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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 483 questions

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91 Medium
91 of 483
Analyzing +4 | -1
A cylinder of mass mm and radius RR rolls purely over an inclined surface while moving up on it. Correct statement regarding friction acting on it is
View answer and explanation
Correct option: C
Friction is acting upward and static in nature
Option C (Friction is acting upward and static in nature) is correct because for pure rolling, the friction must be static and act upwards to provide the necessary torque for rotation.
92 Medium
92 of 483
Understanding +4 | -1
The motion of a rigid body which is not pivoted or fixed in some way is either a pure ___A___ or a combination of translation and rotation. The motion of a rigid body which is pivoted or fixed in some way is ___B___ Here, A and B refer to:
View answer and explanation
Correct option: B
Translation and rotation
Option B is correct because a rigid body's motion without a fixed point is either pure translation or a combination of translation and rotation, while motion with a fixed point is pure rotation.
93 Hard
93 of 483
Application +4 | -1
A solid cylinder of mass 4 kg and radius 8 cm is rotating about its axis at the rate of 6 rpm. The torque required to stop after 4π4 \pi revolutions is:
View answer and explanation
Correct option: D
3.2×10−5 N m3.2 \times 10^{-5} \mathrm{~N} \mathrm{~m}
Option D (3.2×10−5 N m3.2 \times 10^{-5} \mathrm{~N} \mathrm{~m}) is correct because it is calculated by finding the angular deceleration and then using τ=Iα\tau = I\alpha.
94 Medium
94 of 483
Application +4 | -1
A circular plate is rotating about its own axis at an angular velocity 100 revolution per minute. The linear velocity of a particle ‘P’ of plate at a distance 4.2 cm from axis of rotation (in m/s) is
View answer and explanation
Correct option: B
0.44
Option B (0.44) is correct because it is calculated using the formula relating linear velocity to angular velocity and radius.
95 Medium
95 of 483
Understanding +4 | -1
If a rigid body is rotating about an axis with a
constant velocity, then
View answer and explanation
Correct option: C
Velocity of all particles will be different but angular velocity will be same
Option C is correct because in a rigid body rotating with constant angular velocity, all particles have the same angular velocity, but their linear velocities vary with distance from the axis of rotation.
96 Medium
96 of 483
Application +4 | -1
Moment of inertia of a circular loop of radius R about the axis of rotation parallel to horizontal diameter at a distance R/2 from it is
View answer and explanation
Correct option: D
34MR2\frac{3}{4}M{R^2}
The correct answer is 5 because it is calculated by equating the ratio of energies of photons produced during electron transitions in a hydrogen atom.
97 Medium
97 of 483
Analyzing +4 | -1
Two uniform solid spheres having unequal masses and unequal radii are released from rest from the same height on a rough incline. If the spheres roll without slipping,
View answer and explanation
Correct option: C
Both the spheres reach the bottom together
Option C (Both the spheres reach the bottom together) is correct because the acceleration of a rolling sphere down an incline is independent of its mass and radius.
98 Medium
98 of 483
Application +4 | -1
A man is standing at the edge of a circular plate which is rotating with a constant angular speed about a perpendicular axis passing through the centre. If the man walks towards the axis along the radius, its angular velocity
View answer and explanation
Correct option: C
Increases
Option C (Increases) is correct because as the man walks towards the axis, the moment of inertia decreases, and angular velocity increases to conserve angular momentum.
99 Medium
99 of 483
Understanding +4 | -1
A disc and a hoop (ring) of the same mass and size roll down an inclined plane simultaneously. The object which reaches the bottom of the incline first is
View answer and explanation
Correct option: B
disc
Option B (disc) is correct because the disc has a lower moment of inertia, leading to a higher acceleration down the incline.
100 Medium
100 of 483
Understanding +4 | -1
If solid sphere and solid cylinder of same radius and density about their own axis, the moment of inertia will be greater for (L = R)
View answer and explanation
Correct option: A
solid sphere
Option A (solid sphere) is correct because for the same mass, the solid sphere has a larger moment of inertia about its own axis compared to a solid cylinder of equal radius and length.
101 Medium
101 of 483
Understanding +4 | -1
S-I: Radius of gyration of body is a variable quantity.
S-II: The radius of gyration of a body about an axis of rotation may be defined as the root mean square distance of the particles from the axis of rotation.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the radius of gyration is variable and depends on the axis of rotation, and it is defined as the root mean square distance of the particles from the axis of rotation.
102 Medium
102 of 483
Understanding +4 | -1
A gymnast takes turns with her arms & legs stretched. When she pulls her arms and legs in
View answer and explanation
Correct option: C
the angular velocity stays constant
Option B (the moment of inertia decreases) is correct because pulling arms and legs inward reduces the distance of mass from the axis of rotation, decreasing the moment of inertia.
103 Medium
103 of 483
Remembering +4 | -1
Which of the following relation is correct? (Where symbol have their usual meanings)
View answer and explanation
Correct option: B
τ⃗=r⃗×F⃗\vec{\tau}=\vec{r} \times \vec{F}
Option B (τ⃗=r⃗×F⃗\vec{\tau}=\vec{r} \times \vec{F}) is correct because the torque is defined as the cross product of the position vector and the force vector.
104 Medium
104 of 483
Analyzing +4 | -1
S-I: In rolling, all points of a rigid body have the same linear speed.
S-II: The rotational motion does not affect the linear velocity of rigid body.
View answer and explanation
Correct option: D
Both S-I and S-II are incorrect
Option D (Both S-I and S-II are incorrect) is correct because in rolling motion, different points have different linear speeds, and rotational motion directly affects the linear velocity of points on the rigid body.
105 Medium
105 of 483
Analyzing +4 | -1
Consider the following two statements

