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JEE • PHYSICS • RAY OPTICS

Ray optics practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 443 questions

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361 Medium
361 of 443
Remembering +4 | -1
If both the object and image are at infinite distance from a refracting telescope its magnifying power will be equal to
View answer and explanation
Correct option: C
The ratio of the focal length of the objective and eyepiece
Option C (The ratio of the focal length of the objective and eyepiece) is correct because the magnifying power of a refracting telescope is given by the ratio of the objective's focal length to the eyepiece's focal length when both object and image are at infinity.
362 Medium
362 of 443
Remembering +4 | -1
Myopia can be corrected by using the
View answer and explanation
Correct option: A
Concave lens
Option A (Concave lens) is correct because concave lenses diverge light rays, correcting the focusing issue in myopic eyes.
363 Medium
363 of 443
Application +4 | -1
An object of length 6  cm6\,\,cm is placed on the principal axis of a concave mirror of focal length ff at a distance of 4 f4\,f. The length of the image will be
View answer and explanation
Correct option: A
2  cm2\,\,cm
Option A (2  cm2\,\,cm) is correct because the length of the image is calculated using the magnification formula for a concave mirror.
364 Medium
364 of 443
Remembering +4 | -1
The principle used in the transmission of signal through an optical fibre is
View answer and explanation
Correct option: A
Total internal reflection
Option A (Total internal reflection) is correct because optical fibers rely on total internal reflection to transmit signals.
365 Medium
365 of 443
Understanding +4 | -1
To increase the magnifying power of telescope (f0=({f_0} = focal length of the objective and fe={f_e} = focal length of the eye lens)
View answer and explanation
Correct option: A
f0{f_0} should be large and fe{f_e} should be small
Option A (f0{f_0} should be large and fe{f_e} should be small) is correct because the magnifying power of a telescope is directly proportional to the focal length of the objective lens and inversely proportional to the focal length of the eyepiece.
366 Medium
366 of 443
Application +4 | -1
A hollow prism having refracting angle 60∘60^\circ is filled with a liquid having refractive index μ.\mu . If angle of minimum deviation produced by the prism is 30∘,30^\circ , then value of μ\mu will be
View answer and explanation
Correct option: A
2\sqrt 2
Option A (2\sqrt 2) is correct because it is calculated using the formula for the refractive index of a prism at minimum deviation, substituting the given values for the prism angle and the angle of minimum deviation.
367 Medium
367 of 443
Analyzing +4 | -1
Assertion : The minimum distance between a real object and its real image formed by a convex lens is 4f4 \mathrm{f}.

