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JEE • PHYSICS • NUCLEI

Nuclei practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 351 questions

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271 Medium
271 of 351
Understanding +4 | -1
Given below are two statements: one is labelled as
Assertion A and the other is labelled as Reason R

Assertion A : The binding energy per nucleon is
practically independent of the atomic number for
nuclei of mass number in the range 30 to 170.

Reason R : Nuclear force is short ranged.

In the light of the above statements, choose the
correct answer from the options given below
View answer and explanation
Correct option: B
Both A and R are true and R is the correct
explanation of A
Option B (Both A and R are true and R is the correct explanation of A) is correct because the short-range nature of the nuclear force explains the near-constant binding energy per nucleon.
272 Medium
272 of 351
Application +4 | -1
In half life of a radio isotope is 2  seconds\mathrm{2}\,\,\mathrm{seconds} and number of atoms are only 4\mathrm{4}, then after one half life remaining (without decay) atoms are probably
View answer and explanation
Correct option: B
2\mathrm{2}
Option B (2) is correct because after one half-life, half of the radioactive atoms will have decayed, leaving half of the original number.
273 Medium
273 of 351
Understanding +4 | -1
Assertion: Radioactive nuclei emit β−1\beta^{-1} particles.
Reason: Electrons exist inside the nucleus.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because radioactive nuclei do emit β−1\beta^{-1} particles, but electrons do not exist inside the nucleus.
274 Medium
274 of 351
Application +4 | -1
A count rate metre shows a count of 240\mathrm{240} per minute from a given radioactive source later the metre shows a count rate 0f 30  min⁡−130\,\,{\min ^{ - 1}}⁡ . The half-life of the source is
View answer and explanation
Correct option: C
20 min\mathrm{20}\,\mathrm{ min}
Option C (20 min) is correct because it is the half-life that satisfies the decay equation given the initial and final count rates over a period of 60 minutes.
275 Medium
275 of 351
Application +4 | -1
In a reactor, 2kg of 92U235_{92}{U^{235}} fuel is fully used up in 30 days. The energy released per fission is 200 MeV.
Given that, the Avogadro number, N=6.023×1026K−1 mol−1N = 6.023 \times {10^{26}}{K^{ - 1}}\,mo{l^{ - 1}} and 1  eV=1.6×10−19J.1\,\,eV = 1.6 \times {10^{ - 19}}J. The power output of the reactor is close to
View answer and explanation
Correct option: C
60 MW
Option C (60 MW) is correct because it is the closest value to the calculated power output of the reactor, considering the energy released per fission and the amount of fuel used.
276 Medium
276 of 351
Understanding +4 | -1
At a specific instant emission of radioactive compound is deflected in a magnetic field. The compound cannot emit
View answer and explanation
Correct option: D
neutrons
Option D (neutrons) is correct because neutrons are neutral particles and are not deflected by magnetic fields.
277 Medium
277 of 351
Remembering +4 | -1
π\pi mesons can be
View answer and explanation
Correct option: D
π+{\pi ^ + }, π−{\pi ^ - } or π0{\pi ^0}
Option D (π+{\pi ^ + }, π−{\pi ^ - } or π0{\pi ^0}) is correct because pions can be positively charged, negatively charged, or neutral.
278 Medium
278 of 351
Application +4 | -1
The half -life period of a radioactive substance is 20 days. What is the time taken for (7/8)th (7 / 8)^{\text {th }} of its original mass to disintegrate?
View answer and explanation
Correct option: B
6060 days
Option B (6060 days) is correct because after 3 half-lives, (7/8)th of the substance will have disintegrated, which corresponds to 60 days.
279 Medium
279 of 351
Understanding +4 | -1
Our bodies are mostly made of hydrogen (Z=1)(\mathrm{Z}=1), carbon (Z=6)(Z=6), and oxygen (Z=8)(Z=8). In our bodies, are there many more neutrons than protons, many fewer neutrons than protons, or are there about the same number of each?
View answer and explanation
Correct option: C
There are about the same number of neutrons and protons.
Option C (There are about the same number of neutrons and protons) is correct because for lighter elements like hydrogen, carbon, and oxygen, the number of neutrons is approximately equal to the number of protons.
280 Medium
280 of 351
Application +4 | -1
A radio active material is reduced to 1/81 / 8 of its original amount in 3 days. If 8×10−3 kg8 \times 10^{-3} \, \mathrm{kg} of the material is left after 5 days the initial amount of the material is
View answer and explanation
Correct option: D
256 g256 \, \mathrm{g}
Option D (256,g256 \\, \mathrm{g}) is correct because it is the initial amount calculated using the half-life and the amount remaining after 5 days.
281 Medium
281 of 351
Understanding +4 | -1
If the nuclear force between two protons, two neutrons and between proton and neutron is denoted by Fpp,Fnn\mathrm{F}_{\mathrm{pp}}, \mathrm{F}_{\mathrm{nn}} and Fpn\mathrm{F}_{\mathrm{pn}} respectively, then
View answer and explanation
Correct option: D
Fpp≠Fnn≠FpuF_{p p} \neq F_{n n} \neq F_{p u}
Option C (Fpp=Fnn=FpnF_{pp} = F_{nn} = F_{pn}) is correct because the nuclear force is approximately the same between any two nucleons regardless of whether they are protons or neutrons.
282 Medium
282 of 351
Analyzing +4 | -1
Assertion : Size of nucleus is constant in electron scattering or gamma scattering.