a. Among a given set of axis for a rigid body, the moment of inertia is always minimum about the one passing through the center of mass.

b. Perpendicular axis theorem for moment of inertia would be applicable for a solid sphere.

The correct statement(s) is/are
View answer and explanation
Correct option: D
Neither a nor b
Option D (Neither a nor b) is correct. Statement a is false because it requires parallel axes, and statement b is false because the perpendicular axis theorem applies only to planar bodies.
106 Medium
106 of 483
Application +4 | -1
A body is rotating with angular velocity 20 rad/s. If
its kinetic energy is 400 J, then its moment of
inertia is
View answer and explanation
Correct option: A
2 kg m22\,kg\,{m^2}
Option A (2 kg m22\,kg\,{m^2}) is correct because the moment of inertia is calculated using the formula K.E=12Iω2K.E = \frac{1}{2}I\omega^2.
107 Medium
107 of 483
Application +4 | -1
If a solid sphere is rolling the ratio of its rotational energy to the total kinetic energy is given by :-
View answer and explanation
Correct option: D
2:72: 7
Option D (2:72: 7) is correct because the ratio of rotational kinetic energy to total kinetic energy for a rolling solid sphere is 2/7.
108 Medium
108 of 483
Application +4 | -1
The ratio of rotational and translatory kinetic energies of a sphere is
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (25\frac{2}{5}) is correct because the ratio of rotational to translational kinetic energy for a sphere is Iω2mv2\frac{I \omega^2}{mv^2} which simplifies to 25\frac{2}{5} for a solid sphere.
109 Medium
109 of 483
Application +4 | -1
The torque of a force F=2i^−3j^+5k^\mathbf{F}=2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+5 \hat{\mathbf{k}} acting at a point whose position vector r=3i^−3j^+5k^\mathbf{r}=3 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+5 \hat{\mathbf{k}} about the origin is
View answer and explanation
Correct option: C
−5j^−3k^-5 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}
The correct answer is C (−5j^−3k^-5 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}) because the torque is calculated by taking the cross product of the position vector and the force vector.
110 Medium
110 of 483
Application +4 | -1
The angular speed of a body changes from ω1\omega_1 to ω2\omega_2 without applying a torque but due to change in its moment of inertia. The ratio of radii of gyration in the two cases is
View answer and explanation
Correct option: A
ω2:ω1\sqrt{\omega_2}: \sqrt{\omega_1}
Option A (ω2:ω1\sqrt{\omega_2}: \sqrt{\omega_1}) is correct because angular momentum is conserved, and the radius of gyration is inversely proportional to the square root of the angular speed.
111 Medium
111 of 483
Understanding +4 | -1
Statement-I: Gravitational torque due to weight of a body about its centre of gravity is zero.

