: B
the body will rotate about its centre of mass
Option the body will rotate about its centre of mass is correct because two equal and opposite forces acting at a distance create a torque, causing rotation about the center of mass.
242 Medium
242 of 451
Application +4 | -1
A projectile of mass 1 kg1 \mathrm{~kg} is projected with a speed of 10 m/s10 \mathrm{~m} / \mathrm{s} at an angle of 60∘60^{\circ} from the horizontal when projectile is at its highest point, its magnitude of angular momentum (about point of projection)
View answer and explanation
Correct option: B
754Nm/s\frac{75}{4} \mathrm{Nm} / \mathrm{s}
Option B (754Nm/s\frac{75}{4} \mathrm{Nm} / \mathrm{s}) is correct because it is calculated by finding the angular momentum at the highest point using the horizontal velocity and maximum height.
243 Medium
243 of 451
Application +4 | -1
A car wheel is rotated to uniform angular acceleration about its axis. Initially its angular velocity is zero. It rotates through an angle θ1{\mathrm{\theta }_1} in the first 2 s , in the next 2 s, it rotates through an additional angle θ2{\mathrm{\theta }_2}, the ratio of θ2θ1\frac{{{\mathrm{\theta }_2}}}{{{\mathrm{\theta }_1}}} is
View answer and explanation
Correct option: C
3
Option C (3) is correct because the angle rotated is proportional to the square of the time, given uniform angular acceleration.
244 Medium
244 of 451
Application +4 | -1
Assume the earth's orbit around the sun as circular and the distance between their centre as D\mathrm{D}. Mass of the earth is M\mathrm{M} and its radius is R\mathrm{R}. If earth has an angular velocity ω0\omega_0 with respect to its centre and ω\omega with respect to the centre of the sun, the total kinetic energy of earth is
View answer and explanation
Correct option: B
MR2ω025[1+52(DωRω0)2]\frac{\mathrm{MR}^2 \omega_0^2}{5}\left[1+\frac{5}{2}\left(\frac{\mathrm{D} \omega}{\mathrm{R} \omega_0}\right)^2\right]
Option B (MR2ω025[1+52(DωRω0)2]\frac{{\mathrm{{MR}}^2 \omega_0^2}}{{5}}\left[1+\frac{{5}}{{2}}\left(\frac{{\mathrm{{D}} \omega}}{{\mathrm{{R}} \omega_0}}\right)^2\right]) is correct because it is derived from the sum of the rotational kinetic energy about its center and the translational kinetic energy due to its orbit around the sun.
245 Medium
245 of 451
Analyzing +4 | -1
STATEMENT-1: If there is no external torque on a body about its center of mass, then the velocity of the center of mass remains constant.

STATEMENT-2: The linear momentum of an isolated system remains constant.
View answer and explanation
Correct option: D
Statement- 1 is False, Statement-2 is True
Option D (Both A and R are correct and R is the correct explanation of A) is correct because the change in phase difference is directly caused by the difference in wavelengths in different media.
246 Medium
246 of 451
Application +4 | -1
Two uniform rods AA and BB of lengths 5 m5 {~m} and 3 m3{~m} are placed end to end. If their linear densities are 3 kg/m3 {~kg} / {m} and 2 kg/m2 {~kg} / {m}, the position of their centre of mass from their interface is
View answer and explanation
Correct option: C
19/14 m19 / 14 {~m} on the side of heavier rod
Option C (19/14 m19 / 14 {~m} on the side of heavier rod) is correct because it's the calculated center of mass position relative to the interface.
247 Medium
247 of 451
Application +4 | -1
A flywheel rotates with uniform angular acceleration of 2πrad/s22 \pi {rad} / {s}^2. Its initial angular velocity is 20πrad/s20 \pi {rad} / {s}. What are the total number of rotations made in 20 s20 {~s} ?
View answer and explanation
Correct option: C
400
Option C (400) is correct because the total number of rotations is calculated using the kinematic equation for angular displacement and then dividing by 2π2\pi.
248 Medium
248 of 451
Analyzing +4 | -1
Statement-1: If the centre of mass of a system is the origin then the total mass to the right of origin is same as total mass to left of origin.
Statement-2: xcm=ΣmixiΣmix_{\mathrm{cm}}=\frac{\Sigma_{m_i x_i}}{\Sigma_{m_i}}
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because Statement-1 is false (it's about the sum of m_i*x_i, not total mass), and Statement-2 is true (it's the correct formula for the center of mass).
249 Medium
249 of 451
Understanding +4 | -1
(A): If body or a system has neither translational nor rotational motion then it is in complete mechanical equilibrium.
(R): A body or system is said to be in mechanical equilibrium when net force and net torque acting on the body are zero.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because both the assertion and reason are true, and the reason correctly explains why a body is in complete mechanical equilibrium when it has neither translational nor rotational motion.
