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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 388 questions

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181 Medium
181 of 388
Application +4 | -1
A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of 3 ms−23 \mathrm{~m} \mathrm{s}^{-2} for 0.5 minutes. If the maximum height reached by it is 80 m80 \mathrm{~m}, then the angle of projection is
(Take g=10 ms−2g=10 \mathrm{~m} \mathrm{s}^{-2} )
View answer and explanation
Correct option: C
tan⁡−1(49)\tan ^{-1}\left(\frac{4}{9}\right)
Option C (tan⁡−1(49)\tan ^{-1}(\frac{4}{9})) is correct because it's derived by relating the horizontal and vertical components of the projectile's initial velocity using the given maximum height and horizontal velocity information.
182 Medium
182 of 388
Analyzing +4 | -1
Two projectiles A and B are thrown with the same speed such that A makes angle q\mathrm{q} with the horizontal and B makes angle qq with the vertical, then
View answer and explanation
Correct option: D
Both may have same time of flight
Option D (Both may have same time of flight) is correct because the time of flight depends on the angle of projection, and they will be the same only if the angle is 45 degrees.
183 Medium
183 of 388
Analyzing +4 | -1
Consider the following statements about three vectors a→,b→\overrightarrow{{a}}, \overrightarrow{{b}} and c→\overrightarrow{{c}} that have non-zero magnitudes. It follows b→=c→\overrightarrow{{b}}=\overrightarrow{{c}}

(i) if a→⋅b→=a→⋅c→\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{b}}=\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{c}}

(ii) if a⃗×b⃗=a⃗×c⃗b⃗\vec{a} \times \vec{b}=\vec{a} \times \vec{c} \quad \vec{b} must be perpendicular to c→\overrightarrow{\mathrm{c}}
View answer and explanation
Correct option: C
(i) only
Option B is correct because neither statement (i) nor (ii) necessarily implies that b→=c→\overrightarrow{{b}}=\overrightarrow{{c}} when dealing with dot and cross products of vectors.
184 Medium
184 of 388
Analyzing +4 | -1
Statement-I: Two bodies thrown with same speed from the same point at the same instants but at different angles never collide in air.
Statement-II: xx and yy co-ordinates of the two projectiles always differ
View answer and explanation
Correct option: A
Both statements are true
The correct answer is D because both statements are false. The resistivity of a semiconductor decreases with temperature, and the reason is incorrect.
185 Medium
185 of 388
Understanding +4 | -1
Statement-I: Minimum number of non-equal vectors in a plane required to give zero resultant is three.
Statement-II: If a⃗+b⃗+c⃗=0\vec{a}+\vec{b}+\vec{c}=0, then they must lie in one plane
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct. Three non-equal vectors are needed for a zero resultant in a plane, and if the sum of vectors is zero, they must be coplanar.
186 Medium
186 of 388
Analyzing +4 | -1
Assertion: Two projectiles of masses mm and 4m4m when projected with same initial velocity vector have different ranges.
Reason: The horizontal range of a projectile depends on mass of the body.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct. The range of a projectile depends on initial velocity and angle of projection, not mass. Therefore, both the assertion and reason are false.
187 Medium
187 of 388
Understanding +4 | -1
The component of a vector r along X-axis will
have a maximum value, if :
View answer and explanation
Correct option: A
r is along positive X-axis
Option A (r is along positive X-axis) is correct because the component of a vector along the X-axis is maximized when the vector is aligned with the X-axis.
188 Medium
188 of 388
Application +4 | -1
A body constrained to move along the zz-axis of a co-ordinate system is subjected to a constant force F⃗\vec{F} given by F⃗=−i^+2j^+3k^\vec{F}=-\hat{i}+2 \hat{j}+3 \hat{k} newton where i^,j^\hat{i}, \hat{j} and k^\hat{k} represent unit vectors along x,yx,y and zz-axis of the system respectively. Calculate the work done by the force in displacing the body through a distance of 4 m4 \mathrm{~m} along the zz-axis.
View answer and explanation
Correct option: A
12 joule12 \text { joule}
Option A (12 joule12 \text { joule}) is correct because only the force component along the z-axis contributes to the work done when the displacement is along the z-axis.
189 Medium
189 of 388
Application +4 | -1
A particle moves in XYX Y-plane from positions (2 m,4 m)(2 \mathrm{~m}, 4 \mathrm{~m}) to (6 m,8 m)(6 \mathrm{~m}, 8 \mathrm{~m}) is 2 s2 \mathrm{~s}. Magnitude and direction of average velocity is
View answer and explanation
Correct option: B
22 ms−12 \sqrt{2} \mathrm{~ms}^{-1} and 45∘45^{\circ}
Option B (22 ms−12 \sqrt{2} \mathrm{~ms}^{-1} and 45∘45^{\circ}) is correct because it is calculated by finding the displacement vector and dividing by the time interval to get the average velocity, then finding its magnitude and direction.
190 Medium
190 of 388
Understanding +4 | -1
Can scalar product be ever negative?
View answer and explanation
Correct option: A
P⃗.Q⃗\vec{P} . \vec{Q} will be negative
Option A (P⃗.Q⃗\vec{P} . \vec{Q} will be negative) is correct because the scalar product is negative when the angle between the vectors is greater than 90 degrees.
191 Medium
191 of 388
Remembering +4 | -1
Which of the following statement is correct?
View answer and explanation
Correct option: A
Displacing a vector parallel to itself leaves the vector unchanged
Option A (Displacing a vector parallel to itself leaves the vector unchanged) is correct because a vector is defined by its magnitude and direction, which remain constant when displaced parallel to itself.
192 Medium
192 of 388
Analyzing +4 | -1
Assertion: A coin is allowed to fall in a train moving with constant velocity. Its trajectory is a straight line as seen by an observer attached to the train.
Reason: An observer on ground will see the path of coin as a parabola.
View answer and explanation
Correct option: B
If both Assertion & reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & reason are True but Reason is not a correct explanation of the Assertion) is correct because both the trajectory inside the train is a straight line and the trajectory observed from the ground is a parabola, but the reason doesn't explain the assertion.
193 Medium
193 of 388
Understanding +4 | -1
Two vectors are perpendicular, if
View answer and explanation
Correct option: C
A→⋅B→=0\overrightarrow{\mathrm{A}} \cdot \overrightarrow{\mathrm{B}}=0
Option C (A→⋅B→=0\overrightarrow{\mathrm{A}} \cdot \overrightarrow{\mathrm{B}}=0) is correct because the dot product of two perpendicular vectors is zero, as the cosine of 90 degrees is zero.
194 Medium
194 of 388
Analyzing +4 | -1
Assertion: Generally the path of a projectile from the earth is parabolic but it is elliptical for projectiles going to a very great height.

