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JEE • PHYSICS • NUCLEI

Nuclei practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 351 questions
31 Medium
31 of 351
Application +4 | -1
If mass of U235=235.12142amuU^{235}=235.12142 \mathrm{amu}, mass of U236=1.008665amu\mathrm{U}^{236}=1.008665 \mathrm{amu}, then the energy required to remove one neutron from the nucleus U236\mathrm{U}^{236} is nearly about -
View answer and explanation
Correct option: B
6.5MeV6.5 \mathrm{MeV}
Option B (6.5MeV6.5 \mathrm{MeV}) is correct because the energy required to remove a neutron is equal to the mass defect multiplied by the energy equivalent of 1 amu (931 MeV).
32 Medium
32 of 351
Understanding +4 | -1
Nuclear fission experiments show that the neutrons split the uranium nuclei into two fragments of about same size. This process is accompanised by the emission of several
View answer and explanation
Correct option: C
Neutrons
Option C (Neutrons) is correct because nuclear fission is accompanied by the emission of several neutrons, which sustain the chain reaction.
33 Medium
33 of 351
Remembering +4 | -1
Atomic nuclei having same mass number but difference atomic numbers are called
View answer and explanation
Correct option: A
Isobars
Option A (Isobars) is correct because isobars are defined as atomic nuclei having the same mass number but different atomic numbers.
34 Medium
34 of 351
Remembering +4 | -1
Modern treatment method P.E.T. is besed on !
View answer and explanation
Correct option: B
Positron emission
Option B (Positron emission) is correct because P.E.T. stands for Positron Emission Tomography.
35 Medium
35 of 351
Remembering +4 | -1
In nuclear fusion process, heat energy released is
View answer and explanation
Correct option: A
26.7 MeV26.7 \, \mathrm{MeV}
Option A (26.7 MeV26.7 \, \mathrm{MeV}) is correct because it's the approximate energy released during the fusion of light nuclei into heavier ones, specifically in reactions like the proton-proton chain.
36 Medium
36 of 351
Application +4 | -1
An unstable element is produced in a nuclear reactor at a constant rate. If its half life is 100 years, how much time in years is required to produce 50%50 \% of the equilibrium quantity?
View answer and explanation
Correct option: A
100
Option A (100) is correct because the time required to produce 50% of the equilibrium quantity is equal to the half-life of the unstable element.
37 Medium
37 of 351
Application +4 | -1
Calculate the disintegration energy Q for the fission of  4298M{ ~}_{42}^{98} \mathrm{M} o into two equal fragments, 2149 Sc{ }_{21}^{49} \mathrm{~S} c. If QQ turns out to be positive, explain why this process does not occur spontaneously. Given that :

m(4298Mo)=97.90541 amum\left({ }_{42}^{98} \mathrm{Mo}\right) =97.90541 \mathrm{~amu}

m(2149Sc)=48.95002 amum\left({ }_{21}^{49} \mathrm{Sc}\right) =48.95002 \mathrm{~amu}

mn=1.00867 amum_n =1.00867 \mathrm{~amu}.
View answer and explanation
Correct option: B
944.6 MeV944.6 \mathrm{~MeV}
Option B (944.6 MeV944.6 \text{{ MeV}}) is correct because it is the disintegration energy Q calculated using the mass defect and the conversion factor from amu to MeV.
38 Medium
38 of 351
Understanding +4 | -1
For the radioactive nuclei that undergo either α\alpha or β\beta-decay, which one of the following cannot occur?
View answer and explanation
Correct option: B
Isotope of original nucleus
Option B is correct because alpha and beta decay change the atomic number, thus an isotope of the original nucleus cannot be formed.
39 Medium
39 of 351
Understanding +4 | -1
Two nucleons are at a separation of 1 fm\mathrm{1 }\,\mathrm{fm}. The net force between them is F1{\mathrm{F}_\mathrm{1}} if both neutrons, F2{F_2} if both are protons, and F3{F_3} if one is a proton and the other is a neutron.
View answer and explanation
Correct option: C
F1=F3>F2{F_1} = {F_3} > {F_2}
Option C is correct because the nuclear force is approximately the same between any two nucleons (neutron-neutron, proton-proton, or proton-neutron), but the electrostatic repulsion between protons reduces the net force.
40 Medium
40 of 351
Understanding +4 | -1
Read the following statements:

(A) Volume of the nucleus is directly proportional to the mass number.

(B) Volume of the nucleus is independent of mass number.

(C) Density of the nucleus is directly proportional to the mass number.

(D) Density of the nucleus is directly proportional to the cube root of the mass number.