Reason : Electron scattering or gamma scattering is controlled by distribution of charge in
nucleus.
View answer and explanation
Correct option: C
If Assertion is True but the reason is false
Option C is correct because the size of the nucleus is determined by the distribution of nucleons (protons and neutrons), not just the charge distribution. Electron and gamma scattering can probe the size, but it's not solely controlled by charge.
283 Medium
283 of 351
Application +4 | -1
Natural water contains a small amount of tritium (13H)\left({ }_1^3 \mathrm{H}\right). This isotope beta-decays with a half-life of 12.5 years. A mountaineer while climbing towards a difficult peak finds debris of some earlier unsuccessful attempt. Among other things he finds a sealed bottle of whisky. On return he analyses the whisky and finds that it contains only 1.5 per cent of the 13H{ }_1^3 \mathrm{H} radioactivity as compared to a recently purchased bottle marked '8 years old'. Estimate the time of that unsuccessful attempt.
View answer and explanation
Correct option: A
About 83 years ago
Option A (About 83 years ago) is correct because it is calculated by using the radioactive decay formula and the given half-life of tritium to determine the time elapsed since the whisky was originally produced.
284 Medium
284 of 351
Analyzing +4 | -1
U238{U^{238}} decays into Th234T{h^{234}} by the emission of an α−\alpha - particle. There follows a chain of further radioactive decays, either by α−\alpha - decay or by β−\beta - decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. Which of the following stable nuclides is the end product of the U238{U^{238}} radioactive decay chain
View answer and explanation
Correct option: A
Pb206P{b^{206}}
Option A (Pb206P{b^{206}}) is correct because the (4n+2) series starts from U238{U^{238}} and its stable end product is Pb206P{b^{206}}.
285 Medium
285 of 351
Understanding +4 | -1
For the stability of any nucleus
View answer and explanation
Correct option: A
Binding energy per nucleon should be more
Option A is correct because a higher binding energy per nucleon indicates a more stable nucleus due to the greater energy required to separate the nucleons.
286 Medium
286 of 351
Understanding +4 | -1
During a nuclear fusion reaction
View answer and explanation
Correct option: D
Two light nuceli combine to give a heavier nucleus and possible other products
Option D (Two light nuceli combine to give a heavier nucleus and possible other products) is correct because nuclear fusion is the process where two light nuclei combine to form a heavier nucleus, releasing energy and potentially other particles.
287 Medium
287 of 351
Remembering +4 | -1
For maintaining sustained chain reaction, the following is required
View answer and explanation
Correct option: C
neutrons
Option C (neutrons) is correct because neutrons are required to sustain a chain reaction by inducing further fission events.
288 Medium
288 of 351
Application +4 | -1
If a proton and anti-proton come close to each other and annihilate, how much energy will be released
View answer and explanation
Correct option: B
3  ×  10−10  J3\,\, \times \,\,{10^{ - 10}}\,\,J
Option B (3  ×  10−10 J3\,\, \times \,\,{10^{ - 10}}\,J) is correct because the total energy released is twice the energy equivalent of the proton's mass.
289 Medium
289 of 351
Understanding +4 | -1
The rate of disintegration of fixed quantity of a radioactive element can be increased by
View answer and explanation
Correct option: D
It is not possible
Option D (It is not possible) is correct because the rate of radioactive decay is an intrinsic property of the element and is unaffected by external factors like temperature, pressure, or chemical reactions.
290 Medium
290 of 351
Remembering +4 | -1
The phenomenon of pair production is-
View answer and explanation
Correct option: D
The production of an electron and a positron from γ\gamma-rays.
Option D (The production of an electron and a positron from γ\gamma-rays) is correct because pair production is the process where a high-energy photon (gamma ray) transforms into an electron and a positron.
291 Medium
291 of 351
Understanding +4 | -1
Number of neutrons in a gold nucleus with A = 197 and Z = 79 is
View answer and explanation
Correct option: C
118
Option C (118) is correct because the number of neutrons (N) is calculated by subtracting the atomic number (Z) from the mass number (A): N = A - Z.
292 Medium
292 of 351
Understanding +4 | -1
Assertion: In He-Ne laser, population inversion takes place between energy level of neon atoms.