Reason: Up to ordinary height the projectile moves under a uniform gravitational force, but for great heights, projectile moves under a variable force.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why the projectile's path changes from parabolic to elliptical at great heights due to the varying gravitational force.
195 Medium
195 of 388
Application +4 | -1
The horizontal and vertical displacements xx and yy of projectile at a given time tt are given by x=12 t mx = 12\,t\,m and y=5t−5t2 my = 5t - 5{t^2}\,m. The range of the projectile in metres is
View answer and explanation
Correct option: B
12
Option B (12) is correct because the range is calculated by finding the time of flight and then using the horizontal displacement equation.
196 Medium
196 of 388
Analyzing +4 | -1
Which of the following is not true? If A⃗=3i^+4j^\vec{A}=3 \hat{i}+4 \hat{j} and B⃗=6i^+8j^\vec{B}=6 \hat{i}+8 \hat{j} where AA and BB are the magnitudes of A→\overrightarrow{\mathrm{A}} and B→\overrightarrow{\mathrm{B}}
View answer and explanation
Correct option: C
A⃗⋅B⃗=48\vec{A} \cdot \vec{B}=48
Option C is correct because the dot product of vectors A and B is calculated to be 50, not 48.
197 Medium
197 of 388
Application +4 | -1
The resultant of two forces 3P and 2P is R. If the first force is doubled them the resultant is also doubled. The angle between the two forces is
View answer and explanation
Correct option: B
1200\mathrm{12}{\mathrm{0}^0}
Option B (1200\mathrm{12}{\mathrm{0}^0}) is correct because the angle between the two forces is found by solving the resultant equations.
198 Medium
198 of 388
Application +4 | -1
A force is inclined at 50∘50^{\circ} to the horizontal. If its rectangular component in the horizontal direction be 50 N50 \mathrm{~N}, find the magnitude of the force and its vertical component.
View answer and explanation
Correct option: A
59.58 N59.58 \mathrm{~N}
Option A (59.58 N) is correct because it is the vertical component of the force, calculated using trigonometry.
199 Medium
199 of 388
Analyzing +4 | -1
Assertion: Adding a scalar to a vector of the same dimensions is a meaningful algebraic operation.
Reason : Displacement can be added to distance.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because adding a scalar to a vector is not a meaningful operation, and displacement cannot be added to distance.
200 Medium
200 of 388
Understanding +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: When a body is projected at an angle 45∘,45^{\circ}, it's range is maximum.