Reason : Convex mirror and concave lens form a virtual and erect image for all position of the real object.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion
Option B is correct because both the assertion and reason are true, but the reason does not explain the assertion. The assertion is about the minimum distance between a real object and its real image formed by a convex lens, while the reason is about the image formation by convex mirrors and concave lenses.
368 Medium
368 of 443
Remembering +4 | -1
The spectrum obtained from a sodium vapour lamp is an example of
View answer and explanation
Correct option: B
Emission spectrum
Option B (Emission spectrum) is correct because the spectrum from a sodium vapor lamp consists of discrete bright lines, which is characteristic of an emission spectrum.
369 Medium
369 of 443
Remembering +4 | -1
Image is formed for the short sighted person at
View answer and explanation
Correct option: B
Before retina
Option B (Before retina) is correct because in myopia (short-sightedness), the eye focuses the image in front of the retina.
370 Medium
370 of 443
Understanding +4 | -1
During a cloudy day, a primary and a secondary rainbow may be created, then the:
View answer and explanation
Correct option: D
Secondary rainbow is due to double internal
reflection and is formed above the primary
one
Option D (Secondary rainbow is due to double internal reflection and is formed above the primary one) is correct because secondary rainbows are formed by double internal reflection within water droplets and appear higher in the sky than primary rainbows.
371 Medium
371 of 443
Application +4 | -1
What is the power of the spectacles required by a myopic eye whose far point is 50 cm50 \mathrm{~cm}?
View answer and explanation
Correct option: A
- 2 D
Option A (-2 D) is correct because the power of the spectacles is calculated using the lens formula with the far point as the image distance.
372 Medium
372 of 443
Understanding +4 | -1
The ratio real depthapparent depth\frac{\text {real depth}}{\text {apparent depth}} is equal to
View answer and explanation
Correct option: B
Refractive index of denser medium with respect to rare medium
Option B (Refractive index of denser medium with respect to rare medium) is correct because the ratio of real depth to apparent depth defines the refractive index of the denser medium relative to the rarer medium.
373 Medium
373 of 443
Understanding +4 | -1
In the visible region the dispersive powers and the mean angular deviations for crown and flint glass prisms are ω,  ω′\omega ,\,\,\omega ' and d,  d′d,\,\,d' respectively. The condition for getting deviation without dispersion when the two prisms are combined is
View answer and explanation
Correct option: C
ωd+ω′d′=0\omega d + \omega 'd' = 0
Option C is correct because the condition for deviation without dispersion requires the net angular dispersion to be zero, which is expressed as ωd+ω′d′=0\omega d + \omega 'd' = 0.
374 Medium
374 of 443
Application +4 | -1
The focal length of convex lens is 10 cm. Its magnifying power when it is used as a magnifying glass to form the image at (i) near point and (ii) for point is
View answer and explanation
Correct option: A
3.5 ; 2.53.5\,;\,2.5
Option A (3.5 ; 2.53.5\,;\,2.5) is correct because the magnifying power is calculated using m=1+Dfm = 1 + \frac{D}{f} for the near point and m=Dfm = \frac{D}{f} for the far point.
375 Medium
375 of 443
Remembering +4 | -1
Deviation of light ray by a thin prism of refractive index μ\mu and refracting angle AA is
View answer and explanation
Correct option: D
(μ−1)A(\mu-1) A
Option D ((μ−1)A(\mu-1) A) is correct because the deviation of light ray by a thin prism is given by the formula (μ−1)A(\mu-1) A.
376 Medium
376 of 443
Analyzing +4 | -1
Assertion: Two plane mirrors kept at right angles, Deviate any ray of light by 180∘180^{\circ} after two reflections.

Reason: The above conditions satisfied only for angle of incidence i=45∘i=45^{\circ}
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C (If Assertion is true but Reason is false) is correct because two plane mirrors at right angles deviate any ray of light by 180 degrees, regardless of the angle of incidence.
377 Medium
377 of 443
Analyzing +4 | -1
Assertion: When a convex lens (μg=3/2)\left(\mu_g=3 / 2\right) of focal length ff is dipped in water, its focal length becomes 43f\frac{4}{3} f.

Reason: The focal length of convex lens in water becomes 3f3 f.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because the focal length becomes 4f when dipped in water, not 43f\frac{4}{3}f or 3f.
378 Medium
378 of 443
Understanding +4 | -1
The magnifying power of a microscope decreases when its length is
View answer and explanation
Correct option: B
Decreased
Option B (Decreased) is correct because the magnifying power of a microscope is inversely proportional to the focal length of the objective lens and the eyepiece, and directly proportional to the tube length. Decreasing the length decreases magnification.
379 Medium
379 of 443
Remembering +4 | -1
A spherometer is used to measure
View answer and explanation
Correct option: A
Radius of curvature of a lens
Option A (Radius of curvature of a lens) is correct because a spherometer is specifically designed to measure the radius of curvature of spherical surfaces, including lenses.
380 Medium
380 of 443
Analyzing +4 | -1
An astronomical refracting telescope is being
used by an observer to observe planets in
normal adjustment. The focal lengths of the
objective and eye piece used in the
construction of the telescope are 20 m and
2 cm respectively. Consider the following
statements about the telescope:
(a) The distance between the objective and
eyepiece is 20.02 m.

(b) The magnification of the telescope is (–) 1000.

(c) The image of the planet is erect and diminished.

(d) The aperture of eye piece is smaller than that of objective.

