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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Medium
91 of 451
Application +4 | -1
A man is standing at the edge of a circular plate which is rotating with a constant angular speed about a perpendicular axis passing through the centre. If the man walks towards the axis along the radius, its angular velocity
View answer and explanation
Correct option: C
Increases
Option C (Increases) is correct because as the man walks towards the axis, the moment of inertia decreases, and angular velocity increases to conserve angular momentum.
92 Medium
92 of 451
Understanding +4 | -1
A disc and a hoop (ring) of the same mass and size roll down an inclined plane simultaneously. The object which reaches the bottom of the incline first is
View answer and explanation
Correct option: B
disc
Option B (disc) is correct because the disc has a lower moment of inertia, leading to a higher acceleration down the incline.
93 Medium
93 of 451
Understanding +4 | -1
If solid sphere and solid cylinder of same radius and density about their own axis, the moment of inertia will be greater for (L = R)
View answer and explanation
Correct option: A
solid sphere
Option A (solid sphere) is correct because for the same mass, the solid sphere has a larger moment of inertia about its own axis compared to a solid cylinder of equal radius and length.
94 Medium
94 of 451
Understanding +4 | -1
S-I: Radius of gyration of body is a variable quantity.
S-II: The radius of gyration of a body about an axis of rotation may be defined as the root mean square distance of the particles from the axis of rotation.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the radius of gyration is variable and depends on the axis of rotation, and it is defined as the root mean square distance of the particles from the axis of rotation.
95 Medium
95 of 451
Understanding +4 | -1
A gymnast takes turns with her arms & legs stretched. When she pulls her arms and legs in
View answer and explanation
Correct option: C
the angular velocity stays constant
Option B (the moment of inertia decreases) is correct because pulling arms and legs inward reduces the distance of mass from the axis of rotation, decreasing the moment of inertia.
96 Medium
96 of 451
Remembering +4 | -1
Which of the following relation is correct? (Where symbol have their usual meanings)
View answer and explanation
Correct option: B
τ⃗=r⃗×F⃗\vec{\tau}=\vec{r} \times \vec{F}
Option B (τ⃗=r⃗×F⃗\vec{\tau}=\vec{r} \times \vec{F}) is correct because the torque is defined as the cross product of the position vector and the force vector.
97 Medium
97 of 451
Analyzing +4 | -1
S-I: In rolling, all points of a rigid body have the same linear speed.
S-II: The rotational motion does not affect the linear velocity of rigid body.
View answer and explanation
Correct option: D
Both S-I and S-II are incorrect
Option D (Both S-I and S-II are incorrect) is correct because in rolling motion, different points have different linear speeds, and rotational motion directly affects the linear velocity of points on the rigid body.
98 Medium
98 of 451
Analyzing +4 | -1
Consider the following two statements

a. Among a given set of axis for a rigid body, the moment of inertia is always minimum about the one passing through the center of mass.

b. Perpendicular axis theorem for moment of inertia would be applicable for a solid sphere.

The correct statement(s) is/are
View answer and explanation
Correct option: D
Neither a nor b
Option D (Neither a nor b) is correct. Statement a is false because it requires parallel axes, and statement b is false because the perpendicular axis theorem applies only to planar bodies.
99 Medium
99 of 451
Application +4 | -1
A body is rotating with angular velocity 20 rad/s. If
its kinetic energy is 400 J, then its moment of
inertia is
View answer and explanation
Correct option: A
2 kg m22\,kg\,{m^2}
Option A (2 kg m22\,kg\,{m^2}) is correct because the moment of inertia is calculated using the formula K.E=12Iω2K.E = \frac{1}{2}I\omega^2.
100 Medium
100 of 451
Application +4 | -1
If a solid sphere is rolling the ratio of its rotational energy to the total kinetic energy is given by :-
View answer and explanation
Correct option: D
2:72: 7
Option D (2:72: 7) is correct because the ratio of rotational kinetic energy to total kinetic energy for a rolling solid sphere is 2/7.
101 Medium
101 of 451
Application +4 | -1
The ratio of rotational and translatory kinetic energies of a sphere is
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (25\frac{2}{5}) is correct because the ratio of rotational to translational kinetic energy for a sphere is Iω2mv2\frac{I \omega^2}{mv^2} which simplifies to 25\frac{2}{5} for a solid sphere.
102 Medium
102 of 451
Application +4 | -1
The torque of a force F=2i^−3j^+5k^\mathbf{F}=2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+5 \hat{\mathbf{k}} acting at a point whose position vector r=3i^−3j^+5k^\mathbf{r}=3 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+5 \hat{\mathbf{k}} about the origin is
View answer and explanation
Correct option: C
−5j^−3k^-5 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}
The correct answer is C (−5j^−3k^-5 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}) because the torque is calculated by taking the cross product of the position vector and the force vector.
103 Medium
103 of 451
Application +4 | -1
The angular speed of a body changes from ω1\omega_1 to ω2\omega_2 without applying a torque but due to change in its moment of inertia. The ratio of radii of gyration in the two cases is
View answer and explanation
Correct option: A
ω2:ω1\sqrt{\omega_2}: \sqrt{\omega_1}
Option A (ω2:ω1\sqrt{\omega_2}: \sqrt{\omega_1}) is correct because angular momentum is conserved, and the radius of gyration is inversely proportional to the square root of the angular speed.
104 Medium
104 of 451
Understanding +4 | -1
Statement-I: Gravitational torque due to weight of a body about its centre of gravity is zero.

