Back to OSCILLATIONS
Your Progress
0 / 445 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • OSCILLATIONS
Oscillations practice · Medium
Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.
Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
Take a chapter quiz →
Showing 301-330 of 445 questions
Preparing practice and saved progress…
301
Medium
301 of 445
Analyzing
+4 | -1
A simple harmonic motion is represented by . The angular frequency of oscillation is given by
View answer and explanation
Correct option: B
Option B () is correct because the given expression can be simplified to a cosine function with angular frequency .
302
Medium
302 of 445
Application
+4 | -1
The period of oscillation of a simple pendulum is given by , where is the length of the pendulum and is the acceleration due to gravity. The length is measured using a meter scale which has 2000 divisions. If the measured value is , the accuracy in the determination of is and the time taken for 100 oscillations is 100 seconds, what should be the resolution of the clock (in milliseconds)?
View answer and explanation
Correct option: C
5
Option C (5) is correct because the resolution of the clock is calculated by error propagation formula from the given percentage error in g and the least count of the meter scale.
303
Medium
303 of 445
Application
+4 | -1
The potential energy of a particle of mass in motion along the -axis is given by , where is in metres. The period of small oscillations (in second) is
View answer and explanation
Correct option: C
Option C () is correct because the period of small oscillations is calculated using the second derivative of the potential energy.
304
Medium
304 of 445
Understanding
+4 | -1
The motion of a particle in SHM is of
View answer and explanation
Correct option: D
Non-uniform speed
Option D (Non-uniform speed) is correct because the speed of a particle in SHM varies sinusoidally with time, meaning it is not constant.
305
Medium
305 of 445
Understanding
+4 | -1
In order that the resultant path on superimposing two mutually perpendicular SHM be a circle, the conditions are that
View answer and explanation
Correct option: A
the amplitudes on both SHM should be equal and they should have a phase difference of
The correct answer is A because for the resultant of two perpendicular SHMs to be a circle, their amplitudes must be equal and they must have a phase difference of π/2.
306
Medium
306 of 445
Application
+4 | -1
Time period of a simple pendulum in a stationary lift is If the lift accelerates with vertically upwards then the time period will be
(Where = acceleration due to gravity)
(Where = acceleration due to gravity)
View answer and explanation
Correct option: C
Option C () is correct because the effective acceleration due to gravity increases when the lift accelerates upwards, thus decreasing the time period.
307
Medium
307 of 445
Application
+4 | -1
The average life of an Indian is 56 years. Find the number of times the human heart beats in the life of an Indian, if the heart beats once in .
View answer and explanation
Correct option: A
Option A () is correct because it is the result of dividing the total seconds in 56 years by the period of one heart beat.
308
Medium
308 of 445
Understanding
+4 | -1
Choose the correct statement in the following statements.
View answer and explanation
Correct option: D
The graph between length of the pendulum and time period is a parabola.
Option D (The graph between length of the pendulum and time period is a parabola) is correct because the relationship between length and time period is T = 2π√(l/g), which implies T² ∝ l, representing a parabola.
309
Medium
309 of 445
Understanding
+4 | -1
Which one of the following is NOT a characteristic of SHM?
View answer and explanation
Correct option: D
Its velocity time graph is a straight line
Option D (Its velocity time graph is a straight line) is correct because the velocity-time graph for SHM is sinusoidal, not a straight line.
310
Medium
310 of 445
Understanding
+4 | -1
If the displacement equation of a particle be represented by the particle executes
View answer and explanation
Correct option: C
A S.H.M.
Option C (A S.H.M.) is correct because the given equation can be rewritten as a simple harmonic motion equation.
311
Medium
311 of 445
Analyzing
+4 | -1
The bob of a simple pendulum is a hollow
sphere filled with water. If a hole is made at its
bottom, so that water emerges out slowly, then
time period of oscillations
sphere filled with water. If a hole is made at its
bottom, so that water emerges out slowly, then
time period of oscillations
View answer and explanation
Correct option: D
will first increase and then decrease
Option D is correct because as water drains, the center of mass shifts, increasing the effective length and thus the time period, until the bob is empty and the length returns to its original value.
312
Medium
312 of 445
Analyzing
+4 | -1
What happens to the natural frequency of vibration of stretched spring, when its length and diameter are increased?
View answer and explanation
Correct option: A
Frequency decreases
Option A (Frequency decreases) is correct because increasing the length and diameter of a stretched spring reduces its natural frequency of vibration.
313
Medium
313 of 445
Analyzing
+4 | -1
Out of the following functions representing motion of a particle which represents SHM (i) (ii) (iii) (iv)
View answer and explanation
Correct option: D
Only (i) and (iii)
Option D (Only (i) and (iii)) is correct because only these functions can be expressed in the form or .
314
Medium
314 of 445
Application
+4 | -1
Two pendulums of lengths 1m and 1.21m respectively start swinging together with same amplitude. The number of vibrations that will be executed by the longer pendulum before the two will swing together again are
View answer and explanation
Correct option: B
10
Option B (10) is correct because the number of vibrations executed by the longer pendulum before they swing together again is calculated based on the ratio of their time periods.
315
Medium
315 of 445
Understanding
+4 | -1
The speed of the particle on a reference circle of radius is . The time period of oscillations of the projection on a diameter of the circle is
View answer and explanation
Correct option: B
Option B is correct because the time period of oscillations is equal to the circumference of the reference circle divided by the speed of the particle.
