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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 483 questions
31 Medium
31 of 483
Understanding +4 | -1
A solid sphere, a hollow sphere and a ring are released from top of an inclined plane (frictionless) so that they slide down the plane. Then maximum acceleration down the plane is for (no rolling)
View answer and explanation
Correct option: D
All same
Option D is correct because, in the absence of friction, all objects sliding down an inclined plane experience the same acceleration due to gravity.
32 Medium
32 of 483
Understanding +4 | -1
In uniform circular motion
View answer and explanation
Correct option: C
Both the angular velocity and the angular momentum stay constant
Option C (Both the angular velocity and the angular momentum stay constant) is correct because in uniform circular motion, both the magnitude and direction of angular velocity and angular momentum remain constant.
33 Easy
33 of 483
Remembering +4 | -1
Centre of mass for a uniform semi-circular ring will be at (from centre)
View answer and explanation
Correct option: A
2Rπ\frac{{2R}}{\pi }
Option A (2Rπ\frac{{2R}}{\pi }) is correct because the center of mass of a uniform semi-circular ring is located at a distance of 2Rπ\frac{{2R}}{\pi } from the center of the ring.
34 Medium
34 of 483
Application +4 | -1
A particle of mass m is circulating on a circle of radius r having angular momentum L, then the centripetal force will be
View answer and explanation
Correct option: C
L2/mr3{L^2}/m{r^3}
Option C (L2/mr3{L^2}/m{r^3}) is correct because the centripetal force can be expressed in terms of angular momentum as L2/mr3{L^2}/m{r^3}.
35 Medium
35 of 483
Application +4 | -1
Moment of inertia of a uniform circular disc about a diameter is I2\frac{I}{2}. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be
View answer and explanation
Correct option: C
3 I
Option C (3 I) is correct because the moment of inertia about a diameter is 14MR2\frac{1}{4}MR^2, and using the parallel axis theorem, the moment of inertia about an axis perpendicular to the plane and passing through a point on its rim is 32MR2\frac{3}{2}MR^2.
36 Easy
36 of 483
Application +4 | -1
The angular speed of fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration in rad/s2\mathrm{rad/}{\mathrm{s}^2} is:
View answer and explanation
Correct option: C
4 π4\,\pi
Option C (4π4\pi) is correct because it is calculated using the formula for angular acceleration, converting rpm to rad/s.
37 Medium
37 of 483
Understanding +4 | -1
The principle used by a gymnast to increase the number of somersaults, is law of conservation of
View answer and explanation
Correct option: D
Angular momentum
Option A (χd<χp<χf\chi_{\mathrm{d}} < \chi_{\mathrm{p}} < \chi_{\mathrm{f}}) is correct because diamagnetic materials have small negative susceptibility, paramagnetic materials have small positive susceptibility, and ferromagnetic materials have large positive susceptibility.
38 Medium
38 of 483
Understanding +4 | -1
Choose the correct statement about the centre of mass (CM) of a system of two particles
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Correct option: B
The CM lies on the line joining them at a point whose distance from each particle is inversely proportional to the mass of that particle
Option B (The CM lies on the line joining them at a point whose distance from each particle is inversely proportional to the mass of that particle) is correct because the center of mass position is inversely proportional to the mass of each particle.
39 Medium
39 of 483
Application +4 | -1
A straight thin uniform rod of length 4L and mass 4M is bent into a square. Its M.I about one side is
View answer and explanation
Correct option: B
53ML2\frac{5}{3}M{L^2}
Option B (53ML2\frac{5}{3}M{L^2}) is correct because it's calculated by summing the moments of inertia of each side of the square about one side.
40 Medium
40 of 483
Application +4 | -1
The motor of an engine is rotating about its axis with an angular velocity of 100 rpm100 \mathrm{~rpm}. It comes to rest in 15 s15 \mathrm{~s}, after being switched OFF. Assuming constant angular deceleration, what are the numbers of revolutions made by it before coming to rest?
