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JEE • PHYSICS • OSCILLATIONS
Oscillations practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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331
Medium
331 of 483
Application
+4 | -1
The average life of an Indian is 56 years. Find the number of times the human heart beats in the life of an Indian, if the heart beats once in .
View answer and explanation
Correct option: A
Option A () is correct because it is the result of dividing the total seconds in 56 years by the period of one heart beat.
332
Medium
332 of 483
Understanding
+4 | -1
Choose the correct statement in the following statements.
View answer and explanation
Correct option: D
The graph between length of the pendulum and time period is a parabola.
Option D (The graph between length of the pendulum and time period is a parabola) is correct because the relationship between length and time period is T = 2π√(l/g), which implies T² ∝ l, representing a parabola.
333
Medium
333 of 483
Understanding
+4 | -1
Which one of the following is NOT a characteristic of SHM?
View answer and explanation
Correct option: D
Its velocity time graph is a straight line
Option D (Its velocity time graph is a straight line) is correct because the velocity-time graph for SHM is sinusoidal, not a straight line.
334
Medium
334 of 483
Understanding
+4 | -1
If the displacement equation of a particle be represented by the particle executes
View answer and explanation
Correct option: C
A S.H.M.
Option C (A S.H.M.) is correct because the given equation can be rewritten as a simple harmonic motion equation.
335
Medium
335 of 483
Analyzing
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The bob of a simple pendulum is a hollow
sphere filled with water. If a hole is made at its
bottom, so that water emerges out slowly, then
time period of oscillations
sphere filled with water. If a hole is made at its
bottom, so that water emerges out slowly, then
time period of oscillations
View answer and explanation
Correct option: D
will first increase and then decrease
Option D is correct because as water drains, the center of mass shifts, increasing the effective length and thus the time period, until the bob is empty and the length returns to its original value.
336
Medium
336 of 483
Analyzing
+4 | -1
What happens to the natural frequency of vibration of stretched spring, when its length and diameter are increased?
View answer and explanation
Correct option: A
Frequency decreases
Option A (Frequency decreases) is correct because increasing the length and diameter of a stretched spring reduces its natural frequency of vibration.
337
Medium
337 of 483
Analyzing
+4 | -1
Out of the following functions representing motion of a particle which represents SHM (i) (ii) (iii) (iv)
View answer and explanation
Correct option: D
Only (i) and (iii)
Option D (Only (i) and (iii)) is correct because only these functions can be expressed in the form or .
338
Medium
338 of 483
Application
+4 | -1
Two pendulums of lengths 1m and 1.21m respectively start swinging together with same amplitude. The number of vibrations that will be executed by the longer pendulum before the two will swing together again are
View answer and explanation
Correct option: B
10
Option B (10) is correct because the number of vibrations executed by the longer pendulum before they swing together again is calculated based on the ratio of their time periods.
339
Medium
339 of 483
Understanding
+4 | -1
The speed of the particle on a reference circle of radius is . The time period of oscillations of the projection on a diameter of the circle is
View answer and explanation
Correct option: B
Option B is correct because the time period of oscillations is equal to the circumference of the reference circle divided by the speed of the particle.
340
Medium
340 of 483
Application
+4 | -1
A spring is stretched by when a mass of is suspended from it. The period of oscillations of the spring loaded by and put to oscillations is close to__
View answer and explanation
Correct option: C
Option C (0.82 s) is correct because the period of oscillation is calculated using the formula T = 2*pi*sqrt(m/k), where k is the spring constant.
341
Medium
341 of 483
Analyzing
+4 | -1
The acceleration of a particle moving along -axis is . It is released from . Here ' ' and ' ' are in S.I. units. The motion of particle will be :-
View answer and explanation
Correct option: D
Simple harmonic
Option D is correct because the acceleration can be written in the form a = -kx', which indicates simple harmonic motion.
342
Medium
342 of 483
Application
+4 | -1
The Displacement of a particle varies with time as (in ). if its motion is S.H.M, Then its maximum accelaration is
View answer and explanation
Correct option: B
Option B () is correct because the displacement equation can be simplified to , and the maximum acceleration is where is the amplitude and is the angular frequency.
343
Medium
343 of 483
Application
+4 | -1
The maximum force acting on a particle executing simple harmonic motion is . The force on the particle when it is midway between mean and extreme positions will be
View answer and explanation
Correct option: C
Option C (5 N) is correct because the force on a particle in SHM is proportional to its displacement from the mean position, so at midway, the force is half of the maximum force.
344
Medium
344 of 483
Analyzing
+4 | -1
Assertion: Time average KE and time average PE are not exactly equal in simple pendulum.
Reason: Friction is not negligible in simple pendulum.
Reason: Friction is not negligible in simple pendulum.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because friction causes energy loss, leading to unequal average KE and PE.
345
Easy
345 of 483
Understanding
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Assertion: In simple harmonic motion, the motion is to and fro and periodic
Reason: Velocity of the particle in simple harmonic motion (where is the displacement and is spring factor).
Reason: Velocity of the particle in simple harmonic motion (where is the displacement and is spring factor).
View answer and explanation
Correct option: C
If Assertion is true but Reason is false
Option C is correct because the assertion is true (SHM is to and fro and periodic), but the reason provides an incorrect formula for the velocity in SHM.