Statement-II: In the absence of external torque the angular momentum of a body changes.
View answer and explanation
Correct option: A
Statement-I is true and Statement-II is false
Option A (Statement-I is true and Statement-II is false) is correct because gravitational torque about the center of gravity is zero, and angular momentum is conserved in the absence of external torque.
105 Medium
105 of 451
Application +4 | -1
Two masses of 6 and 2 units are at positions (6i^−7j^)(6 \hat{{i}}-7 \hat{{j}}) and (2i^+5j^−8k^)(2 \hat{{i}}+{5} \hat{{j}}-{8} \hat{{k}}) respectively. The co-ordinates of the centre-of-mass (c.m.) are
View answer and explanation
Correct option: C
(5,−4,−2)(5,-4,-2)
Option C ((5,−4,−2)(5,-4,-2)) is correct because the center of mass coordinates are calculated by the formula x⃗cm=m1r⃗1+m2r⃗2m1+m2\vec{x}_{cm} = \frac{{m_1 \vec{r}_1 + m_2 \vec{r}_2}}{{m_1 + m_2}}.
106 Medium
106 of 451
Understanding +4 | -1
Assertion: When a body rolls down an inclined plane it has both kinetic and potential energy.
Reason: The rolling body follow the conservation law of mechanical energy.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A (If both assertion and reason are true and reason is the correct explanation of assertion) is correct because a rolling body possesses both kinetic and potential energy, and the conservation of mechanical energy explains the energy transformation during rolling.
107 Medium
107 of 451
Application +4 | -1
A solid body rotates about a stationary axis with an angular retardation α=kω\alpha=k \sqrt{\omega} where ω\omega is the angular velocity of body. Find time after which body will come to rest if at t=0t=0 angular velocity of body was ω0\omega_0.
View answer and explanation
Correct option: D
t=2ω0kt=\frac{2 \sqrt{\omega_0}}{k}
Option D (t=2ω0kt=\frac{2 \sqrt{\omega_0}}{k}) is correct because it is derived by integrating the given angular retardation equation to find the time when the angular velocity becomes zero.
108 Medium
108 of 451
Analyzing +4 | -1
Out of the following bodies of same mass, which one will have maximum moment of inertia about an axis passing through its center of gravity and perpendicular to its plane?
View answer and explanation
Correct option: C
Square frame of sides 2r2r
Option C (Square frame of sides 2r2r) is correct because, for the same mass, its mass is distributed farthest from the axis of rotation, resulting in the highest moment of inertia.
109 Medium
109 of 451
Application +4 | -1
The moment of inertia of a uniform circular disc of radius RR and mass MM about an axis passing from the edge of the disc and normal to the disc is:
View answer and explanation
Correct option: C
32MR2\frac{3}{2} {M} {R}^2
Option C (32MR2\frac{3}{2}MR^2) is correct because it is calculated using the parallel axis theorem.
110 Medium
110 of 451
Analyzing +4 | -1
A uniform rod is placed vertically on a smooth surface and then released then,
View answer and explanation
Correct option: A
the centre of rod follows straight line path
Option A (the centre of rod follows straight line path) is correct because there is no external horizontal force, so the horizontal component of the center of mass's velocity remains constant (zero).
111 Medium
111 of 451
Application +4 | -1
A rigid body rotates about a fixed axis such that its angular velocity (ω)(\omega) depends on θ\theta as ω=kθ\omega=\frac{k}{\theta}, where kk is a positive constant. At t=0,θ=πt=0, \theta=\pi, then the θ\theta is related to time (t)(t) as
View answer and explanation
Correct option: B
θ=(2kt+π2)\theta=\sqrt{\left(2 k t+\pi^2\right)}
Option B (θ=(2kt+π2)\theta=\sqrt{\left(2 k t+\pi^2\right)}) is correct because it is the solution to the differential equation ω=dθdt=kθ\omega = \frac{{d\theta}}{{dt}} = \frac{k}{\theta} with the initial condition θ(0)=π\theta(0) = \pi.
112 Medium
112 of 451
Understanding +4 | -1
(A): The total kinetic energy of rolling solid sphere is the sum of translational and rotational kinetic energies.
(R): For all solid bodies total kinetic cnergy is always twice translational kinetic energy.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C ((A) is true but (R) is false) is correct because the total kinetic energy of a rolling sphere is the sum of translational and rotational energies, but it's not always twice the translational energy.
113 Medium
113 of 451
Analyzing +4 | -1
Assertion(A): If a particle moves with a constant velocity, then angular momentum of this particle about any point remains constant.