View answer and explanation
Correct option: A
12.5
Option A (12.5) is correct because it is the number of revolutions calculated using the angular deceleration and initial angular velocity.
41 Medium
41 of 483
Application +4 | -1
Two bodies of masses 2 kg and 4 kg are moving with velocities 20 ms−1\mathrm{m}{\mathrm{s}^{ - 1}} and 10 ms−1\mathrm{m}{\mathrm{s}^{ - 1}} towards each other due to mutual gravitation attraction. What is the velocity of their centre of mass?
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the net external force on the system is zero, so the velocity of the center of mass remains constant.
42 Medium
42 of 483
Analyzing +4 | -1
Two identical solid cylinders run a race starting from rest at the top of an inclined plane. If one cylinder slides and the other rolls:
View answer and explanation
Correct option: A
Sliding cylinder will reach the bottom first with greater speed
Option A is correct. The sliding cylinder will reach the bottom first with greater speed because it doesn't lose energy to rotational kinetic energy.
43 Medium
43 of 483
Remembering +4 | -1
Angular momentum is conserved
View answer and explanation
Correct option: D
When external torque is absent
Option D (When external torque is absent) is correct because angular momentum is conserved when the net external torque acting on the system is zero.
44 Medium
44 of 483
Analyzing +4 | -1
Assertion: A satellite is orbiting around a planet then its angular momentum is conserved.

Reason: Linear momentum conservation leads to angular momentum conservation.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is incorrect.
Option C is correct. The assertion is true because the angular momentum of a satellite orbiting a planet is conserved due to the central force. The reason is incorrect because linear momentum is not conserved due to the continuously changing direction of velocity.
45 Medium
45 of 483
Application +4 | -1
A hollow sphere of mass 2 kg2 \mathrm{~kg} and radius 2 cm2 \mathrm{~cm} is rolling down a rough incline of inclination θ=30∘\theta=30^{\circ}. The acceleration of its centre down the incline is (g=10 m/s2)\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)
View answer and explanation
Correct option: C
3 m/s23 \mathrm{~m} / \mathrm{s}^2
Option C (3 m/s23 \mathrm{~m} / \mathrm{s}^2) is correct because it is the acceleration calculated using the formula for a hollow sphere rolling down an incline.
46 Medium
46 of 483
Application +4 | -1
A circular disc ' XX ' of radius ' RR ' made from iron plate of thickness ' tt ' has moment of inertia ' IxI_x ' about an axis passing through the centre of disc and perpendicular to its plane. Another disc ' YY ' of radius ' 3R3 R ' made from an iron plate of thickness (t3)\left(\frac{t}{3}\right) has moment of inertia ' II ', about the axis same as that of disc XX. The relation between IxI_x and IyI_y is
View answer and explanation
Correct option: D
Iy=27Ix{I}_{{y}}=27{I}_{{x}}
Option D (Iy=27Ix{I}_{{y}}=27{I}_{{x}}) is correct because the moment of inertia of disc Y is 27 times that of disc X, calculated using the formula for the moment of inertia of a disc.
47 Medium
47 of 483
Understanding +4 | -1
Assertion: If the head of a right-handed screw rotates with the body, the screw advances in the direction of the angular velocity.
Reason: For rotation about a fixed axis, the angular velocity vector lies along the axis of rotation.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because the assertion and reason are both true, and the reason correctly explains why the screw advances in the direction of the angular velocity.
48 Medium
48 of 483
Analyzing +4 | -1
A solid sphere of radius RR is placed on a smooth horizontal surface. A horizontal force ' FF ' is applied at height ' hh ' from the lowest point. For the maximum acceleration of the centre of mass, which is correct?
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Correct option: D
No relation between hh and RR
Option D is correct because the acceleration of the center of mass depends only on the applied force and the mass of the sphere, not on the height at which the force is applied since the surface is smooth.
