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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 483 questions

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301 Medium
301 of 483
Application +4 | -1
A loop of radius 3 meter and weighs 150 kg150 \mathrm{~kg}. It rolls along a horizontal floor so that its centre of mass has a speed of 15 cm/sec\mathrm{cm} / \mathrm{sec}. How much work has to be done to stop it
View answer and explanation
Correct option: A
3.375 J3.375 \mathrm{~J}
Option A (3.375 J) is correct because the work done to stop the loop is equal to its total kinetic energy, considering both translational and rotational motion.
302 Medium
302 of 483
Understanding +4 | -1
For a given mass and size, moment of inertia of a solid disc is:
View answer and explanation
Correct option: B
Less than that of a ring
Option B is correct because, for a given mass and size, the mass of a disc is distributed closer to the center than a ring, resulting in a lower moment of inertia.
303 Medium
303 of 483
Understanding +4 | -1
Two spheres of masses 2M and M are initially at rest at a distance R apart. Due to mutual force of attraction, they approach each other. When they are at separation R/2, the acceleration of the centre of mass of spheres would be
View answer and explanation
Correct option: A
0   m/s20\;\,m/{s^2}
Option A (0   m/s20 \;\,m/{s^2}) is correct because the center of mass of an isolated system experiences no acceleration in the absence of external forces.
304 Medium
304 of 483
Understanding +4 | -1
A solid object is rotating freely without experiencing any external torque. In this case
View answer and explanation
Correct option: A
both the angular momentum and angular velocity have constant direction.
The correct answer is both the angular momentum and angular velocity have constant direction because in the absence of external torque, angular momentum is conserved, and if the object is a rigid body, angular velocity also has a constant direction.
305 Medium
305 of 483
Understanding +4 | -1
Assertion: The total distance moved by any point on the periphery of a wheel of radius RR along the surface in one revolution is 2πR.2 \pi R.
Reason: In rolling motion of a wheel, every point on its periphery comes in contact with the surface once in one revolution.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the distance moved by a point on the wheel's periphery in one revolution is indeed 2πR2 \pi R, and this is because every point comes into contact with the surface once per revolution.
306 Medium
306 of 483
Understanding +4 | -1
(A): Value of radius of gyration of a body depends on axis of rotation.
(R): Radius of gyration is root mean square distance of particle of the body from the axis of rotation.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the radius of gyration depends on the axis of rotation, and the reason correctly defines the radius of gyration.
307 Medium
307 of 483
Understanding +4 | -1
Two particles of mass m1{m_1} and m2 (m1>m2){m_2}\,({m_1} > {m_2}) attract each other with a force inversely proportional to the square of the distance between them. If the particles are initially held at rest and then released, the centre of mass will
View answer and explanation
Correct option: C
remains at rest
Option C (remains at rest) is correct because the center of mass remains at rest due to the absence of external forces acting on the system.
308 Easy
308 of 483
Analyzing +4 | -1
When a sphere rolls down an inclined plane, then identity the correct statement related to the work done by friction force
View answer and explanation
Correct option: C
The net work done by friction is zero
Option C (The net work done by friction is zero) is correct because for pure rolling, the point of contact is instantaneously at rest, so friction does no work.
309 Medium
309 of 483
Understanding +4 | -1
The two persons of masses 55 kg and 65 kg respectively, are at at opposite ends of a boat. The length of the boat is 30 m and weight 100 kg. The 55 kg man walkup to the 65 kg man and its with him. If the boat is in still water the centre of mass of the system shifts by
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because, in the absence of external forces, the center of mass of the system (persons + boat) remains unchanged.
310 Medium
310 of 483
Application +4 | -1
A solid sphere is under pure rolling on a table. The fraction of its total kinetic energy associated with rotation is
View answer and explanation
Correct option: C
27\frac{2}{7}
Option C (27\frac{2}{7}) is correct because it represents the ratio of rotational kinetic energy to the total kinetic energy for a solid sphere in pure rolling.
311 Medium
311 of 483
Analyzing +4 | -1
Assertion: If ice caps of the pole melts, the day length will shorten.
