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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 421-450 of 483 questions

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421 Medium
421 of 483
Analyzing +4 | -1
Assertion (A): If two different axes are at same distance from the centre of mass of a rigid body then moment of inertia of the given rigid body about both the axes will always be equal.
Reason (R): According to perpendicular axis theorem I=Icm+Md2\mathrm{I}=\mathrm{I}_{\mathrm{cm}}+\mathrm{Md}^2 where symbols have their usual meaning.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because the moment of inertia depends on the distribution of mass relative to the axis, and the parallel axis theorem is I=Icm+Md2\mathrm{I} = \mathrm{I}_{cm} + \mathrm{Md}^2, not the perpendicular axis theorem.
422 Medium
422 of 483
Application +4 | -1
A sphere of mass m and radius r rolls on a horizontal plane without slipping with the speed u. Now, if it rolls up vertically, the maximum height it would attain will be
View answer and explanation
Correct option: C
7u210g\frac{{7{u^2}}}{{10\mathrm{g}}}
Option C (7u210g\frac{{7{u^2}}}{{10\mathrm{g}}}) is correct because it is the maximum height calculated considering both translational and rotational kinetic energy.
423 Medium
423 of 483
Analyzing +4 | -1
Assertion: A shell at rest, explodes. The centre of mass of fragments moves along a straight path.
Reason: In explosion the linear momentum of the system is not conserved.
View answer and explanation
Correct option: D
If the assertion and reason both are false.
Option D (If the assertion and reason both are false) is correct because the center of mass remains at rest after the explosion, and linear momentum is conserved in the explosion.
424 Medium
424 of 483
Analyzing +4 | -1
STATEMENT-1 : Two cylinders, one hollow (metal) and the other solid (wood) with the same mass and identical dimensions are simultaneously allowed to roll without slipping down an inclined plane from the same height. The hollow cylinder will reach the bottom of the inclined plane first.

STATEMENT-2 : By the principle of conservation of energy, the total kinetic energies of both the cylinders are identical when they reach the bottom of the incline.
View answer and explanation
Correct option: D
Statement - 1 is False, Statement-2 is True
Statement - 1 is False, Statement-2 is True because the solid cylinder reaches the bottom first due to higher acceleration, and the total kinetic energies are identical due to conservation of energy.
425 Medium
425 of 483
Understanding +4 | -1
Very thin ring of radius R is rotated about its centre. It’s radius will
View answer and explanation
Correct option: A
Increase
Option A is correct because when a ring rotates, the centrifugal force causes it to expand, thus increasing its radius.
426 Medium
426 of 483
Application +4 | -1
A T shape with dimensions shown in Figure is lying on a smooth floor. A force F⃗\vec F is applied at the point PP parallel to ABAB, such that the object has only the translation motion without rotation. Find the location of PP with respect to CC
View answer and explanation
Correct option: B
43l\frac{4}{3}l
Option B (43l\frac{4}{3}l) is correct because the force must be applied at the center of mass to avoid rotation, and the center of mass is located at a distance of 43l\frac{4}{3}l from point C.
427 Medium
427 of 483
Understanding +4 | -1
If the torque is zero, what will be the value of angular momentum?
View answer and explanation
Correct option: C
Constant on both magnitude and direction
Option C is correct because if the torque is zero, the angular momentum is conserved, meaning it remains constant in both magnitude and direction.
428 Medium
428 of 483
Analyzing +4 | -1
Assertion: The centre of mass of an electron and proton, when released moves faster towards proton.
Reason: Proton is lighter than electron.
View answer and explanation
Correct option: D
If the assertion and reason both are false.
The correct answer is D because both the assertion and the reason are false. The center of mass remains at rest, and the proton is heavier than the electron.
429 Medium
429 of 483
Understanding +4 | -1
Which relation is not correct of the following?
View answer and explanation
Correct option: C
Moment of inertia == Torque ×\times angular acceleration
Option C (Moment of inertia == Torque ×\times angular acceleration) is correct because it is dimensionally incorrect; the correct relation is Torque = Moment of inertia ×\times angular acceleration.
430 Medium
430 of 483
Understanding +4 | -1
Two balls are thrown simultaneously in air. The acceleration of the centre of mass of the two balls in air
View answer and explanation
Correct option: D
Is equal to gg
Option D (Is equal to gg) is correct because the only external force acting on the balls is gravity, so the center of mass accelerates at gg.
431 Medium
431 of 483
Application +4 | -1
When a motor cyclist takes a UU-turn in 4 s what is the average angular velocity of the motor cyclist.
View answer and explanation
Correct option: A
0.7855 rads−10.7855 \mathrm{~rad} \mathrm{s}^{-1}
Option D (0.02 N.m0.02 \mathrm{~N} . \mathrm{m}) is correct because it is the result of applying the torque formula τ=MBsin⁡θ\tau = MB \sin \theta.
