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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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121 Medium
121 of 388
Application +4 | -1
Find a vector whose length is 7 and which is perpendicular to each of the vectors: A⃗=2i^−3j^+6k^ and B⃗=i^+j^−k^\vec{A}=2 \hat{i}-3 \hat{j}+6 \hat{k} \text { and } \vec{B}=\hat{i}+\hat{j}-\hat{k}
View answer and explanation
Correct option: A
12(−3i^+8j^+5k^)\frac{1}{\sqrt{2}}(-3 \hat{i}+8 \hat{j}+5 \hat{k})
The correct answer is A (12(−3i^+8j^+5k^)\frac{1}{\sqrt{2}}(-3 \hat{i}+8 \hat{j}+5 \hat{k})) because it is a vector of length 7 that is perpendicular to both given vectors, found using the cross product.
122 Medium
122 of 388
Application +4 | -1
The resultant of two forces acting at an angle of 150∘150^{\circ} is 10 N10 {~N} and is perpendicular to one of the forces. One of the two other forces is
View answer and explanation
Correct option: C
20 N20 {~N}
Option C (75.52∘75.52^{\circ}) is correct because the angle between the two vectors is calculated using the law of cosines.
123 Medium
123 of 388
Application +4 | -1
A ball is projected horizontally from the top of a building 80 m high. If the line joining the point of projection to the point where it hits the ground makes an angle of 45∘45^{\circ} to the horizontal, the initial velocity of the ball is
View answer and explanation
Correct option: A
20 ms−120 \mathrm{~ms}^{-1}
Option A (20 ms−120 \mathrm{~ms}^{-1}) is correct because it is the initial velocity calculated using projectile motion principles and the given angle.
124 Medium
124 of 388
Understanding +4 | -1
Assertion: A projectile that traverses a parabolic path shows deviation from its idealized trajectory in the presence of air resistance.

Reason: Air resistance affects the motion of the projectile.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A is correct because air resistance, a dissipative force, affects the trajectory of a projectile, causing it to deviate from its ideal parabolic path.
125 Medium
125 of 388
Application +4 | -1
The magnitude of i^+j^\hat{i}+\hat{{j}} is
View answer and explanation
Correct option: C
2\sqrt{2}
Option C (2\sqrt{2}) is correct because the magnitude of a vector is calculated using the square root of the sum of the squares of its components.
126 Medium
126 of 388
Application +4 | -1
The equation of trajectory of an oblique projectile is y=x−12x2y=x-\frac{1}{2} x^2. The time of flight of projectile will be.
View answer and explanation
Correct option: A
2g\frac{2}{\sqrt{g}}
Option A (2g\frac{2}{\sqrt{g}}) is correct because it is the time of flight calculated by comparing the given trajectory equation with the standard equation and using the formula for time of flight.
127 Medium
127 of 388
Analyzing +4 | -1
Statement-I: If a⃗⋅b⃗=b⃗⋅c⃗\vec{a} \cdot \vec{b}=\vec{b} \cdot \vec{c}, then a⃗\vec{a} may not always be equal to c⃗\vec{{c}}.
Statement-II: The dot product of two vectors involves cosine of the angle between the two vectors.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct. Statement-I is true because the dot product doesn't guarantee vector equality, and Statement-II is true because the dot product involves the cosine of the angle between the vectors.
128 Medium
128 of 388
Understanding +4 | -1
Statement-I: If dot product and cross product of a⃗\vec{a} and b⃗\vec{b} are zero, it implies that one of the vector a⃗\vec{a} and b⃗\vec{b} must be a null vector.
Statement-II: Null vector is a vector with zero magnitude.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because both statements are factually accurate and logically consistent.
129 Medium
129 of 388
Analyzing +4 | -1
Two boys PP and QQ are playing on a river bank. PP plans to swim across the river directly and come back. QQ plans to swim downstream by a length equal to the width of the river and then come back. Both of them bet each other, claiming that the boy succeeding in less time will win. Assuming the swimming rate of both PP and QQ to the same, it can be concluded that
View answer and explanation
Correct option: A
PP wins
Option A (PP wins) is correct because the time taken by P to swim across and back is less than the time taken by Q.
130 Medium
130 of 388
Analyzing +4 | -1
A river flows with a speed more than the maximum speed with which a person can swim in still water. He intends to cross the river by the shortest possible path (i.e., he wants to reach the point on the opposite bank which directly opposite to the starting point). Which of the following is correct?
View answer and explanation
Correct option: D
The man cannot cross the river in that way.
Option D (The man cannot cross the river in that way) is correct because the swimmer's speed is less than the river's speed, making it impossible to swim directly across.
131 Medium
131 of 388
Application +4 | -1
If a⃗+b⃗\vec{a}+\vec{b} is perpendicular to a⃗\vec{a} and 2a⃗+b⃗2 \vec{a}+\vec{b} is perpendicular to b⃗\vec{b}. Then ∣b⃗∣∣a⃗∣\frac{|\vec{b}|}{|\vec{a}|} is
View answer and explanation
Correct option: B
2\sqrt{2}
Option B (2\sqrt{2}) is correct because it is derived from the dot product conditions given, leading to the ratio of magnitudes.
