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JEE • PHYSICS • RAY OPTICS

Ray optics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 468 questions

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211 Medium
211 of 468
Understanding +4 | -1
Assertion: The setting sun appears to be red.

Reason: Scattering of light is directly proportional to the wave length.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Option C (If assertion is true but reason is false) is correct because the setting sun appears red due to scattering, but scattering is inversely proportional to the fourth power of wavelength.
212 Medium
212 of 468
Understanding +4 | -1
When a glass lens with n=1.47n = 1.47 is immersed in a trough of liquid, it looks to be disappeared. The liquid in the trough could be
View answer and explanation
Correct option: C
Glycerin
The glass lens disappears when immersed in a liquid with the same refractive index. Glycerin has a refractive index close to that of the glass lens.
213 Medium
213 of 468
Understanding +4 | -1
What causes chromatic aberration?
View answer and explanation
Correct option: D
Variation of focal length of lens with colour
Option D (Variation of focal length of lens with colour) is correct because chromatic aberration arises from the fact that the refractive index of the lens material varies with the wavelength (color) of light, leading to different focal lengths for different colors.
214 Medium
214 of 468
Understanding +4 | -1
Assertion: Just before setting, the sun may appear to be elliptical. This happens due to refraction.

Reason: Refraction of light ray through the atmosphere may cause different magnification in mutually perpendicular directions.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion
The correct answer is A (If both assertion and reason are true and the reason is the correct explanation of the assertion) because atmospheric refraction causes the sun to appear elliptical due to differential magnification.
215 Medium
215 of 468
Application +4 | -1
A plane wave of sound travelling in air is incident upon a plane water surface. The angle of incidence is 60∘60^{\circ}. If velocity of sound in air and water are 330 m/s330 \mathrm{~m} / \mathrm{s} and 1400 m/s1400 \mathrm{~m} / \mathrm{s}, then the wave undergoes
View answer and explanation
Correct option: B
reflection only
Option B (reflection only) is correct because the angle of incidence is greater than the critical angle, leading to total internal reflection.
216 Hard
216 of 468
Application +4 | -1
A beam of light of width tt is incident on an air-water boundary at an angle of incidence 45∘45^{\circ}. The width of the beam in water is (Refractive index of water =μ=\mu):
View answer and explanation
Correct option: C
2μ2−1μ⋅t\frac{\sqrt{2 \mu^2-1}}{\mu} \cdot t
Option C (2μ2−1μ⋅t\frac{\sqrt{2 \mu^2-1}}{\mu} \cdot t) is correct because it is derived from Snell's law and trigonometric relationships to find the width of the beam in water.
217 Medium
217 of 468
Analyzing +4 | -1
Assertion: In ionospheric reflection, phase change does not occurs with the light wave.
Reason: The ionosphere reflection is similar to the total internal reflection which is similar to the total internal reflection in miraj
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion
Option A (If both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because ionospheric reflection is similar to TIR, where no phase change occurs.
218 Medium
218 of 468
Understanding +4 | -1
A convex lens is immersed in a liquid, whose refractive index is equal to the refractive index of the material of the lens. Then its focal length will
View answer and explanation
Correct option: C
Become infinite
Option C (Become infinite) is correct because when the refractive index of the lens and the surrounding medium are equal, the lens no longer refracts light, effectively making its focal length infinite.
219 Medium
219 of 468
Understanding +4 | -1
How does the angle of minimum deviation of a glass prism vary, if the incident violet light is replaced with red light?
View answer and explanation
Correct option: C
Decreases
Option C (Decreases) is correct because the refractive index of glass is lower for red light than for violet light, leading to a smaller angle of minimum deviation.
220 Medium
220 of 468
Understanding +4 | -1
The frequency of a light ray is 6  ×  1014  Hz6\,\, \times \,\,{10^{14}}\,\,Hz. Its frequency when it propagates in a medium of refractive index 1.5\mathrm{1}\mathrm{.5}, will be
View answer and explanation
Correct option: C
6  ×  1014  Hz6\,\, \times \,\,{10^{14}}\,\,Hz
Option C is correct. The frequency of light does not change when it propagates from one medium to another. Only the wavelength and velocity change.
221 Medium
221 of 468
Application +4 | -1
Two thin lens have a combined power of 10D10 \mathrm{D} in contact. When separated by 20 cm20 \mathrm{~cm} their equivalent power is 6.25D6.25 \mathrm{D}. Find their in dividual powers in dioptres -
View answer and explanation
Correct option: C
7.5 and 2.5
Option C (7.5 and 2.5) is correct because it satisfies both the combined power and separated power equations for the two lenses.
222 Medium
222 of 468
Understanding +4 | -1
Assertion : In bright light camera with high f no. must be used.

