Skip to main content
Back to NUCLEI

Your Progress

0 / 380 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • NUCLEI

Nuclei practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 301-330 of 380 questions

Preparing practice and saved progress…

301 Medium
301 of 380
Remembering +4 | -1
π\pi mesons can be
View answer and explanation
Correct option: D
π+{\pi ^ + }, π−{\pi ^ - } or π0{\pi ^0}
Option D (π+{\pi ^ + }, π−{\pi ^ - } or π0{\pi ^0}) is correct because pions can be positively charged, negatively charged, or neutral.
302 Medium
302 of 380
Application +4 | -1
The half -life period of a radioactive substance is 20 days. What is the time taken for (7/8)th (7 / 8)^{\text {th }} of its original mass to disintegrate?
View answer and explanation
Correct option: B
6060 days
Option B (6060 days) is correct because after 3 half-lives, (7/8)th of the substance will have disintegrated, which corresponds to 60 days.
303 Medium
303 of 380
Understanding +4 | -1
Our bodies are mostly made of hydrogen (Z=1)(\mathrm{Z}=1), carbon (Z=6)(Z=6), and oxygen (Z=8)(Z=8). In our bodies, are there many more neutrons than protons, many fewer neutrons than protons, or are there about the same number of each?
View answer and explanation
Correct option: C
There are about the same number of neutrons and protons.
Option C (There are about the same number of neutrons and protons) is correct because for lighter elements like hydrogen, carbon, and oxygen, the number of neutrons is approximately equal to the number of protons.
304 Medium
304 of 380
Application +4 | -1
A radio active material is reduced to 1/81 / 8 of its original amount in 3 days. If 8×10−3 kg8 \times 10^{-3} \, \mathrm{kg} of the material is left after 5 days the initial amount of the material is
View answer and explanation
Correct option: D
256 g256 \, \mathrm{g}
Option D (256,g256 \\, \mathrm{g}) is correct because it is the initial amount calculated using the half-life and the amount remaining after 5 days.
305 Medium
305 of 380
Understanding +4 | -1
If the nuclear force between two protons, two neutrons and between proton and neutron is denoted by Fpp,Fnn\mathrm{F}_{\mathrm{pp}}, \mathrm{F}_{\mathrm{nn}} and Fpn\mathrm{F}_{\mathrm{pn}} respectively, then
View answer and explanation
Correct option: D
Fpp≠Fnn≠FpuF_{p p} \neq F_{n n} \neq F_{p u}
Option C (Fpp=Fnn=FpnF_{pp} = F_{nn} = F_{pn}) is correct because the nuclear force is approximately the same between any two nucleons regardless of whether they are protons or neutrons.
306 Medium
306 of 380
Analyzing +4 | -1
Assertion : Size of nucleus is constant in electron scattering or gamma scattering.