132 Medium
132 of 388
Application +4 | -1
The position of a particle is given by r⃗=3.0ti^+2.0t2j^+5.0k^\vec{r}=3.0 t \hat{i}+2.0 t^2 \hat{j}+5.0 \hat{k} where tt is in seconds and the coefficients have the proper units for rr to be in metres. Find v(t)v(t) and a(t)a(t) of the particle.
View answer and explanation
Correct option: A
3.0i^+4.0tj^,+4.0j^3.0 \hat{i}+4.0 t \hat{j}, +4.0 \hat{j}
Option A (3.0i^+4.0tj^,+4.0j^3.0 \hat{i}+4.0 t \hat{j}, +4.0 \hat{j}) is correct because it is found by taking the first and second derivatives of the position vector with respect to time.
133 Medium
133 of 388
Understanding +4 | -1
If the angle between the vectors A⃗\vec{A} and B⃗\vec{B} is θ\theta, the value of the product (B→×A→)⋅A→(\overrightarrow{{B}} \times \overrightarrow{{A}}) \cdot \overrightarrow{{A}} is equal:
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the scalar triple product of vectors where one vector is repeated is always zero, as the cross product results in a vector orthogonal to A, and the dot product of orthogonal vectors is zero.
134 Medium
134 of 388
Application +4 | -1
A body is projected with speed v  ms−1v\;\mathrm{m}{\mathrm{s}^{ - 1}} at angle θ\theta. The kinetic energy at the highest point is half of the initial kinetic energy. The value of θ\theta is
View answer and explanation
Correct option: B
450{45^0}
Option B (450{45^0}) is correct because at the highest point, the kinetic energy is half the initial kinetic energy, implying cos⁡2θ=12\cos^2 \theta = \frac{1}{2}, thus θ=45∘\theta = 45^\circ.
135 Medium
135 of 388
Application +4 | -1
A large number of bullets are fired in all directions with same speed v. What is the maximum area on the ground on which these bullets will spread
View answer and explanation
Correct option: B
πv4g2\pi \frac{{{v^4}}}{{{g^2}}}
Option B (πv4g2\pi \frac{{{v^4}}}{{{g^2}}}) is correct because the maximum area is determined by the maximum range of the projectiles, which occurs at an angle of 45 degrees.
136 Medium
136 of 388
Understanding +4 | -1
Three balls are projected from the top of a building with equal speeds but at different angles. Balls strike the ground with velocities v1{v} 1, v2v2 and v3{v} 3 respectively, then
View answer and explanation
Correct option: C
v1=v2=v3{v} 1={v} 2={v} 3
Option C (v1=v2=v3{v} 1={v} 2={v} 3) is correct because the speed at which the balls strike the ground depends only on the initial speed and the height, not the angle of projection.
137 Medium
137 of 388
Analyzing +4 | -1
Of the vectors given below, the parallel vectors are,

A⃗=6i^+8j^B⃗=210i^+280k^C⃗=5.1i^+6.8j^D⃗=3.6i^+6j^+48k^\begin{aligned} & \vec{A}=6 \hat{i}+8 \hat{j} \\ & \vec{B}=210 \hat{i}+280 \hat{k} \\ & \vec{C}=5.1 \hat{i}+6.8 \hat{j} \\ & \vec{D}=3.6 \hat{i}+6 \hat{j}+48 \hat{k} \end{aligned}
View answer and explanation
Correct option: B
A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}
Option B is correct because vectors A and C have proportional components, indicating they are parallel.
138 Medium
138 of 388
Analyzing +4 | -1
If a2+b2+c2=1a^2+b^2+c^2=1 where a,b,c∈Ra, b, c \in R, then the maximum value of (4a−3b)2+(5b−4c)2+(3c−5a)2(4 a-3 b)^2+(5 b-4 c)^2+(3 c-5 a)^2 is
View answer and explanation
Correct option: B
50
Option B (50) is correct because the maximum value is found using vector properties and the Cauchy-Schwarz inequality.
139 Medium
139 of 388
Analyzing +4 | -1
Statement-I: If a⃗\vec{a} is perpendicular to b⃗\vec{b} and c→\overrightarrow{{c}}, then a→×(b→×c→)=0\overrightarrow{{a}} \times(\overrightarrow{{b}} \times \overrightarrow{{c}})=0
Statement-II: If b→\overrightarrow{{b}} is perpendicular to c→\overrightarrow{{c}}, then b→×c→=0\overrightarrow{{b}} \times \overrightarrow{{c}}=0
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B is correct because if a⃗\vec{a} is perpendicular to both b⃗\vec{b} and c⃗\vec{c}, then b⃗×c⃗\vec{b} \times \vec{c} will not be zero, and a⃗×(b⃗×c⃗)\vec{a} \times (\vec{b} \times \vec{c}) will be non-zero, and b⃗\vec{b} being perpendicular to c⃗\vec{c} does not mean their cross product is zero.