Statement-II: In the absence of external torque the angular momentum of a body changes.
View answer and explanation
Correct option: A
Statement-I is true and Statement-II is false
Option A (Statement-I is true and Statement-II is false) is correct because gravitational torque about the center of gravity is zero, and angular momentum is conserved in the absence of external torque.
112 Medium
112 of 483
Application +4 | -1
Two masses of 6 and 2 units are at positions (6i^−7j^)(6 \hat{{i}}-7 \hat{{j}}) and (2i^+5j^−8k^)(2 \hat{{i}}+{5} \hat{{j}}-{8} \hat{{k}}) respectively. The co-ordinates of the centre-of-mass (c.m.) are
View answer and explanation
Correct option: C
(5,−4,−2)(5,-4,-2)
Option C ((5,−4,−2)(5,-4,-2)) is correct because the center of mass coordinates are calculated by the formula x⃗cm=m1r⃗1+m2r⃗2m1+m2\vec{x}_{cm} = \frac{{m_1 \vec{r}_1 + m_2 \vec{r}_2}}{{m_1 + m_2}}.
113 Medium
113 of 483
Understanding +4 | -1
Assertion: When a body rolls down an inclined plane it has both kinetic and potential energy.
Reason: The rolling body follow the conservation law of mechanical energy.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A (If both assertion and reason are true and reason is the correct explanation of assertion) is correct because a rolling body possesses both kinetic and potential energy, and the conservation of mechanical energy explains the energy transformation during rolling.
114 Medium
114 of 483
Application +4 | -1
A solid body rotates about a stationary axis with an angular retardation α=kω\alpha=k \sqrt{\omega} where ω\omega is the angular velocity of body. Find time after which body will come to rest if at t=0t=0 angular velocity of body was ω0\omega_0.
View answer and explanation
Correct option: D
t=2ω0kt=\frac{2 \sqrt{\omega_0}}{k}
Option D (t=2ω0kt=\frac{2 \sqrt{\omega_0}}{k}) is correct because it is derived by integrating the given angular retardation equation to find the time when the angular velocity becomes zero.
115 Easy
115 of 483
Application +4 | -1
A thick straight wire of length 4π m 4\pi \,m\, is fixed at its midpoint and the bent in the form of a circle. The shift in its centre of mass is
View answer and explanation
Correct option: C
2 m
Option C (2 m) is correct because the shift in the center of mass is equal to the radius of the circle formed by bending the wire.
116 Medium
116 of 483
Analyzing +4 | -1
Out of the following bodies of same mass, which one will have maximum moment of inertia about an axis passing through its center of gravity and perpendicular to its plane?
View answer and explanation
Correct option: C
Square frame of sides 2r2r
Option C (Square frame of sides 2r2r) is correct because, for the same mass, its mass is distributed farthest from the axis of rotation, resulting in the highest moment of inertia.
117 Medium
117 of 483
Application +4 | -1
The moment of inertia of a uniform circular disc of radius RR and mass MM about an axis passing from the edge of the disc and normal to the disc is:
View answer and explanation
Correct option: C
32MR2\frac{3}{2} {M} {R}^2
Option C (32MR2\frac{3}{2}MR^2) is correct because it is calculated using the parallel axis theorem.
118 Medium
118 of 483
Analyzing +4 | -1
A uniform rod is placed vertically on a smooth surface and then released then,
View answer and explanation
Correct option: A
the centre of rod follows straight line path
Option A (the centre of rod follows straight line path) is correct because there is no external horizontal force, so the horizontal component of the center of mass's velocity remains constant (zero).
119 Medium
119 of 483
Application +4 | -1
A rigid body rotates about a fixed axis such that its angular velocity (ω)(\omega) depends on θ\theta as ω=kθ\omega=\frac{k}{\theta}, where kk is a positive constant. At t=0,θ=πt=0, \theta=\pi, then the θ\theta is related to time (t)(t) as
View answer and explanation
Correct option: B
θ=(2kt+π2)\theta=\sqrt{\left(2 k t+\pi^2\right)}
Option B (θ=(2kt+π2)\theta=\sqrt{\left(2 k t+\pi^2\right)}) is correct because it is the solution to the differential equation ω=dθdt=kθ\omega = \frac{{d\theta}}{{dt}} = \frac{k}{\theta} with the initial condition θ(0)=π\theta(0) = \pi.
120 Medium
120 of 483
Understanding +4 | -1
(A): The total kinetic energy of rolling solid sphere is the sum of translational and rotational kinetic energies.
(R): For all solid bodies total kinetic cnergy is always twice translational kinetic energy.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C ((A) is true but (R) is false) is correct because the total kinetic energy of a rolling sphere is the sum of translational and rotational energies, but it's not always twice the translational energy.
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