Reason : Electron scattering or gamma scattering is controlled by distribution of charge in
nucleus.
View answer and explanation
Correct option: C
If Assertion is True but the reason is false
Option C is correct because the size of the nucleus is determined by the distribution of nucleons (protons and neutrons), not just the charge distribution. Electron and gamma scattering can probe the size, but it's not solely controlled by charge.
307 Medium
307 of 380
Application +4 | -1
Natural water contains a small amount of tritium (13H)\left({ }_1^3 \mathrm{H}\right). This isotope beta-decays with a half-life of 12.5 years. A mountaineer while climbing towards a difficult peak finds debris of some earlier unsuccessful attempt. Among other things he finds a sealed bottle of whisky. On return he analyses the whisky and finds that it contains only 1.5 per cent of the 13H{ }_1^3 \mathrm{H} radioactivity as compared to a recently purchased bottle marked '8 years old'. Estimate the time of that unsuccessful attempt.
View answer and explanation
Correct option: A
About 83 years ago
Option A (About 83 years ago) is correct because it is calculated by using the radioactive decay formula and the given half-life of tritium to determine the time elapsed since the whisky was originally produced.
308 Medium
308 of 380
Analyzing +4 | -1
U238{U^{238}} decays into Th234T{h^{234}} by the emission of an α−\alpha - particle. There follows a chain of further radioactive decays, either by α−\alpha - decay or by β−\beta - decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. Which of the following stable nuclides is the end product of the U238{U^{238}} radioactive decay chain
View answer and explanation
Correct option: A
Pb206P{b^{206}}
Option A (Pb206P{b^{206}}) is correct because the (4n+2) series starts from U238{U^{238}} and its stable end product is Pb206P{b^{206}}.
309 Medium
309 of 380
Understanding +4 | -1
For the stability of any nucleus
View answer and explanation
Correct option: A
Binding energy per nucleon should be more
Option A is correct because a higher binding energy per nucleon indicates a more stable nucleus due to the greater energy required to separate the nucleons.
310 Medium
310 of 380
Understanding +4 | -1
During a nuclear fusion reaction
View answer and explanation
Correct option: D
Two light nuceli combine to give a heavier nucleus and possible other products
Option D (Two light nuceli combine to give a heavier nucleus and possible other products) is correct because nuclear fusion is the process where two light nuclei combine to form a heavier nucleus, releasing energy and potentially other particles.
311 Medium
311 of 380
Remembering +4 | -1
For maintaining sustained chain reaction, the following is required
View answer and explanation
Correct option: C
neutrons
Option C (neutrons) is correct because neutrons are required to sustain a chain reaction by inducing further fission events.
312 Medium
312 of 380
Application +4 | -1
If a proton and anti-proton come close to each other and annihilate, how much energy will be released
View answer and explanation
Correct option: B
3  ×  10−10  J3\,\, \times \,\,{10^{ - 10}}\,\,J
Option B (3  ×  10−10 J3\,\, \times \,\,{10^{ - 10}}\,J) is correct because the total energy released is twice the energy equivalent of the proton's mass.
313 Medium
313 of 380
Understanding +4 | -1
The rate of disintegration of fixed quantity of a radioactive element can be increased by
View answer and explanation
Correct option: D
It is not possible
Option D (It is not possible) is correct because the rate of radioactive decay is an intrinsic property of the element and is unaffected by external factors like temperature, pressure, or chemical reactions.
314 Medium
314 of 380
Remembering +4 | -1
The phenomenon of pair production is-
View answer and explanation
Correct option: D
The production of an electron and a positron from γ\gamma-rays.
Option D (The production of an electron and a positron from γ\gamma-rays) is correct because pair production is the process where a high-energy photon (gamma ray) transforms into an electron and a positron.
315 Medium
315 of 380
Understanding +4 | -1
Number of neutrons in a gold nucleus with A = 197 and Z = 79 is
View answer and explanation
Correct option: C
118
Option C (118) is correct because the number of neutrons (N) is calculated by subtracting the atomic number (Z) from the mass number (A): N = A - Z.
316 Medium
316 of 380
Understanding +4 | -1
Assertion: In He-Ne laser, population inversion takes place between energy level of neon atoms.

Reason: Helium atom has a metastable energy level.
View answer and explanation
Correct option: B
If both assertion and reason are true and reason is not correct explanation of assertion.
Option B (If both assertion and reason are true and reason is not correct explanation of assertion) is correct because both the assertion and reason are true, but the reason doesn't explain the assertion.
317 Medium
317 of 380
Understanding +4 | -1
Fusion reactions take place at high temperature because
View answer and explanation
Correct option: D
kinetic energy is high enough to overcome repulsion between nuclei
Option D (kinetic energy is high enough to overcome repulsion between nuclei) is correct because fusion requires overcoming the electrostatic repulsion between positively charged nuclei, which is achieved by high kinetic energy at high temperatures.
318 Medium
318 of 380
Application +4 | -1
An accident in a nuclear laboratory resulted in depostion of a certain amount of radioactive material of half - life 18 days inside the laboratory. Tests revealed that the radiation was 64 times more than the permissible level required for safe operation of the laboratory. What is the minimum number of days after which the laboratory can be considered safe for use?
View answer and explanation
Correct option: C
108
Option C (108) is correct because the radiation needs to decay for 6 half-lives (64=2664 = 2^6) to reach a safe level, thus 18×6=10818 \times 6 = 108 days.
319 Medium
319 of 380
Analyzing +4 | -1
Identify the pair of physical quantities that have same dimensions:
View answer and explanation
Correct option: D
wave number and Avogadro number
Option A (velocity gradient and decay constant) is correct because both have dimensions of inverse time [T⁻¹].
320 Medium
320 of 380
Application +4 | -1
If 50%50 \% of energy released during fission would be converted into electrical energy, then number of fissions in a second in a nuclear reactor of 6.4 MWMW output is (Energy per fission is 200 MeV200 \,{MeV} )
View answer and explanation
Correct option: C
4×10174 \times 10^{17}
Option C (4×10174 \times 10^{17}) is correct because it's calculated by dividing the effective power output by the energy released per fission.
321 Medium
321 of 380
Application +4 | -1
The half life of a radioactive substance is T\mathrm{T}. The time taken, for disintegrating 78\frac{7}{8} th part of its original mass will be:
View answer and explanation
Correct option: B
3T3 T
Option B (3T3T) is correct because after 3 half-lives, 78\frac{7}{8} of the original mass will have disintegrated, leaving 18\frac{1}{8} remaining.
322 Medium
322 of 380
Understanding +4 | -1
A radioactive nucleus AA finally transforms into a stable nucleus BB. Then AA and BB can be
View answer and explanation
Correct option: C
Isotopes
Option C (Isotopes) is correct because alpha and beta decays can change the number of neutrons and protons in the nucleus, resulting in isotopes.
323 Medium
323 of 380
Understanding +4 | -1
In which radioactive disintegration, neutron dissociates into proton and electron
View answer and explanation
Correct option: B
β−\beta - emission
Option B (β−\beta - emission) is correct because in beta-minus decay, a neutron in the nucleus transforms into a proton, an electron, and an antineutrino.
324 Medium
324 of 380
Analyzing +4 | -1
In the nuclear decay given below:

ZAX⟶Z+1AY⟶Z−1A−4 B∗⟶Z−1A−4 B, { }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \longrightarrow{ }_{\mathrm{Z}+1}^{\mathrm{A}}\mathrm{Y} \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B}^* \longrightarrow{ }_{\mathrm{Z}-1}^{\mathrm{A}-4} \mathrm{~B} \text {, }

the particles emitted in the sequence are
View answer and explanation
Correct option: D
β,α,γ\beta, \alpha, \gamma
Option D (β,α,γ\beta, \alpha, \gamma) is correct because the decays in the sequence correspond to beta, alpha, and gamma emissions, respectively.
325 Medium
325 of 380
Application +4 | -1
The decay constant of a radioactive element, which disintegrates to 20 grams from 40 grams in 100 minutes is
View answer and explanation
Correct option: A
0.00693  min⁡−10.00693\,\,{\min ^{ - 1}}
Option A (0.00693 min⁻¹) is correct because it's calculated directly from the half-life using the formula for the decay constant.
326 Medium
326 of 380
Application +4 | -1
Two radioactive substances A and B have decay constant 5λ  5\lambda \; and λ\lambda respectively. At t = 0 they have the same number of active nuclei. The ratio of number of active nuclei of A to those of B will be 2(1/e2)2\left( {1/{e^2}} \right) after a time interval
View answer and explanation
Correct option: C
1/2λ1/2\lambda
Option B (01:03) is correct because the amplitude ratio is the square root of the intensity ratio.
327 Medium
327 of 380
Understanding +4 | -1
Assertion: The magnetism of the magnet is due to the spin motion of electron.

Reason: The dipole moment of electron is smaller than that due to orbit motion around nucleus.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Option C (If assertion is true but reason is false) is correct because the magnetism of a magnet is primarily due to electron spin, but the spin dipole moment is generally larger.
328 Medium
328 of 380
Application +4 | -1
A radioactive material has a half life of 10  days\mathrm{10}\,\,\mathrm{days}. What fraction of the material would remain after 30  days\mathrm{30}\,\,\mathrm{days}
View answer and explanation
Correct option: C
0.125\mathrm{0}\mathrm{.125}
Option C (0.125\mathrm{0}\mathrm{.125}) is correct because after 30 days (3 half-lives), the fraction remaining is (1/2)3=1/8=0.125(1/2)^3 = 1/8 = 0.125.
329 Medium
329 of 380
Application +4 | -1
Calculate no. of fissions of U235U^{235} required per sec\mathrm{sec} to generate power of 10 KW10 \mathrm{~KW}.
View answer and explanation
Correct option: B
3.12×10143.12 \times 10^{14}
Option B (3.12×10143.12 \times 10^{14}) is correct because it is calculated by converting MeV to Joules and dividing the total energy by the energy per fission.
330 Medium
330 of 380
Application +4 | -1
In a radioactive material the activity at time t1{t_1} is R1{R_1} and at a later time t2{t_2}, it is R2{R_2}. If the decay constant of the material is λ\lambda , then
View answer and explanation
Correct option: D
R1=R2{R_1} = {R_2}
Option A (R1=R2e−λ(t1−t2){R_1} = {R_2}{e^{ - \lambda \left( {{{{t_1} - {t_2}}}} \right)}}) is correct because it correctly represents the relationship between activity and time based on the radioactive decay law.
Revision notes and key takeaways

Review NUCLEI in your textbook or class notes, then use this set to check your understanding.

Showing 301-330 of 380 questions

Your practice

0 / 380 answered · 380 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.