432 Hard
432 of 483
Application +4 | -1
A body rolls down an inclined plane without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is
View answer and explanation
Correct option: B
Solid cylinder
Option B (Solid cylinder) is correct because the moment of inertia derived from the kinetic energy relationship matches that of a solid cylinder.
433 Medium
433 of 483
Understanding +4 | -1
Three identical metal balls, each of radius rr are placed touching each other on a horizontal surface, such that an equilateral triangle is formed, when centres of three balls are joined. The centre of mass of the system is located at:
View answer and explanation
Correct option: D
Point of intersection of the medians
Option D (Point of intersection of the medians) is correct because the center of mass of a system of identical objects arranged symmetrically lies at the geometric center, which is the intersection of the medians in an equilateral triangle.
434 Medium
434 of 483
Application +4 | -1
The coordinates of the centre of mass of a system of three particles of masses 1 mg,2 mg1 \mathrm{~mg}, 2 \mathrm{~mg} and 3 mg3 \mathrm{~mg} are (2,2,2)(2,2,2). The coordinates of the fourth particle of mass 4 mg4 \mathrm{~mg} to be positioned so that the centre of mass of the four particles system is at the origin of the three-dimensional rectangular coordinate system are
View answer and explanation
Correct option: D
(−3,−3,−3)(-3,-3,-3)
Option D ((-3,-3,-3)) is correct because it ensures the center of mass of the four-particle system is at the origin.
435 Medium
435 of 483
Understanding +4 | -1
The moment of inertia of a body does not depend on
View answer and explanation
Correct option: B
the angular velocity of the body
Option B is correct because the moment of inertia depends on mass distribution, axis of rotation, and mass itself, but not on the angular velocity.
436 Medium
436 of 483
Application +4 | -1
A fan rotating with ω=100rad/s\omega=100 \mathrm{rad} / \mathrm{s}, is switched off. After 2n2 \mathrm{n} rotation its angular velocity reduces to 50rad/s50 \mathrm{rad} / \mathrm{s}. Find out the angular velocity of the fan after nn rotations.
View answer and explanation
Correct option: A
2510 rad/s25 \sqrt{10} \mathrm{~rad} / \mathrm{s}
Option A (2510 rad/s25 \sqrt{10} \mathrm{~rad} / \mathrm{s}) is correct because it is derived from using the equations of rotational motion with constant angular acceleration.
437 Medium
437 of 483
Application +4 | -1
A thin hollow cylinder is free to rotate about its geometrical axis. It has a mass of 8 kg8 \mathrm{~kg} and a radius of 20 cm\mathrm{cm}. A rope is wrapped around the cylinder. What force must be exerted along the rope to produce an angular acceleration of 3 rad/s23\, \mathrm{rad} / \mathrm{s}^2 ?
View answer and explanation
Correct option: C
4.8 N4.8 \mathrm{~N}
Option C (4.8 N4.8 \mathrm{~N}) is correct because it is the force required to produce the given angular acceleration, calculated using the moment of inertia and torque.
438 Medium
438 of 483
Understanding +4 | -1
If the external forces acting on a system have zero resultant, the center of mass
View answer and explanation
Correct option: A
May move but not accelerate
Option A (May move but not accelerate) is correct because if the net external force is zero, the center of mass moves with constant velocity (zero acceleration).
439 Medium
439 of 483
Application +4 | -1
A flywheel of mass 2 kg2 \mathrm{~kg} has radius of gyration 0.5 m0.5 \mathrm{~m}. If it makes 10 r.p.s. then its rotational kinetic energy will be
View answer and explanation
Correct option: C
100π2 J100 \pi^2 \mathrm{~J}
Option C (100π2 J100 \pi^2 \mathrm{~J}) is correct because it is the rotational kinetic energy calculated using the moment of inertia and angular velocity.
440 Medium
440 of 483
Analyzing +4 | -1
A particle of mass m moving with a velocity (3i^+2j^)ms−1\left( {3\hat i + 2\hat j} \right)m{s^{ - 1}} collides with a stationary body mass M and finally moves with a velocity (−2i^+j^)ms−1. If mM=113,\left( { - 2\hat i + \hat j} \right)\mathrm{m}{\mathrm{s}^{ - 1}}.\,If\,\frac{m}{M} = \frac{1}{{13}}, then
View answer and explanation
Correct option: D
All the above are correct
Option D is correct because all the statements regarding impulse, velocity of M, and coefficient of restitution are correct based on the collision parameters.
441 Medium
441 of 483
Application +4 | -1
M.I of a solid sphere about its diameter is 64 kg m264\,kg\,{m^2}. If that sphere is recast into 8 identical small spheres then M.I. of such small sphere about its diameter is
View answer and explanation
Correct option: D
2 kg m22\,kg\,{m^2}
Option D (2 kg m22\,kg\,{m^2}) is correct because the moment of inertia of the smaller sphere is calculated based on the conservation of mass and the change in radius.