250 Medium
250 of 451
Application +4 | -1
Given that force (5i^+7j^−3k^)N(5 \hat{i}+7 \hat{j}-3 \hat{k}) \mathrm{N} acts on a particle at position (i^+j^−k^)m(\hat{i}+\hat{j}-\hat{k}) \mathrm{m}. Find torque of this force on the particle about origin.
View answer and explanation
Correct option: A
4i^−2j^+2k^4 \hat{i}-2 \hat{j}+2 \hat{k}
Option A (4i^−2j^+2k^4 \hat{i}-2 \hat{j}+2 \hat{k}) is correct because it results from the correct cross product calculation of the position vector and the force vector.
251 Medium
251 of 451
Understanding +4 | -1
A non-zero external force acts on a systems of particles. The velocity and acceleration of the centre of mass are found to be v0 and a0{v_0}\,and\,{a_0} at an instant t. It is possible that
View answer and explanation
Correct option: B
v0=0,a0≠0{v_0} = 0,{a_0} \ne 0
Option B (v0=0,a0≠0{v_0} = 0,{a_0} \ne 0) is correct because a non-zero external force implies a non-zero acceleration of the center of mass, but the velocity at a particular instant can be zero.
252 Medium
252 of 451
Application +4 | -1
Two particles of equal mass have velocities v1=4i^ and v2=4j^ ms−1{v_1} = 4\hat i\,and\,{v_2} = 4\hat j\,m{s^{ - 1}}. First particle has an acceleration a1=(5i^+5j^)ms−2{a_1} = \left( {5\hat i + 5\hat j} \right)m{s^{ - 2}} , while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of
View answer and explanation
Correct option: A
Straight line
Option A (Straight line) is correct because the center of mass has a constant acceleration, resulting in a straight-line path.
253 Medium
253 of 451
Understanding +4 | -1
When no external torque acts on a rotating system,
View answer and explanation
Correct option: D
Its rotational kinetic energy is inversely proportional to moment of inertia
Option D (Its rotational kinetic energy is inversely proportional to moment of inertia) is correct because when no external torque acts, angular momentum is conserved, and kinetic energy is inversely proportional to the moment of inertia.
254 Medium
254 of 451
Understanding +4 | -1
Where will be the centre of mass on combining two masses m and (M > m)
View answer and explanation
Correct option: B
Towards M
Option B is correct because the center of mass is always closer to the heavier mass.
255 Medium
255 of 451
Analyzing +4 | -1
Assertion: Practically a body rolling on a surface will loose its complete K.E.
Reason: Friction will convert its K.E. into P.E. of atoms.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because rolling motion eventually ceases due to friction converting kinetic energy into internal energy (heat) of the atoms in the surfaces.
256 Medium
256 of 451
Application +4 | -1
A rod of mass mm and length ll rotates about an axis passing through its end and perpendicular to its length. If its angular velocity it decreased from 4ω4\omega to 2ω2\omega in 3 seconds the torque applied on it
View answer and explanation
Correct option: C
2nl2ω9\frac{{2n{l^2}\omega }}{9}
Option D (ml2ω9\frac{{m{l^2}\omega }}{9}) is incorrect, the correct answer is C (2ml2ω9\frac{{2m{l^2}\omega }}{9}). The torque is calculated using the moment of inertia and angular acceleration.
257 Medium
257 of 451
Analyzing +4 | -1
Two solid cylinders P and Q of same mass and same radius start rolling down a fixed inclined plane from the same height at the same time. Cylinder P has most of its mass concentrated near its surface, while Q has most of its mass concentrated near the axis. Which statement (s) is (are) correct
View answer and explanation
Correct option: D
Cylinder Q reaches the ground with larger angular speed
Option D (Cylinder Q reaches the ground with larger angular speed) is correct because cylinder Q has a smaller moment of inertia, leading to a larger angular speed at the bottom of the incline.
258 Medium
258 of 451
Understanding +4 | -1
(A): When a rigid body rotates there is always a fixed axis or a fix point about which it has to perform the rotation.
(R): In a pure rotation different particle in a rigid body has different linear velocity.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B (Both (A) and (R) are true and (R) is not the correct explanation of (A)) is correct because both the assertion and reason are true, but the reason doesn't explain why a rigid body rotates about a fixed axis.
259 Medium
259 of 451
Application +4 | -1
The distance b/w the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1A01.1{A^0}. Given mass of carbon atom is 12.a.m.u., and mass of oxygen atom is 16.a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule
View answer and explanation
Correct option: C
0.63A00.63{A^0} from the carbon atom
Option C (0.63A00.63{A^0} from the carbon atom) is correct because the center of mass is calculated based on the masses and distances of the atoms.
260 Medium
260 of 451
Application +4 | -1
The centre of mass of a system of three particles of masses 1g,2g and 3g is taken as the origin of a coordinate system. The position vector of a fourth particle of mass 4g such that the centre of mass of the four particle system lies at the point (1, 2, 3) is α(i^+2j^+3k^)\alpha \left( {\hat i + 2\hat j + 3\hat k} \right), where α\alpha is a constant. The value of α\alpha is
View answer and explanation
Correct option: B
52\frac{5}{2}
Option B (5/2) is correct because it's the value of α that places the center of mass of the four-particle system at the specified coordinates (1, 2, 3).