Reason: Ice flows towards the equator and decreases the moment of inertia of the earth and hence increases the frequency of rotation of the earth.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option D is correct because the charge will oscillate about the origin, but the restoring force is not proportional to the displacement, so it's not SHM.
312 Medium
312 of 483
Analyzing +4 | -1
A metre stick is placed vertically at the origin on a frictionless surface. A gentle push in +x+x-direction is given to the top most point of the rod. When it has fallen completely, the xx-coordinate of centre of rod is at
View answer and explanation
Correct option: A
Origin
Option A (Origin) is correct because there is no external horizontal force acting on the rod, so the center of mass remains at the origin.
313 Medium
313 of 483
Understanding +4 | -1
A cylinder is rolling over a surface. Which points on it move rectilinearly?
View answer and explanation
Correct option: C
All points on the axis of the cylinder
Option C (All points on the axis of the cylinder) is correct because the axis of the cylinder moves in a straight line when the cylinder is rolling without slipping.
314 Medium
314 of 483
Application +4 | -1
A solid sphere is rotating about a diameter at an angular velocity ω\omega. If it cools so that its radius reduces to 1n\frac{1}{n} of its original value, its angular velocity becomes
View answer and explanation
Correct option: D
n2ω{n^2}\omega
Option D (n2ω{n^2}\omega) is correct because angular momentum is conserved, and the moment of inertia changes with the square of the radius.
315 Medium
315 of 483
Understanding +4 | -1
A closed tube partly filled with water lies in a horizontal plane. If the tube is rotated about perpendicular bisector, the moment of inertia of the system
View answer and explanation
Correct option: A
increases
Option A (increases) is correct because when the tube rotates, the water moves away from the axis of rotation, increasing the moment of inertia.
316 Medium
316 of 483
Understanding +4 | -1
Assertion: There are very small sporadic changes in the period of rotation of the earth.
Reason: Shifting of large air masses in the earth's atmosphere produce a change in the moment of inertia of the earth causing its period of rotation to change.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the shifting of air masses does affect the Earth's moment of inertia, causing changes in its rotation period.
317 Medium
317 of 483
Application +4 | -1
A body of radius RR and mass MM is rolling horizontally without slipping with speed vv, it then rolls up a hill to a maximum height hh. If h=3v2/4 gh=3 v^2 / 4 \mathrm{~g}, what is the moment of inertia of the body?
View answer and explanation
Correct option: A
MR22\frac{\mathrm{MR}^2}{2}
Option A (MR22\frac{\mathrm{MR}^2}{2}) is correct because it satisfies the energy conservation equation when the rolling body climbs the hill to the given height.
318 Medium
318 of 483
Remembering +4 | -1
Angular momentum is
View answer and explanation
Correct option: A
Axial vector
Option A (Axial vector) is correct because angular momentum is a vector quantity that is directed along the axis of rotation.
319 Medium
319 of 483
Understanding +4 | -1
When a disc rotates with uniform angular velocity, which of the following is not true?
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Correct option: D
The angular acceleration is non-zero and remains same.
Option D (The angular acceleration is non-zero and remains same) is correct because with uniform angular velocity, the angular acceleration is zero.
320 Medium
320 of 483
Application +4 | -1
A solid sphere and a spherical shell roll down an incline from same height the ratio of times taken by them is
View answer and explanation
Correct option: A
21/25\sqrt {21/25}
Option A (21/25\sqrt {21/25}) is correct because the ratio of times is inversely proportional to the square root of the acceleration, which depends on the moment of inertia.
321 Medium
321 of 483
Application +4 | -1
Two blocks of masses 10 kg and 4 kg connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14  ms−114\mathrm{\;m}{\mathrm{s}^{ - 1}} to the heavier block in the direction of the lighter block. The velocity of the centre of mass is
View answer and explanation
Correct option: C
10  ms−110\mathrm{\;m}{\mathrm{s}^{ - 1}}
Option D (10  ms−110\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because it is the velocity of the center of mass calculated using the formula for the center of mass velocity.
