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JEE • PHYSICS • NUCLEI

Nuclei practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 351 questions

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181 Medium
181 of 351
Understanding +4 | -1
Choose the suitable condition in order to carry out the nuclear reaction

1H1+1H1+1H2=2H4+1e0+ energy { }_1 \mathrm{H}^1+{ }_1 \mathrm{H}^1+{ }_1 \mathrm{H}^2={ }_2 \mathrm{H}^4+{ }_1 \mathrm{e}^0+\text { energy }
View answer and explanation
Correct option: C
very high temperature and relatively high pressure would be necessary
Option C (very high temperature and relatively high pressure would be necessary) is correct because nuclear fusion requires extremely high temperatures and pressures to overcome electrostatic repulsion.
182 Medium
182 of 351
Application +4 | -1
A nuclear reactor delivers a power of 109 W10^9 {~W}. What is the amount of fuel consumed by the reactor in one hour?
View answer and explanation
Correct option: A
0.04 g0.04 {~g}
Option A (0.04 g0.04 {~g}) is correct because it is calculated using the mass-energy equivalence formula E=mc2E = mc^2.
183 Medium
183 of 351
Application +4 | -1
In an experiment, the activity of 1.2 milligrams of radioactive potassium chloride (chloride of isotope K−40\mathrm{K}-40 ) was found to be 170 s−1170 \mathrm{~s}^{-1}. Taking molar mass of to be 0.075 kg mole−10.075 \mathrm{~kg} \mathrm{~mole}^{-1}, find the number of K−40K-40 atoms in the same and hence find the half-life of K-40. Avogadros' number =6.0×1023=6.0 \times 10^{23} mole −1^{-1}.
View answer and explanation
Correct option: A
3.91×1016s3.91 \times 10^{16} \mathrm{s}
Option B (1.062×10−2amp1.062 \times {10^{ - 2}}\mathrm{ amp}) is correct because it is the displacement current calculated using the given parameters of the parallel plate capacitor.
184 Medium
184 of 351
Application +4 | -1
The ratio of molecular mass of two radioactive substances is 3/2\mathrm{3/2} and the ratio of their decay constants is 4/3\mathrm{4/3}. Then, the ratio of their initial activity per mole will be
View answer and explanation
Correct option: B
4/34/3
Option B (4/3) is correct because the ratio of initial activities is equal to the ratio of their decay constants, as the number of nuclei per mole is the same for both substances.
185 Medium
185 of 351
Remembering +4 | -1
Mean life of neutron is about
View answer and explanation
Correct option: B
1000 seconds\begin{array}{llllllllllllllllllll} {\mathrm{1000 }\,\mathrm{seconds}} \end{array}
Option B (1000 seconds) is correct because the mean life of a neutron is approximately 1000 seconds.
186 Medium
186 of 351
Application +4 | -1
Calculate the radius of Ge70\mathrm{Ge}^{70}. Given R0=1.1 fmR_0=1.1 \mathrm{~fm}
View answer and explanation
Correct option: D
4.53 fm4.53 \mathrm{~fm}
Option B is correct because the initial acceleration is calculated using the thrust force and the mass of the rocket.
187 Medium
187 of 351
Understanding +4 | -1
In a fission process, nucleus AA divides into two nuclei BB and CC, their binding energies being Ea,Eb{E_a},{E_b} and Ec{E_c} respectively. Then
View answer and explanation
Correct option: B
Eb+  Ec>Ea{E_b} + \,\,{E_c} > {E_a}
Option B (Eb+ Ec>Ea{E_b} + \,{E_c} > {E_a}) is correct because the binding energy per nucleon is higher for the fission products than for the original nucleus.
188 Medium
188 of 351
Application +4 | -1
A radioactive sample has 6.0×10186.0 \times 10^{18} active nuclei at a certain instant. How many of these nuclei will still be in the same active state after two half-lives?
View answer and explanation
Correct option: A
1.5×10181.5 \times 10^{18}
Option A (1.5×10181.5 \times 10^{18}) is correct because after two half-lives, the number of active nuclei is reduced to one-fourth of the original number.
189 Medium
189 of 351
Application +4 | -1
The mass number of HeHe is 4\mathrm{4} and that for sulphur is 32\mathrm{32}. The radius of sulphur nucleus is larger than that of helium, by times
View answer and explanation
Correct option: C
2
Option C (2) is correct because the radius of a nucleus is proportional to the cube root of its mass number, so the ratio of radii is the cube root of the ratio of mass numbers.