(E) Density of the nucleus is independent of the mass number.
Choose the correct option from the following options
View answer and explanation
Correct option: B
(A)(\mathrm{A}) and (E)(\mathrm{E}) only
The correct answer is B ((A) and (E) only) because the volume of the nucleus is proportional to the mass number, and the density is independent of it.
41 Medium
41 of 351
Analyzing +4 | -1
Fpe{\mathbf{F}_{pe}} represents electrical force on proton due to electron and Fep{\mathbf{F}_{ep}} on electron due to proton in a hydrogen atom.Similarly Fpe{\mathbf{F}_{pe}} represents the gravitational force on proton due to electron and Fep{\mathbf{F}_{ep}} the corresponding force on electron due to proton. Which of the following is not true?
View answer and explanation
Correct option: D
FPe+F′ Pe=0{\mathbf{F}_{Pe}} + \mathbf{F'}{\,_{Pe}} = 0
Option D (FPe+F′ Pe=0{\mathbf{F}_{Pe}} + \mathbf{F'}{\,_{Pe}} = 0) is not true because the electrical and gravitational forces between the proton and electron are not necessarily equal and opposite.
42 Medium
42 of 351
Analyzing +4 | -1
The half-life period of a radioactive element X is same as the mean life time of another radioactive element Y. Initially both of them have the same number of atoms. Then
View answer and explanation
Correct option: C
Y will decay at a faster rate than X initially
Option C (Y will decay at a faster rate than X initially) is correct because the decay constant of Y is greater than that of X, leading to a faster initial decay rate.
43 Medium
43 of 351
Remembering +4 | -1
Which of the following has the mass closest in value to that of the positron
1  a.m.u=931  MeV1\,\,a.m.u = 931\,\,MeV
View answer and explanation
Correct option: B
Electron
Option B (Electron) is correct because a positron is the antiparticle of an electron, and thus has the same mass as an electron.
44 Medium
44 of 351
Remembering +4 | -1
The density of uranium is of the order of
View answer and explanation
Correct option: A
1020  kgm−3{10^{20}}\,\,\mathrm{kg}{\mathrm{m}^{ - 3}}
Option D (1017 kg/m−3{10^{17}} \,\mathrm{kg}/\mathrm{m}^{ - 3}) is the closest order of magnitude to the actual density of the nucleus.
45 Medium
45 of 351
Understanding +4 | -1
Nuclear binding energy is equivalent to
View answer and explanation
Correct option: D
Mass defect of nucleus
Option D (Mass defect of nucleus) is correct because the nuclear binding energy is equivalent to the mass defect of the nucleus multiplied by c² (from E=mc²).
46 Medium
46 of 351
Understanding +4 | -1
Ionization power and penetration range of radioactive radiation increases in the order
View answer and explanation
Correct option: B
γ,β,α\mathrm{\gamma },\mathrm{\beta },\mathrm{\alpha } and α,β,γ\mathrm{\alpha },\mathrm{\beta },\mathrm{\gamma } respectively
Option D is correct because alpha particles have the highest ionization power and the lowest penetration range, while gamma rays have the lowest ionization power and the highest penetration range.
47 Medium
47 of 351
Application +4 | -1
The half-life of radium is 1600 years. After how many years 25%25 \% of a radium block remains undecayed?
View answer and explanation
Correct option: C
32003200 years
Option C (32003200 years) is correct because it accurately calculates the time required for the radium block to decay to 25% of its original amount, using the concept of half-life.
48 Medium
48 of 351
Application +4 | -1
A 280 days old radioactive substance shows an activity of 6000 dps, 140 days later it’s activity becomes 3000 dps. What was its initial activity.
View answer and explanation
Correct option: B
24000 dps
Option B (24000 dps) is correct because the initial activity is calculated by using the half-life formula and the given activities at different times.
49 Medium
49 of 351
Application +4 | -1
The radius of germanium (Ge\mathrm{Ge}) nuclide is measured to be twice the radius of 49Be{}_4^9\mathrm{Be}. The number of nucleons in Ge\mathrm{Ge} are
View answer and explanation
Correct option: D
72
Option D (72) is correct because the number of nucleons is calculated using the relationship between nuclear radius and mass number.
50 Medium
50 of 351
Remembering +4 | -1
Average binding energy of a nucleon inside an atomic nucleus is about
View answer and explanation
Correct option: A
8 MeV8 \, {MeV}
Option A (8 MeV8 \, {MeV}) is correct because the average binding energy per nucleon in an atomic nucleus is approximately 8 MeV.
51 Medium
51 of 351
Analyzing +4 | -1
Assertion: All natural radioactive elements are ultimately converted to lead.