Reason : As f no. increases the aperture size decreases.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is a correct explanation of the Assertion
Option A (If both Assertion and Reason are true and the Reason is a correct explanation of the Assertion) is correct because a higher f-number corresponds to a smaller aperture, which is necessary in bright light to avoid overexposure.
223 Medium
223 of 468
Understanding +4 | -1
In a microscope orange light is used for resolution. The resolving power of microscopes can be increased by using
View answer and explanation
Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because resolving power is inversely proportional to wavelength and directly proportional to the refractive index.
224 Medium
224 of 468
Understanding +4 | -1
A concave mirror forms the image of an object on a screen. If the lower half of the mirror is covered with an opaque card, the effect would be to make the
View answer and explanation
Correct option: A
image less bright.
Option A (image less bright) is correct because covering part of the mirror reduces the amount of light reflected, making the image dimmer but not incomplete.
225 Medium
225 of 468
Application +4 | -1
Two thin lenses whose powers are + 2 D+ \,2\,D and − 4 D- \,4\,D respectively combine, then the power of combination is
View answer and explanation
Correct option: A
− 2 D- \,2\,D
Option A (− 2 D- \,2\,D) is correct because the power of the combination is the sum of the individual lens powers.
226 Medium
226 of 468
Application +4 | -1
The angle of incidence for a ray of light at a refracting surface of a prism is 45o{45^\mathrm{o}}. The angle of prism is 60o{60^\mathrm{o}} . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are:
View answer and explanation
Correct option: B
30o; 2{30^\mathrm{o}};\,\sqrt 2
Option B (30o;,2{30^\mathrm{o}};\\,\sqrt 2) is correct because the angle of minimum deviation and refractive index are calculated using the given angle of incidence and prism angle.
227 Medium
227 of 468
Application +4 | -1
Four lenses A, B, C and D power + 100 D, −50 D, 20 D+ \,100\,D,\, - 50\,D,\,20\,D and 5D. Which lenses will you use to design a compound microscope for best magnification?
View answer and explanation
Correct option: A
A and C
Option A (A and C) is correct because lenses with higher power provide better magnification in a compound microscope.
228 Medium
228 of 468
Application +4 | -1
A person can see objects clearly placed beyond 1m. Power of lens required to correct defect will be:-
View answer and explanation
Correct option: A
#ERROR!
Option A (+3D) is correct because the power of the lens is calculated correctly based on the person's near point and the desired near point.
229 Medium
229 of 468
Understanding +4 | -1
The images of clouds and trees in water always less bright than in reality –
View answer and explanation
Correct option: C
because only a portion of the incident light is reflected and quite a large portion goes mid water
The correct answer is because only a portion of the incident light is reflected and quite a large portion goes mid water. This is due to the reflection and refraction properties of water.
230 Medium
230 of 468
Application +4 | -1
A small object is placed at a distance of 3.6 cm3.6 \mathrm{~cm} from a magnifier of focal length 4.0 cm4.0 \mathrm{~cm}. (a) Find the position of the image. (b) Find the linear magnification. (c) Find the angular magnification.
View answer and explanation
Correct option: D
−36 cm; 10; 7.0-36 \mathrm{~cm};\,10;\,7.0
Option D (−36 cm;,10;,7.0-36 \mathrm{~cm};\\,10;\\,7.0) is correct because it accurately calculates the image position using the lens formula, the linear magnification, and the angular magnification.
231 Medium
231 of 468
Analyzing +4 | -1
Assertion: Convergent lens property of converging remains same in mediums.
Reason: Property of lens whether the ray is diverging or converging depends on the surrounding medium.
View answer and explanation
Correct option: D
Assertion is false but Reason is true
Option D (Assertion is false but Reason is true) is correct because the converging or diverging property of a lens depends on the surrounding medium's refractive index.
232 Medium
232 of 468
Application +4 | -1
A convergent lens of power 16D is used as a simple microscope. The magnification produced by the lens, when the final image is formed at least distance of distinct vision is
View answer and explanation
Correct option: D
5
Option D (5) is correct because it is calculated using the formula for magnification of a simple microscope when the final image is at the least distance of distinct vision.
233 Medium
233 of 468
Understanding +4 | -1
If a parallel beam of white light is incident on a converging lens, the colour which is brought to focus nearest to the lens is
View answer and explanation
Correct option: A
Violet
Option A (Violet) is correct because violet light has the shortest wavelength and is refracted the most by the lens, thus focusing closest to it.
234 Medium
234 of 468
Application +4 | -1
A square wire frame of side 3.0 cm3.0 \mathrm{~cm} is placed 25 cm25 \mathrm{~cm} away from a concave mirror of focal length 10 cm10 \mathrm{~cm}. The centre of the wire frame is on the axis of the mirror, with its two sides normal to the mirror. The area enclosed by the image of the wire frame is -
View answer and explanation
Correct option: B
4 cm24 \mathrm{~cm}^2
Option B (4 cm24 \mathrm{~cm}^2) is correct because it is the area of the image calculated using the magnification formula for a concave mirror.
235 Medium
235 of 468
Understanding +4 | -1
fv{f_v} and fr{f_r} are the focal lengths of a convex lens for violet and red light respectively and Fv{F_v} and Fr{F_r} are the focal lengths of a concave lens for violet and red light respectively, then
View answer and explanation
Correct option: B
fv<  fR{f_v} < \,\,{f_R} and Fv<Fr{F_v} < {F_r}
Option B is correct because the refractive index is higher for violet light than for red light, leading to a shorter focal length for violet light in both convex and concave lenses.
236 Medium
236 of 468
Analyzing +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: The phase difference of two light waves change if they travel through different media having same thickness, but different indices of refraction.