322 Hard
322 of 483
Application +4 | -1
The rotors velocity of a helicopter engine changes from 300 rev/min300 \,\mathrm{rev} / \mathrm{min} to 110 rev/min110 \,\mathrm{rev} / \mathrm{min} in 2 minutes. How long does the rotor blades take to stop
View answer and explanation
Correct option: A
3 min
Option A (3 min) is correct because it is calculated by first finding the angular acceleration and then the time it takes for the rotor to stop.
323 Medium
323 of 483
Application +4 | -1
Two circular iron discs are of the same thickness. The diameter of A is twice that of B. The moment of inertia of A as compared to that of B is
View answer and explanation
Correct option: D
16 times as large
Option D (16 times as large) is correct because the moment of inertia of a disc is proportional to the fourth power of its radius (or diameter).
324 Medium
324 of 483
Analyzing +4 | -1
Two discs having moment of inertia I1\mathrm{I}_1 and I2\mathrm{I}_2 are made from same material have same mass. Their thickness and radii are t1,t2\mathrm{t}_1, \mathrm{t}_2 and R1,R2\mathrm{R}_1, \mathrm{R}_2 respectively. The relation between moment of inertia of each disc about an axis passing through its centre and perpendicular to its plane and its thickness is
View answer and explanation
Correct option: B
I1t1=I2t2\mathrm{I}_1 \mathrm{t}_1=\mathrm{I}_2 \mathrm{t}_2
Option C (I₁t₁=I₂t₂) is correct because the moment of inertia is proportional to the mass and the square of the radius, and the mass is related to the density, radius, and thickness.
325 Medium
325 of 483
Application +4 | -1
A motor is rotating at a constant angular velocity of 600 rpm. The angular displacement per second is
View answer and explanation
Correct option: D
50π3  rad\frac{{50\mathrm{\pi }}}{3}\mathrm{\;rad}
Option D (50π3  rad\frac{{50\mathrm{\pi }}}{{3}}\mathrm{\;rad}) is correct because it represents the angular displacement per second calculated from the given angular velocity in rpm.
326 Medium
326 of 483
Remembering +4 | -1
The correct relation between moment of inertial II, radius of gyration KK and mass MM of the body is:
View answer and explanation
Correct option: D
K=IMK=\sqrt{\frac{I}{M}}
Option D (K=IMK=\sqrt{\frac{{I}}{{M}}}) is correct because it is the correct formula for the radius of gyration.
327 Medium
327 of 483
Application +4 | -1
Two particles of masses 5 kg and 3 kg moves with velocity 2 ms−12\,m{s^{ - 1}} and 4 ms−14\,m{s^{ - 1}} in the same direction. Find the velocity of centre of mass of the system of two particles is
View answer and explanation
Correct option: A
228 ms−1\frac{{22}}{8}\,m{s^{ - 1}}
Option A (22/8 m/s) is correct because it is the velocity of the center of mass calculated using the formula for the center of mass velocity.
328 Medium
328 of 483
Application +4 | -1
A wheel is rotating at 900rpm900 \mathrm{rpm} about its axis. When power is cut-off, it comes to rest in 1 min1 \mathrm{~min}. The angular retardation (in rads−2\mathrm{rad} \mathrm{s}^{-2} ) is
View answer and explanation
Correct option: A
π2\frac{\pi}{2}
Option A (π2\frac{\pi}{2}) is correct because the angular retardation is calculated by dividing the initial angular velocity by the time taken to come to rest.
329 Medium
329 of 483
Application +4 | -1
Moment of inertia of a solid sphere about its diameter is ' I\mathrm{I} '. It is then casted into 27 small sphere of same diameter. The moment of inertia of each new sphere is
View answer and explanation
Correct option: C
I243\frac{\mathrm{I}}{243}
Option C (I243\frac{\mathrm{I}}{243}) is correct because the moment of inertia is proportional to MR², and both mass and radius change when the sphere is recast.
330 Medium
330 of 483
Application +4 | -1
A wheel is rotating at 480 rpm480 \mathrm{~rpm}. Find the magnitude of angular acceleration required to stop the wheel in 8 seconds?
View answer and explanation
Correct option: A
2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}
Option A (2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}) is correct because it is the angular acceleration required to stop the wheel, calculated using the formula α=ΔωΔt\alpha = \frac{\Delta \omega}{\Delta t}.
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