Reason(R): Angular momentum has the units of Planck's constant.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B is correct because both Assertion and Reason are correct, but the Reason is not the correct explanation of Assertion. Angular momentum is constant when velocity is constant, and angular momentum has the units of Planck's constant.
114 Medium
114 of 451
Understanding +4 | -1
The conservation of angular momentum demands that
View answer and explanation
Correct option: B
the external torque on the system must be zero
The correct answer is that the external torque on the system must be zero because conservation of angular momentum requires zero net external torque.
115 Medium
115 of 451
Analyzing +4 | -1
Assertion: Torque on a body can be zero even if there is a net force on it.

Reason: Torque and force on a body are always perpendicular.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because while both statements are true, the reason doesn't explain why torque can be zero with a net force.
116 Medium
116 of 451
Application +4 | -1
An automobile engine develops 105 W{10^5}\,\mathrm{W} power when rotating at an angular speed of 900 rad/minute. The instantaneous torque delivered by the engine is
View answer and explanation
Correct option: C
23×104N−m\frac{2}{3} \times {10^4}N - m
Option D (10 kHz) is correct because the carrier signal frequency must be much greater than the reciprocal of the time constant (RC) of the output circuit for proper detection.
117 Medium
117 of 451
Application +4 | -1
A wheel is subjected to uniform angular acceleration about its axis. Initially its angular velocity is zero. In the first 2 sec, it rotates through an angle θ1{\theta _1}. In the next 2 sec, it rotates through an additional angle θ2{\theta _2}. The ratio of θ2/θ1{\theta _2}/{\theta _1} is
View answer and explanation
Correct option: C
3
Option C (3) is correct because the ratio of the additional angle to the first angle is calculated using the equations of rotational motion, resulting in 3.
118 Medium
118 of 451
Application +4 | -1
A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is –
View answer and explanation
Correct option: B
27\frac{2}{7}
Option B (27\frac{2}{7}) is correct because it represents the ratio of rotational kinetic energy to the total kinetic energy of a rolling solid sphere.
119 Medium
119 of 451
Application +4 | -1
The radius of gyration of a sphere of radius RR about a certain axis is also R.R. The distance of this axis from the center of the sphere is:
View answer and explanation
Correct option: D
0.6R\sqrt{0.6} {R}
Option D (0.6R\sqrt{0.6} {R}) is correct because it is derived from the parallel axis theorem and the moment of inertia of a sphere.
120 Medium
120 of 451
Analyzing +4 | -1
A body is under the action of two equal and oppositely directed forces and the body is rotating with constant non-zero angular acceleration. Which of the following cannot be the separation between the lines of action of the forces?
View answer and explanation
Correct option: D
zero
Option D (zero) is correct because if the separation is zero, the net torque and angular acceleration will also be zero, contradicting the problem statement.
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