Reason: All the elements above lead are unstable.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion.
Option B is correct because all natural radioactive elements decay until they reach a stable element, and lead is a stable element, but not all elements above lead are unstable.
52 Medium
52 of 351
Remembering +4 | -1
One Becquerel is defined as
View answer and explanation
Correct option: A
1\mathrm{1} disintegration per sec
Option A (1 disintegration per sec) is correct because the Becquerel (Bq) is the SI unit of radioactivity, defined as one disintegration per second.
53 Medium
53 of 351
Understanding +4 | -1
In β+\beta^{+}emission what happens to upquarks
View answer and explanation
Correct option: B
Is converted into down-quarks
Option B (Is converted into down-quarks) is correct because in β+\beta^+ decay, an up quark transforms into a down quark.
54 Medium
54 of 351
Understanding +4 | -1
Choose the incorrect statement about the strong nuclear force.
View answer and explanation
Correct option: D
The force of interaction F is proportional to 1r2\frac{1}{{{r^2}}}
Option D (The force of interaction F is proportional to 1r2\frac{1}{{{r^2}}}) is correct because the strong nuclear force does not follow the inverse square law.
55 Medium
55 of 351
Understanding +4 | -1
Consider α−Particles,  β−Particles  and  γ−rays\alpha - \mathrm{Particles},\,\,\mathrm{\beta } - \mathrm{Particles }\,\,\mathrm{and}\,\,\gamma - \mathrm{rays}, each having an energy of 0.5 MeV\mathrm{0}\mathrm{.5 }\,\mathrm{MeV}. In increasing order of penetrating powers, the radiations are
View answer and explanation
Correct option: A
α,  β,  γ\alpha ,\,\,\beta ,\,\,\gamma
Option A is correct. Alpha particles have the lowest penetrating power, followed by beta particles, and then gamma rays have the highest penetrating power.
56 Medium
56 of 351
Application +4 | -1
A uranium reactor develops thermal energy at a rate of 300 MW. Calculate the amount of 235U{ }^{235} \mathrm{U} being consumed every second. Average energy released per fission is 200 MeV200 \mathrm{~MeV}.
View answer and explanation
Correct option: A
3.7 mg3.7 \mathrm{~mg}
Option A (3.7 mg3.7 \mathrm{~mg}) is correct because it's the mass of 235U^{235} \mathrm{U} consumed per second, calculated from the power and energy per fission.
57 Medium
57 of 351
Application +4 | -1
A radioactive isotope X\mathrm{X} with a half-life of 1.37  ×  1091.37\,\, \times \,\,{10^9} years decays to YY which is stable. A sample of rock from the moon was found to contain both the elements XX and YY which were in the ratio 1:7\mathrm{1:7}. The age of the rock is
View answer and explanation
Correct option: C
4.11  ×  109  years4.11\,\, \times \,\,{10^9}\,\,years
Option C (4.11×1094.11 \times 10^9 years) is correct because it is calculated by determining the number of half-lives that have passed based on the ratio of the parent and daughter isotopes.
58 Medium
58 of 351
Application +4 | -1
The half life period of radioactive nucleus is 12.5 hours and its mass is 256 gm. The time after which amount of remaining substance is 1gm will be...... hours
View answer and explanation
Correct option: A
100
Option A (100) is correct because after 100 hours, the remaining substance will be 1gm, calculated using the half-life formula.
59 Medium
59 of 351
Remembering +4 | -1
Which is the correct expression for half-life
View answer and explanation
Correct option: D
(t)1/2=2.303  log⁡2λ{\left( t \right)_{1/2}} = \frac{{2.303\,\,\log 2}}{\lambda }
Option D ((t)1/2=2.303  log⁡2λ{\left( t \right)_{1/2}} = \frac{{2.303\,\,\log 2}}{\lambda }) is correct because it is the correct formula for half-life in terms of the decay constant.
60 Medium
60 of 351
Understanding +4 | -1
For a nucleus ZAX{ }_Z^A X having mass number A{A} and atomic number Z{Z}

A. The surface energy per nucleon (bs)=a1A2/3\left(b_s\right)=a_1 A^{2 / 3}

B. The coulomb contribution to the binding energy bc=−a2Z(Z−1)A4/3b_c=-a_2 \frac{Z(Z-1)}{A^{4 / 3}}

C. The volume energy bv=a3Ab_v=a_3 A

D. Decrease in the binding energy is proportional surface area.

E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons,
( a1,a2a_1, a_2 and a3a_3 are constants)

Choose the most appropriate answer form the options given below;
View answer and explanation
Correct option: A
C, D only
Option C (A, D only) is correct because the surface energy is inversely proportional to A(1/3), and the decrease in binding energy is proportional to surface area.
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