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JEE • PHYSICS • OSCILLATIONS

Oscillations practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 481-483 of 483 questions

481 Medium

481 of 483

Application +4 | -1

A mass

M

is suspended from a massless spring. An additional mass

m

stretches the spring further by a distance

x

. The combined mass will oscillate with a period

View answer and explanation

Correct option: A

2 \pi \sqrt{\left\{\frac{(M+m) x}{m g}\right\}}

Option A (

2 \pi \sqrt{\{{\frac{{(M + m)x}}{{mg}}\}}}}

) is correct because it accurately gives the period of oscillation for the combined mass.

482 Medium

482 of 483

Analyzing +4 | -1

Two SHM are represented by equations,

{y_1} = 6\cos \left( {6\pi t + \frac{\pi }{6}} \right),{y_2} = 3\left( {\sqrt 3 \sin 3\pi t + \cos 3\pi t} \right)

View answer and explanation

Correct option: A

ratio of their amplitudes is 1

Option A (ratio of their amplitudes is 1) is correct because after simplifying the second equation, the amplitudes of both SHMs are found to be equal.

483 Medium

483 of 483

Application +4 | -1

A uniform disc of radius

r

is to be suspended through a small hole made in the disc. Find the minimum possible time period of the disc for small oscillations. What should be the distance of the hole from the centre for it to have minimum time period?

View answer and explanation

Correct option: A

2 \pi \sqrt{\frac{r \sqrt{2}}{g}}, r / \sqrt{2}

Option A (

2 \pi \sqrt{\frac{{r \sqrt{{2}}}}{{g}}}, r / \sqrt{{2}}

) is correct because it represents the minimum time period calculated using the moment of inertia and the condition for minimum time period.

Revision notes and key takeaways

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Showing 481-483 of 483 questions

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