261 Medium
261 of 451
Application +4 | -1
Four identical spheres each of mass M and radius 10 cm each are placed on a horizontal surface touching one another so that their centres are located at the corners of a square of side 20 cm. What is the distance of their centre of mass from centre of any sphere?
View answer and explanation
Correct option: D
102 cm10\sqrt 2 \,cm
Option D (102 cm10\sqrt 2 \,cm) is correct because it is calculated using the center of mass formula for a system of particles.
262 Medium
262 of 451
Understanding +4 | -1
Assertion (A): Angular speed, linear speed as Kinetic energy change with time but angular momentum remains constant for a planet orbiting the sun.

Reason (R): Angular momentum is constant as no torque acts on the planet.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are true and R\mathrm{R} is a correct explanation for A\mathrm{A}
Option A (Both A\mathrm{A} and R\mathrm{R} are true and R\mathrm{R} is a correct explanation for A\mathrm{A}) is correct because angular momentum conservation explains the changes in speed and kinetic energy.
263 Medium
263 of 451
Analyzing +4 | -1
Assertion: At the centre of earth, a body has centre of mass, but no centre of gravity.
Reason: Acceleration due to gravity is zero at the centre of earth.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the assertion and reason are both true, and the reason correctly explains why a body at the Earth's center has a center of mass but no center of gravity.
264 Medium
264 of 451
Application +4 | -1
The moment of inertia of a body is I and its coefficient of linear expansion is α\alpha if temperature of body rises by a small amount ΔT\Delta \mathrm{T}. Then change in moment of inertia about the same axis
View answer and explanation
Correct option: B
2αIΔT2 \alpha I \Delta \mathrm{T}
Option B (2αIΔT2 \alpha I \Delta \mathrm{T}) is correct because the change in moment of inertia is proportional to the coefficient of linear expansion, the moment of inertia, and the change in temperature.
265 Medium
265 of 451
Remembering +4 | -1
Angular momentum LL of body with mass moment of inertia II and angular velocity ω\omega rad / sec is equal to
View answer and explanation
Correct option: C
IωI\omega
Option A (Nuclear forces are short ranging and charge dependent) is correct because nuclear forces are short-range but charge-independent, not charge-dependent.
266 Medium
266 of 451
Analyzing +4 | -1
Assertion (A): If the moment of inertia of a non-uniform thin circular ring is same about two different axes parallel to each other and lying in the plane of ring, then both the axis can be at same distance from geometrical centre of the ring.
Reason (R): From parallel axis theorem I=Icm+md2,I=I_{\mathrm{cm}}+{md}^2, (where terms have usual meaning). Moment of inertia of a body about two axes parallel to each other and at a same distance from centre of mass of the body is same.
View answer and explanation
Correct option: A
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Option A (Both (A) & (R) are true and the (R) is the correct explanation of the (A)) is correct because the parallel axis theorem explains why equal distances from the center of mass result in equal moments of inertia.
267 Medium
267 of 451
Understanding +4 | -1
Let IAI_A and IBI_B be the moments of inertia of two solid cylinders of identical geometrical shape and size about their axes, the first made of aluminium and the second of iron.
View answer and explanation
Correct option: A
IA<IBI_A < I_B
Option A (IA<IBI_A < I_B) is correct because iron has a higher density than aluminum, resulting in a higher mass and thus a higher moment of inertia for the same shape and size.
268 Medium
268 of 451
Understanding +4 | -1
S-I: Centre of mass is that fixed point of a system of particles or a rigid body with in the boundaries or a rigid body with in the boundaries of the system where the entire mass is concentrated.
S-II: Center of gravity of a body is the point through which the whole weight of the body acts.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the center of mass is the point where the entire mass is considered concentrated, and the center of gravity is the point where the entire weight acts.
269 Medium
269 of 451
Understanding +4 | -1
A thin circular disc of mass MM and radius RR is rotating about an axis passing through centre of mass and perpendicular to plane of disc with constant angular velocity ω\omega. The angular momentum of the disc about same axis is :
View answer and explanation
Correct option: B
12MR2ω\frac{1}{2} \mathrm{MR}^2 \omega
Option B (12MR2ω\frac{1}{2} \mathrm{MR}^2 \omega) is correct because it is the correct formula for the angular momentum of a thin circular disc rotating about an axis through its center and perpendicular to the plane.
270 Medium
270 of 451
Analyzing +4 | -1
Assertion: A sharp needle when balanced on a edge falls even under a small disturbance.
Reason: Small disturbance causes torque in the same direction as that of angular displacement.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
The correct answer is A because a small disturbance on a sharp needle creates a torque in the direction of angular displacement, causing it to fall.
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