Reason R: The wavelengths of waves are different in different media.

In the light of the above statements, choose the most appropriate answer from the options given below
View answer and explanation
Correct option: D
Both A and R are correct and R is the correct explanation of A
Option C (3r) is correct because the particle travels from its extreme position to the origin and then to the opposite extreme position, covering a total distance of 3r.
237 Medium
237 of 468
Application +4 | -1
Monochromatic light of frequency 5  ×  1014  Hz5\,\, \times \,\,{10^{14}}\,\,\mathrm{Hz} travelling in vaccum enters a medium of refractive index 1.5\mathrm{1}\mathrm{.5}. It wavelength in the medium is
View answer and explanation
Correct option: A
4000  A04000\,\,{A^0}
Option A (4000 A04000 \,{A^0}) is correct because the wavelength in the medium is calculated by dividing the wavelength in vacuum by the refractive index of the medium.
238 Medium
238 of 468
Understanding +4 | -1
If the lower half of a concave mirror’s reflecting surface is made opaque, which of the following statements describe the image of an object placed infront of the mirror

S1\mathrm{S1}: Intensity of the image will increase

S2\mathrm{S2}: The image will show only half of the object

S3\mathrm{S3}: No change in the image

S4\mathrm{S4}: Intensity of the image will be reduced to half
View answer and explanation
Correct option: D
S4\mathrm{S4} only
Option D (S4 only) is correct because blocking half the mirror reduces the intensity of the image to half, but the entire object's image is still formed.
239 Medium
239 of 468
Analyzing +4 | -1
A particle is projected above a plane mirror. Taking up as positive and down as negative. Mark the correct options:
View answer and explanation
Correct option: D
Sign of acceleration of object is negative and image positive
The correct answer is that the sign of acceleration of the object is negative and the image is positive because the acceleration of the image is in the opposite direction to the object's acceleration.
240 Medium
240 of 468
Application +4 | -1
A thin glass lens (μ=1.5)(\mu=1.5) of focal length 15 cm15 \mathrm{~cm} is kept inside water (μ=43)\left(\mu=\frac{4}{3}\right). The new focal length of lens in water is
View answer and explanation
Correct option: D
60 cm60 \mathrm{~cm}
Option D (60 cm60 \mathrm{~cm}) is correct because the new focal length is calculated using the lens maker's formula, considering the refractive index of water.
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