442 Medium
442 of 483
Application +4 | -1
Find the angular velocity of a body rotating with an acceleration of 2 rev/s22 \mathrm{~rev} / \mathrm{s}^2 as it completes the 5th revolution after the start.
View answer and explanation
Correct option: A
25 rev/s2 \sqrt{5} \mathrm{~rev} / \mathrm{s}
Option C (npn p) is correct because the bulk modulus is derived from the given process equation TVn−1=constantTV^{n-1} = constant and the definition of bulk modulus.
443 Medium
443 of 483
Analyzing +4 | -1
A flywheel rotating about an axis experiences an angular retardation proportional to the angle through which it rotates. If itsrotational kinetic energy gets reduced by ΔE\Delta {E} while it rotates through an angle θ\theta then
View answer and explanation
Correct option: A
ΔE∝θ2\Delta {E} \propto \theta^2
Option A (ΔE∝θ2\Delta {E} \propto \theta^2) is correct because the angular retardation is proportional to the angle, leading to a change in kinetic energy proportional to the square of the angle.
444 Medium
444 of 483
Application +4 | -1
A wheel rotating with uniform angular acceleration
covers 50 revolutions in the first five seconds after the
start. Find the angular acceleration and the angular
velocity at the end of five seconds.
View answer and explanation
Correct option: A
4 rev/s2,20 rev/s4 \mathrm{~rev} / \mathrm{s}^2, 20 \mathrm{~rev} / \mathrm{s}
Option A (4 rev/s2,20 rev/s4 \mathrm{~rev} / \mathrm{s}^2, 20 \mathrm{~rev} / \mathrm{s}) is correct because it correctly calculates angular acceleration and angular velocity using kinematic equations.
445 Medium
445 of 483
Application +4 | -1
A rigid system consists of two point masses, AA and BB of masses 1 kg1 \mathrm{~kg} and 2 kg2 \mathrm{~kg} respectively. At an instant the kinetic energy of AA and BB with respect to the centre of mass is 2 Joule and 1 Joule respectively. The velocity of centre of mass is 2 m/s2 \mathrm{~m} / \mathrm{s}. The kinetic energy of the system with respect to ground at this instant is:
View answer and explanation
Correct option: A
9 J9 \mathrm{~J}
Option A (9 J) is correct because the total kinetic energy is the sum of the kinetic energy with respect to the center of mass and the kinetic energy of the center of mass.
446 Medium
446 of 483
Application +4 | -1
A rod of mass 5 kg5 \mathrm{~kg} is connected to the string at point BB. The span of rod is along horizontal. The other end of the rod is hinged at point AA. If the string is massless, then the reaction of hinge at the instant when string is cut, is (Take, g=10 ms−2g=10 \mathrm{~ms}^{-2} )
View answer and explanation
Correct option: B
12.5 N12.5 \mathrm{~N}
Option B (12.5 N12.5 \mathrm{~N}) is correct because it is the reaction force calculated at the hinge when the string is cut, considering the torque and angular acceleration of the rod.
447 Medium
447 of 483
Understanding +4 | -1
Assertion: The centre of mass of a proton and an electron, released from their respective positions remains at rest.
Reason: The centre of mass remain at rest, if no-external force is applied.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because the center of mass remains at rest when no external force is applied, which is the case for the proton and electron system.
448 Medium
448 of 483
Analyzing +4 | -1
A solid sphere of radius R{R} is placed on a smooth horizontal surface. A horizontal force FF is applied at height hh from the lowest point. For the maximum acceleration of centre of mass, which is correct?
View answer and explanation
Correct option: D
No relation between hh and R{R}
Option D (No relation between hh and R{R}) is correct because the acceleration of the center of mass depends only on the applied force and the mass of the sphere.
449 Medium
449 of 483
Analyzing +4 | -1
Assertion: For the purpose of calculation of moment of inertia, body's mass can be assumed to be concentrated at its centre of mass.
Reason: Moment of inertia of rigid body about an axis passing through its centre of mass is zero.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because the assertion that a body's mass can be concentrated at its center of mass for moment of inertia calculations is false, and the moment of inertia about the center of mass is not always zero.
450 Medium
450 of 483
Application +4 | -1
A uniform rod of mass mm and length ll is struck at an end by a force FF perpendicular to the rod for a short time interval tt. Calculate

(a) the speed of the centre of mass
(b) the angular speed of the rod about the centre of mass

Assume that tt is so small that the rod does not appreciably change its direction while the force acts.
View answer and explanation
Correct option: A
(a) Ftm;\frac{F t}{m}; (b) 6Ftml\frac{6 F t}{m l}
Option C (1/2λ1/2\lambda) is correct because it is derived from the radioactive decay formula and the given ratio of active nuclei.
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