190 Medium
190 of 351
Understanding +4 | -1
O2{O}_2 molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms
View answer and explanation
Correct option: A
Is not important because nuclear forces are short-ranged
Option A is correct because nuclear forces are short-ranged and do not significantly affect the interaction between nuclei in a molecule like O2, where the nuclei are relatively far apart.
191 Medium
191 of 351
Application +4 | -1
A heavy nucleus X\mathrm{X} of mass number 240 and binding energy per nucleon 7.6 MeV7.6 \mathrm{~MeV} is split into two fragments Y\mathrm{Y} and Z\mathrm{Z} of mass numbers 110 and 130. The binding energy of nucleons in Y\mathrm{Y} and Z\mathrm{Z} is 8.5 MeV\mathrm{MeV} per nucleon. Calculate the energy Q\mathrm{Q} released per fission in MeV\mathrm{MeV}
View answer and explanation
Correct option: D
216 MeV216 \mathrm{~MeV}
Option D (216 MeV) is correct because the energy released is the difference between the binding energies of the products and the reactant.
192 Medium
192 of 351
Understanding +4 | -1
The volume of a nucleus is directly proportional to
(where A=A = mass number of the nucleus)
View answer and explanation
Correct option: A
AA
Option A (AA) is correct because the volume of a nucleus is directly proportional to its mass number.
193 Medium
193 of 351
Application +4 | -1
What is approximately the ratio of nuclear radii of gold isotope 79238Au_{79}^{238}Au and silver isotope 47108Ag_{47}^{108}Ag.
View answer and explanation
Correct option: A
1.23
Option A (1.23) is correct because it is the approximate ratio calculated using the formula relating nuclear radius and mass number.
194 Medium
194 of 351
Understanding +4 | -1
Choose the WRONG statement.
View answer and explanation
Correct option: D
The nuclear force becomes very strong if
the nucleus contains a large number of
nucleons
Option D (The nuclear force becomes very strong if the nucleus contains a large number of nucleons) is the WRONG statement because while nuclear force is strong, adding too many nucleons can lead to instability.
195 Medium
195 of 351
Understanding +4 | -1
Mass of the nucleons together in a heavy nucleus is
View answer and explanation
Correct option: A
Greater than mass of nucleus
Option A is correct because the mass of the nucleons (protons and neutrons) when separate is greater than the mass of the nucleus they form due to the binding energy.
196 Medium
196 of 351
Understanding +4 | -1
Two nuclei hare their mass numbers in the ratio of 1 : 3, the ratio of their nuclear densities would be
View answer and explanation
Correct option: B
0.042361111
Option B is correct because nuclear density is independent of mass number.
197 Medium
197 of 351
Understanding +4 | -1
The decay of a proton to neutron is
View answer and explanation
Correct option: B
possible only inside the nucleus
Option B (possible only inside the nucleus) is correct because the neutron is more massive than the proton, and this mass difference can be compensated by the binding energy inside the nucleus.
198 Medium
198 of 351
Understanding +4 | -1
When the number of nucleons in nuclei increase, the binding energy per nucleon
View answer and explanation
Correct option: D
First increases and then decreases with increases of mass number
Option D (First increases and then decreases with increases of mass number) is correct because the binding energy per nucleon initially increases, reaches a peak, and then gradually decreases as the mass number increases.
199 Medium
199 of 351
Understanding +4 | -1
Mass numbers of two nuclei are in the ratio of 4:34: 3. Their nuclear densities will be in the ratio of
View answer and explanation
Correct option: C
1:11: 1
Option C is correct because nuclear density is independent of the mass number.
200 Medium
200 of 351
Application +4 | -1
A certain substance decays 132\frac{1}{32} of its initial activity in 50 days. Calculate its half-life.
View answer and explanation
Correct option: C
10
Option C (10) is correct because the half-life is calculated by finding the number of half-lives in the given time and dividing the total time by that number.
201 Medium
201 of 351
Application +4 | -1