49 Medium
49 of 483
Understanding +4 | -1
Consider the following statements and choose the correct option
I) Position vector of centre of mass of two particles of equal mass is equal to the position vector of either particle
II) Centre of mass is always at the midpoint of the line joining two particles
III) Centre of mass of a body can lie where there is no mass
View answer and explanation
Correct option: C
II and III
Option C (II and III) is correct because the center of mass is always at the midpoint of the line joining two particles of equal mass and can lie where there is no mass.
50 Medium
50 of 483
Analyzing +4 | -1
Assertion: A sphere cannot roll on a smooth inclined surface.
Reason: The motion of a rigid body which is pivoted or fixed in some way is rotation.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because the assertion and reason are both true, but the reason does not explain the assertion. A sphere cannot roll on a smooth surface because there's no friction to provide torque, and the reason correctly states the nature of rotational motion.
51 Easy
51 of 483
Application +4 | -1
If an angular momentum of a body of fixed M.I. increases by 50%50 \%, its kinetic energy of rotation increases by:
View answer and explanation
Correct option: D
125%125 \%
Option D is correct because the angular speed is determined by conservation of angular momentum.
52 Medium
52 of 483
Application +4 | -1
A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly, then
View answer and explanation
Correct option: B
its speed of rotation decreases
The correct answer is that its speed of rotation decreases because when the rod is heated, its moment of inertia increases, and angular momentum is conserved.
53 Medium
53 of 483
Understanding +4 | -1
A large number of particles are placed around the origin, each at a distance RR from the origin. The distance of the centre of mass of the system from the origin is
View answer and explanation
Correct option: B
less than or equal to RR
Option B (less than or equal to RR) is correct because the center of mass will either be at the origin (if particles are uniformly distributed) or closer to the origin than the farthest particle.
54 Medium
54 of 483
Understanding +4 | -1
A fan is moving around its axis. What will be its motion regarded as?
View answer and explanation
Correct option: D
Pure rotation
Option D (Pure rotation) is correct because the fan is rotating about a fixed axis, and there is no translational motion of the center of mass.
55 Medium
55 of 483
Understanding +4 | -1
The momentum of a system is defined
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the momentum of a system can be defined in all the ways mentioned.
56 Medium
56 of 483
Understanding +4 | -1
Assertion: For a system of particles under central force field, the total angular momentum is conserved.
Reason: The torque acting on such a system is zero.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because a central force field results in zero torque, leading to conservation of angular momentum.
57 Medium
57 of 483
Application +4 | -1
The position of particle is given by r→=i^+2j^−k^\overrightarrow r = \hat i + 2\hat j - \hat k and momentum p→=3i^+4j^−2k^.\overrightarrow p = 3\hat i + 4\hat j - 2\hat k. The angular momentum is perpendicular to
View answer and explanation
Correct option: A
x – axis
Option A (x – axis) is correct because the angular momentum is perpendicular to the x-axis, which is determined by the dot product of the angular momentum and the x-axis being zero.
58 Medium
58 of 483
Understanding +4 | -1
A particle moves in a force field given by: F⃗=r^F(r)\vec{F}=\hat{r} F(r), where r^\hat{r} is a unit vector along the position vector r⃗\vec{r}, then which is true?
View answer and explanation
Correct option: C
The angular momentum of the particle is conserved.
Option C is correct because the torque acting on the particle is zero, implying that the angular momentum of the particle is conserved.
59 Medium
59 of 483
Remembering +4 | -1
A spherical shell has mass MM and radius RR. Moment of inertia about its diameter will be
View answer and explanation
Correct option: B
23MR2\frac{2}{3}M{R^2}
Option B (23MR2\frac{2}{3}M{R^2}) is correct because the moment of inertia of a spherical shell about its diameter is given by this formula.
60 Medium
60 of 483
Analyzing +4 | -1
What happens to the centripetal acceleration of a particle, when its speed is doubled and angular velocity is halved?
View answer and explanation
Correct option: C
Remains unchanged
Option C (Remains unchanged) is correct because the centripetal acceleration remains the same when speed is doubled and angular velocity is halved.
Revision notes and key takeaways

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