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346
Medium
346 of 483
Application
+4 | -1
The bob of a pendulum of length l is pulled aside from its equilibrium position through an angle θ and then released. The bob will then pass through its equilibrium position with a speed , where equals
View answer and explanation
Correct option: A
Option A () is correct because it is derived from the conservation of energy, equating the potential energy at the initial position to the kinetic energy at the equilibrium position.
347
Medium
347 of 483
Analyzing
+4 | -1
Which of the following quantity is always negative in S.H.M? (Symbols have their usual meanings)
View answer and explanation
Correct option: A
The correct answer is A because in SHM, the force and displacement are always in opposite directions, making their dot product negative.
348
Easy
348 of 483
Analyzing
+4 | -1
Statement-1: A particle is moving along -axis. The resultant force acting on it is given by where and are both positive constants. The motion of this particle is not S.H.M.
Statement-2: In S.H.M. resultant force must be proportional to the displacement from mean position.
Statement-2: In S.H.M. resultant force must be proportional to the displacement from mean position.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because the force equation indicates SHM about a shifted equilibrium, and the definition of SHM requires proportionality to displacement from the *mean* position.
349
Hard
349 of 483
Application
+4 | -1
The phase difference (in radian) between two SHM whose equations are and at is:
View answer and explanation
Correct option: B
Option B () is correct because it is the phase difference calculated at t=0.5s using the given SHM equations.
350
Easy
350 of 483
Application
+4 | -1
The acceleration of a particle in SHM at 5 cm from its mean position is The value of angular frequency in radian/sec will be:
View answer and explanation
Correct option: B
4
Option B (4) is correct because the angular frequency can be found using the formula a = ω²y.
351
Medium
351 of 483
Understanding
+4 | -1
Which of the following functions represents a simple harmonic oscillation?
View answer and explanation
Correct option: A
Option A () is correct because it can be expressed as a single sinusoidal function, satisfying the condition for SHM.
352
Medium
352 of 483
Application
+4 | -1
A heavy brass sphere is hung from a spring and it executes vertical vibrations with period . The sphere is now immersed in a non-viscous liquid with a density th that of brass. When set into vertical vibrations with the sphere remaining inside liquid all the time, the time period will be
View answer and explanation
Correct option: D
Unchanged
Option D (Unchanged) is correct because the time period of a mass oscillating on a spring is independent of the acceleration due to gravity (g).
353
Medium
353 of 483
Application
+4 | -1
The ratio of angular speed of a second- hand to the hour-hand of a watch is:
View answer and explanation
Correct option: B
Option B () is correct because the hour hand takes 12 hours to complete a revolution while the second hand takes 60 seconds to complete a revolution, leading to the ratio of their angular speeds being 720:1.
354
Medium
354 of 483
Understanding
+4 | -1
(A): Since and cosine functions are periodic functions
(R): Sinusoidal functions repeat its values after a definite interval of time
(R): Sinusoidal functions repeat its values after a definite interval of time
View answer and explanation
Correct option: A
If Both A R are true and R is correct explanation of A
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why sine and cosine functions are periodic.
355
Medium
355 of 483
Application
+4 | -1
A particle performs linear S.H.M. At a particular instant, velocity of the particle is ' ' and acceleration is ' ' while at another instant velocity is ' ' and acceleration is ' ' . The distance between the two positions is
View answer and explanation
Correct option: A
Option A () is correct because it is derived from the equations of SHM relating velocity, acceleration, and displacement.
356
Medium
356 of 483
Application
+4 | -1
The ratio of the magnitudes of maximum velocity to the maximum acceleration of a particle making is . The minimum time taken by the particle to move between the extreme points of its path is
View answer and explanation
Correct option: B
Option B (3.14 S) is correct because it correctly uses the ratio of maximum velocity to maximum acceleration to find the time period and then half of it.
357
Medium
357 of 483
Understanding
+4 | -1
Assertion (A): Damped vibrations indicate loss of energy.
Reason (R): The loss may be due to friction, air resistance etc.
Reason (R): The loss may be due to friction, air resistance etc.
View answer and explanation
Correct option: A
If Both A R are true and R is correct explanation of A
Option A is correct because damped vibrations indeed indicate energy loss, and this loss is accurately attributed to factors like friction and air resistance.
358
Medium
358 of 483
Application
+4 | -1
A vertical spring with a load of mass has the same frequency of oscillation as that of a seconds pendulum at a place. The spring constant of the spring is nearly
View answer and explanation
Correct option: B
1
Option B (1) is correct because the spring constant is calculated by equating the frequency of the spring-mass system to that of a seconds pendulum.
359
Medium
359 of 483
Application
+4 | -1
Time period of a simple pendulum of length is and time period of uniform rod of same length pivoted about one end and oscillating in a vertical plane is . Amplitude of oscillations in both the cases is small, then is
View answer and explanation
Correct option: C
Option C () is correct because it represents the ratio of the time periods of a simple pendulum and a uniform rod oscillating about one end, calculated using their respective formulas.
360
Medium
360 of 483
Application
+4 | -1
A particle is executing SHM of amplitude ' ' and time period ' '. Find the time (T) taken by the particle to go from to .
View answer and explanation
Correct option: A
Option A (T/12) is correct because the time taken to go from x=0 to x=A/2 in SHM is T/12, derived from the equation x = A sin(ωt).
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Showing 331-360 of 483 questions