Consider a radioactive substance which decays, following the law of disintegration. At an instant t1t_1 its activity is RR and at time t2t_2 it becomes 1R\frac{1}{R}. Find the average life of radioactive substance, if t2>t1t_2 > t_1.
View answer and explanation
Correct option: C
(t2−t1)2ln⁡(R)\frac{\left(t_2-t_1\right)}{2 \ln (R)}
Option C ((t2−t1)2ln⁡(R)\frac{\left(t_2-t_1\right)}{2 \ln (R)}) is correct because it correctly relates the average life to the given activities at times t1t_1 and t2t_2.
202 Medium
202 of 351
Application +4 | -1
10  g10\,\,g of radioactive material of half-life 15 year\mathrm{15 }\,\mathrm{year} is kept in store for 20 years\mathrm{20 }\,\mathrm{years}. The disintegrated material is
View answer and explanation
Correct option: C
6.03  g6.03\,\,g
Option C (6.03 g6.03\,g) is correct because after 20 years, approximately 6.03g of the radioactive material will have disintegrated.
203 Medium
203 of 351
Application +4 | -1
The half-life of radioactive Radon is 3.8  days\mathrm{3}.\mathrm{8}\,\,\mathrm{days}. The time at the end of which (1/20\mathrm{1/20})th of the Radon sample will remain undecayed is (given log⁡10 e=0.4343{\log _{10}}\,e = 0.4343)
View answer and explanation
Correct option: B
16.5 days\mathrm{16}\mathrm{.5 }\,\mathrm{days}
Option B (16.5 days\mathrm{16}\mathrm{.5 }\,\mathrm{days}) is correct because it is calculated using the half-life formula and the given logarithmic value.
204 Medium
204 of 351
Understanding +4 | -1
Which of the following cannot be emitted by radioactive substances during their decay?
View answer and explanation
Correct option: A
Protons
Option A (Protons) is correct because protons are not typically emitted during radioactive decay processes such as alpha, beta, or gamma decay.
205 Medium
205 of 351
Understanding +4 | -1
The ratio of the density of oxygen nucleus (816O)\left({ }_{8}^{16} \mathrm{O}\right) and helium nucleus (24He)\left({ }_{2}^{4} \mathrm{He}\right) is
View answer and explanation
Correct option: C
1:11: 1
Option C (1:1) is correct because nuclear density is approximately constant for all nuclei, independent of mass number.
206 Medium
206 of 351
Application +4 | -1
Half-life of a radioactive substance is 20  minutes20\,\,minutes. Difference between points of time when it is 33  %\mathrm{33}\,\,\mathrm{\% } disintegrated and 67  %\mathrm{67}\,\,\mathrm{\% } disintegrated is approximately
View answer and explanation
Correct option: B
20  min⁡20\,\,\min
Option B (20  min⁡20\,\,\min) is correct because it is the approximate difference in time between 33% and 67% disintegration, calculated using the half-life formula.
207 Medium
207 of 351
Understanding +4 | -1
Nuclear fission can be explained based on
View answer and explanation
Correct option: B
Liquid drop model
Option B (Liquid drop model) is correct because the liquid drop model of the nucleus explains nuclear fission by treating the nucleus as a liquid drop.
208 Medium
208 of 351
Understanding +4 | -1
The rad is the correct unit used to report the measurement of
View answer and explanation
Correct option: C
The biological effect of radiation
Option C (The biological effect of radiation) is correct because the rad is a unit used to measure the absorbed dose of radiation, which is related to its biological effect.
209 Medium
209 of 351
Understanding +4 | -1
The mass of an α\alpha-particle is
View answer and explanation
Correct option: A
Less than the sum of masses of two protons and two neutrons
Option D (Equal to sum of masses of two protons and two neutrons) is incorrect because the mass of an alpha particle is less than the sum of the masses of its constituent protons and neutrons due to the binding energy.
210 Medium
210 of 351
Application +4 | -1
Calculate binding energy of helium nuclei

Given mp=1.0073um_p=1.0073 \mathrm{u}

mn=1.0087u\mathrm{m}_{\mathrm{n}}=1.0087 \mathrm{u}

Nuclear mass of He4=4.0015u\mathrm{He}^4=4.0015 \mathrm{u}
View answer and explanation
Correct option: A
28.4MeV28.4 M e V
Option A (28.4MeV28.4 M e V) is correct because it is the binding energy calculated using the mass defect and the energy equivalent.
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