Reason: Helium atom has a metastable energy level.
View answer and explanation
Correct option: B
If both assertion and reason are true and reason is not correct explanation of assertion.
Option B (If both assertion and reason are true and reason is not correct explanation of assertion) is correct because both the assertion and reason are true, but the reason doesn't explain the assertion.
293 Medium
293 of 351
Understanding +4 | -1
Fusion reactions take place at high temperature because
View answer and explanation
Correct option: D
kinetic energy is high enough to overcome repulsion between nuclei
Option D (kinetic energy is high enough to overcome repulsion between nuclei) is correct because fusion requires overcoming the electrostatic repulsion between positively charged nuclei, which is achieved by high kinetic energy at high temperatures.
294 Medium
294 of 351
Application +4 | -1
An accident in a nuclear laboratory resulted in depostion of a certain amount of radioactive material of half - life 18 days inside the laboratory. Tests revealed that the radiation was 64 times more than the permissible level required for safe operation of the laboratory. What is the minimum number of days after which the laboratory can be considered safe for use?
View answer and explanation
Correct option: C
108
Option C (108) is correct because the radiation needs to decay for 6 half-lives (64=2664 = 2^6) to reach a safe level, thus 18×6=10818 \times 6 = 108 days.
295 Medium
295 of 351
Analyzing +4 | -1
Identify the pair of physical quantities that have same dimensions:
View answer and explanation
Correct option: D
wave number and Avogadro number
Option A (velocity gradient and decay constant) is correct because both have dimensions of inverse time [T⁻¹].
296 Medium
296 of 351
Application +4 | -1
If 50%50 \% of energy released during fission would be converted into electrical energy, then number of fissions in a second in a nuclear reactor of 6.4 MWMW output is (Energy per fission is 200 MeV200 \,{MeV} )
View answer and explanation
Correct option: C
4×10174 \times 10^{17}
Option C (4×10174 \times 10^{17}) is correct because it's calculated by dividing the effective power output by the energy released per fission.
297 Medium
297 of 351
Application +4 | -1
The half life of a radioactive substance is T\mathrm{T}. The time taken, for disintegrating 78\frac{7}{8} th part of its original mass will be:
View answer and explanation
Correct option: B
3T3 T
Option B (3T3T) is correct because after 3 half-lives, 78\frac{7}{8} of the original mass will have disintegrated, leaving 18\frac{1}{8} remaining.
298 Medium
298 of 351
Understanding +4 | -1
A radioactive nucleus AA finally transforms into a stable nucleus BB. Then AA and BB can be
View answer and explanation
Correct option: C
Isotopes
Option C (Isotopes) is correct because alpha and beta decays can change the number of neutrons and protons in the nucleus, resulting in isotopes.
299 Medium
299 of 351
Understanding +4 | -1
In which radioactive disintegration, neutron dissociates into proton and electron
View answer and explanation
Correct option: B
β−\beta - emission
Option B (β−\beta - emission) is correct because in beta-minus decay, a neutron in the nucleus transforms into a proton, an electron, and an antineutrino.
300 Medium
300 of 351
Analyzing +4 | -1
In the nuclear decay given below:

ZAX⟶Z+1AY⟶Z−1A−4 B∗⟶Z−1A−4 B, { }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \longrightarrow{ }_{\mathrm{Z}+1}^{\mathrm{A}}\mathrm{Y} \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B}^* \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B} \text {, }

the particles emitted in the sequence are
View answer and explanation
Correct option: D
β,α,γ\beta, \alpha, \gamma
Option D (β,α,γ\beta, \alpha, \gamma) is correct because the decays in the sequence correspond to beta, alpha, and gamma emissions, respectively.
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