Reason R: For maximum range, the value of sin⁡2θ\sin 2 \theta should be equal to one.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: C
Both A and R are correct and R is the correct explanation of A
Option C (Both A and R are correct and R is the correct explanation of A) is correct because the maximum range of a projectile occurs at 45 degrees, which is when sin(2θ) = 1.
201 Medium
201 of 388
Application +4 | -1
The resultant of the tow vectors having magnitude 2 and 3 is 1. What is their cross product.
View answer and explanation
Correct option: D
0
Option D (0) is correct because if the resultant of two vectors is the difference of their magnitudes, the angle between them is 180 degrees, making the cross product zero.
202 Medium
202 of 388
Analyzing +4 | -1
It is found that ∣A+B∣=∣A∣,\left| {A + B} \right| = \left| A \right|, this necessarily implies
View answer and explanation
Correct option: A
B=0B = 0
Option A (B=0B = 0) is correct because if the magnitude of A+B is equal to the magnitude of A, then B must be a zero vector.
203 Medium
203 of 388
Application +4 | -1
One fielder throws a ball and in 4 secs it reaches to another player. So, the maximum height reached by the ball above the point of projection would be about
View answer and explanation
Correct option: D
20 m20 \mathrm{~m}
Option D (20 m20 \mathrm{~m}) is correct because it is calculated using the time of flight and the formula for maximum height.
204 Medium
204 of 388
Application +4 | -1
A projectile is fired at an angle of 30° to the horizontal such that the vertical component of its initial velocity is 80  ms−180\mathrm{\;m}{\mathrm{s}^{ - 1}}. Its time of flight is T. Its velocity at t=T4t = \frac{T}{4} has a magnitude of nearly
View answer and explanation
Correct option: C
140 ms−1140\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option C (140  ms−1140\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because it is the magnitude of the velocity at t=T/4, calculated using projectile motion principles.
205 Medium
205 of 388
Analyzing +4 | -1
The angle between vector Q→\overrightarrow{Q} and the resultant of (2Q→+2P→)(2 \overrightarrow{Q}+2 \overrightarrow{{P}}) and (2Q→−2P→)(2 \overrightarrow{{Q}}-2 \overrightarrow{{P}}) is:
View answer and explanation
Correct option: A
0∘0^{\circ}
Option A (0∘0^{\circ}) is correct. The resultant vector is in the same direction as Q→\overrightarrow{Q}, making the angle between them zero.
206 Medium
206 of 388
Application +4 | -1
Two forces of 5 N5 \mathrm{~N} and 7 N7 \mathrm{~N} act on a particle with an angle of 60∘60^\circ between them. Find the resultant force.
View answer and explanation
Correct option: A
35∘29′35^\circ 29'
The correct answer is A (35∘29′35^\circ 29'), which is the angle the resultant force makes with the 5N force, calculated using the formula for the resultant of two vectors.
207 Medium
207 of 388
Application +4 | -1
The torque force Fˉ=2i−3j+4k\bar F = 2i - 3j + 4k newtons acting at the point rˉ=3i+2j+3k\bar r = 3i + 2j + 3k meters about the origin is
View answer and explanation
Correct option: B
17iˉ−6jˉ−13kˉ 17\bar i - 6\bar j - 13\bar k\,
Option D (−17iˉ+6jˉ+13kˉ- 17\bar i + 6\bar j + 13\bar k) is incorrect. The correct answer is B (17iˉ−6jˉ−13kˉ 17\bar i - 6\bar j - 13\bar k\,) because it is the correct cross product of rˉ\bar r and Fˉ\bar F.
208 Medium
208 of 388
Understanding +4 | -1
Choose the wrong statement.
View answer and explanation
Correct option: B
Two vectors of different magnitudes can be combined to give a zero resultant.
Option B (Two vectors of different magnitudes can be combined to give a zero resultant) is correct because two vectors can only result in zero if they have equal magnitudes and opposite directions.
209 Medium
209 of 388
Application +4 | -1
An ant starts from the origin and crawls 10 cm10 \mathrm{~cm} along the xx - axis and then 20 cm20 \mathrm{~cm} along the y−y- axis. The dot product of the ant's displacement vector with the position vector of a point that makes 45∘45^{\circ} with the xx - axis and has a magnitude of 2 cm\sqrt{2} \mathrm{~cm} is
View answer and explanation
Correct option: A
30 cm30 \mathrm{~cm}
Option A (30 cm30 \mathrm{~cm}) is correct because it is the dot product of the ant's displacement vector and the position vector of the point.
210 Medium
210 of 388
Understanding +4 | -1
Minimum number of vectors of unequal magnitude whose vector sum can equal to zero is
View answer and explanation
Correct option: B
Three
Option B (Three) is correct because at least three vectors of unequal magnitude are needed to form a closed polygon (triangle) resulting in a zero vector sum.
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