Explore Other Chapters in PHYSICS
View All →
316
Medium
316 of 445
Application
+4 | -1
A spring is stretched by when a mass of is suspended from it. The period of oscillations of the spring loaded by and put to oscillations is close to__
View answer and explanation
Correct option: C
Option C (0.82 s) is correct because the period of oscillation is calculated using the formula T = 2*pi*sqrt(m/k), where k is the spring constant.
317
Medium
317 of 445
Analyzing
+4 | -1
The acceleration of a particle moving along -axis is . It is released from . Here ' ' and ' ' are in S.I. units. The motion of particle will be :-
View answer and explanation
Correct option: D
Simple harmonic
Option D is correct because the acceleration can be written in the form a = -kx', which indicates simple harmonic motion.
318
Medium
318 of 445
Application
+4 | -1
The Displacement of a particle varies with time as (in ). if its motion is S.H.M, Then its maximum accelaration is
View answer and explanation
Correct option: B
Option B () is correct because the displacement equation can be simplified to , and the maximum acceleration is where is the amplitude and is the angular frequency.
319
Medium
319 of 445
Application
+4 | -1
The maximum force acting on a particle executing simple harmonic motion is . The force on the particle when it is midway between mean and extreme positions will be
View answer and explanation
Correct option: C
Option C (5 N) is correct because the force on a particle in SHM is proportional to its displacement from the mean position, so at midway, the force is half of the maximum force.
320
Medium
320 of 445
Analyzing
+4 | -1
Assertion: Time average KE and time average PE are not exactly equal in simple pendulum.
Reason: Friction is not negligible in simple pendulum.
Reason: Friction is not negligible in simple pendulum.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because friction causes energy loss, leading to unequal average KE and PE.
321
Medium
321 of 445
Application
+4 | -1
The bob of a pendulum of length l is pulled aside from its equilibrium position through an angle θ and then released. The bob will then pass through its equilibrium position with a speed , where equals
View answer and explanation
Correct option: A
Option A () is correct because it is derived from the conservation of energy, equating the potential energy at the initial position to the kinetic energy at the equilibrium position.
322
Medium
322 of 445
Analyzing
+4 | -1
Which of the following quantity is always negative in S.H.M? (Symbols have their usual meanings)
View answer and explanation
Correct option: A
The correct answer is A because in SHM, the force and displacement are always in opposite directions, making their dot product negative.
323
Medium
323 of 445
Understanding
+4 | -1
Which of the following functions represents a simple harmonic oscillation?
View answer and explanation
Correct option: A
Option A () is correct because it can be expressed as a single sinusoidal function, satisfying the condition for SHM.
324
Medium
324 of 445
Application
+4 | -1
A heavy brass sphere is hung from a spring and it executes vertical vibrations with period . The sphere is now immersed in a non-viscous liquid with a density th that of brass. When set into vertical vibrations with the sphere remaining inside liquid all the time, the time period will be
View answer and explanation
Correct option: D
Unchanged
Option D (Unchanged) is correct because the time period of a mass oscillating on a spring is independent of the acceleration due to gravity (g).
325
Medium
325 of 445
Application
+4 | -1
The ratio of angular speed of a second- hand to the hour-hand of a watch is:
View answer and explanation
Correct option: B
Option B () is correct because the hour hand takes 12 hours to complete a revolution while the second hand takes 60 seconds to complete a revolution, leading to the ratio of their angular speeds being 720:1.
326
Medium
326 of 445
Understanding
+4 | -1
(A): Since and cosine functions are periodic functions
(R): Sinusoidal functions repeat its values after a definite interval of time
(R): Sinusoidal functions repeat its values after a definite interval of time
View answer and explanation
Correct option: A
If Both A R are true and R is correct explanation of A
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why sine and cosine functions are periodic.
327
Medium
327 of 445
Application
+4 | -1
A particle performs linear S.H.M. At a particular instant, velocity of the particle is ' ' and acceleration is ' ' while at another instant velocity is ' ' and acceleration is ' ' . The distance between the two positions is
View answer and explanation
Correct option: A
Option A () is correct because it is derived from the equations of SHM relating velocity, acceleration, and displacement.
328
Medium
328 of 445
Application
+4 | -1
The ratio of the magnitudes of maximum velocity to the maximum acceleration of a particle making is . The minimum time taken by the particle to move between the extreme points of its path is
View answer and explanation
Correct option: B
Option B (3.14 S) is correct because it correctly uses the ratio of maximum velocity to maximum acceleration to find the time period and then half of it.
329
Medium
329 of 445
Understanding
+4 | -1
Assertion (A): Damped vibrations indicate loss of energy.
Reason (R): The loss may be due to friction, air resistance etc.
Reason (R): The loss may be due to friction, air resistance etc.
View answer and explanation
Correct option: A
If Both A R are true and R is correct explanation of A
Option A is correct because damped vibrations indeed indicate energy loss, and this loss is accurately attributed to factors like friction and air resistance.
330
Medium
330 of 445
Application
+4 | -1
A vertical spring with a load of mass has the same frequency of oscillation as that of a seconds pendulum at a place. The spring constant of the spring is nearly
View answer and explanation
Correct option: B
1
Option B (1) is correct because the spring constant is calculated by equating the frequency of the spring-mass system to that of a seconds pendulum.
Revision notes and key takeaways
Review OSCILLATIONS in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 445 questions