140 Medium
140 of 388
Application +4 | -1
Two objects are projected with same velocity ' uu ' however at different angles α\alpha and β\beta with the horizontal. If α+β=90∘\alpha+\beta=90^{\circ}, the ratio of horizontal range of the first object to the 2nd object will be :
View answer and explanation
Correct option: D
1:11: 1
Option D (1:11:1) is correct because the horizontal range is the same for complementary angles of projection.
141 Medium
141 of 388
Understanding +4 | -1
A football is kicked into the air vertically upwards with velocity u.u. The velocity of the ball at the highest point is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because at the highest point of its trajectory, the football momentarily stops moving upwards before it starts falling back down, hence its vertical velocity is zero.
142 Medium
142 of 388
Understanding +4 | -1
If vectors i^−3j^+5k^\hat{i}-3 \hat{j}+5 \hat{k} and i^−3j^−ak^\hat{i}-3 \hat{j}-a \hat{k} are equal vectors, then the value of aa is
View answer and explanation
Correct option: D
-5
Option D (-5) is correct because for two vectors to be equal, their corresponding components must be equal.
143 Medium
143 of 388
Understanding +4 | -1
Assertion: Angle between i^+j^\hat{i}+\hat{j} and i^\hat{i} is 45∘45^{\circ}.
Reason: i^+j^\hat{i}+\hat{j} is equally inclined to both i^\hat{i} and j^\hat{j} the angle between i^\hat{i} and j^\hat{j} is 90∘90^{\circ}.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A is correct because both the assertion and reason are true, and the reason correctly explains why the angle is 45 degrees.
144 Medium
144 of 388
Analyzing +4 | -1
Assertion: Flight path of an object moving under the acceleration due to gravity can be straight line or a parabola depending on the initial conditions.
Reason: The shape of the flight path of the motion of an object is determined by the acceleration only.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct. The assertion is true because trajectory depends on initial conditions, but the reason is false as trajectory depends on both acceleration and initial conditions.
145 Medium
145 of 388
Understanding +4 | -1
When forces P⃗1,P⃗2,P⃗3\vec{P}_1, \vec{P}_2, \vec{P}_3 are acting on a particle of mass (m)(m) such that P⃗2\vec{P}_2 and P⃗3\vec{P}_3 are mutually perpendicular if particle remains stationary then
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the given conditions are valid when the particle is stationary under the influence of the given forces.
146 Medium
146 of 388
Analyzing +4 | -1
If none of the vectors A⃗,B⃗\vec{A}, \vec{B} and C⃗\vec{C} are zero and if A⃗×B⃗=0\vec{A} \times \vec{B}=0 and B→×C→=0\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}=0, then the value of ∣A⃗×C⃗∣|\vec{A} \times \vec{C}| is
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because if A⃗×B⃗=0\vec{A} \times \vec{B} = 0 and B⃗×C⃗=0\vec{B} \times \vec{C} = 0, then A⃗\vec{A}, B⃗\vec{B}, and C⃗\vec{C} are parallel, making A⃗×C⃗=0\vec{A} \times \vec{C} = 0.
147 Medium
147 of 388
Application +4 | -1
A hiker stands on the edge of a cliff 490 m490 \mathrm{~m} above the ground and throws a stone horizontally with an intial speed of 15 m/s15 \mathrm{~m} / \mathrm{s}. Neglecting air resistance. Find the time taken by the stone to reach the ground, and the speed with which it hits the ground (g=9.8 m/s2)\left({g}=9.8 \mathrm{~m} / \mathrm{s}^2\right):
View answer and explanation
Correct option: B
10 sec,99 m/s10 \mathrm{~sec}, 99 \mathrm{~m} / \mathrm{s}
Option B (10 sec,99 m/s10 \mathrm{~sec}, 99 \mathrm{~m} / \mathrm{s}) is correct because it accurately calculates the time of flight and final velocity of the stone using kinematic equations.
148 Medium
148 of 388
Analyzing +4 | -1
Statement I: For angle of projection tan⁡−1(4)\tan ^{-1}(4), the horizontal range and maximum height are equal.

Statement II: The maximum range of projectile is directly proportional to square of velocity and inversely proportional to acceleration of gravity.
View answer and explanation
Correct option: B
If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I
Option B (If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I) is correct because both statements are true, but the second statement does not explain the first.
149 Medium
149 of 388
Understanding +4 | -1
Assertion: If the initial and final positions coincide, the displacement is a null vector.
Reason: A physical quantity cannot be called a vector, if its magnitude is zero.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because while a null displacement vector is possible, a physical quantity can have a magnitude of zero and still be a vector.
150 Medium
150 of 388
Analyzing +4 | -1
A particle has been projected with a speed of 20 ms−120 \mathrm{~ms}^{-1} at an angle of 30∘30^{\circ} with the horizontal. The time taken when the velocity vector becomes perpendicular to the initial velocity vector is
View answer and explanation
Correct option: D
Not possible in this case
Option D is correct. The time when the velocity vector becomes perpendicular to the initial velocity vector is not possible because it occurs after the time of flight.
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