The correct statements are:
View answer and explanation
Correct option: A
(a), (b) and (d)
Option A ((a), (b) and (d)) is correct because the distance between the objective and eyepiece is the sum of their focal lengths, the magnification is the ratio of the objective's focal length to the eyepiece's, and the eyepiece aperture is smaller.
381 Medium
381 of 443
Understanding +4 | -1
To increase both the resolving power and magnifying power of a telescope
View answer and explanation
Correct option: A
both the focal length and aperture of the objective has to be increased
Option A (both the focal length and aperture of the objective has to be increased) is correct because magnifying power is proportional to the focal length of the objective and resolving power is proportional to the aperture of the objective.
382 Medium
382 of 443
Understanding +4 | -1
A spectrum is formed by a prism of dispersive power ′ω′'\omega '. If the angle of deviation is ′δ′'\delta ' then the angular dispersion is
View answer and explanation
Correct option: D
ωδ\omega \delta
Option D (ωδ\omega \delta) is correct because angular dispersion is the product of the dispersive power and the angle of deviation.
383 Medium
383 of 443
Application +4 | -1
In normal adjustment, magnifying power of an astronomical telescope is 6 and length of telescope is 21 cm21 \mathrm{~cm}. The focal length of objective and eye piece are
View answer and explanation
Correct option: A
18 cm,3 cm18 \mathrm{~cm}, 3 \mathrm{~cm}
Option A (18 cm,3 cm18 \mathrm{~cm}, 3 \mathrm{~cm}) is correct because it satisfies both the magnification and length equations for a telescope in normal adjustment.
384 Medium
384 of 443
Application +4 | -1
A plano-convex lens when silvered in the plane side behaves like a concave mirror of focal length 30  cm30\,\,cm. However, when silvered on the convex side it behaves like a concave mirror of focal length 10  cm10\,\,cm. Then the refractive index of its material will be
View answer and explanation
Correct option: D
1.5
Option D (1.5) is correct because the refractive index is calculated using the lens maker's formula and the given focal lengths when the lens is silvered on either side.
385 Medium
385 of 443
Understanding +4 | -1
The optical fibres have an inner core of refractive index n1{n_1} and a cladding of refractive index n2{n_2} such that
View answer and explanation
Correct option: D
n1>n2{n_1} > {n_2}
Option D (n1>n2{n_1} > {n_2}) is correct because for total internal reflection to occur within the optical fiber, the refractive index of the core must be greater than that of the cladding.
386 Medium
386 of 443
Remembering +4 | -1
In reflection over a spherical mirror, ray parallel to principal axis, after reflection from mirror pass through
View answer and explanation
Correct option: A
Focus
Option A (Focus) is correct because, by the laws of reflection, a ray parallel to the principal axis of a spherical mirror will pass through the focus after reflection.
387 Medium
387 of 443
Analyzing +4 | -1
The minimum distance between the object and its real image for concave mirror of focal length ff is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the minimum distance between an object and its real image for a concave mirror occurs when the object is at the center of curvature, resulting in the image also forming at the center of curvature, hence the distance is zero.
388 Medium
388 of 443
Understanding +4 | -1
Why sun has elliptical shape on the time when rising and setting? It is due to
View answer and explanation
Correct option: A
Refraction
Option A (Refraction) is correct because atmospheric refraction causes the elliptical shape of the sun during sunrise and sunset.
389 Medium
389 of 443
Analyzing +4 | -1
Statement-A: If a convex lens of glass is immersed in water its powder decreases.

Statement-B: In water it behaves as a concave lens.
View answer and explanation
Correct option: C
A is correct and B is wrong
Option C (A is correct and B is wrong) is correct because a convex lens in water has reduced power but still behaves as a convex lens.
390 Medium
390 of 443
Understanding +4 | -1
Assertion: Propagation of light through an optical fibre is due to total internal reflection taking place at the core-clade interface.
Reason: Refractive index of the material of the core of the optical fibre is greater than that of air.
View answer and explanation
Correct option: B
Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
Option B (Both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because total internal reflection requires the core to have a higher refractive index than the cladding, not air.
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